Extract First Character Of String
Oct 11, 2009
I have a column that has various codes such as "E123" and "X456" and "S345". I just want to extract the numbers and leave the letters in each cell. How do you write a formula using the LEFT function to extract the last three numbers?
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Nov 3, 2012
Junior Fit Softstyle T-Shirt
Antique Cherry Red
Junior Fit Softstyle T-Shirt
Antique Cherry Red
Softstyle T-Shirt
Antique Heliconia
Softstyle T-Shirt
Antique Heliconia
Softstyle T-Shirt
Antique Heliconia
This is column a and b. Looking at b I am looking for a formula that will pull the first capital letter out of each word like ACR to create color codes.
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Aug 15, 2007
I have a cell in my worksheet with a fully qualified filename like 'D:abcDefGHIJklxyz123.app
I would like to extract only the xyz123.app. Obviously, the number of characters is going to vary based on the filename. The find and search functions appear to locate the cell but not the substring in the text. The right and left appear to work based on number of characters and in my case these are varying. Also, there does not appear to be any function that can do a search a string from right to left.
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Dec 28, 2013
My mission is to extract email addresses from cells. or I want any word that contains "@" in column A to be extracted in column B.
For example, if cell A1 contains: tracy jane@gmail.com , I want jane@gmail.com to be put in B1.
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May 12, 2014
I have list like the below. I need to pull out everything before the space for each of these and after the _ which is after the CRN_, SA_ or MA_
CRN_212141 JRDC 7402-01_ICT-ICM IT Services Basel PDiv 3702 POPEnd 01/31/2015
MA_7500007822 JRDC
SA_GS-35F-4461G No Alias Determined
CRN_179764 Director of Administration and Managem PDiv 3799 POPEnd 06/30/2014
MA_N00189-09-D-Z044 USJFCOM Projects
SA_GS-35F-4461G No Alias Determined
Desired Results:
212141
7500007822
GS-35F-4461G
179764
N00189-09-D-Z044
GS-35F-4461G
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Aug 15, 2007
I have a cell in my worksheet with a fully qualified filename like 'D:abcDefGHIJklxyz123.app
I would like to extract only the xyz123.app. Obviously, the number of characters is going to vary based on the filename. The find and search functions appear to help locate the cell but not the substring in the text. The right and left appear to work based on number of characters and in my case these are varying. Also, there does not appear to be any function that can do a search a string from right to left.
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Dec 19, 2007
I have as an example two products. One called PORAW VC and the other PORAW WC30
I need to extract from the 7th character (in this case) to the end of the string. The string length always changes and to complicate matters some products dont have a space in their name.
eg PORTP060DUS ( here I want to extract just the 060DUS )
PORAW VC (Just need to extract VC)
PORAW WC30 (Just need to extract WC30)
I suppose this is some sort of dynamic extraction
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Aug 18, 2014
I need to extract the text located before last specified character () From C:PicturesPersonalChristmasDSC_00001.jpg ----> C:PicturesPersonalChristmas
I found a nice formula in another thread but that one returns the text located after the last "". The formula is =RIGHT(A1,LEN(A1)-FIND("@",SUBSTITUTE(A1,"","@",LEN(A1)-LEN(SUBSTITUTE(A1,"","")))))
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Jun 15, 2007
I have the function below from http://www.ozgrid.com/VBA/extract-words-function.htm
and have it working exactly as it's supposed to. Is it possible to adapt this to remove the last character of the text string, specifically the commas? My problem is that the raw data in one cell is like this (including commas) 0.333, 5.8874, 6.85423, 0.025. I separate each text string into separate cells but am left with the commas. I'm not using the "Data Text to Columns" option as I need the results in specific cells so they can then be used in calculations.
Function Get_Word(text_string As String, nth_word) As String
Dim lWordCount As Long
With Application.WorksheetFunction
lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1
If IsNumeric(nth_word) Then
nth_word = nth_word - 1
Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
. Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _
.Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ ............................
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Jul 24, 2007
Say for example I have ABCD-ABC12 basically an arbitrary length of alpha (A-Z) characters followed by an hypen "-" followed by another arbitrary length of alpha (A-Z) characters and then
immediately followed by an arbitrary length of numbers. (with no spaces between alpha and number)
How can I extract just the numbers from the group of alphanumberic characters after the hyphen
and set it to a LONG variable?
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Feb 8, 2008
I am attempting to make a macro for. It requires me to scan a column of cells worth of data (characters) for parts of what they contain and place those parts into a variable or string so that I can use an IF statement to place text in another cell.
I used to know someone who could do this via VBA, but I have been unable to reach him.
This sheet is fairly basic. The cells to be scanned are all in one column, they are all four digit numbers and I need to read the first two digits into separate variables.
Example: If the cell has "4101" in it, I want to be able to read the first digit "4" into one variable and the second digit "1" into another variable.
This way I can place text based on either one of those digits into the next cell over with an IF statement and can enclose it into a large loop to do the entire column.
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Sep 4, 2012
I am working with flight numbers and want to split out the letters from the digits. Examples,
BA1234A
BA123
EZY4566H
BE7893B
In column A I need the first two or three letters only,
BA
BA
EZY
BE
In column B I need everything to the right of what appears in column A
1234A
123
4566H
893B
etc.
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Dec 22, 2013
I have the following type of info in A1,A2,A3...
Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50
My goal is to get as close as possible to this,so it will be easier to sort and manage
Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one
Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))
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Aug 23, 2007
I have a problems here. The problems is attached in the file. I wanna extract alpha/char from a string. Example: I wanna extract the words "(M)" with the bracket from the string "Toothbrush (M)" in column A. After extracting the (M) out, I wanna do a validation to compare the (M) in column B with another data in column C, if the (M) is same as the data called "Medium" in column c, the validation will return "Match" in the column d!
