Say for example I have ABCD-ABC12 basically an arbitrary length of alpha (A-Z) characters followed by an hypen "-" followed by another arbitrary length of alpha (A-Z) characters and then
immediately followed by an arbitrary length of numbers. (with no spaces between alpha and number)
How can I extract just the numbers from the group of alphanumberic characters after the hyphen
and set it to a LONG variable?
I have this formula that extracts numbers from alphanumeric strings.
{=1*MID(A1,MATCH(TRUE,ISNUMBER(1*MID(A1,ROW($1:$100),1)),0),COUNT(1*MID(A1,ROW($1:$100),1)))}
However this extracts only the 1st instance of the numbers
In a string like 123avfbsdf4556.. it'll extract only 123.
My questions are the following:
1. Is there a way that i could get the result as 1234556
2. A way which refers to a cell where I put in a number and it'll extract those many number instances. In the above example, if I put the number as 1, it'll extract 123. If I put the number as 2, it'll extract 4556 and so on.
I guess this would require some modifications to the Match function so that it does not look at only the 1st instance.
I'm looking for a way to extract numbers from a string.
The string can potentially have as few as one number or as many as 25. Each number is separated by a comma.
Here is the code that creates the string: ...
I have the following text string.
What formula can I use to extract these results on the right?
Sample file.xlsx
I've got a cell with codes, such as:
21ML,
43GKP,
etc.
I want these to look like :
ML21,
GKP43,
i.e. swap the numbers with the letters but keeping the order of the characters.
I would like to parse a part number.
ab24s-12-g4a
if there is a "-#-" in the string, that is the value I want. If the "-#-" is not present, I would like to take the first number. Currently, as written in your first example, I am getting the first number - excellent and thank you!
In the sku, the first digit reprepresents capacity. If a second number is present after the capacity portion of the sku (i.e. "-#-"), that means that they want to order it filled with less than capacity. For instance, a carton of eggs and they want 6 eggs instead of the max capacity of 12. (i.e. egg12-6-z2z). Numbers after the second octet (i.e. z2z) do not matter.
It would be a number only in the second octet. If there are characters with it, the equation should disregard it.
Here are the scenarios, and what the formula should accomplish
1) egg12 --> currently returns 12
2) egg12-6 --> would return 6
3) egg12-6-g2c --> would return 6
4) egg12-g2c --> would return 12
Have many rows of alphanumeric strings. 2-4 letters followed by a variety of numbers, some spaces, and some additional letters. What I need is to return the first number after the initial 2-4 letters, everything after that first digit is junk. Thus, I would like a formula that takes me from:
AB23400 12 -> 2
CET25800 1 -> 2
NYT67300 H01 -> 6
HSRF49900 1 -> 4
I need to extract just the text from cells which contain both letters and numbers. There can be one or two letters, followed by one, two or three numbers. (For info, these are chemical elements and their masses). So for instance,a cell could contain anything from the following B9, B11, S32, Ca44, Mo100, I129, Th226, U238 etc etc. I know I've seen this done before, but I can't find it now. It also has to be formula based, not using VBA.
View 4 Replies View RelatedI have got a list of numeric abbreviations, for instance 10739011/21/31/41. What it should really display are the numbers 10739011, 10739021, 10739031 and 10739041 (the first six figures stay the same). All the numbers in my list are 8 figures long. I want to change the list from the list seperated by the backward slash to the complete numbers. I have uploaded an example of the list with backward slash between the numbers. Is there a way that Excel can automatically change these numbers to the full numbers?
Because all the numbers are 8 figures long, I thought the first 6 figures of the 1st number can be copied and those 6 figures pasted before the other two figures after the backslash. Auto Merged Post Until 24 Hrs Passes;sorry, pressed OK too quickly. The problem is that there are sometimes 4 numbers in the cell, sometimes 6 and once three. I would like Excel to complete all the numbers in the cell and then move on to the cell underneath it and so on. Also, I would like each number to have it's own cell.
Is there a way either by VBA or manually (preferably both, if possible) to actually unite the X amount of numbers that are in a cell given the contents is alphanumeric? I'll give you the following examples to see if you can understand what I' referring to?
