I have a problem that I just dont seem to have the brain power to solve right now. I have a list of websites and I need to extract all characters after the last / in the URL. URL example:.....
I have been using the find function in conjunction with LEN and RIGHT etc but the multiple instances of / is causing headaches for me. Also, the trailing string of characters that I want to extract can be both text or numeric and are of differing lenths.
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Having trouble with this one. Searches seem to bring up every other variation of extracting info from strings except this.
I have cells which contain alphanumeric strings as below and, using a formula, I want to extract everything from and including the last letter to give A 2-3, B 3 and C 3-4 in the examples below.
I am trying to create a CSV file to import all of our workers into a payroll software. Unfortunately the list of workers that I have been given to work with has a first and a last name together in one cell. I need to split them into separate cells so the data ends up in the right field in our software. By importing external data and separating the names with the comma as a delimiter, I have ended up with the first name in one cell and the second in another, which is exactly what I need. However, this process also ends up putting a quotation mark in front of the first names in the cells in column A, and a quotation mark after the second name in the cells in column B.
I remember to removing trailing spaces with a macro once, and I am hoping the same theory can be applied to make two macros - one to remove preceding quotation marks, and one to remove trailing quotation marks. The only trouble is, I know no VBA whatsoever, and don't even know how to make a macro unfortunately. Would someone mind letting me know if what I need is possible, and then - literally step by basic step - explain how to make a macro and provide the code to paste into it?
I want to alert a user that he or she has typed in a text string that begins or ends with an apostrophe ' or begins or ends with a quotation mark " so that they can take corrective action in removing these characters. The reasons for this are superflous to this post but what I thought was a logical answer returns a formula error. Here's the scenario:-
A user enters a string of text in cell A1.
Cell B1 checks if the text, if any, in A1 begins or ends with a ' or a " and if it does, returns an "Error" message
The formula I've tried in B1 is =IF(OR(LEFT(A1,1)="'",LEFT(A1,1)=""",RIGHT(A1,1)="'",RIGHT(A1,1)=""")),"Error","Ok") but Excel will have none of it.
I'm scanning data into a spreadsheet using a barcode scanner, but I want the starting character and trailing characters to be removed after I hit enter.
For example...let's say I'm scanning the following text in cell A1:
=W05281212345600
When I hit enter (or the barcode scanner does auto-enter), I want cell A1 to read:
W052812123456
I will always want the "=" and the last two zeros removed from the 16 character number, leaving the 13-character number in its place.
I tried using Excel's various truncate functions (LEFT,RIGHT,MID, etc.), but that only places the corrected text in another cell. That would be fine if I could copy that truncated text back over the original text...but that created a loop problem.
I've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.
Is there an easy way to do something similar to the following that will remove the CR/LF characters?
I have a problems here. The problems is attached in the file. I wanna extract alpha/char from a string. Example: I wanna extract the words "(M)" with the bracket from the string "Toothbrush (M)" in column A. After extracting the (M) out, I wanna do a validation to compare the (M) in column B with another data in column C, if the (M) is same as the data called "Medium" in column c, the validation will return "Match" in the column d!
I have a column contains Postal Adress in more than 5000 rows. Column contains Door Number, Area, City and Zip code. I need to separate "Zip code" alone in next coulmn. Zip code (of India) will be in six digits like "600083" also some cases contain space in middle of zip code like "600 083" (after 3 digits). Is there any way to do this without doing cut & paste?
I have a column contains Telephone numbers with or without area code and country code for across the country (India). I need to extract the telephone numbers alone (neither area code nor country code). Telephone numbers will be 6 or 7 or 8 digits (not more than that). Is it possible to extract any set of numbers contain 6 or 7 or 8 digits continously? Some of the cases contains 2 contact numbers (2 set of 6 or 7 or 8 digit characters, between special characters will be there like slash, comma, space, hypen, etc.,
Column A in Excel has loads of numbers all in this format 971-417. I need to have each of those two numbers in a separate cell from each other(and without the hyphen of course).
Column A Needs to be: Column A Column B 971-417 971 417
In short, I'm looking for a quick way to put each number in its own cell for hundreds of rows. Are there formulas I can use to do this or does it have to be done slowly, one at a time, stripping the information from one cell to another?
i have a list of information, and from that i want to extract a certain piece from that information and out it in a new cell... eg. 'KLM00506', 'KLM00409-10', 'KLM00821-9' etc
as you can see, the info is not in the same length what i need is to take out the FIRST 6 characters and have the remaining to be in a new cell
anyone has an excel formula that i can use ? not really interested in code, cause in this particular worksheet, everything is at its' place, no code required
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
I am attempting to utilize the Mid, Left, and Right functions to parse out data returned in a single cell. There are twelve months of data returned with the "title" listed after. I would like to be able to FIND the title and return a specific number of characters of data to the LEFT not the right (as Mid seems to do).
I have a list of numbers in which I need to return the last 5 digits; the length of the string may vary.
However, if the last two digits of the number ends in a specific value then it should skip over the last two numbers and return the preceding 5 digits.
I have tried and have used the very basic Left, Right and Mid functions. My problem is I dont know how to code the formula to identify the last two digits and skip over them, if necessary.
I have provided an attached example.
Extract numeric value based upon ending characters.xlsm
I'm working with a large list of items of varying length. A sample worksheet is attached. I need to do the following:
1) If the characters after the final forward slash from the right are of the pattern "tttxxx" (where "t" is text and "x" is a number/digit), then return all characters to the right of the final slash, including the slash itself:
Y:/Series/hun/hun109 ----> /hun109
2) if the characters after the final slash from the right are not of the pattern "tttxxx", then return all characters after the second slash from the right, including the slash:
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
i have 8 digit invoice numbers. Each 8 digit number starts with one of three 4 digit ID codes. Depending on the first 4 digits, I want a different "company" to show up.
I want to select any record where 5th and 6th character from the right hand end of the string which = either "SP" or "TQ". Where this is the case I'm then looking to truncate the string to remove the last 7 chacters.
None of what I have so far found using mid or right string appears to be particularly applicable.
I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.
