Extract Trailing String Of Characters From A URL
Dec 23, 2009
I have a problem that I just dont seem to have the brain power to solve right now. I have a list of websites and I need to extract all characters after the last / in the URL. URL example:.....
I have been using the find function in conjunction with LEN and RIGHT etc but the multiple instances of / is causing headaches for me. Also, the trailing string of characters that I want to extract can be both text or numeric and are of differing lenths.
View 3 Replies
ADVERTISEMENT
Dec 22, 2013
I have the following type of info in A1,A2,A3...
Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50
My goal is to get as close as possible to this,so it will be easier to sort and manage
Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one
Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))
View 3 Replies
View Related
Nov 7, 2008
Say I have a string "09800EBHR052708"
How would I take the first 5 characters and get a number out of them?
View 14 Replies
View Related
May 14, 2013
Having trouble with this one. Searches seem to bring up every other variation of extracting info from strings except this.
I have cells which contain alphanumeric strings as below and, using a formula, I want to extract everything from and including the last letter to give A 2-3, B 3 and C 3-4 in the examples below.
Sub-base A 2-3
Sub-base B 3
Paving C 3-4
View 7 Replies
View Related
Feb 27, 2009
I am trying to create a CSV file to import all of our workers into a payroll software. Unfortunately the list of workers that I have been given to work with has a first and a last name together in one cell. I need to split them into separate cells so the data ends up in the right field in our software. By importing external data and separating the names with the comma as a delimiter, I have ended up with the first name in one cell and the second in another, which is exactly what I need. However, this process also ends up putting a quotation mark in front of the first names in the cells in column A, and a quotation mark after the second name in the cells in column B.
I remember to removing trailing spaces with a macro once, and I am hoping the same theory can be applied to make two macros - one to remove preceding quotation marks, and one to remove trailing quotation marks. The only trouble is, I know no VBA whatsoever, and don't even know how to make a macro unfortunately. Would someone mind letting me know if what I need is possible, and then - literally step by basic step - explain how to make a macro and provide the code to paste into it?
View 2 Replies
View Related
Jun 23, 2014
I want to alert a user that he or she has typed in a text string that begins or ends with an apostrophe ' or begins or ends with a quotation mark " so that they can take corrective action in removing these characters. The reasons for this are superflous to this post but what I thought was a logical answer returns a formula error. Here's the scenario:-
A user enters a string of text in cell A1.
Cell B1 checks if the text, if any, in A1 begins or ends with a ' or a " and if it does, returns an "Error" message
The formula I've tried in B1 is =IF(OR(LEFT(A1,1)="'",LEFT(A1,1)=""",RIGHT(A1,1)="'",RIGHT(A1,1)=""")),"Error","Ok") but Excel will have none of it.
View 9 Replies
View Related
Jun 11, 2012
I'm scanning data into a spreadsheet using a barcode scanner, but I want the starting character and trailing characters to be removed after I hit enter.
For example...let's say I'm scanning the following text in cell A1:
=W05281212345600
When I hit enter (or the barcode scanner does auto-enter), I want cell A1 to read:
W052812123456
I will always want the "=" and the last two zeros removed from the 16 character number, leaving the 13-character number in its place.
I tried using Excel's various truncate functions (LEFT,RIGHT,MID, etc.), but that only places the corrected text in another cell. That would be fine if I could copy that truncated text back over the original text...but that created a loop problem.
View 1 Replies
View Related
Jan 31, 2014
I've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.
Is there an easy way to do something similar to the following that will remove the CR/LF characters?
[Code] .....
View 5 Replies
View Related
Sep 4, 2012
I am working with flight numbers and want to split out the letters from the digits. Examples,
BA1234A
BA123
EZY4566H
BE7893B
In column A I need the first two or three letters only,
BA
BA
EZY
BE
In column B I need everything to the right of what appears in column A
1234A
123
4566H
893B
etc.
