Overflow / Declaration
Jan 2, 2007The following is not working for me with an overflow #6 error.
Sub multiplythis()
Dim highnumber ' As Long, I've tried Double, Long and now Variant
highnumber = 50 * 250 * 300 * 400 * 20
End Sub
ADVERTISEMENT
OverFlow Error "Overflow" In For Loop
Aug 9, 2009I used to have a ton of experience with Java and C# but now my job calls for VB scripts in excel. Probably an assignment error or logic error but here's the ....
i m doing is i have two workbooks "New Dashboard" and "Book1". I search column A in Book1 for HELLO, and then i use the row it was found in to grab a value "HrsVal". I take that value and i put it "New Dashboard". I then do the same for every sheet. It seems to fail in my second loop in the 2nd sheet. Error says "Overflow".
Variable Declaration
Jan 7, 2008I've been asked to produce a spread sheet that will calculate split payments for a list of households built by our company. The bill amount will be given to us by the power company, and the basis for bill separation is base on the billing period, and the date of house settlement.
The codes I've produced are written below, however I couldn't get it to run properly. The software keeps on telling me that my variables aren't declared correctly.
I've attached all my codes below for your reference.
Public Start_Date As Date
Start_Date = Worksheets("Sheet_Input").Cells("D", 1).Value
Public End_Date As Date
End_Date = Worksheets("Sheet_Input").Cells("F", 1).Value
Public Total_Date As Integer
Total_Date = Worksheets("Sheet_Input").Cells("H", 1).Value
Public aAverage As Integer
aAverage = Worksheets("Sheet_Input").Cells("B", 3).Value
Public bAverage As Integer
bAverage = Worksheets("Sheet_Input").Cells("D", 3).Value
Duplicate Declaration Error
Nov 20, 2008I am getting "Duplicate Declaration" error while running my code. Cant post entire code as its too long but i am pasting the problem line.
View 12 Replies View RelatedPublic Worksheet Declaration
Aug 28, 2009I'm using a public declaration for a worksheet but I seem to have to initialize it in each routine. Is there a way to set it and leave it? So in a module I have:
View 4 Replies View RelatedUpdating Declaration For 64bit?
Apr 23, 2012I have some code that runs a mouse event and keeps my computer active when I'm away. It works on my 32-bit computer, but doesn't work on my 64-bit. What is the correct syntax to have it work on a 64-bit?
I get the error: "declare stmts must be updated for 64 bit and marked with PtrSafe attribute."
BTW, I already tried changing "user32" to "user64", that didn't work.
Code follows:
Public Declare Function SetCursorPos Lib "user32" (ByVal x As Long, ByVal y As Long) As Long
Public Declare Sub mouse_event Lib "user32" (ByVal dwFlags As Long, ByVal dx As Long, ByVal dy As Long, ByVal cButtons As Long, ByVal dwExtraInfo As Long)
Public Const MOUSEEVENTF_LEFTDOWN = &H2
Public Const MOUSEEVENTF_LEFTUP = &H4
Dim TimerActive As Boolean
Sub KeepWindowsActive()
[code].....
using win 7.
Declaration Of Variable In Sum Product
Aug 14, 2012I have two issues in SumProduct formula.
1.Formula Def.Cells(c, d).Formula = "=SUMPRODUCT(--(Severity =" & """" & severity_3 & """" & "),
--(OFFSET(Severity,0,4)=" & """" & module & """" & "))"
Where severity_3= Shipping
There are many fields like Shipping, Shipping-UI, Shipping-BE.
I want the formula to consider all the above when severity_3= Shipping and take the count & not only consider Shipping(Shipping*) .
2.Formula test = "0 - Unclassified" Or "Alpha Testing" Or "Beta Testing" Or "Functional - Interface" Or "Functional - Report" Or "Regression Testing" Or "Requirement Review"
when i use the above formula , it is displaying the message "Run-time error'13':Type mismatch There are spaces in the criteria i have used but i am not sure how to resolve this
Array Declaration Returns 0
Jun 21, 2008I suspect the array variables declaration in the following example is the problem.
