Unable To Set XValues Property Of Series Class

Feb 19, 2009

I'm trying to add the xvalues, but I get an error that says "Unable to set XValues property of Series Class"

Set buildSeries = ws.Cells(6, 2)
For k = 4 To Col Step 2
Set buildSeries = Union(buildSeries, ws.Cells(6, k))
Next k
ActiveChart.SeriesCollection(1).XValues = buildSeries

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Unable To Set The Xvalues Property Of The Series Class

Sep 19, 2007

For the last day I have been getting the following error: "Run-time error '1004': Unable to set the Xvalues property of the series class."

The archetecture of the marco is sound being that I have used this methology in another macro and it works correctly every time. The XValuesand Values range are also correct and I know this because I had the macro select the data cells and it does this correctly as well. The data for simplicity at the moment has no empty cells or abnormal data. The data cells are all filled with some kind of data. For the XValue Range the data would look something like "2070087 4/27/2007" and the Values range is filled with a number between 0 and 100. What I can't figure out is why it crashes with a valid establish range. I highlighted the lines it crashes on in read, they are near the bottom.

Sub Proto1()
'
' Proto1 Macro
' Macro recorded 8/30/2007 by aaron.verellen
'

'
Dim CurrentSheet As String, ChartName As String
Dim RowCount As Integer, ColumnCount As Integer, FirstColumn As Integer, LastColumn, _
FirstRow As Integer, LastRow As Integer, Row As Integer, Column As Integer, _
ProductColumn As Integer, ArrayIndex As Integer, ParameterCount As Integer, _
ItemCount As Integer, MyIndex As Integer
Dim UserProductFlag As Boolean, NewProductFlag As Boolean
Dim Possibilities() As String
Dim ProductXRange As Range, ProductYRange As Range .................

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Unable To Set AxisGroup Property Of Series Class

Dec 28, 2011

I made a macro to plot several line graphs on two axis (up to 5) side by side. I made the macro open up the files i need, and extract the necessary data into a common workbook. I put the common element, time as the x axis and heat as one y axis and pressure as the secondary axis. The source data on the excel worksheet is as follows:

(column A = time; column b = heat1; column c = pressure1, column d= heat2; and so on.

So when i have 3 workbooks i need to compare, it should have 6 lines. 3 sources work fine, but 2 sources gives me the "Unable to set the AxisGroup Property of the series class" error message.

Code:

Range("A1:" & Chr(65 + (2 * lNum)) & CStr(Lastrow + 1)).Select
Charts.Add
ActiveChart.ApplyCustomType ChartType:=xlBuiltIn, TypeName:= _
"Lines on 2 Axes"
ActiveChart.SetSourceData Source:=Sheets("Sheet1").Range("A1:" & Chr(65 + (2 * lNum)) & CStr(Lastrow + 1))

[Code]...

I don't get why it works for 3 but not 2 sources.

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Jul 14, 2006

I am struggling with one problem. I am trying to change formulae of series in a chart using VBA code given below. But I am getting

'Runtime Error 1004, Unable to set the formula property of the series class'

ActiveChart.SeriesCollection(1).Formula = _
Replace(ActiveChart.SeriesCollection(1).Formula, "Sheet1", "test")

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Set XValues For Series Class (Chart)

Feb 5, 2010

I'm getting an error when I try to set the XValues for a chart in my excel worksheet. The chart shows up fine and the new series adds fine though when I try to set the XValues the below error occurs

'Unable to set the Xvalues property of the Series Class' 1004. My Code is below. Can anyone see anything wrong with it? This could be a floor in my understanding of the chart object. I don't want to be selecting charts and working on an activechart because I'll have several in the one worksheet.

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Unable To Set Hidden Property Of Range Class

Mar 19, 2014

I locked the cells on Sheet1 from B4 to B10.

I protect the Sheet1 Review > protect sheet and selected two checkboxes from protect sheet property "Select locked Cell" and "Select unlocked cells".

It is working fine and it does not allow the user to view the locked cells B17:B24 while protection is on.

