How To Trim Last 3 Characters From End Of String
Aug 21, 2012
I'm having difficulty figuring out how i can Trim the last 3 characters from this string
Code:
FeatureCode1 = Split(errorChecker.lstErrorMessage.List(0), " [")(0))
I tried
Code:
FeatureCode1 = Left(Split(errorChecker.lstErrorMessage.List(0), " [")(0)), 3)
But that only SHOWS the last 3 characters... how i can just cut off the last 3 characters?
I'm guessing something to do with TRIM, but not sure how to implement it?
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Sep 11, 2013
I want to trim text into 10 characters.I am new to excel.
Attached is the sample sheet.
TRIM.xls‎
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Aug 22, 2007
I have a cell which holds text with a maximum number of characters of 6. Let´s say I want this cell to hold a word which is bigger, and trim it till it has 6 characters.
Example: word "Hippopotamus" (longer than 6 characters) should be trimmed so its displayed as "Hippop"(6 characters)
is there a way to specify how i want to trim, either right or left?
Example "Hippop"(6 characters trim right) or "otamus" (6 characters trim left)
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Feb 24, 2009
I have something simple (i think) but i cant think it through. I have a range of cells that are populated by a link and so even though the value shows #,### It really shows #,###.########
I would like to trim everything after the decimal point without having to adjust format of the range since some cells are general format and others are Percentage format but they all suffer from .####### HOWEVER, the last digits are variable and never the exact same amount of characters.
for each cell in range("C4:J9")
if cell.value "" then
Trim(Left(cell,4))
end if
next cell
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Apr 9, 2014
This formula I want to apply it in another workbook. It split in different columns the content of a cell.
The formula is below:
[Code] .....
In cell A2 I have the following data:
|516582-001-99|414816-001-99|414816-003-99|516582-001-99|
If I apply the formula above in cells B2 to E2 it returns a blank cells. But if I delete the first "|" sign in the left side manually the formula works perfectly by splitting the cell into columns from B2 to E2. The issue here is that I have more than 300,000 records. Just imagine the amount of time invested in just deleting the first "|" at the left side.
I need a variation of the formula above that in first place delete the first "|" at the left side and after that continue with the proper work of the formula.
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Mar 11, 2014
I have some code that grabs the name of a staff member. The format is:
Code:
Result = Trim(Sess0.Screen.GetString(8, 33, 10))
.Cells(r, 15).Value = Result
How do you trim the string before the first space so the value in Result would be just the last name (DOE)?
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Jan 31, 2014
I've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.
Is there an easy way to do something similar to the following that will remove the CR/LF characters?
[Code] .....
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Dec 2, 2013
i have a device that produce its data as following:
NTFLog_D2013-02-12_T104016.csv
I need to divide the single column to 7 column as separated by semicolon ";"
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Dec 22, 2013
I have the following type of info in A1,A2,A3...
Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50
My goal is to get as close as possible to this,so it will be easier to sort and manage
Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one
Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))
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Apr 25, 2007
I have come up with this to Trim all of the data from rows 2:30 removing any trailing spaces after the last word in each cell. The macro takes a couple of minutes to run have I got something wrong that is making it run slowly or does the Trim process just take longer?
Sub TRIM_RANGE()
Dim myRange As Range
Dim myRow As Range
Sheets("CAMPAIGNS_2007").Select
Set myRange = Range("2:30")
If myRange Is Nothing Then Exit Sub
Application. ScreenUpdating = False
myRange.Replace What:=Chr(160), Replacement:=Chr(32), _
LookAt:=xlPart, SearchOrder:=xlByRows, MatchCase:=False
For Each myRow In myRange.Columns
If Application. CountA(myRow) > 0 Then
myRow.TextToColumns Destination:=myRow(1), _
DataType:=xlFixedWidth, FieldInfo:=Array(0, 1)
End If
Next myRow
Application.ScreenUpdating = True
End Sub
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Feb 17, 2014
i have 8 digit invoice numbers. Each 8 digit number starts with one of three 4 digit ID codes. Depending on the first 4 digits, I want a different "company" to show up.
First seems to work fine.
=IF(E6>"1NCC","North Carolina",IF(E6>"2ALA","Alabama",IF(E6>"3SCC","South Carolina")))
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Feb 24, 2014
I have variable length strings, as shown in the sample cells below
TopographyTAB_FormatSP9200
TopographyTAB_FormatSP9400
OS_DataLandline
ITNTileTabTQ2286
I want to select any record where 5th and 6th character from the right hand end of the string which = either "SP" or "TQ". Where this is the case I'm then looking to truncate the string to remove the last 7 chacters.
None of what I have so far found using mid or right string appears to be particularly applicable.
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Dec 26, 2009
I'm trying to remove everything after a specific character in a string.
I.e. change a website address to the hostname
http://www.excelforum.com/newthread.php
http://usa.excelforum.com/forum/new
to
excelforum.com
usa.excelforum.com
I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A2,"www.",""), A2,"http://",""), A2, "/*", "")
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Feb 11, 2009
Replace characters in a string. I have this macro:
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Feb 21, 2010
I'm importing data from the internet. The cell I'm trying to get is B8 on "Temp_Data" onto cell E3 on "Other Data". When it imports the cell into Temp_Data for some reason the cell expands, and I can't have that. I would manually copy and "Paste Special", text, into the proper cell, and that works. I can also copy the fist 7 letters in the string from B8 and paste them into E3. My code currently looks like this:
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Dec 30, 2008
I am trying to count the characters in a string in one cell. For example, I want to count the number of "-"'s in the cell. The version number of part numbers is always the last two characters if the value contains at least one "-". However the parts have a non standard number of characters.
