Basic Syntax / Type Mismatch

Jul 15, 2014

I am trying to accomplish the following: iterate through rows of a selection, delete row if the first column cell is empty or the second column cell equals 0.

So far I have:

[Code] ........

I am getting a type mismatch error at my if statement.

View 3 Replies


ADVERTISEMENT

Type Mismatch Error Message Comparing Value To Cell Error "Type Mismatch"

Nov 4, 2006

I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:

- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)

- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)

Etc.

The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the

Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............

View 6 Replies View Related

Basic Range Copy, Match Sheetnames: Logic, Style, And Syntax

Feb 11, 2009

I am wondering if using an "if" statement or a case statement would be good ways to check two worksheets in two different workbooks to see if their names match? I could use some help correcting my syntax too:


For 1 to ws.count
If Worksheet("one").Name = Worksheet("two").Name
Worksheet("one").Range("A1:G84").Copy
Worksheet("two").Range("A1:G84").Paste
Endif
Next ws.Count

View 9 Replies View Related

VBA Type Mismatch

Aug 21, 2014

I am getting a type mismatch with the following:

HTML Code: 

Private Sub Export2Pdf()
Dim sFileName As String
'Create file name
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")

[Code] ........

something to do with this:

HTML Code: 

sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")

View 1 Replies View Related

Type Mismatch

Feb 14, 2009

I have used this code previously and it worked however I now get a type mismatch error in the line coloured red..

View 8 Replies View Related

Type Mismatch IF Statement?

Feb 24, 2014

The line I first used was:

var all_spans = document.getElementsByTagName( 'SPAN' );
for( var i =0,skip =0 ; i [code].....

View 3 Replies View Related

Error 13,Type Mismatch

Jul 1, 2009

I am getting error Type mismatch error the moment i enter value in Cell T54 and CLICK "DAILY" on Daily button.Waiting for the solution.

I am attaching the file.

View 10 Replies View Related

Type Mismatch For RowSource

Aug 25, 2009

I have four columns of data and 25 rows (A1:D25). I wish to add this to a multi-column list box in my user form. My userform is called FundSelect, and my listbox is called FundList. The ColumnCount property is set to 4. When I use the command:

View 4 Replies View Related

Type Mismatch Error 13

Feb 8, 2010

I'm trying to write a pretty simple macro which invokes a built-in DDE function to retrieve some data, then when the data is retrieved, just show a msgbox. When the data is finished being retrieved, cell(20,11) in the sheet "Historical Data" will automatically have "FINISHED" placed in it. So while the retrieval is taking place, I'm simply looping and checking the contents of this cell waiting for it to read "FINISHED". My problem is the 'Do While Sheets("Historical Data").Cells(20, 11) <> "FINISHED"' line generates a "Type Mismatch Runtime Error 13", which I can't for the life of me understand why.

View 2 Replies View Related

While Loop With Type Mismatch?

Mar 23, 2012

I have a while loop that counts backwards in a seriescollection to find the last value with data. In one particular case, I had to use an IF formula in the source data where it would output NA() if the statment was false, so instead of loop through empty strings until the loop finds a number, it loops through #NA until it finds a number.

This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.

Code:
Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long

[Code]....

(P.S. why I would have "NA" as an output, its because it won't graph, where putting "" for my false condition did)

View 9 Replies View Related

Getting Type Mismatch Error

Jan 16, 2013

I am using this code:

Code:
With wshvar
.Range("A16") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) - 1)
.Range("A18") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) + 1)
End With

but receiving a 'Type mismatch' error with the highlighted code.

View 1 Replies View Related

Find Value - Type Mismatch

Feb 23, 2013

I tried to find value on the other workbook. Gives me error "Type mismatch"

Below is the code in my VBA project

Code:
Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub

[Code] .......

View 7 Replies View Related

Type Mismatch From VBA .Find

Jan 16, 2007

This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch
dim c as Range
...
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
MatchCase:=False)
ActiveCell is a single cell on an unhidden sheet - cell A279.