The array Function MyRoots() incorrectly returns 0.0 results to cells I11:J13.
cell B8::3
cell B9: myTrue
cells B11:C14 numerical values
cells I11:J13:: array function {=MyRoots(B11:C14, B8, B9)}
Function MyRoots (a, m As Integer, polish As String)
ReDim a(m + 1, 2) As Double
ReDim roots(m, 2) As Double
Dim j As Integer, its As Integer
Dim x(2) As Double
ReDim ad(m + 1, 2) As Double
......................................my code............
For j = 1 To m + 1
ad(j, 1) = a(j, 1)
ad(j, 2) = a(j, 2)
Next j
......................................my code............
Call Laguer (ad, j, x, its)
......................................my code............
roots(j, 1) = x(1)
roots(j, 2) = x(2)
......................................my code............
MyRoots = roots
End Function
Sub Laguer (a, m, x, its)
Dim x1(2) As Double
......................................my code.......................................
x(1) = x1(1)
x(2) = x1(2)
......................................my code............
Exit Sub
End Sub
Global Variable Declaration
Dec 25, 2007I have a smattering of experience within various programming languages, but am still coming to terms with the basics of VBA. I am trying to declare a global variable, assign it a value, then use that global variable. Within 'ThisWorkbook' I have the following...
Public myText As String
Private Sub Workbook_Open()
myText = "Hi There"
End Sub
...and in the Microsoft Worksheet Object Sheet1 (Sheet1) I have...
Private Sub Worksheet_SelectionChange(ByVal Target As Range)
MsgBox myText
End Sub
Now, my understanding of this code is that upon opening the workbook, myText variable will be declared, and then assigned the value "Hi There". Then, once I have clicked anywhere on Sheet1, a message box will appear stating "Hi There". Problem is, the message box is blank. This is all fine, except I want the message box to state "Hi There". What am I doing wrong? Is the variable declared (publically) correctly? Am I assigning the public variable the value correctly?
Am I referencing the public variable correctly in the Worksheet_SelectionChange procedure correctly?
Range As Parameter In Function Declaration
Aug 3, 2009I have a formula that hides rows within a range for a sheet.
View 2 Replies View RelatedCorrect Declaration For A File Path
Nov 19, 2009I am using the format of using variables for declaring file paths and document names in VBA however I want to make sure I am doing it properly...
Dim Server, VersionName As String
Server = Worksheets("Calculation Matrix").Range("CalculationMatrix_Server").Value
VersionName = Worksheets("Calculation Matrix").Range("CalculationMatrix_VersionName").Value
ActiveWorkbook.SaveAs Filename:="" & Server & "uploadcomplete" & VersionName & "", FileFormat:=xlNormal, Password:="", WriteResPassword:="", ReadOnlyRecommended:=False, CreateBackup:=False
Should these variables be declared as String?
Duplicate Declaration In Current Script
Jun 3, 2007I am trying to run a VB script that will copy data from 3 worksheets and past it into 3 New worksheets, sort that data into alpha order then delete all rows containing Zeros that may be found in Column B, Then copy that data from the 3 New worksheet back into the original 3 worksheets.
The copying and sorting of the data from one sheet to another is easy. The problem is trying to delete the zeros found in column B once its been copied over into the 3 New worksheets.
The script I am using to delete any Zeros found in Column B is below.
If I try to use this script more then once, so that I can delete all the zeros found in column B on all the New worksheets I get this error “Duplicate declaration in current script”
Is there a way for me to refer back to this script instead of me trying to past it more then once within the VB script.
