In my macro, I have a variable 'logDate' that is a 6 digit date in the format mmddyy
If 'logDate' falls on a Monday then I need to set another variable 'd' to equal 1, if Tuesday then 2 etc.
ie: 'logdate' = 062308 I need to set 'd' =
I need to extract a set of 5 numbers from a string of characters. The number set I need is always 5 digits long, always starts with a 1, and always begins after a period. But the number I need can occur in different parts of the string:
In each example below I would want to extract only the 10572 portion.
5194003.10572.N
5194003.10572.R
5194003.1.0010785.10572
7500008.N.5999900.10572
Additionally (if possible) if the cell is blank I don't want anything to show up, and if the string begins with a letter then I don't want anything to show up either.
I am working with data where I need to extract a 10-digit number from a string. Where the 10-digit number is in the string varies, so I can't use a simple left/len combination. Here's an example below:
Something and email@me.com 1234567890 stuff thingsThe formula I am using now is this:
=MID(F4,MIN(FIND({0,1,2,3,4,5,6,7,8,9},F4&"0123456789")),10)
This finds the first number in a string and returns that number and the next 9 digits for a total of a 10-digit string (so it would return 1234567890). However, I run into an issue when I have a string that has numbers in the email address.
So this:
number in email123@me.com 1234567890 exampleWould return this:
123@me.comIs there a way to modify the formula above so that it searches for 10 consecutive numbers and not just the first number in a string?
I am trying to extract a 7-consecutive-digit number from a mixed string (letters and numbers). The only condition is that the number has to start with a "7" or "6" and be exactly 7 consecutive numbers long. My function only evaluates for one and one within the other but not both. It's faulted because it only looks for the occurrance of "6". rCell is the string range.
Function ExtractNumber(rCell As Range)
If Len(Mid(rCell, InStr(1, rCell, "6"))) > 6 Then
ExtractInvoice = Mid(rCell, InStr(1, rCell, "6"), 7)
ElseIf Len(Mid(rCell, InStr(1, rCell, "7"))) > 6 Then
ExtractInvoice = Mid(rCell, InStr(1, rCell, "7"), 7)
End If
End Function
I know you can take a number from one cell and combine it with number from another cell and make it one number. What I need to do is the reverse. Take a two digit number in a cell and separate it into single digits in two cells. If you have the number 50 in a cell, then is there a formula that will take the 5 and put it in cell and take the 0 and put it in the cell beside it?
View 4 Replies View RelatedI have a column of 6 digit numbers in excel, and I need to remove the last digit from each number, turning it into a 5 digit number. No rounding, just simply remove the last digit. Each number is different. Does anyone know how to quickly and efficiently remove the last digit from each number? I can convert to alphanumeric string if need be...
View 4 Replies View RelatedHow to calculate a check digit in excel. The details to calculate this are as follows:
All variables in the calculation are positive integers.
We take each integer of the pro number and multiply it by a value and sum them to get a total.
An Example: 8 Digit Pro Number: 66988757
Pro Number: 6 6 9 8 8 7 5 7
Position in the Pro Number: 1 2 3 4 5 6 7 8
Multiply each digit in the pro number by (10-position) in the number, to achieve a sum.
Using our example pro again:
6*(10-1) + 6*(10-2) + 9*(10-3) + 8*(10-4) + 8*(10-5) + 7*(10-6) + 5*(10-7) + 7*(10-8)
6*9 + 6*8 + 9*7 + 8*6 + 8*5 + 7*4 + 5*3 + 7*2
54+ 48+ 63+48+40+28+15+14 = 310
Take the Sum of the previous calculation and divide it by 11
310/11 = 28
(Actually, it's 28.181818, but since we're working with integers, we truncate everything behind the decimal).
Figure a remainder by multiplying the quotient by 11 and subtracting from the sum.
Remainder = 310 - (28*11) ---> Remainder = 310 - 308 ----> Remainder = 2
Check Digit = 11- Remainder
Check Digit = 11 - 2 ---> Check Digit = 9
Note: if the check digit is 10 or 11, need to subtract 10 from the Check Digit.
I have a running time sheet daily. It has 2 columns for Labor and 2 columns for travel
i.e. travel From / To 1300-1400 calculate 1 hour then travel home 1600-1700 1 hour this is calculated by the date entry 01/02/10 I have another calculation that tracks by the date i.e. 01/02/10 then Next job which all works fine.