I can Control-F at this point in Excel, and it finds "LIQ" just fine.

Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.

Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)

View 9 Replies View Related

Type Mismatch Error When The Value Is Zero In VBA

Feb 19, 2007

I have a piece of VBA code that acts weird. For brevity I am doing a function call like this:

val=MyFunc( [D1] )

and

Function MyFunc(mean As Double)

D1 is a named range which is a single cell. It contains a double.
The problem occurs when the value is zero, I get a type mismatch on the function call. If it is non-zero all is well.

What would cause this? I could see if zero was invalid inside MyFunc() that some calculation might blow, but it nevers gets into the function. Looks like the compiler is stopping it.

View 9 Replies View Related

2007 Type Mismatch

May 18, 2007

Range("C1:C" & x).Value = WorksheetFunction.Transpose(Result)
I'm trying to run it in 2007. It works in earlier versions.

I get Type Mismatch error. Result is dimmed as variant type.

View 9 Replies View Related

Run Time 13 Type Mismatch

Dec 14, 2008

I have some code which i trialled in a blank workbook and was fine. when i pasted it into the workbook i am working on, i get runtime error 13 type mismatch.

Sub Trackj()
Dim a As Long
For a = 1 To Sheets.Count
If InStr("master", Worksheets(a).Name) < 1 Then
Worksheets(a).Cells(40, 6).NumberFormat = "hh:mm"
Worksheets(a).Cells(41, 6).NumberFormat = "hh:mm"
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(40, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("B52:B80").PasteSpecial (xlPasteValues)
End If
If Hour(Worksheets(a).Cells(41, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(41, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("D52:D80").PasteSpecial (xlPasteValues)
End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:

If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then

View 9 Replies View Related

VB Enquiries - Type Mismatch

Jan 9, 2009

what i know what's actually type mismatch and how do i solve it?

View 9 Replies View Related

TimeDiff Type Mismatch

Jul 24, 2009

When my macro runs through the above code, I get a type mismatch error. All of the cells are formatted at Date only.

View 9 Replies View Related

Run Time Error - Type Mismatch?

May 16, 2014

When I run the following code I get a (Run-Time error '13': Type mismatch). When I click debug it highlights line 41

[Code].....

View 1 Replies View Related

Runtime Error 13 Type Mismatch?

Aug 18, 2014

i have written a vba code to open excel file saved at network server. The issue is code opens the file but gives "Runtime Error 13 Type mismatch"

Code :

<code>
Sub test_opening()
Dim filepath As String, filename As String, completename As String
Dim hurray_macros As Workbooks

[Code].....

View 1 Replies View Related

Runtime Error 13 Type Mismatch

Jan 30, 2009

I seem to have some type mismatch in my macro...

The error appears every time i insert or delete a row in the worksheet.

This is the ....

View 9 Replies View Related

Case Statement Getting A Type Mismatch

Jun 16, 2009

I made this case statment below to look at a cell in Q and if the cell value is "Large Area" then the cell in P same row should be 1 if the case is Varsity then it would be 2 however I keep getting a Type Mismatch. I tried Picker.Text and Picker.Value as well I didn't get errors but it didn't work either.

View 5 Replies View Related

Run Time Error - Type Mismatch

Aug 6, 2009

I have attached a sample file for you to easy reference. So when the code run until the loop function, it will prompt an error message.

The idea is to open the selected file and the copy the data from the selected to this master file by searching the column A. Column A has the identical text in all the files that are to be copied from.

View 7 Replies View Related

Type Mismatch Error On InputBox

Oct 16, 2009

I am trying to only have the option 1, 2, or 3 be entered. I have that part down, but if someone clicks cancel or just closes the input box i get the type mismatch I believe because no integer was found....is there a way around this?

