Runtime Error '6' : Overflow
Oct 19, 2007
I have read the other posts on here and swapped, Dim timeinc As Interger to Dim timeinc As Long and Dim timeinc As Double but neither worked. They both make the calculation 0 and I can not figure out why. This macro has worked before and is failing only on this new dataset which I have attached as well.
I am solving this problem on a PC and the macro was built for a Mac but I do not think that should change much as when I run it on a Mac it fails the same
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Sep 14, 2012
I have a script that usually runs, but all of a sudden gives me a run-time error 6: Overflow error. Basically I'm searching for certain criteria and copying or cutting and pasting lines from one sheet to another. Why I'm getting the error by the code below?
Sub teal()
Dim i As Long
Dim qq As Long
Dim assignmentnum As Long[code]......
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Nov 11, 2004
I am currently trying to develop a code for calculating the value of an asian option using a binomial tree... In running the macro I get a run-time error 6 - overflow message. I have put the code below. note that the code is still under construction - in order to check it I have put in some hard-coded figures. Of course, these should be calculated in the model eventually. The bug is in calculating the "InterO1" value ...
Sub bereken_asian_call()
sig = Sheets("Sheet1"). Range("B1").Value
T = Sheets("Sheet1").Range("B2").Value
N = Sheets("Sheet1").Range("B3").Value
r = Sheets("Sheet1").Range("B7").Value
div = Sheets("Sheet1").Range("B8").Value
S = Sheets("Sheet1").Range("B12").Value
K = Sheets("sheet1").Range("b13").Value
alpha = Sheets("Sheet1").Range("B14").Value
Dim St() As Double
Dim F() As Double
Dim O() As Double
Dim NewAv1() As Double
Dim NewAv2() As Double
Dim Ffut1() As Double
Dim Ffut2() As Double
Dim Ffut3() As Double
Dim Ffut4() As Double
Dim den1() As Double
Dim den2() As Double
Dim InterO1() As Double
Dim InterO2() As Double
dt = T / N
u = Exp(sig * Sqr(dt))
d = 1 / u
pu = (Exp(dt * r) - d) / (u - d)................
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Aug 9, 2009
I used to have a ton of experience with Java and C# but now my job calls for VB scripts in excel. Probably an assignment error or logic error but here's the ....
i m doing is i have two workbooks "New Dashboard" and "Book1". I search column A in Book1 for HELLO, and then i use the row it was found in to grab a value "HrsVal". I take that value and i put it "New Dashboard". I then do the same for every sheet. It seems to fail in my second loop in the 2nd sheet. Error says "Overflow".
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Apr 7, 2008
I have a sub that takes the value in 2 textboxes and creates a profit margin in another textbox. It's a simple sub but it keeps returning the overflow error, and I can't figure out how to fix it.
Here is what the sub says that is causing the overflow:
Sub FindNetProfitMargin()
UserForm2.tbProfitNetProfitMargin.Value = Val(Mid(UserForm2.tbTotalContractPrice2.Value, 2)) / Val(Mid(UserForm2.tbProfitNetProfit.Value, 2))
End Sub
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Aug 13, 2008
I declare a bunch of variables and arrays, mostly longs and doubles, then run a DLL. After that, I redim one of my arrays (2D) to the right size and try to fill in some values. The array is a double and the values are less than one million. On the first element the code breaks and throws an overflow error.
If I choose "Debug", I can then click continue and it finishes just fine as if there was no error. I can see in the debugger that the array is sized properly, has the correct type, etc. I have no idea what could be wrong here. Could it be a memory problem?
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Jan 4, 2007
Range("J" & (Count)) = (Range("E" & (Count)) / Range("H" & (Count))) - 1
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Mar 6, 2007
I'm experiencing a overflow error in Excel VBA. The operation that causes this problem is (I have very long for loop, but that is correct only this following sentence is causing the problem):
Sheet2. Cells(2, m+4) = Sheet2.Cells(23, m+4)/Sheet2.Cells(25, m+4)
NB: No zero values are involved in this calculation and the problem is caused by long decimal result! I dont know how to get rid of it!!
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Jul 9, 2007
whenever i run my code below that states "Runtime error '6' Overflow". At debug, the affected statement is " Cells(x + 1, 12) = Cells(x + 1, 11) / Cells(x + 1, 8) ". Can anybody help me with this error ?