I have a RadioButton1 on the same Sheet1 and i put the following code behind the button to hide the 4 up to 10 rows. When i will press the button while password protection is on; it is giving me the following error:

Unable to set the Hidden property of the Range class.

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Unable To Set The Visible Property Of The Worksheet Class

Jan 6, 2009

I've been using the following code successfully for years. Today I would get the error 1004:Unable to set the visible property of the worksheet class. All my searches came up with someone not realizing they had protected the workbook. As you can see, the first thing I do before trying to set the worksheet visible is to unprotect the workbook. In frustration and on a lark I tried .Sheets("items").Visible = True and it worked. These kind of intermittent errors in Excel VBA are very frustrating. Can anyone tell me what I am doing wrong?

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Unable To Get The FindNext Property Of The Range Class

Jun 26, 2009

I keep getting that error when I'm running my macro. When I debug, it points me to the bolded line in the code below. The larger macro I'm running this function in runs this function some 101 times without error before this happens.

The values of the parameters are as follows when it gives me the error:
Find_Exact("hchen", ws1, "B:B"). The first parameter is the only one that changes in the previously mentioned running of this function.

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Unable To Get The VLookup Property Of The WorksheetFunction Class...

Dec 4, 2009

I am trying to look at column at of two different workBOOKS and then when a match is found take the value from column D in workbook two and copy it to the corresponding row in the current column of workbook one.

this is the code I'm using and I get that unable to get the vlookup function. I thought maybe it was because not all of them will have matches so it could return an error if it is trying to return empty, so I put int on error resume next, and it ran through but never brought over ANY data, and there ARE matches and data to be brought over.

destRng is the range in the current column(that i just inserted) on the active worksheet that we will be putting the new info into. srcRng is the range in column A on the other workbook that the numbers are being compared to. src is just an integer

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Unable To Set Weight Property Of Border Class

Apr 22, 2010

I am using the following few lines of code:

Code:

Range("A3:L" & ActiveCell.Offset(1, 0).Row).Select
With Selection

.Borders(xlEdgeLeft).Weight = xlMedium
.Borders(xlEdgeTop).Weight = xlMedium
.Borders(xlEdgeBottom).Weight = xlMedium
.Borders(xlEdgeRight).Weight = xlMedium
.Borders(xlInsideVertical).Weight = xlThin
.Borders(xlInsideHorizontal).Weight = xlThin

End With

However am receiving an error: "Unable to set the Weight Property of the Border Class". The odd thing is, I only receive the error on the following 2 lines:

Code:

.Borders(xlEdgeBottom).Weight = xlMedium
'and
.Borders(xlInsideHorizontal).Weight = xlThin

The sheet is not protected, events are disabled, and the range that gets selected changes dynamically based on the number of rows of data in the table, however in this example cells A3:L15 are selected.

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May 1, 2014

The problem is coming from the Else statement.

Code:
Sub LockByColor()
ActiveSheet.Unprotect "pc"
Dim cl As Range
For Each cl In Range("$BO$1:$BZ$45")
If cl.Interior.Color = 6299648 Then
cl.Locked = True
Else: cl.Locked = False
End If
Next cl
ActiveSheet.Protect "pc"
End Sub

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Jul 3, 2014

I have been working on this small project and I it works to create checkboxes and check what boxes are checked. However, at the end of checking which boxes are checked there is a pop up error message saying Run-Time error '1004': Unable to get the CheckBoxes property of the Worksheet class. These are the lines of code, where is the error?

Sub IsBoxChecked()
Dim titles(200) As String
Dim wks As Worksheet

[Code]....

