I'm currently doing some research for the World Cup (Soccer) and I want to create a formula that finds the largest gap between two dates. Basically, I'm copy and pasting player data into an Excel template I've created and one of the columns in each player's data is a list of dates when he has played over the last 12 months. I want to create a formula that shows me the length (in days) of his longest break from playing competitive football AFTER Oct 1st 2013.
I want to take two dates, a start date and an end date and get the number of days elapsed.
I also want to enter the dates quickly, as in 070808 for 07/08/08 (not having to enter the dashes). I have tried 00/00/00 and ##"/"##"/"## in the cells format, number, custom.
Using that format, entering 070808 in A1, and 070809 for A2 and finally in A3 =DATEDIF(A4,B4,"d") to get the difference in days. What I get is 1 day instead of 365 days. So it's thinking 70809 - 70808 = 1.
How do I get it to give me 365 days? What format can I use in the date cells?
I am trying choose the nearest date, from todays date out of a small array of numbers, and then also find the number of days between them. Additional to that, i would like it to ignore a date if that is in the past i.e. <now(). So I have a list of dates in column a, and i would like it to show me the number of days till the next closest 1, considering it hasnt passed already. I have tried many different ways and itteration of IF statement to solve this 1 but just cannot do it.
Formula query Column “A” list of dates correspondence in Column “B” list of dates correspondence reply out Need to calculate how many times the difference between date in and reply date is <= 5 in a specific time period.
The start date is entered in say, “K1” The end date is entered in say, “L1”
Also calculate difference in dates between 14 days and 21 days for time period Also with reply in column “B” not sent until over 28 days. I have tried SUMPRODUCT with (date_in=K1)*(date_out<=L1) for the dates but unsure how to define <=5
I need to calculate the amount of time between two dates, and show it in the number of hours and minutes. My dates are formatted to show the time in Zulu time. So 1406 = 2:06PM.
Here is what I have:
A1 = 6/4/08 1406Z B1 = 6/5/08 0402Z
For this example, the formula should return a result of 13 hours and 58 minutes. With the result, there is no need to desingate Zulu time with a 'Z'. But I need the result in a format that will allow me to calculate an average for all my data.
I work at a call center and I get the data as Date, Time of calling and Duration of the call. Now since this is an overseas call center, even though the calls spills over 12midnight, the corresponding date shows as the date when the agent logged in.
So I get the data in this format, Date: 06/11/2012, Time: 19:00:00 - 04:00:00.
How do I calculate the time difference at one go without first getting the time difference from the time of login till midnight and then add that to the time difference of midnight till time of logout. I have attached a file for your review.
I am trying to figure out what formula to use to calculate the difference between the creation date and resolved date in hours and days. That is, In once column I would like to see the difference in 'hours' and in another column I would like to see the difference in 'days'.
say C2= 22/02/2007. in cell C4 When I use this formula =TODAY()-C2 to get the difference between today and a past date the result the formula give is 07/05/1900 i would like to receive the difference in Months between the past date and today? I.E. HOW MANY MONTHS IN BETWEEN
how to calculate the difference in value of an item between two dates on a pivot table. I have one table that feeds the Pivot Table and it has three fields:
Data as of Date Item Value
So each day, the Data as of Date is updated to the current day and the items are the same but the values are different. I need to calculate the difference in value between the most recent date and x days ago. I cannot figure out how to do this via Pivot Table.
I'm just trying to calculate the difference between dates in two columns and applying conditional formatting based on if it is a positive or negative number. But when there is a null value in either of the date columns I don't want anything returned.
So far I'm either getting a 0 or a FALSE.
Column A = Date 1 Column B = Date 2 Column C = Formula
I am having difficulty finding the difference between two times and dates in Excel. I have researched this on Google and tried several formulas but none have worked for me. The format the data is currently in can be seen below:
From the below example, I would need to know the difference between date & time of Received and Resolved in number of days. Meaning - time difference should also be calculated in days
CELL ACELL BCELL CCELL DCELL E - REQUIRED OUTPUTReceived DateReceived TimeResolved DateResolved TimeTurn Around Time - IN DAYS20-Jan-122:43:00 PM23-Jan-124:50:00 PMDifference between Resolved date & time and Received date & time
I have two Rows of data. Each row contains a unique Name column and separate columns for Date, Hour and Minute. I would like to calculate the Time difference in Days, Hours and Minutes between the two Dates. I’m not sure if the way I’ve set it up is the most practical. I’ll attach the spreadsheet to better explain.
I need to calculate the date difference between two dates and get the result in the number of years and proportion of months ie;
20/09/99 to 01/02/02 is 2.33333333 years. I can use the DATEDIF function to get 2 years 4 months as the result but for the calc I'm doing I need it in the format of 2.33333333. Thinking I just need to tweak the DATEDIF a bit but just can't work it out!
I have a vacation data of my company. I want to calculate difference between two dates (relieving date & rejoining date) after excluding holiday(which I will decide as per my company policy) also note that now i m in gulf country hence here Friday is weekly off not Sunday.
I wanted to calculate the difference between dates, excluding the weekends. After much thought i used =NETWORKDAYS(A1,B1)+IF(NETWORKDAYS(A1,A1)+ NETWORKDAYS(B1,B1)=2,-SIGN(NETWORKDAYS(A1,B1)),0) that seemed to be working fine. However, I had a problem today with this formula when my start day was saturday (24/05/08) and the last day was monday (26/05/08). What i want is that when i take the difference between these two days, i should get zero as answer as we are not including the weekends in calculation so the start date should ideally be the first weekday which is Monday. However, the formula is giving me 1 as an answer.
This formula works fine if i select 27/05/08 as last date in which case i get 2 as an answer which is right. In gist, what i am looking for is a formula which will give me the difference between two dates and exclude the weekends from the calculation. The last date can't be a weekend, but the start date can. Hence, whenever the start date is a weekend, the formula should take monday as a start day.
I am attempting to get the formula in Column "E" (see attached excel file) to work based off the individual reps 'days off / holidays' (Columns K:P (or more as needed) that they might have. the formula I am using (which works fine) is:
My issue comes up when I am coping this formula for say 100+ rows. When I copy the formula to all of the rows, the (COUNTIF($K$2:$S$2) becomes static and does not realize that the row (ie. Row 26 Rep C) has different days off than Rep A. I can manually change the reference for the countif to specify the correct row to their own days but that becomes tedious very quickly. I was wondering if anyone has come across a way to make the countif work based off of that the name in Column B matches the name in Column G then looks 'to the right' and uses the 'days off' that are listed for the corresponding Rep. I have tried a few different ideas but nothing has worked so far.
I have two rows of data (A & D) which I would like to determine the amout of time spent for each issue. The value in both column appears as DD/MMM/YY HH:MM:SS. I am looking for a formula to obtain the below result.