Finding String In Excel Using VB6 ADO - Return Column And Row

Jul 13, 2011

I am trying to use ADO via VB6 to find a specific input in row A of my excel sheet.

I then want it to return the Column and Row to me separately.

I have a code I already use for returning specific values from cells:

Code:
Function Look(ClosedWorkbookFullName As String, _
SheetName As String, RangeAddress As String) As Variant

Dim conn As Object, rs As Object, SQL As String
Set conn = CreateObject("ADODB.Connection")
Set rs = CreateObject("ADODB.Recordset")

[Code] ......

Now I want something like this I can use as a function, but it obviously needs tweaks.

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I am trying to search for a string of numbers (column 2) in an array, and have "YES" be written on the same line in column 3 if the string is found in the names ANYWHERE in column 1. Please see the desired results on the picture in column 3.

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I have made this function that returns the string value for a column based on it's number but it starts getting more complicated after I've been thru the alphabet once and have to return two string values to move across the chart.

PHP
Function colnum_string(ByVal num As Integer) As String    colnum_string = "IV"    If num = 1 Then        colnum_string = "A"    End If    If num = 2 Then        colnum_string = "B"    End If    If num = 3 Then        colnum_string = "C"    End If    If num = 4 Then        colnum_string = "D"    End If    If num = 5 Then        colnum_string = "E"    End If    If num = 6 Then        colnum_string = "F"    End If    If num = 7 Then        colnum_string = "G"    End If    If num = 8 Then        colnum_string = "H"    End If    If num = 9 Then        colnum_string = "I"    End If    If num = 10 Then        colnum_string = "J"    End If    If num = 11 Then        colnum_string = "K"    End If    If num = 12 Then        colnum_string = "L"    End If    If num = 13 Then        colnum_string = "M"    End If    If num = 14 Then        colnum_string = "N"    End If    If num = 15 Then        colnum_string = "O"    End If    If num = 16 Then        colnum_string = "P"    End If    If num = 17 Then        colnum_string = "Q"    End If    If num = 18 Then        colnum_string = "R"    End If    If num = 19 Then        colnum_string = "S"    End If    If num = 20 Then        colnum_string = "T"    End If    If num = 21 Then        colnum_string = "U"    End If    If num = 22 Then        colnum_string = "V"    End If    If num = 23 Then        colnum_string = "W"    End If    If num = 24 Then        colnum_string = "X"    End If    If num = 25 Then        colnum_string = "Y"    End If    If num = 26 Then        colnum_string = "Z"    End IfEnd Function 

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[Code] ......

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