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May 22, 2007

I get the "Unable to get the Correl Property of the worksheetfunction class" Error when I try to run the following code

CurrentRow = 2
CurrentColumn = 2
Finalrow = 5
WS2 = Sheet2
Finalrow2 = 5
Num_Records = 4

Correlation1 = Application.WorksheetFunction.Correl(Range(Cells(CurrentRow, CurrentColumn) & ":" & Cells(Finalrow, CurrentColumn)), WS2.Range("B" & Finalrow2 - Num_Records + 1 & ":B" & Finalrow2

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Sep 22, 2008

Sheets("PRODUCTIVITY").Select
Range("A20").Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlDown)).Select
Range(Selection, Selection.End(xlDown)).Select
With Selection
.Locked = False (***debug screen is highlighting this line***)
.FormulaHidden = False
.ClearContents
End With
Range("A20").Select
ActiveCell.FormulaR1C1 = "PASTE NEW DATA HERE"
Range("A20").Select

This worksheet was built for use of many users so this sheet is PROTECTED.
The user is instructed to copy/paste information from our internal web into the selected areas in the worksheet.
When i UNPROTECT the worksheet the VBA works fine.

The data in the worksheet spans from columns A to P, and the length (# of records) is variable.

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Unable To Get The Sum Property Of The Worksheet Function Class

Jan 19, 2009

Here is the code that generates the error:

Set rng = Range("I:I")
LR = ActiveSheet.Cells(Rows.count, "I").End(xlUp).Row + 2
Range("I" & LR).Value = Application.WorksheetFunction.Sum(rng)
Range("I" & LR).NumberFormat = "#,##0"

and from what I've read on google the .SUM(rng) need to be set to a range, but isn't it already a range? I tried plugging in there Range("I:I") for rng and that didn't work either.

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Feb 23, 2009

I am having trouble with IsError function consistently catching errors in my call to the Search worksheetfunction. For example, here is a snippet of my code that works just fine:

Code: .....

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Apr 27, 2003

When I try and run my macro I keep getting an error message saying Unable to get the Find Property of the Range Class and it refers me to:

TeamRef = Worksheets("Info Reference").Range("A3:A120").Find(What:=strFind1, After:=Worksheets("Info Reference"), _
LookIn:=xlValues, LookAt:=xlWhole, SearchOrder:=xlByRows, _
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Jan 4, 2007

I have a UserForm with one ComboBox and one TextBox. The ComboBox is populated from another sheet with product codes in Col A and names in Col B. When the user selects a product code from the ComboBox the respective name appears in the adjacent TextBox. Once both boxes have been filled the user can then save the data to a third sheet. Now the problem arises when the user tries to manually enter a code into the ComboBox that does not appear in its rowsource - VBA states a run-time error and my new keyboard goes flying out the window again. Attached is an example sheet

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Jul 17, 2007

I am using the below code to unloock certain columns based upon a value in cell a1. The value is the previosu month end date. It was working, but now I am getting " run-time error 1004 Unable to set the locked property of the range class" Can anyone help me to fix the error.

Sub UnlockMe()
Dim cl As Range
ActiveSheet. Unprotect "password"
For Each cl In Range("$B$1:$M$1")
If cl = [a1] Then
cl.EntireColumn.Locked = False
cl.EntireColumn.Interior.ColorIndex = 6
Else
cl.EntireColumn.Locked = True
cl.EntireColumn.Interior.ColorIndex = xlNone
End If
Next cl
ActiveSheet.Protect "password"
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Jan 18, 2012

I'm creating a simple bit of code which needs to include an array formula - but the code below fails;

Selection.FormulaArray = _
"=IF($L3="","",IF(ISERROR(INDEX(Data!$BG$7:$BP$11,MATCH('Pay Advice'!$A$2,Data!$A$7:$A$11,0),MATCH(1,IF(Data!$BG$6:$BP$6='Pay Advice'!$L3,IF(Data!$BG$5:$BP$5='Pay Advice'!H$11,1)),0))),0,INDEX(Data!$BG$7:$BP$11,MATCH('Pay Advice'!$A$2,Data!$A$7:$A$11,0),MATCH(1,IF(Data!$BG$6:$BP$6='Pay Advice'!$L3,IF(Data!$BG$5:$BP$5='Pay Advice'!H$11,1))))))"

"Runtime error 1004: Unable to set the FormulaArray property of the range class"

What am I doing wrong? The formula is fine when typed in.

