Remove Multiple Characters From Text

Nov 20, 2006

This may be a very simple question so forgive me for my ignorance. I have text in individual cells that look something like this (not actually addresses but same format):

Doe, John – 123, Anywhere St (Apt A), Anytown Anystate 12345

I have about 5,000 records. I would like to convert the records to look like this:

Doe John 123 Anywhere St Anytown Anystate 12345

Basically I want to take out all non alphanumeric characters and anything between curved or square brackets. In my minds eye my macro would read something like this:

Do until last character.

If character = alphanumericTrue – Move to next characterFalse – If character = spaceTrue – Move to next characterFalse – If character = curved or square bracketTrue – Delete all text in brackets including brackets then move to next characterFalse – Delete character then move to next character
Loop. I would of course create an additional loop to run down the 5,000 records.

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Is there a function that can remove all text and other characters from cell and only keep the numbers? The numbers can be randomly in the cell so not only in the end or beginning.

See attached file.

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lowtusmaximus

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But I keep finding what looks like double-spaces after some of the important text within the Range of cells I'm working with. I need to be able to select & conditional format the values of the text in some columns of the sheet, so need to loose these trailing spaces.

Unfortunately, it's not consistence as to how many spaces trail the text I need. Sometimes it's only one space, sometimes its two spaces ?

So far, I've had mixed success with a recorded "Replace" code but none of the other codes I have found on forum pages either don't work all or seem to give any consistent results. E;g; TRIM, CLEAN

I suspect my problem is, I do not know how to call the code properly, or trying to work with too large a range ?

The start of my code reads:

Code:

Sheets("Data").Select
Sheets("Data").Name = "Old Data"
Sheets.Add After:=Sheets(Sheets.Count)
Sheets(Sheets.Count).Select
ActiveSheet.Name = "Data"

[Code]...

' At the moment I'm using to select the pasted range I want to work on: Range(Range("C46"), Range("C46").SpecialCells(xlLastCell)).Select

This is where I need a code to work on the new Data sheet and remove all the trailing characters.

MsgBox "All data cleaned successfully !", vbInformation + vbOKOnly, "All Done"

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Option Explicit

Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
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End If
Next intLoopCounter
End Function

Two requests:

1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?

2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"

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