444444 = 0
444-44 = 1
44-44-44 = 2
There can be 0,1 or 2 "-" in the string. I can use the substitute formula to get the root part number, but I was wondering if there is an easier way. The raw data is from our ERP system, so I multiply the value by 1 to get a number if there are no "-" for the vlookup in another formula to work....
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Dec 22, 2009
Is it possible to format a character in a string using vba?
For example if i had a string of GGGFF, and i wanted to make the G's appear as Green font and the F's as Red font.
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Nov 16, 2006
I have a string like: AAJDGYE030000460. How can I remove the first character in a macro? I need to look at the second,third, and forth character
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Dec 21, 2006
I have a set of data in column a that consists of email addresses. These email addresses all have underscores after them, ie "abc@hotmail.com_______". It will be a different amount of underscores everytime and I don't want underscores to be removed that are actually part of the address. I had been using the find replace function through vba, ie
Range("A:A").Select
Selection.Replace What:="_", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
however this ofcourse removes from actual parts of the email address. Is there a way to do this?
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Apr 11, 2007
I have a string, specifically a file path, and I want to take the last 5 characters of the string. How would I got about doing this?
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Jan 22, 2008
I've come across multiple times where I have to do this same sort of task, and I don't think I am doing it the most efficient way.
What I need to do is take a variable which holds a string and remove the last 9 characters from it. Don't need to know what the last 9 characters are, all I care about is knowing what the other characters are in the string. I know this can be done through thingslike susbstrings, but I don't think VBA has a substring function.
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Oct 24, 2012
I want to get only unique characters in a text. For ex. ozgrid.com. I should get ozgrid.cm (o is already came). another one. For ABCEABC the result will be ABCE. So I have written an UDF. Unfortunately there was "Argument is not optional" error in "UNIQUECHARS = Join(JoinT.Item)".
How could I get rid from this error and get my result?
Below is my code.
VB:
Public Function UNIQUECHARS(chtxt As String)
Dim c() As Variant
Dim JoinT As New Collection
Dim sp As String
cchtxt = Application.WorksheetFunction.Substitute(chtxt, " ", "")
[Code] ......
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Aug 2, 2006
I am trying to remove all characters that aren't letters or numbers from a string. Is there any way to differentiate between a non-alphanumeric characters and alphanumeric characters? I'm thinking of something like "ISTEXT()" that I could use on one character at a time. Or are there any wildcards I could use in the Replace function?
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Dec 23, 2008
I'm using Excel 2007. I want to write a formula that will list all characters in a string to the left of a "-". See below example. What formula would I use?.......
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Jul 11, 2014
Is it possible to find the location of different characters in a string (using VBA)? Normally I would use InStr of InStrRev option in VBA but my situation is a little more complicated.
The character I am looking for is not always the same, sometimes it is a , or a . or a : or a "blank" etc
I tried to do it like:
dim strChar as string
strChar = "[,.? /]"
SearchPosition = InStr ("cell location", strChar) (searchposition is the name of the function I am trying to make)
This works if I define only 1 character, this way it gives me a 0 as outcome
I have tried to change it to strChar = "[,]" or strChar = "[.]" or strChar = "[ ]" but this doesn't work.
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Nov 21, 2009
I have about 700 cells I want to interrogate. Within each cell the following text appears “Estimate – BOLB/02/1234 – Some more text here”. I want to search all the cells and delete the cell contents but leave the “BOLB/02/1234”.
The problem I have is that the string is different in each cell but the format is the same. It always starts with BOLB followed by /, followed by 2 numbers, followed by / followed by 4 numbers i.e. BOLB/**/****.
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Dec 23, 2009
I have a problem that I just don’t seem to have the brain power to solve right now. I have a list of websites and I need to extract all characters after the last “/” in the URL. URL example:.....
I have been using the find function in conjunction with LEN and RIGHT etc but the multiple instances of “/” is causing headaches for me. Also, the trailing string of characters that I want to extract can be both text or numeric and are of differing lenths.
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Jan 30, 2013
I haven't had the need to work with partial strings till now and having difficulty finding the right context in other threads. I need to put the first 4 characters of one cell into another cell. The line in the below code with the comment is the one I need. It's the only one where I need only part of what is in the cell.
It should be = the first four characters of cells(zRow, "A")
Code:
Dim LastRow As Long
Dim zRow As Long
Dim cRow as Long
LastRow = Sheets("Datasheet").Range("N65536").End(xlUp).Row
zRow = 1
cRow = 2
[Code] ......
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Oct 10, 2013
I have a sheet of about 10k rows that I need to switch some things around on. The string is below:
Acura|TL|1995^^Acura|TL|1996^^Acura|TL|1997^^Acura|TL|1998^^Acura|TL|1999
It needs to say:
1995|Acura|TL^^1996|Acura|TL^^1997|Acura|TL^^1998|Acura|TL^^1999|Acura|TL
How to fix this with a macro or formula. The Make Model and Year on each string will be different. Basically I need the format to be Make|Model|Year.
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Feb 15, 2014
A string contain a number like AB12345 or B7845 How could I remove the alphabetic characters and keep only the number.
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