Count Characters In A String

Dec 30, 2008

I am trying to count the characters in a string in one cell. For example, I want to count the number of "-"'s in the cell. The version number of part numbers is always the last two characters if the value contains at least one "-". However the parts have a non standard number of characters.

444444 = 0
444-44 = 1
44-44-44 = 2

There can be 0,1 or 2 "-" in the string. I can use the substitute formula to get the root part number, but I was wondering if there is an easier way. The raw data is from our ERP system, so I multiply the value by 1 to get a number if there are no "-" for the vlookup in another formula to work....

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Code:
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Code:
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My question is somewhat similar to this one
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Code:
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I tried

Code:
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VB:
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