Type Mismatch From VBA .Find

Jan 16, 2007

This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch

dim c as Range
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
ActiveCell is a single cell on an unhidden sheet - cell A279.

I can Control-F at this point in Excel, and it finds "LIQ" just fine.

Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.

Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)

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Find Value - Type Mismatch

Feb 23, 2013

I tried to find value on the other workbook. Gives me error "Type mismatch"

Below is the code in my VBA project

Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub

[Code] .......

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I'm using a find statement to locate a text string in a column but I get a 'type mismatch' error when I run it. I'm guessing that it's because of what I'm trying to find is a text and it is looking for a number. Anyway to point to the row number of where I find the macthing text in the column?

'Dimension variables used in Macro.
Dim Logon As String
Dim Level As String
Dim RangeFind As Range
Set RangeFind = Nothing

On Error Goto Error ...

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Nov 4, 2006

I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:

- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)

- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)


The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the

Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............

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Aug 21, 2014

I am getting a type mismatch with the following:

HTML Code: 

Private Sub Export2Pdf()
Dim sFileName As String
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[Code] ........

something to do with this:

HTML Code: 

sFileName = Range("employeename").Value & " - Payslip" & " - " & _
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The line I first used was:

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for( var i =0,skip =0 ; i [code].....

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I am attaching the file.

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Feb 8, 2010

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This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.

Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long


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I am using this code:

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Function MyFunc(mean As Double)

D1 is a named range which is a single cell. It contains a double.
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Sub Trackj()
Dim a As Long
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End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:

If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then

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So far I have:

[Code] ........

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I seem to have some type mismatch in my macro...

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Dim indexData As Range

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[Code] ......

I am struggling to get this to work though. Everytime I step over this piece of code:

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I have hardcoded the range into the formula just to try and get it to work. Eventually this will be two variables and will look like this:

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Dim old_value
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prev = old_value
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