Finding Interest Rate Using Loan Constant - Iterative Calculation

Apr 9, 2014

I have a created a Data Chart Below. A - C are the columns and 1-7 are the rows. I have hard-coded the equation in cell B5 that I am using.

What I want to do is input an number into B3 that automatically makes Cell B5 equal to Cell C1. Is there a process in excel you can use to do this. Or do you just have to use trial and error?

A B C
1Loan Amount$10,500,000 0.0730041581143804
2Term 10 years
3Rate
4Amortization30 years
5Constant (K) =PMT(B3/12,(B4*12),-1000)*0.012
6Annual Payment$766,544
7Monthly Payment$63,879

Example is attached.

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Effective Rate Calculation, Interest Only Loan

Aug 27, 2008

I have a calculation I do that calculates a clients "effective interest rate" if they make extra payments towards principal.. Calculation works fine.. However, I am now trying to figure out how to amend that code if it's an interest only loan, anyone have any ideas?

Here is the effective rate calcs on a random normal amortization loan:

this is in B2, and answer is 7%
=RATE(B4*B5,-((B3+B7)/B6),B7)*12

B3 = Total*Interest 279017.8
B4 = #*Years*in*Loan 30
B5 = #*Payments*/*Year 12
B6 = Total*Payments 360
B7 = Beginning*Principal 200000
B8 - Ending*Balance 0
problem is when someone is on an interest only loan they pay more interest than a normal amortization because they are not reducing the principal in the first x number of years. So I need to compare the interest only effective rate to an interest only loan.

Here is the example I'm working on... A client's loan is the following:
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interest rate - 6.15
30 year amortization
10 years interest only

normal client would pay an interest only payment of 674.13, then after i/o period would go to 953.80 for last 20 years of the loan, and they'd pay about $178k in interest.. Now if that client pays an extra 1,000 per year, I can calculate the amount of interest they'd accrue, but have no clue how to back into the "effective interest rate", basically that says you are paying the same amount of interest as someone with a x.xx% interest only loan.

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