Sub QQQQ()
Dim v As Long, x As Integer, k As Variant
Dim arr(0 To 100, 0 To 100) As Variant
For Each k In check_case_arr1
Cells(x + 1, 1) = arr(k, 1)
Cells(x + 1, 2) = arr(k, 2)
Cells(x + 1, 3) = arr(k, 3)
Cells(x + 1, 4) = arr(k, 4)
Cells(x + 1, 5) = arr(k, 5)
Cells(x + 1, 6) = arr(k, 6)
Cells(x + 1, 7) = arr(k, 7)
Cells(x + 1, 8) = arr(k, 8)
Cells(x + 1, 9) = arr(k, 9)
Cells(x + 1, 10) = arr(k, 10)
Cells(x + 1, 11) = arr(k, 11)
Cells(x + 1, 12) = Cells(x + 1, 11) / Cells(x + 1, 8)
Next
End Sub
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Mar 16, 2007
According to Microsoft in Visual Basic an Integer can contain -2,147,483,648 to 2,147,483,647.
Yet when I store 5,000,000 to an integer I get an overflow error.
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Oct 29, 2007
I worked a while on getting a macro to do what I needed in VBA. I am sure it is not the most efficient way of doing it, but its all I know. The only problem I am now encountering is getting an "Overflow" error and I can not fix it.
Sub CodeRateChange()
'Keyboard Shortcut: Ctrl+t
'Vlookup of PC to get PG
Sheets("CODE").Select
For I = 1 To 1000
If Left(Cells(I, 1), 1) = "P" Then
Cells(I, 2) = Application.WorksheetFunction.VLookup(Cells(I, 1), Range("Hierarchy"), 2, False)
End If
Next I
'Calculate Base Sales Dollars
Sheets("CODE").Select
For I = 1 To 1000
If Left(Cells(I, 1), 1) = "P" Then
Cells(I, 39) = (Cells(I, 3) * Cells(I, 15))
Cells(I, 40) = (Cells(I, 4) * Cells(I, 16))....................
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May 13, 2008
I've been contracted some work and I was asked to add an additional metric on the report summary page. I have completed adding metric, tested it, and everything works fine. I was asked to put the code I worked on into an updated copy and thats where I get this "Run Time Error 6 - OverFlow" error message. The only difference between the two files is that the data worksheet (where the Summary page gets the info) in the new file has 100 more row of data. I understand that the code may be stuck in a loop, but what would cause this?
A little background on what the file does. Every month the user enters the publication name, whether it is a color or black or white ad, and the size of the ad. The macro then summerizes the data onto a different worksheet (similar to what the results of a pivot table would give you), calculating the revenue for each publicaton (based on b/w x rate + color x rate). The file worked fine until I replaced the old data with the new data.
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May 24, 2006
extracting data from notepad to excel cells
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Sep 28, 2006
I have code that performs calculations, adding to counters and division. All of my Dim statements are set to Long but I still get them. The code works sometimes but other times not. Do you get that error when trying to divide by zero? Anyone have any idea what to try next?
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Mar 14, 2007
Upon running this code I get an overflow runtime error. This DID work until I rewrote it and I cannot figure out why it does not anymore. Note the highlighted code which produces the overflow. It DOES produce the proper result- but once I click the SUBMIT button it gives me the runtime and points to the highlighted code.
Private Sub btnSubmit_Click()
ActiveWorkbook. Sheets("Rejections").Activate
Range("A4").Select
Do
If IsEmpty(ActiveCell) = False Then
ActiveCell.Offset(1, 0).Select
End If
Loop Until IsEmpty(ActiveCell) = True
ActiveCell.Value = txtDate.Value
ActiveCell.Offset(0, 1) = txtWO.Value
If optCD.Value = True Then
ActiveCell.Offset(0, 2) = "CD"
End If
If optDVD.Value = True Then
ActiveCell.Offset(0, 2) = "DVD"
End If
ActiveCell.Offset(0, 3) = txtInitialBurn.Value.........................