Application. ScreenUpdating = False
Application.Calculation = xlCalculationManual
Const StartRow As Long = 1 'Row to Start looking at
Dim StopRow As Long
Dim Col As Long
Col = ActiveCell.Column
StopRow = Cells(Rows.Count, Col).End(xlUp).Row
Dim cnt As Long
For cnt = StopRow To StartRow Step -1
If Not IsEmpty(Cells(cnt, Col)) Then
If IsNumeric(Cells(cnt, Col)) Then
If Cells(cnt, Col) = 0 Then Rows(cnt).Delete
End If
End If
Next cnt
Application.Calculation = xlCalculationAutomatic
Application.ScreenUpdating = True
Please see attached workbook. You will understand it better once you see the workbook and the VB script in it.
Public Variable Declaration Not Being Recognized
Jul 27, 2007Hopefully this isn't too vague, but almost every project I've worked on so far has not recognized Public variables in all modules. I've constantly been searching for exceptions to this rule that could be contributing to this issue but haven't been successful.
I have read a million times that declaring a variable as Public makes it visible to all modules and preserves the value throughout. I've also read that if you edit code or reset your project, the values may be lost. I also know that if you try to use a variable before you give it a value (or for object variables set it = to something), it doesn't have a value yet. But all this applied, I'm still not getting Public variables to be consistently recognized or stay with the value I want them to have throughout the lifetime of my project (while the workbook is open)
My specific current issue (one of many so far) is that I have 4 command buttons within a worksheet object. Each triggers a different group of procedures, some of these are user forms. In the first button, I create two worksheets one to contain the current fiscal period "Options" the other for "Summary" of all the totals etc... (all financial data). In this first userform, triggered by the button, I allow the user to name these worksheets: like Summer2007Options or Summer2007Summary and I declare these publically as object variables OptSheet and SumSheet. These variable names and sheets are recognized for the next 2 buttons but now that I'm on the fourth, I have object variable not set errors when I try to refer to this variable.
Error: Duplicate Declaration In Current Scope
Jun 28, 2009I get an error: Duplicate declaration in current scope? The formula calculates the compound annual growth rate.
View 5 Replies View RelatedCompile Error - Duplicate Declaration In Current Scope?
Feb 17, 2012I have the following code which performs the same action on 2 different tabs within the same workbook:
Dim Rng As Range, Dn As Range
Set Rng = Range(Range("O1"), Range("O" & Rows.Count).End(xlUp))
Rng.NumberFormat = "@"
For Each Dn In Rng
If Len(Dn) < 7 Then Dn = String(7 - Len(Dn), "0") & Dn
Next Dn
i get the following error:
Compile Error: Duplicate declaration in current scope
Duplicate Declaration In Current Scope (Deselecting All Items In Pivot Table Except One)
Oct 27, 2011I am trying to automate the creation of 3 pivot tables. At first I was having a problem with deselecting all items in the drop-down except one, then I found the code to fix it.
I replaced this code:
ActiveSheet.PivotTables("PivotTable15").PivotFields( _
"Beta")
.PivotItems("Escalated").Visible = False
.PivotItems("Hang Up").Visible = False
.PivotItems("New Hire Requests").Visible = False
.PivotItems("No Trouble Found").Visible = False
.PivotItems("Priority Exchange").Visible = False
[code].....
This fixed the problem, but there are still two other pivot tables that need to be created after this first one. I scrolled down through the code and deleted the other code blocks for the selection of the PivotItems and replaced it with the code above, but then when I ran it I got the "Compile Error: Duplicate Declaration in current scope".
I read more through the forum and realize that it's because VBA is dimensioning it twice, and I read that you're supposed to Dimension at the beginning of your program, but how do I implement this into my coding?
I can't dimension literally at the start of the code, there is some formatting that needs to take place first. (Basically I paste in a bunch of data into Sheet1 of my workbook, center it, space it out, then insert a pivot table into the pre-existing Sheet2 based on that data, filtered on the blank entries in Column N. Then I need to create ANOTHER pivot table based on that same data in Sheet1, but filtered on the blank entries in Column O. Then I center the words in the Pivot tables' headers in Sheet2, and finally I need to create one last pivot table on pre-existing Sheet3 based on the data on Sheet1, filtered for 2 specific entry types in Column N.)