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Feb 1, 2012

The vlookup worked earlier but now it doesn't and everything looks OK to me. Scroll down a little bit in the code view to see the error line.

HTML Code:
Sub Email_Executed()
Dim OutlookApp As Outlook.Application
Dim MItem As Outlook.MailItem

[Code]...

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Unable To Get The Find Property Of The Worksheet Function Class

Feb 16, 2009

I am using the "Find" in VBA and wanted to test if the value searched for could not be found.

So I get the
error = "Unable to get the find property of the worksheet function class"
When the text cannot be found.

Dim zz As Variant
zz = Application.WorksheetFunction.Find("xx", "Hello", 1)

I also tried
Dim xx as boolean
xx = Application.WorksheetFunction.IsError(Application.WorksheetFunction.Find("xx", "Hello", 10))

But this produced the same error.

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I have popup calendar in a spread sheet that works fine until I share the film which produces the error in the title. Here is the code for the calender:

Private Sub Calendar1_Click()
ActiveCell.Value = CDbl(Calendar1.Value)
'ActiveCell.NumberFormat = "mm/dd/yyyy"
ActiveCell.Select
End Sub

[Code] ...........

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May 3, 2013

If I type in the VBA Editor immediate window

Code:
?application.WorksheetFunction.average(array(1,3))

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Code:
?application.WorksheetFunction.mode(array(1,3))

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(Excel 2010 on 64 bit machine)

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Jul 30, 2013

Here is my code:

Code:
Private Sub ComboBox1_Change()
ActiveSheet.Rows("3:62").Hidden = False
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End Sub

I get a runtime error '1004' when I make my combo box selection. I don't have any security or password protection type stuff. The combo box is part of a more complicated spreadsheet and I don't want to switch to a data validation type drop down and I really want it to be activeX.

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Dec 26, 2013

I am having problems with some vba codes when I protect my workbook; 'I get an run-time error 1004 Unable to set visible property of the worksheet class'

The code I am trying is:

Sub Stats1_Return_TextBox1_Click()
ActiveSheet.Unprotect "meme"
Application.Goto Worksheets("BCM Database").Range("L15")
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How to sort this. One more question is there away of protecting you vba code? stop users being able to view or edit them for instance?

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Oct 31, 2006

I have recently tried to implement the password protect from viewing code from this site. It worked brilliant on a basic spreadsheet, but when I tried to implement it on a worksheet with links I keep getting the error:

Run-time error '1004'
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May 14, 2006

I went through a lot of threads in this forum, although there were a couple relating to the same problem am facing, they didnt solve my error .. so here's my question again ..

When am trying to delink charts , i get an error stating "Unable to set the formula property of series class".

The code is as follows :

Sub DelinkChartData()

Dim iCtr As Integer, iChars As Integer, SH As Shape, iPlotOrder As Integer
Dim nPts As Long, iPts As Long 'Holds the total no of points in the chart
Dim xArray, yArray, sChtName As String, sSrsName As String
Dim xVals, yVals
Dim ChtSeries As Series ' var used to loop thru the series collection
Dim ws As Worksheet
Dim sChartType As String, iCtr1 As Integer

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Mar 3, 2014

I'm looking to loop a comparison code. I'm using dynamic referencing (using x and y) to find maximum values for specific time intervals. The code works on a cell to cell basis, meaning if I input the formula and change the cell referencing manually then the equation will give the desired results. However when I attempted to create a VBA code to speed up the process I kept getting a 1004 Unable to set FormulaArray Property of the Range Class error, I later figured out that the Formula Array function is limited to a certain number of characters so I split up my function into 3 different string formulas. I still get the same error.

[Code] ............

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Jul 10, 2014

I use Excel 2010 andexample.xlsx cannot make my code working because of the so famous errore above.

I have several pivot tables (pt) in different worksheets (ws), and a list of items stored in an array I created. I've written a macro for setting ON all items in pt except those ones in the array (listOffnet within the code). Everything works properly.

Now, I would like to do the complementary action: setting OFF all items that are not in the array. Unfortunately, I get the error at line:

[Code]....

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