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Apr 10, 2008
I've created a price sheet that I distribute to customers that is very customer specific. I have to add spacing, logo's, borders and highlighting depending on the products being listed. Because of all of this specialization I'm controlling the page breaks and overflow. I have a counter to keep the current line number of the report and another to determine the row within the current page. I've designed my form to have 77 lines per page and I call a pagebreak/overflow routine when I hit line 72 of each page. Works perfectly when I test on my PC and works about 80% of the time when I send to customers, but I have about 20% who have problems with page size and overflow. In working with them I've found that it's not just the printed copy, but also when they print preview on screen. The first few lines of the second page print at the bottom of the first, so the top of page two is cut off. Then 4 lines from page three print at the bottom of two and so on...
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Nov 18, 2009
I am transferring 10000 rows from 1 workbook to another..
It takes place smoothly for the first 30000 rows, but after that on the 'select' line it gives me an overflow error.
The code that I am using is as following: .....
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Jul 2, 2012
I was quite a few problems using worksheetfunction.ln() to calculate % change. I decided to write more basic code to try to accomplish this but I'm getting an overflow error.
Code:
DRows = WorksheetFunction.CountA(Sheets("INFO").Range("A:A"))
For r = 1 To (DRows - 1) '***** -1 is bc of ln property
percentchange = 0
newval1 = Worksheets("INFO").Cells(1 + r, 2).Value
old1 = Worksheets("INFO").Cells(1 + r, 2).Value
percentchange = (newval1 - old1) / old1
Worksheets("info").Cells(2 + r, 3).Value = percentchange
Next r
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Jan 29, 2014
The code below works fine on smaller data sets. I tried it on a data set of over 165000 records and it gives me the error:
"Runtime Error '6': Overflow"
Clicking debug highlights this line:
rowCount = .DataBodyRange.rows.Count
Code:
Sub Fixtable()
Dim lo As Excel.ListObject
Dim loRow As Excel.ListRow
[Code]....
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Jul 30, 2007
I'm trying to run a piece of code which checks the length of a cell entry and if it is over 100 characters long it deletes the value. The code is as follows:
Sub Macro1()
If Len(Cells(1, 1)) > 100 Then
Cells(2, 1).ClearContents
End If
End Sub
The string which is causing the error seems to be 255 or more characters long. Any ideas how to tackle the "Overflow" Error?
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Sep 11, 2007
we would use a byte data type as a counter in a For Loop, but just today I have been having trouble with this. When I try to count backwards with " Step -1" I get an "error 6: overflow" on the FOR LOOP line. When I count forwards it works fine.
For example ....
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Jul 17, 2012
I have tracked down an overflow Error 6 to the following line:
dMax = Int(s * DPoints / SPoints)
Where all variables are defined as Integers. The error goes away when I define s as Long, but I don't understand why this should be required since none of the individual variables ever exceed the scope of an Integer (-32768 to 32767).
Strangely, I get the same overflow problem when I type either of the following calculations in the immediate window:
? Int(328 * 100 / 1000)
? 328 * 100 / 1000
? 328 * 100
Note that no variables are defined, so why the overflow problem? Surely Excel/VBA should be able to work with this very basic calculation without any problem, by assigning the appropriate dimension, no?
Is this a known problem with Excel/VBA?
I am using Windows 7, with Excel 2010 (updated from 2009).
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Feb 11, 2009
I wanted to convert a variant to an integer. The variant data is stored in an array, the variant data was entered from a userform.
Private Sub CB_OilPrice_Click()
Dim xx As Long
UserFormSpecifyDetail.Show 'Enter data
For i = 1 To 120
xx = VarType(UserFormInputArray(i)) 'Returns 8
xx = Int(UserFormInputArray(i)) 'Returns error
Next i
End Sub
The value in UserFormInputArray = "50000"
error = Run-Time error 6, overflow
Excel 2003
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May 3, 2006
I'm getting the error for the following piece of code.
Sub itconfandscratch()
Dim Cn As ADODB.Connection
Dim Server_Name As String
Dim Database_Name As String
Dim User_ID As String
Dim Password As String
Dim SQLStr As String
Dim rs As ADODB.Recordset
Set rs = New ADODB.Recordset
Server_Name = "sturecord"
Database_Name = "Scratch" ' Enter your database name here
SQLStr = "SELECT stuname FROM dbo.sturec" ' Enter your SQL here
Set Cn = New ADODB.Connection
Cn.Open "Driver={SQL Server};Server=" & Server_Name & ";Database=" & Database_Name & ""..............