Stack Overflow
May 6, 2009I'm running into an overflow stack with a fairly large MACRO program. Will chopping the VBA MACRO into call routines reduce the stack size of the MACRO?
View 9 Replies View RelatedOverflow On One Computer But Not On The Other
Sep 8, 2007i am experiencing runtime error '6': overflow on one computer but not on another computer when it is the exact same file running on two different computers.
Overflow Error 6
Apr 7, 2008I have a sub that takes the value in 2 textboxes and creates a profit margin in another textbox. It's a simple sub but it keeps returning the overflow error, and I can't figure out how to fix it.
Here is what the sub says that is causing the overflow:
Sub FindNetProfitMargin()
UserForm2.tbProfitNetProfitMargin.Value = Val(Mid(UserForm2.tbTotalContractPrice2.Value, 2)) / Val(Mid(UserForm2.tbProfitNetProfit.Value, 2))
End Sub
VBA Overflow Error
Aug 13, 2008I declare a bunch of variables and arrays, mostly longs and doubles, then run a DLL. After that, I redim one of my arrays (2D) to the right size and try to fill in some values. The array is a double and the values are less than one million. On the first element the code breaks and throws an overflow error.
If I choose "Debug", I can then click continue and it finishes just fine as if there was no error. I can see in the debugger that the array is sized properly, has the correct type, etc. I have no idea what could be wrong here. Could it be a memory problem?
Overflow Error
Jan 4, 2007Range("J" & (Count)) = (Range("E" & (Count)) / Range("H" & (Count))) - 1
Overflow Error In Vba
Mar 6, 2007I'm experiencing a overflow error in Excel VBA. The operation that causes this problem is (I have very long for loop, but that is correct only this following sentence is causing the problem):
Sheet2. Cells(2, m+4) = Sheet2.Cells(23, m+4)/Sheet2.Cells(25, m+4)
NB: No zero values are involved in this calculation and the problem is caused by long decimal result! I dont know how to get rid of it!!
Overflow Error '6'
Jul 9, 2007whenever i run my code below that states "Runtime error '6' Overflow". At debug, the affected statement is " Cells(x + 1, 12) = Cells(x + 1, 11) / Cells(x + 1, 8) ". Can anybody help me with this error ?
Sub QQQQ()
Dim v As Long, x As Integer, k As Variant
Dim arr(0 To 100, 0 To 100) As Variant
For Each k In check_case_arr1
Cells(x + 1, 1) = arr(k, 1)
Cells(x + 1, 2) = arr(k, 2)
Cells(x + 1, 3) = arr(k, 3)
Cells(x + 1, 4) = arr(k, 4)
Cells(x + 1, 5) = arr(k, 5)
Cells(x + 1, 6) = arr(k, 6)
Cells(x + 1, 7) = arr(k, 7)
Cells(x + 1, 8) = arr(k, 8)
Cells(x + 1, 9) = arr(k, 9)
Cells(x + 1, 10) = arr(k, 10)
Cells(x + 1, 11) = arr(k, 11)
Cells(x + 1, 12) = Cells(x + 1, 11) / Cells(x + 1, 8)
Next
End Sub
TRUNC Overflow (display 0)?
Feb 12, 2009I have a very serious problem with my excel and TRUNC function. I have created a spreadsheet to show whether a number is divisible by other number or not. If it is, excel would display 0. when it is not I'd expect something like 0,12123. (the number should never be bigger than 1). The formula I use is:
View 3 Replies View RelatedRuntime Error '6' : Overflow
Oct 19, 2007I have read the other posts on here and swapped, Dim timeinc As Interger to Dim timeinc As Long and Dim timeinc As Double but neither worked. They both make the calculation 0 and I can not figure out why. This macro has worked before and is failing only on this new dataset which I have attached as well.