The problem becomes how do I calculate a weekly total labor and travel by the date So added another column called weekly hour’s labor and use the Weeknum to determine which week is which day/date so the first Monday in January 2010 is week 2
2 problems
Having many multiple day / date entries are the same date x 7 days Monday –Sunday
(Relies on the date entered and the weeknum) 01/03/10 each line is complete however the dates carry over as does the time
When trying to calculate each row x 3 same date time then the value will be incorrect I need to calculate
Say 9.5 hour labor from the date 01/03/10 not 28.5 hours and then calculate the total weekly hours
01/03/10, 9.5 hours labor, 3 hours travel
01/03/10, 9.5 hours labor, 3 hours travel
01/03/10, 9.5 hours labor, 3 hours travel
i do have work and travel times for each job on the same line (separate columns) but I display the total here by date to summarize the totals
i have tried sum products and sumif to avail. I am using Windows XP SP2 with MS Office 2007
how do i calculate weekly hours by date and weeknum ?
Total Work per day
Total Travel per day
Daily....................
I thought I could use
View 12 Replies View RelatedI have a text string in a cell, something like:
000024AC1011.
I need to find a way to find the first nonzero character in the string, and what position it is in. For instance, in the above example, 2 is the first non-zero character, so the function would return 5, since the 2 is the fifth character into the string.
So I want to extract the four digit year found in several strings, for example:
A1: Toyota Camry 1997 Replacement Engine ...
In b1 I'd like to return: 1997 ...
I am trying to write a function that will give me the amount of time a certain number shows up in the same digit place in a large set of numbers.
For example:
111112221233313
111212222233323
111312223233333
111412224233343
111512225233353
111612226233363
111712227233373
111812228233383
111912229233393
given the number set how many times does the number 5 show up in the 4th digit. I know its 3 but for the data size I need to run it on, it is impossible to count.
What function would count how many times a certain number shows up in the same spot?
I've tried everything I know (which isnt that much to be honest. lol). Ive tried the frequency formula but that doesn't work the way I want it - I think its probably the wrong formula to use. I've also tried a pivot table but they always vex me. If a pivot table IS the way to go, could someone talk me through it step by step? (*the wizard is just as confusing as doing it yourself I find) ....
View 9 Replies View RelatedHow to remove minus signs in the digit string in excel 2003
Sample: 1 - 2 - 3 - 4 - 5 - 6
And convert to simple: 123456
I have a column where I am convering the Date into a Fiscal week number.
For example 10/6/2009 is Work week 41
Now I want to show October Week 41
I need to add the month and the text "Week" before the week number. what is the formula I use.
how you can determine if a cel value is a number or a digit
It is actually for a column to determine if it has a heading or not and acordingly y have to count the rows off that "current region" and put some values with a formula next to this column.
Y was testing an expression with this
msg = IIf(target.End(xlUp).Value = "X", "is this a LETTER", "is this a DIGIT")
Well I want to add few numbers in a few number for example I have ten columns containing few cell numbers and i want to add 92 my country code with it. I have tried this by using replace formula but in result it comes in text format from which i cannot use another formula unless text format is removed and for that i have to do it one by on in every single cell. I have attached a sample sheet.
View 4 Replies View RelatedI have the following dates in a column and need to convert them to the short date format:
91113 (Sept 11, 2013)
100713 (Oct 07, 2013)
122612 (Dec 26, 2012)
40413 (April 04, 2013)
Those are just some examples. When I convert these as is I get dates that are really far in the future. Some dates are 5 digit and some are 6.
I have the following
[Code] .....
AK5 value will be 2 - 21.
I need it to display
A1D05
or
A1D21
or whatever the number is after A1D, but when AK8 = a value of 1 or 2 or 3...... It comes back as A1D1 or A1D2... How ca I keep the two digits in AK8 to stay and put the value the way I want in AE5 ...
