Fixing "Type Mismatch"
Mar 9, 2008
I keep getting a type mismatch when I run this code. The code worked fine until I added the last condition to check if the left most character of the active cell is a number.
Do While ActiveCell.Value vbNullString
If 1 >= Range("L" & ActiveCell.Row).Value / Range("AS" & ActiveCell.Row).Value And Range("L" & ActiveCell.Row).Value / Range("AS" & ActiveCell.Row).Value >= 0.9 And IsNumeric(Left(ActiveCell.Value, 1)) Then
myCountA = myCountA + 1
myCandA = myCandA & " " & Range("B" & ActiveCell.Row).Value
End If
View 9 Replies
ADVERTISEMENT
Nov 4, 2006
I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:
- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)
- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)
Etc.
The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the
Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............
View 6 Replies
View Related
Aug 21, 2014
I am getting a type mismatch with the following:
HTML Code:
Private Sub Export2Pdf()
Dim sFileName As String
'Create file name
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")
[Code] ........
something to do with this:
HTML Code:
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")
View 1 Replies
View Related
Feb 14, 2009
I have used this code previously and it worked however I now get a type mismatch error in the line coloured red..
View 8 Replies
View Related
Feb 24, 2014
The line I first used was:
var all_spans = document.getElementsByTagName( 'SPAN' );
for( var i =0,skip =0 ; i [code].....
View 3 Replies
View Related
Jul 1, 2009
I am getting error Type mismatch error the moment i enter value in Cell T54 and CLICK "DAILY" on Daily button.Waiting for the solution.
I am attaching the file.
View 10 Replies
View Related
Aug 25, 2009
I have four columns of data and 25 rows (A1:D25). I wish to add this to a multi-column list box in my user form. My userform is called FundSelect, and my listbox is called FundList. The ColumnCount property is set to 4. When I use the command:
View 4 Replies
View Related
Feb 8, 2010
I'm trying to write a pretty simple macro which invokes a built-in DDE function to retrieve some data, then when the data is retrieved, just show a msgbox. When the data is finished being retrieved, cell(20,11) in the sheet "Historical Data" will automatically have "FINISHED" placed in it. So while the retrieval is taking place, I'm simply looping and checking the contents of this cell waiting for it to read "FINISHED". My problem is the 'Do While Sheets("Historical Data").Cells(20, 11) <> "FINISHED"' line generates a "Type Mismatch Runtime Error 13", which I can't for the life of me understand why.
View 2 Replies
View Related
Mar 23, 2012
I have a while loop that counts backwards in a seriescollection to find the last value with data. In one particular case, I had to use an IF formula in the source data where it would output NA() if the statment was false, so instead of loop through empty strings until the loop finds a number, it loops through #NA until it finds a number.
This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.
Code:
Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long
[Code]....
(P.S. why I would have "NA" as an output, its because it won't graph, where putting "" for my false condition did)
View 9 Replies
View Related
Jan 16, 2013
I am using this code:
Code:
With wshvar
.Range("A16") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) - 1)
.Range("A18") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) + 1)
End With
but receiving a 'Type mismatch' error with the highlighted code.
View 1 Replies
View Related
Feb 23, 2013
I tried to find value on the other workbook. Gives me error "Type mismatch"
Below is the code in my VBA project
Code:
Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub
[Code] .......
View 7 Replies
View Related
Jan 16, 2007
This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch
dim c as Range
...
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
MatchCase:=False)
ActiveCell is a single cell on an unhidden sheet - cell A279.
I can Control-F at this point in Excel, and it finds "LIQ" just fine.
Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.
Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)
View 9 Replies
View Related
Feb 19, 2007
I have a piece of VBA code that acts weird. For brevity I am doing a function call like this:
val=MyFunc( [D1] )
and
Function MyFunc(mean As Double)
D1 is a named range which is a single cell. It contains a double.
The problem occurs when the value is zero, I get a type mismatch on the function call. If it is non-zero all is well.
What would cause this? I could see if zero was invalid inside MyFunc() that some calculation might blow, but it nevers gets into the function. Looks like the compiler is stopping it.
View 9 Replies
View Related
May 18, 2007
Range("C1:C" & x).Value = WorksheetFunction.Transpose(Result)
I'm trying to run it in 2007. It works in earlier versions.
I get Type Mismatch error. Result is dimmed as variant type.
View 9 Replies
View Related
Dec 14, 2008
I have some code which i trialled in a blank workbook and was fine. when i pasted it into the workbook i am working on, i get runtime error 13 type mismatch.
Sub Trackj()
Dim a As Long
For a = 1 To Sheets.Count
If InStr("master", Worksheets(a).Name) < 1 Then
Worksheets(a).Cells(40, 6).NumberFormat = "hh:mm"
Worksheets(a).Cells(41, 6).NumberFormat = "hh:mm"
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(40, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("B52:B80").PasteSpecial (xlPasteValues)
End If
If Hour(Worksheets(a).Cells(41, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(41, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("D52:D80").PasteSpecial (xlPasteValues)
End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
View 9 Replies
View Related
Jan 9, 2009
what i know what's actually type mismatch and how do i solve it?
View 9 Replies
View Related
Jul 24, 2009
When my macro runs through the above code, I get a type mismatch error. All of the cells are formatted at Date only.
View 9 Replies
View Related
May 16, 2014
When I run the following code I get a (Run-Time error '13': Type mismatch). When I click debug it highlights line 41
[Code].....