I am solving this problem on a PC and the macro was built for a Mac but I do not think that should change much as when I run it on a Mac it fails the same
VBA Overflow - Getting Runtime Error 6?
Sep 14, 2012I have a script that usually runs, but all of a sudden gives me a run-time error 6: Overflow error. Basically I'm searching for certain criteria and copying or cutting and pasting lines from one sheet to another. Why I'm getting the error by the code below?
Sub teal()
Dim i As Long
Dim qq As Long
Dim assignmentnum As Long[code]......
Integers Can Contain :: Overflow Error
Mar 16, 2007According to Microsoft in Visual Basic an Integer can contain -2,147,483,648 to 2,147,483,647.
Yet when I store 5,000,000 to an integer I get an overflow error.
Overflow Error In VBA Code
Oct 29, 2007I worked a while on getting a macro to do what I needed in VBA. I am sure it is not the most efficient way of doing it, but its all I know. The only problem I am now encountering is getting an "Overflow" error and I can not fix it.
Sub CodeRateChange()
'Keyboard Shortcut: Ctrl+t
'Vlookup of PC to get PG
Sheets("CODE").Select
For I = 1 To 1000
If Left(Cells(I, 1), 1) = "P" Then
Cells(I, 2) = Application.WorksheetFunction.VLookup(Cells(I, 1), Range("Hierarchy"), 2, False)
End If
Next I
'Calculate Base Sales Dollars
Sheets("CODE").Select
For I = 1 To 1000
If Left(Cells(I, 1), 1) = "P" Then
Cells(I, 39) = (Cells(I, 3) * Cells(I, 15))
Cells(I, 40) = (Cells(I, 4) * Cells(I, 16))....................
Run Time Error 6 - Overflow
May 13, 2008
I've been contracted some work and I was asked to add an additional metric on the report summary page. I have completed adding metric, tested it, and everything works fine. I was asked to put the code I worked on into an updated copy and thats where I get this "Run Time Error 6 - OverFlow" error message. The only difference between the two files is that the data worksheet (where the Summary page gets the info) in the new file has 100 more row of data. I understand that the code may be stuck in a loop, but what would cause this?
A little background on what the file does. Every month the user enters the publication name, whether it is a color or black or white ad, and the size of the ad. The macro then summerizes the data onto a different worksheet (similar to what the results of a pivot table would give you), calculating the revenue for each publicaton (based on b/w x rate + color x rate). The file worked fine until I replaced the old data with the new data.
Runtime Error 6 - Overflow
Nov 11, 2004I am currently trying to develop a code for calculating the value of an asian option using a binomial tree... In running the macro I get a run-time error 6 - overflow message. I have put the code below. note that the code is still under construction - in order to check it I have put in some hard-coded figures. Of course, these should be calculated in the model eventually. The bug is in calculating the "InterO1" value ...
Sub bereken_asian_call()
sig = Sheets("Sheet1"). Range("B1").Value
T = Sheets("Sheet1").Range("B2").Value
N = Sheets("Sheet1").Range("B3").Value
r = Sheets("Sheet1").Range("B7").Value
div = Sheets("Sheet1").Range("B8").Value
S = Sheets("Sheet1").Range("B12").Value
K = Sheets("sheet1").Range("b13").Value
alpha = Sheets("Sheet1").Range("B14").Value
Dim St() As Double
Dim F() As Double
Dim O() As Double
Dim NewAv1() As Double
Dim NewAv2() As Double
Dim Ffut1() As Double
Dim Ffut2() As Double
Dim Ffut3() As Double
Dim Ffut4() As Double
Dim den1() As Double
Dim den2() As Double
Dim InterO1() As Double
Dim InterO2() As Double
dt = T / N
u = Exp(sig * Sqr(dt))
d = 1 / u
pu = (Exp(dt * r) - d) / (u - d)................