DATA output should be
asd67,h876 --------> 67876
2,3,ujdj5&34 -------> 23534
909k86m34 --------> 9098634
What is the formula to be used to extract number from a alphanumeric string located at different row?
example:
test123test128test131
test124test129test132
test125test130test133
test126test131test134
test127test132test135
test128test133test136
result: ....
I have another question regarding extracting Alphabet from the alpha Numeric String:
Column A
POT470G12B
PBY100G12
PCLN6400S12
PCX.US10X12
AAPL6000G12A
BP380S12A
BP390S12
The output i want from the string is :
Column A
Column B
POT470G12B
G
PBY100G12
G
[Code] ........
I have the following in Column A
28VNC
JR2KL
29C9O
PQS11
I'd like have this result
28
2
299
11
How would I achieve this.
I import data from another program in order to evaluate it. Unfortunately, one of the fields I need contains copyright data, however, it has been very inconsistently entered into the database. For example, sometimes the data appears "c1999." or "-1999" or "" or "[1999]" or even "19?" and also sometimes "1999, 1990" and many other variations on that. I discovered the link in the excel help file about extracting numbers from alphanumeric strings, but my situation is still too variable for it to apply; that file didn't take into account that alphanumeric strings don't always lump numbers and letters together. I was able to correct a few things, but my command of excel isn't knowledgeable enough to really come up with something effective.
Some ideas I had that I don't know how to implement: is there a way to strip non-numerical characters from an alphanumeric string? (I've been doing some find/replaces to get rid of some of it, but that is obviously not very efficient when I have to repeat this process daily.) Perhaps then I could just detect the first 4 numbers of the string somehow. However, that doesn't solve the problem of when a wild card is used as in "199?" or "20?" etc.
Bottom line, I just need to grab the first four numbers that appear in the string (but NOT additional numbers that occur after a wild card or a space if the year was not completed in 4 numbers; in that case I'd just be happy with a null value).
I've been doing this with a formula so far. My only experience with macros has been in simply recording them, not actually writing them, but I'll give anything a try.
Having trouble with this one. Searches seem to bring up every other variation of extracting info from strings except this.
I have cells which contain alphanumeric strings as below and, using a formula, I want to extract everything from and including the last letter to give A 2-3, B 3 and C 3-4 in the examples below.
Sub-base A 2-3
Sub-base B 3
Paving C 3-4
I have a cell in my worksheet with a fully qualified filename like 'D:abcDefGHIJklxyz123.app
I would like to extract only the xyz123.app. Obviously, the number of characters is going to vary based on the filename. The find and search functions appear to locate the cell but not the substring in the text. The right and left appear to work based on number of characters and in my case these are varying. Also, there does not appear to be any function that can do a search a string from right to left.
My mission is to extract email addresses from cells. or I want any word that contains "@" in column A to be extracted in column B.
For example, if cell A1 contains: tracy jane@gmail.com , I want jane@gmail.com to be put in B1.
I have list like the below. I need to pull out everything before the space for each of these and after the _ which is after the CRN_, SA_ or MA_
CRN_212141 JRDC 7402-01_ICT-ICM IT Services Basel PDiv 3702 POPEnd 01/31/2015
MA_7500007822 JRDC
SA_GS-35F-4461G No Alias Determined
CRN_179764 Director of Administration and Managem PDiv 3799 POPEnd 06/30/2014
MA_N00189-09-D-Z044 USJFCOM Projects
SA_GS-35F-4461G No Alias Determined
Desired Results:
212141
7500007822
GS-35F-4461G
179764
N00189-09-D-Z044
GS-35F-4461G
I have a column that has various codes such as "E123" and "X456" and "S345". I just want to extract the numbers and leave the letters in each cell. How do you write a formula using the LEFT function to extract the last three numbers?
I have a cell in my worksheet with a fully qualified filename like 'D:abcDefGHIJklxyz123.app
I would like to extract only the xyz123.app. Obviously, the number of characters is going to vary based on the filename. The find and search functions appear to help locate the cell but not the substring in the text. The right and left appear to work based on number of characters and in my case these are varying. Also, there does not appear to be any function that can do a search a string from right to left.