View 1 Replies
View Related
Jul 15, 2014
I am trying to accomplish the following: iterate through rows of a selection, delete row if the first column cell is empty or the second column cell equals 0.
So far I have:
[Code] ........
I am getting a type mismatch error at my if statement.
View 3 Replies
View Related
Aug 18, 2014
i have written a vba code to open excel file saved at network server. The issue is code opens the file but gives "Runtime Error 13 Type mismatch"
Code :
<code>
Sub test_opening()
Dim filepath As String, filename As String, completename As String
Dim hurray_macros As Workbooks
[Code].....
View 1 Replies
View Related
Jan 30, 2009
I seem to have some type mismatch in my macro...
The error appears every time i insert or delete a row in the worksheet.
This is the ....
View 9 Replies
View Related
Jun 16, 2009
I made this case statment below to look at a cell in Q and if the cell value is "Large Area" then the cell in P same row should be 1 if the case is Varsity then it would be 2 however I keep getting a Type Mismatch. I tried Picker.Text and Picker.Value as well I didn't get errors but it didn't work either.
View 5 Replies
View Related
Aug 6, 2009
I have attached a sample file for you to easy reference. So when the code run until the loop function, it will prompt an error message.
The idea is to open the selected file and the copy the data from the selected to this master file by searching the column A. Column A has the identical text in all the files that are to be copied from.
View 7 Replies
View Related
Oct 16, 2009
I am trying to only have the option 1, 2, or 3 be entered. I have that part down, but if someone clicks cancel or just closes the input box i get the type mismatch I believe because no integer was found....is there a way around this?
Dim intResponse As Integer
intResponse = InputBox("Choose One" & Chr(10) & Chr(10) & "1 - Lease Lock" & Chr(10) & "2 - Upgrade" & Chr(10) & "3 - Lease Lock & Upgrade", "Contract(s) sent out")
If inResponse <> 1 Or strResponse <> 2 Or strResponse <> 3 Then
MsgBox "Must choose (1,2,3)"
Exit Sub
End If
View 2 Replies
View Related
Mar 1, 2012
I have built a user defined function called: portAlpha.
Code:
Function portAlpha(assetCode As String, indexCode As String) As Double
Dim assetCol As Long
Dim indexCol As Long
Dim assetData As Range
Dim indexData As Range
With Sheets("Data")
[Code] ......
I am struggling to get this to work though. Everytime I step over this piece of code:
Code:
portAlpha = Application.WorksheetFunction.LinEst(Range("M4:M63"), Range("N4:N63"), 1, 1)
I get a "Type Mismatch Error". All the values in the range are numbers, and LINEST should return a double, so I am puzzled as to why there is a mismatch...
I have hardcoded the range into the formula just to try and get it to work. Eventually this will be two variables and will look like this:
Code:
portAlpha = Application.WorksheetFunction.Index(Application.WorksheetFunction.LinEst(assetData, indexData, 1, 1),1, 1)
View 1 Replies
View Related
Apr 27, 2012
I've written a macro for a set of tests I've created. It says "If the old value of the cell is '-' and the user enters 'Pass,' 'Fail,' or '-' then insert something into the cell directly to the right of the modified cell."
However, I'm receiving a Type Mismatch error any time I insert or delete a row. I think this is because of how I'm getting the previous value of a cell. The conditional is saying "I don't have a solution if there was no previous value of the cell."
Code:
Dim old_value
Private Sub Worksheet_Change(ByVal Target As Range)
prev = old_value
If Not Application.Intersect(Target, Range("E1:E65000")) Is Nothing Then
If prev = "" Or prev = 0 Then
'Do Nothing!
[code]....
View 4 Replies
View Related
Sep 24, 2012
Why is this giving me a Type mismatch Run Time Error 13? The debugger highlights the Columns Select line.
Sheets("LB").Activate
Columns("AA:AZZ").Select
Selection.Delete Shift:=xlToLeft
Rows("20:300").Activate
Selection.Delete Shift:=xlUp
View 5 Replies
View Related
Jan 23, 2013
Here is my line of code producing the error:
Code:
If .Range("T21").Value > Application.VLookup("AE25", .Range("L7:T10"), 6, False) Then
T21 is a time value
AE25 = HPL1
The lookup range: (times are time values)
Excel 2010LMNOPQRST7HPE1Adam W.HPA7:00 AM3:00 PM8HPE2Not StaffedXX9HPL1KourtneyHPC1:00 PM9:00 PM10HPL2Not StaffedXXMain
The HTML representation of range does not show the merging of columns L:M, N:O, Q:R and S:T on a row by row basis. Unmerging did not appear to make a difference.
View 3 Replies
View Related
Jan 24, 2013
I have a bug that pops on when running this line of code and I think it's because the copy area is a miss match against each worksheet.
If Evaluate("COUNTIF(" & sh2.Name & "!C:C,""" & sh1.Cells(i, "C").Value & """)=0") Then sh1.Rows(i).Copy sh2.Rows(j)
Sub Copy()
[Code].....
View 2 Replies
View Related
May 26, 2013
Code:
fma_rng = .Range("C" & fma_top & ":C" & fma_btm)
rows_blnk = Application.CountBlank(fma_rng)
why I would be getting a 'type mismatch' error with the line in red?
View 6 Replies
View Related