I'm trying to figure out how to setup a worksheet to find the most common 2 digit numbers going vertically from the bottom(cold) to the top(hot) it would consist of 90 digits 0 thru 9
it would look like this
4 0 3 9 0 4 3 3 2
9 2 5 6 5 6 9 6 6
8 9 9 3 1 0 2 9 8
1 6 7 5 9 9 8 2 5
2 7 2 2 2 8 5 1 3
0 1 4 7 4 7 6 0 9
3 5 6 4 3 3 0 4 4
7 8 8 1 8 5 7 8 7
5 4 1 8 6 1 1 5 1
6 3 0 0 7 2 4 7 0
each vertical line would be considered weeks 9 thru 1. week 9 would be the first vertical line of digits on the left. it could also contain the most common 2 digits horizontally. Both 2 digit values would be color coded ex. blue equals most common 2 digit horizontally and green equals vertically. I would also like to color code the most common 2 digit value diagonally as long as it is the most common of either the vertical or horizontal 2 digit. Each number is seperate on the worksheet they would not be pairs. im using excell 2003.
The last digit of a number (can be any demonination but always an integer). I know that you can check the last digit of a number with =RIGHT(A1,1) but I would like to check whether the last digit in number is 1,2,3,4,5 and if so change the whole number to a number ending in 5. If the original number ends in 0,9,8,7,6 then I want it to be changed to end in 9. Is this possible and if so is there an excel function that I could use??
e.g. 143 -> 145
e.g. 1037 -> 1039
I have a cell with a number which is a result of several previous sums. It's a number with 8 to 11 digits. For example: 878567663.
I need to add each digit of the number, and then add again the result until I end up with a single digit. In the above example it'd be (8+7+8+5+6+7+6+6+3=56), then (5+6=11), then (1+1=2) and put the end result (2) in a cell
My main doubt is that I don't know how to use a simple "do while" type structure in Excel to achieve the above.
Questions:
1.) How do I create a formula to do that?. I have seen solutions in this board that let me add each digit but that's it... I need to "reduce" it until only one digit is left...
2.) What about if the lenght of the number is not always the same (fe. in one cell is 8, in another is 11, the next one is again 8...)?
I need composing a formula that will add a space after every 4th Number in a 16 digit Character Set.
ex. 0101 0101 0101 0101
="autECLSession.autECLPS.SendKeys """&B4*100&""""
B4 is 3.00% and I need it to be 03 no %, 3.00%*100= 3 but I need anything less then 10 to be two digits still (1-9)
This would be the perfect end result:
autECLSession.autECLPS.SendKeys "03"
and for over 10
autECLSession.autECLPS.SendKeys "10"
I am trying to get a formula to return the last digit from a number in a cell as a number.
If the cell (B3) contains a number such as 164 or 34 I want to return a value of 4 and have it be formated as a number.
I have tried =RIGHT(B3,1) and it returns a 4 but I cannot get another formula to recognize it as a number.
It shows up in the cell on the left side as text would and if I format it as a number nothing happens it is still on the left and the formula does not work.
I'm trying to search a column that has cells with various length strings. Included in the strange (at random locations) could be possibly be a 7 digit number starting with 4. I want a formula that counts the number of cells with contain that 7 digit number. Is this possible?
View 11 Replies View RelatedI have a cell containing body of an email.How can i check for 15 or 16 digit number in the text and extract it. Basically i am checking for a credit card number in the email and if it is there then i need to extract it to adjacent colum.
View 4 Replies View RelatedImage below has a 500 cells I want to delete the 12 digit number but the numbers that align to the 12 digit was in one cell so it is hard to do manually how to delete it
View 6 Replies View RelatedI am using following formulae to convert 16 digit number to with validation that number is not exceeding 16 digits and should always start with "1" else it should give Error with 11 blank spaces
(IF(LEN(L2)+LEFT(L2)=17,TEXT(L2,"0000000000000000"),"ERROR"&REPT(" ",11))))
but when I input any number which has a value other than zero e.g. 1009510010000059 its returning result as 1009510010000050 I need validation also in the same formulae
I would like to attribute a number to each digits 1 in position.
 IJKLMNOPQRSTUVWXYZAAABACADAEAF1Â
12345678910Â Â Â Â Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â Â Â Â 4Â 0111110010Â Â 234569Â Â Â Â Â 5Â 1110010000Â Â 1236Â Â Â Â Â Â Â 6Â 1010010110Â Â 13689Â Â Â Â Â Â 7Â