View 7 Replies
View Related
Aug 23, 2007
I have a problems here. The problems is attached in the file. I wanna extract alpha/char from a string. Example: I wanna extract the words "(M)" with the bracket from the string "Toothbrush (M)" in column A. After extracting the (M) out, I wanna do a validation to compare the (M) in column B with another data in column C, if the (M) is same as the data called "Medium" in column c, the validation will return "Match" in the column d!
View 9 Replies
View Related
Dec 29, 2013
I would like to extract any numerals between the comma and colon. (Format is text)
Example: 8 Dec, 1:52PM (1 to show in another cell)
Format is always the same but date/day & hour may change. (Hence changing number of characters depending on day and time.)
Example: 11 Dec, 10:49AM (10 to show in another cell.)
View 2 Replies
View Related
Feb 3, 2012
In column M I have data that lists a number, then number of metres between brackets. For instance
Column M
11 (79m)
1 (5m)
22 (123m)
Basically what I want to do is to always return the number of metres without m, so the data between "(" and "m".
I tried to do this using the find and mid formulas, but I either haven't got it quite right. I'm only after a spreadsheet solution (not VBA).
View 6 Replies
View Related
Oct 8, 2013
Data in field A1 currently appears as below.
8/10
I want to extract everything to the right of the "/" in a new field.
The formula that I am using is =RIGHT(A1,FIND("/",A1)-1)
For some reason, I am only receiving a 0 in the new field and not the 10 that I expect.
What's odd is that the formula is working as intended on every other field except this one.
View 6 Replies
View Related
Jul 1, 2009
I have a column contains Postal Adress in more than 5000 rows. Column contains Door Number, Area, City and Zip code. I need to separate "Zip code" alone in next coulmn. Zip code (of India) will be in six digits like "600083" also some cases contain space in middle of zip code like "600 083" (after 3 digits). Is there any way to do this without doing cut & paste?
View 9 Replies
View Related
Jul 3, 2009
I have a column contains Telephone numbers with or without area code and country code for across the country (India). I need to extract the telephone numbers alone (neither area code nor country code). Telephone numbers will be 6 or 7 or 8 digits (not more than that). Is it possible to extract any set of numbers contain 6 or 7 or 8 digits continously? Some of the cases contains 2 contact numbers (2 set of 6 or 7 or 8 digit characters, between special characters will be there like slash, comma, space, hypen, etc.,
Here are some examples: ....
View 9 Replies
View Related
Sep 28, 2006
Column A in Excel has loads of numbers all in this format 971-417. I need to have each of those two numbers in a separate cell from each other(and without the hyphen of course).
Column A Needs to be: Column A Column B
971-417 971 417
In short, I'm looking for a quick way to put each number in its own cell for hundreds of rows. Are there formulas I can use to do this or does it have to be done slowly, one at a time, stripping the information from one cell to another?
View 6 Replies
View Related
Nov 15, 2006
i have a list of information, and from that i want to extract a certain piece from that information and out it in a new cell...
eg. 'KLM00506', 'KLM00409-10', 'KLM00821-9' etc
as you can see, the info is not in the same length
what i need is to take out the FIRST 6 characters and have the remaining to be in a new cell
anyone has an excel formula that i can use ? not really interested in code, cause in this particular worksheet, everything is at its' place, no code required
View 4 Replies
View Related
May 6, 2009
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
=LOOKUP(9.99E+307,--MID(C4,MIN(FIND({1,2,3,4,5,6,7,8,9,0},C4&1234567890)),ROW(INDIRECT("1:"&LEN(C4)))))
is the solution, but I'm struggling with making the correct alterations.
View 2 Replies
View Related
Apr 24, 2009
I need a Excel 2007 formula that will extract a string of text that is seperated by characters.