I have as an example two products. One called PORAW VC and the other PORAW WC30
I need to extract from the 7th character (in this case) to the end of the string. The string length always changes and to complicate matters some products dont have a space in their name.
eg PORTP060DUS ( here I want to extract just the 060DUS )
PORAW VC (Just need to extract VC)
PORAW WC30 (Just need to extract WC30)
I suppose this is some sort of dynamic extraction
I need to extract the text located before last specified character () From C:PicturesPersonalChristmasDSC_00001.jpg ----> C:PicturesPersonalChristmas
I found a nice formula in another thread but that one returns the text located after the last "". The formula is =RIGHT(A1,LEN(A1)-FIND("@",SUBSTITUTE(A1,"","@",LEN(A1)-LEN(SUBSTITUTE(A1,"","")))))
I have the function below from http://www.ozgrid.com/VBA/extract-words-function.htm
and have it working exactly as it's supposed to. Is it possible to adapt this to remove the last character of the text string, specifically the commas? My problem is that the raw data in one cell is like this (including commas) 0.333, 5.8874, 6.85423, 0.025. I separate each text string into separate cells but am left with the commas. I'm not using the "Data Text to Columns" option as I need the results in specific cells so they can then be used in calculations.
Function Get_Word(text_string As String, nth_word) As String
Dim lWordCount As Long
With Application.WorksheetFunction
lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1
If IsNumeric(nth_word) Then
nth_word = nth_word - 1
Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
. Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _
.Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ ............................
I am attempting to make a macro for. It requires me to scan a column of cells worth of data (characters) for parts of what they contain and place those parts into a variable or string so that I can use an IF statement to place text in another cell.
I used to know someone who could do this via VBA, but I have been unable to reach him.
This sheet is fairly basic. The cells to be scanned are all in one column, they are all four digit numbers and I need to read the first two digits into separate variables.
Example: If the cell has "4101" in it, I want to be able to read the first digit "4" into one variable and the second digit "1" into another variable.
This way I can place text based on either one of those digits into the next cell over with an IF statement and can enclose it into a large loop to do the entire column.
I have about 200 cells with 2 different format in text and numbers but they all have a number in between right after /vgh/.
Is there a formula I can use that will return only thee set of numbers removing the text before and after it.
Below are the 2 different examples.
Example 1 : h4ffkwd1-5o/vgh/2447044/eml-anet_wlcm-h-visit/?hs=false&tok=3GMdjcBsfbfBk1
Example 2 : h38ahlur-19/vgh/163311/?hs=false&tok=1CIRLlqwLSB5g1
I have these sort of text and just need the middle set of numbers.
I am looking for formulae to identify the first 20 non-zero numbers from a string of alphanumerical and non alphanumeric characters
EG If column A any data such as:
123
0123
01(2)3
0.123
123abc
0123abc
01(2)3abc
0.123abc
a1b2c3
1a2b3c
Then the corresponding row for column B would return 123
Using help from my maths Prof and some IT bods, i have so-far come up with the array-formula:
=1*MID(A7,MATCH(FALSE,ISERROR(1/MID(A7,ROW(1:100),1)),0),20)
assuming that the total string is not more than 100 characters.
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
I have about 10000 cells of varying length in text and numbers but they all end with numbers on the ends of them. Using text to columns doesn't work because they're all different lengths and it cuts them off in the wrong place.
Is there a formula I can use that will return only the text from these cells and remove the numbers. It would definitely save me time from individually deleting the numbers at the end.
I have a list (SIC Codes) and I want to remove the numbers. The numbers range from 2 to 8 deep. The list exists in column B and I want the new list in column C.
01 Agricultural Production Crops
011 Cash Grains
0111 Wheat
0112 Rice
0115 Corn
0116 Soybeans
0119 Cash grains, nec
011901 Pea and bean farms (legumes)
01190101 Bean (dry field and seed) farm
01190102 Cowpea farm
01190103 Lentil farm
01190104 Mustard seed farm
In cell A1 i have the value ABC123.
I want to remove the 123.
Can you tell me how to do this?