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Jul 6, 2006
The code thats generating the error is the following:
For Y = 8 To 131
TmpDate = Empty
Range("A1").Value = "=" + Path + Sheet + "B" + CStr(Y)
TmpDate = Range("A1").Value
For Langd = 1 To Len(TmpDate)
TmpChar = Mid(TmpDate, Langd, 1)
If Not TmpChar = " " Then
TmpComp = TmpComp + TmpChar
End If
Next Langd
TmpDate = TmpComp
TmpComp = Empty
If Len(Dag) = 1 Then
Dag = "0" + CStr(Dag)
End If
Macro continues before the Next-statement...
(it might not be good programming, but I think it should work).
A little explanation to the code.
I have a spreadsheet located on the intranet that has values I need in my spreadsheet. These figures are sorted by date, so I search for the date to find the right figures.
The line Range("A1").Value = "=" + Path + Sheet + "B" + CStr(Y)
works prefectly. I can see the value in my spreadsheet in the cell A1. its the next line that causes the error "Type mismatch".
The value I get from the intranet spreadsheet looks similar to this:
"1 Jul 2006 " (note all the spaces).
What I do is just run it through a loop and cut of all spaces so it will look like this: "1Jul2006" to be sure I dont miss a space or anything.
Now to the funny part.
The error only happens at runtime on the first go.
If I chose to END the macro then and there, and then run it again from the top it works perfectly.
If I set a stopsign to debug the code, it works perfectly on the first go too.
Can anyone explain to me why that happens??
I know enough about programming to handle my syntax errors and so on, but I cant see anything wrong in this one...
Please note that this isnt the the entire code.
I'm building a report on 12 diffrent spreadsheet. The main macro is almost 2000 rows of code, and it call other Subs too (because of limitations in the VBA-editor. A macro cant to be too big), so its impossible for me to post the entire macro...
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Oct 15, 2009
I am getting an error "Overflow" in the following red line.
Sub Test()
Dim a
a = Sheets("ayaz").Range("a4").CurrentRegion.Resize(, 18)
End Sub
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Mar 5, 2007
if I leave the inputbox blank I get an Excel error. I.e. it says that the formula I tried to type contains an error..... Is the Type:=8 not working properly here?
Dim Addr As Range
On Error GoTo Problem
Set Addr = Application.InputBox( _
Prompt:="Enter or Select a cell in the last record", _
Title:="Select Last Record:", Default:=Selection.Address, Type:=8)
If Addr Is Nothing Then Exit Sub
Edit: I guess I should mention that I am trying to retrieve a cell reference from the user via an input box. This cell reference will help me determine the last record in the spreadsheet.
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Sep 18, 2007
In Excel 2003 I have made a model for evaluating co-workers. The model consist of a number of different questions regarding performance. At the top of the sheet, the user have to select som data from a drop down list, and depending on the answer (upward or downward), som of the questions in the sheets is hidden or shown. For this purpose I have created this string of VB-code in the sheet:
Private Sub Worksheet_Change(ByVal Target As Range)
If Target.Address = "$E$5" And Target.Value = "Upward" Then
Rows("20:41").EntireRow.Hidden = True
ElseIf Target.Address = "$E$5" And Target.Value = "Downward" Then
Rows("20:41").EntireRow.Hidden = False
ElseIf Target.Address = "$E$5" And Target.Value = "" Then
Rows("20:41").EntireRow.Hidden = False
End If...........
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Oct 30, 2008
He's the issue i'm getting with the code...
Public Sub Auto_Open()
wrkbkName = Application.ActiveWorkbook.Name
'this little snippet of code determine which branch the user is at
'based on the ip address
'if ip is like 192.168.1.xxx then we on welthsrvr
ipadrr = GetIPAddresses(True)
If Left(ipadrr, 9) = "192.168.1" Then
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Dec 14, 2008
Private Sub Worksheet_Change(ByVal Target As Range)
If Not (Application.Intersect(Target, Range("G9:BF94")) Is Nothing) Then
With Target
If Not .HasFormula Then
.Value = UCase(.Value)
End If
End With
End If
End Sub
However when ever I select more than one cell which already has text in it and press delete I get a runtime error 13 and the debugger highlights this line:
.Value = UCase(.Value)
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