Dim intResponse As Integer
intResponse = InputBox("Choose One" & Chr(10) & Chr(10) & "1 - Lease Lock" & Chr(10) & "2 - Upgrade" & Chr(10) & "3 - Lease Lock & Upgrade", "Contract(s) sent out")
If inResponse <> 1 Or strResponse <> 2 Or strResponse <> 3 Then
MsgBox "Must choose (1,2,3)"
Exit Sub
End If

View 2 Replies View Related

LINEST Type Mismatch Error

Mar 1, 2012

I have built a user defined function called: portAlpha.

Code:
Function portAlpha(assetCode As String, indexCode As String) As Double

Dim assetCol As Long
Dim indexCol As Long
Dim assetData As Range
Dim indexData As Range

With Sheets("Data")

[Code] ......

I am struggling to get this to work though. Everytime I step over this piece of code:

Code:
portAlpha = Application.WorksheetFunction.LinEst(Range("M4:M63"), Range("N4:N63"), 1, 1)

I get a "Type Mismatch Error". All the values in the range are numbers, and LINEST should return a double, so I am puzzled as to why there is a mismatch...

I have hardcoded the range into the formula just to try and get it to work. Eventually this will be two variables and will look like this:

Code:
portAlpha = Application.WorksheetFunction.Index(Application.WorksheetFunction.LinEst(assetData, indexData, 1, 1),1, 1)

View 1 Replies View Related

Type Mismatch Inserting Or Deleting A Row

Apr 27, 2012

I've written a macro for a set of tests I've created. It says "If the old value of the cell is '-' and the user enters 'Pass,' 'Fail,' or '-' then insert something into the cell directly to the right of the modified cell."

However, I'm receiving a Type Mismatch error any time I insert or delete a row. I think this is because of how I'm getting the previous value of a cell. The conditional is saying "I don't have a solution if there was no previous value of the cell."

Code:
Dim old_value
Private Sub Worksheet_Change(ByVal Target As Range)
prev = old_value
If Not Application.Intersect(Target, Range("E1:E65000")) Is Nothing Then
If prev = "" Or prev = 0 Then
'Do Nothing!

[code]....

View 4 Replies View Related

Type Mismatch On Column Selection

Sep 24, 2012

Why is this giving me a Type mismatch Run Time Error 13? The debugger highlights the Columns Select line.

Sheets("LB").Activate
Columns("AA:AZZ").Select
Selection.Delete Shift:=xlToLeft
Rows("20:300").Activate
Selection.Delete Shift:=xlUp

View 5 Replies View Related

Type Mismatch With VLookup Formula

Jan 23, 2013

Here is my line of code producing the error:

Code:
If .Range("T21").Value > Application.VLookup("AE25", .Range("L7:T10"), 6, False) Then
T21 is a time value
AE25 = HPL1

The lookup range: (times are time values)

Excel 2010LMNOPQRST7HPE1Adam W.HPA7:00 AM3:00 PM8HPE2Not StaffedXX9HPL1KourtneyHPC1:00 PM9:00 PM10HPL2Not StaffedXXMain

The HTML representation of range does not show the merging of columns L:M, N:O, Q:R and S:T on a row by row basis. Unmerging did not appear to make a difference.

View 3 Replies View Related

Runtime Error 13 Type Mismatch

Jan 24, 2013

I have a bug that pops on when running this line of code and I think it's because the copy area is a miss match against each worksheet.

If Evaluate("COUNTIF(" & sh2.Name & "!C:C,""" & sh1.Cells(i, "C").Value & """)=0") Then sh1.Rows(i).Copy sh2.Rows(j)
Sub Copy()

[Code].....

View 2 Replies View Related

Type Mismatch With Simple Formula?

May 26, 2013

Code:

fma_rng = .Range("C" & fma_top & ":C" & fma_btm)
rows_blnk = Application.CountBlank(fma_rng)

why I would be getting a 'type mismatch' error with the line in red?

View 6 Replies View Related







Copyrights 2005-15 www.BigResource.com, All rights reserved