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May 23, 2008
How can I extract mid section of the string which is always 5 characters long and is always followed by a period "." ?
My account strings are in 3 sections (but the third section isn't always used)
For example,
1.10210
1.22556.001
900101.56201
955261.54444.001
5566625.58886.957756
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Jun 27, 2006
I'm looking for some VBA code that would look at a column of data, look at each cell value in that column and if the cell value starts with the letter 'G' and the 5th character in that cell is not 'Z' or 'X' I would like to highlight that cell. Example:G123-123 would be highlighted whereas G123Z-123 would not.
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Jan 3, 2007
I would like to get the nth character from a string. For example, let's say there is a string "jupiter", and I would like to get the 3rd character of this string, "p". Is there a function in excel vba that would allow me to do this?
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Apr 8, 2014
I need a formula which can pick out the names from string of text, each name follows "-->", the number of names in each cell differs and is undefined. The result needs to be posted into each column following these cells.
An example of a cell is below:
"W/L FIGHTER Str TD Sub Pass EVENT METHOD ROUND TIME
Loss -->--> Tom Aaron -- -- -- -- Strikeforce - Hen... U. DEC 3 5:00
-->--> Matt Ricehouse -- -- -- -- Dec. 4, 2010
Win -->--> Tom Aaron -- -- -- -- Strikeforce - Hea... SUB 1 0:56
-->--> Eric Steenberg -- -- -- -- May. 15, 2010 Guillotine Choke"
I have tried using text to columns but everything after the first line is not recognised (when I click finish anything after "TIME" is simply not there).
Example attached : UFCv1.xlsx
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Sep 10, 2013
I can do this in Excel, but I don't seem to have a single example to hand of how, using VBA, to extract all characters up to but not including, the first space character in a cell.
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Jun 10, 2008
What formula or function truncates a text field that is in the following consistent format:
number. name
ie. 3. Super Bella
and 150. Taoist
I wish to truncate the field so I have just the integer without the dot, space or word(s).
Tried Len, Left & Replace but they require a specific number of characters. Since the number can be 1 to 3 digits long, this doesn't work.
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Feb 17, 2014
I have this data and want to extract the character after the letter Y if the string has a Y in it.
Example data Output
AU 2013 OD ANR B24 Y2 2
AU 2013 OD ANR B24 Y4 4
AU 2013 OD ANR B24 Y5 5
AU 2013 PD HLD NOV B SPA
AU 2013 PD HLD NOV C SPA
AU2013OD ANR B25 Y1 1
AU2013OD ANU B25 Y5 5
AU2013OD WCR FPVN B49
AU2013OD Y6 FPVN B49 6
AU2013OD WCR FPVN B40
AU2013OD WCR FPVN B43
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May 30, 2014
I want to assign a value to a character or string
Like I have formula p2p3= (n-1)*p +(2*e)
I want to assign values(number) to n,p,e.............so that i can get p2p3....like want to assign 'n'=4
I don't want to use cell number for calling values of n,p,e
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Feb 11, 2010
How can I evaluate just the first part of these stirings so I can just do something like Left("Ca",2)?
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Jul 28, 2008
How do I split the below character or similar strings into 2 columns of 25 characters each without cutting a word off?
BONE CURETTE-RVERSE ANGLE 5.5MM WIDTH-MEDIUM/BAYONETED
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Feb 9, 2012
I have a web query that returns a city and state, but the last character of the state is lower case. I need VBA code to change the last char to upper case. Here is what I have so far:
Code:
tmp = Cells(4, 1).Value
Mid(tmp, Len(tmp), 1) = UCase(Right(tmp, 1))
Cells(4, 1).Value = tmp
Is there any easier way to do this without 3 lines of code?
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Dec 21, 2012
I have some columns in the excel file:
/path1/xyxxx/cccccc/filename12.txt
/path1/bxgdgg/gfdfacc/filenameeee8.txt
/path1/tttwrw/ccefecc/ddddd/filename56.txt
And I would like to delete everything before the LAST slash(just filenames)
filename12.txt
filenameeee8.txt
filename56.txt
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Jun 11, 2014
I have a cell that has approx 22000 characters. I'm trying to remove a specific character string from a cell by doing a find and replace with "". It works for characters in the first part of the cell but not for characters in the last part of the cell.
Example: I do a find/replace for the characters 21242 to "" in column A and I get the expected results. I do a find/replace on 69294 to "", again I get the expected results, but if I do a find/replace on 85203 to "", I get "Excel cannot find what I am searching for" (but its there!)
My cell size is within the max size of 32,767 characters so not sure why its not working.
Attached a sample worksheet.
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May 23, 2007
I would like to find the position of the last occurrence of a character in a string. For example, I have a string with the following:
"c:wwgpeToolbidsTest File.GP$".
I would like to find out the position of the last '' in the string because I want to pull the filename, 'Test File.GP$' into a variable. I would like to avoid writing code to do this. Are there some Excel functions I can use for this?
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Jan 22, 2009
I have a macro that asks the user to enter a file name and have written a small function to search the name given to the file to find any invalid characters, trouble is I must be doing something wrong as I doesn't work. Everytime I write something in the box I'm told it's invalid, regardless of weather it actually is or not.
Function -
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Jun 12, 2014
I am trying to work out how to get nth position of a character in a string. For example in this
Code:
kjishdfiuayigdscka
if I use the formula
Code:
=FIND("i",I$1),
it will give me answer 3. But I want the position of 3rd "i" in the string. The answer should be 12. How can I change this formula to get the correct result?
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