Example:
in Cell (A1) I have the following
ALA 11 : [ MOBILE ] 36619 1/2 ... HOME ... JUNE 2009 / TODAY: $ 50000
End Result wanted:
Cell (A2) 11
Cell (A3) MOBILE
Cell (A4) 36619 1/2
Cell (A5) HOME
Cell (A6) JUNE 2009
Cell (A7) 50000
View 8 Replies
View Related
Oct 6, 2006
I am trying to write a function that finds and breaks a cell about the first space.
Worksheet is:
=LEFT(name,FIND(" ",name)-1)
Have tried...
Function Firstname(name)
Dim Space As Integer
Set Space = .Find(" ", name)
Firstname = Left(name, Space)
End Function
and also...
Function Firstname(name)
firstname = left(name,find(" ",name)-1))
End Function
View 6 Replies
View Related
Nov 10, 2006
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
EX.
Cell A1{ 1 2 4 5 3 5 TITLE1 1 2 3 6 7 4 5 TITLE2 3 4 5 2 4 5 TITLE 4 }
Cell A2{ 1 2 4 5 3 5 TITLE2 1 2 3 6 7 4 5 TITLE3 3 4 5 2 4 5 TITLE 4 }
I would like to be able to search each cell for the "TitleX" then parse data out to the left of that title (and if not found, return "").
There are too many different Titles to use IF statements and I cannot change that the data comes to the left of the title.
View 9 Replies
View Related
Jan 10, 2014
I have a list of numbers in which I need to return the last 5 digits; the length of the string may vary.
However, if the last two digits of the number ends in a specific value then it should skip over the last two numbers and return the preceding 5 digits.
I have tried and have used the very basic Left, Right and Mid functions. My problem is I dont know how to code the formula to identify the last two digits and skip over them, if necessary.
I have provided an attached example.
Extract numeric value based upon ending characters.xlsm
View 5 Replies
View Related
Jun 12, 2008
I have the following in Column A
28VNC
JR2KL
29C9O
PQS11
I'd like have this result
28
2
299
11
How would I achieve this.
View 6 Replies
View Related
May 23, 2008
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
View 4 Replies
View Related
Apr 9, 2014
I'm working with a large list of items of varying length. A sample worksheet is attached. I need to do the following:
1) If the characters after the final forward slash from the right are of the pattern "tttxxx" (where "t" is text and "x" is a number/digit), then return all characters to the right of the final slash, including the slash itself:
Y:/Series/hun/hun109 ----> /hun109
2) if the characters after the final slash from the right are not of the pattern "tttxxx", then return all characters after the second slash from the right, including the slash:
Z:/Series/crd/crd409/editorial ----> /crd409/editorial
3) if there are less than 3 backslashes in the item, return a blank.
View 3 Replies
View Related
Sep 10, 2013
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
View 9 Replies
View Related
Feb 17, 2014
i have 8 digit invoice numbers. Each 8 digit number starts with one of three 4 digit ID codes. Depending on the first 4 digits, I want a different "company" to show up.
First seems to work fine.
=IF(E6>"1NCC","North Carolina",IF(E6>"2ALA","Alabama",IF(E6>"3SCC","South Carolina")))
View 3 Replies
View Related
Feb 24, 2014
I have variable length strings, as shown in the sample cells below
TopographyTAB_FormatSP9200
TopographyTAB_FormatSP9400
OS_DataLandline
ITNTileTabTQ2286
I want to select any record where 5th and 6th character from the right hand end of the string which = either "SP" or "TQ". Where this is the case I'm then looking to truncate the string to remove the last 7 chacters.
None of what I have so far found using mid or right string appears to be particularly applicable.
View 9 Replies
View Related
Dec 26, 2009
I'm trying to remove everything after a specific character in a string.
I.e. change a website address to the hostname
http://www.excelforum.com/newthread.php
http://usa.excelforum.com/forum/new
to
excelforum.com
usa.excelforum.com
I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A2,"www.",""), A2,"http://",""), A2, "/*", "")
View 11 Replies
View Related
Feb 11, 2009
Replace characters in a string. I have this macro:
View 2 Replies
View Related
