Remove Text And Other Characters From Cell?
Aug 18, 2014
Is there a function that can remove all text and other characters from cell and only keep the numbers? The numbers can be randomly in the cell so not only in the end or beginning.
See attached file.
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Nov 20, 2006
This may be a very simple question so forgive me for my ignorance. I have text in individual cells that look something like this (not actually addresses but same format):
Doe, John – 123, Anywhere St (Apt A), Anytown Anystate 12345
I have about 5,000 records. I would like to convert the records to look like this:
Doe John 123 Anywhere St Anytown Anystate 12345
Basically I want to take out all non alphanumeric characters and anything between curved or square brackets. In my minds eye my macro would read something like this:
Do until last character.
If character = alphanumericTrue – Move to next characterFalse – If character = spaceTrue – Move to next characterFalse – If character = curved or square bracketTrue – Delete all text in brackets including brackets then move to next characterFalse – Delete character then move to next character
Loop. I would of course create an additional loop to run down the 5,000 records.
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Mar 2, 2008
I have a column of data; for each line of data I have something like ABCDEEast Anglia, ABCDFFarnborough. The text at the start is standard and all cases of East Anglia will have ABCDE prior to the East Anglia. Is there an easy way [aside from replacing] to loop through 1000 data points and replace the long method with a shorter concise version (i.e. East Anglia only). I have attached what I mean
lowtusmaximus
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Sep 19, 2006
I need to make a macro that will find text between "o/" and "/", remove hyphens from the text it found, and then add it to the end of the current cell contents.
I know how to add to the end of current cell contents, but cannot figure out how to grab text between certain characters or replace hyphens and replace with spaces.
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Oct 12, 2013
Initially I'm simply copying a data table from a web page using "Ctrl + A" then "Ctrl + C", and then pasting the data straight onto a new worksheet so I can work with it. (After temporarily re-naming the old sheet)
But I keep finding what looks like double-spaces after some of the important text within the Range of cells I'm working with. I need to be able to select & conditional format the values of the text in some columns of the sheet, so need to loose these trailing spaces.
Unfortunately, it's not consistence as to how many spaces trail the text I need. Sometimes it's only one space, sometimes its two spaces ?
So far, I've had mixed success with a recorded "Replace" code but none of the other codes I have found on forum pages either don't work all or seem to give any consistent results. E;g; TRIM, CLEAN
I suspect my problem is, I do not know how to call the code properly, or trying to work with too large a range ?
The start of my code reads:
Code:
Sheets("Data").Select
Sheets("Data").Name = "Old Data"
Sheets.Add After:=Sheets(Sheets.Count)
Sheets(Sheets.Count).Select
ActiveSheet.Name = "Data"
[Code]...
' At the moment I'm using to select the pasted range I want to work on: Range(Range("C46"), Range("C46").SpecialCells(xlLastCell)).Select
This is where I need a code to work on the new Data sheet and remove all the trailing characters.
MsgBox "All data cleaned successfully !", vbInformation + vbOKOnly, "All Done"
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Mar 27, 2008
I have a exel file which has been exported from Access to exel. There are many cells which shows the data as in Cell A1 with the Linefeed character in between data in a cell. Is there any way (may be using a macro) where I can remove the character and get it to display as B1 in the same cell(A1). The file is attached herewith.
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Apr 3, 2008
I need to remove the last x characters if its equal to 0's
see:
101190
101200
101300
102000
102010
102020
should be
10119
1012
1013
102
10201
10202
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Jul 21, 2006
The numerical results in column A need to have the last three characters stripped from the cells. I used the =LEFT formula in adjacent cells to return the results but I am looking for a way to run code to remove these three numbers in each cell from row 1 to 8000 in column A.
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Jun 9, 2014
I am currently using the following formula to remove the letter "R" from the end of cells
[=IF(ISNUMBER(--RIGHT(A3)),A3,LEFT(A3,LEN(A3)-1))].
However, I would like a macro to accomplish this goal, along with something else. I have a list of values as follows:
CHD152-2
CHD115-1
CHD40-3
RE224
HPC644R
DOC020R
HPC594R
What I need is a macro that will remove any instance of "R", "-1", "-2", "-3", "-4" from the end of a cell. neither of the 5 values listed in the last sentence are present, the the cell will be unchange. So, after running, the above values would look like this:
CHD152
CHD115
CHD40
RE224
HPC644
DOC020
HPC594
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Mar 5, 2014
I have attached a spread sheet with some code I recoded with macro recorder. I have been searching for some extra code to insert in the middle of the recorded code which will remove the first 5 characters from the active cell and past the result to the next page. I have seen a lot of relevant code but haven't been able to get any to work in my code.
[Code] .....
I am using Windows7 with Excel 2013.
Attached File : DeleteFirst5Char.xlsm‎
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Dec 7, 2012
I have got a cell or cells with certain number of Characters (Alphabetical or Numeric or Alphanumeric). I would like to remove the excess Characters in the Cell from the end.
Example: If a cell contains 234 characters, Excess characters (More than 200) to be removed from the end.
Any formula or Vba program in generic form, so that i can limit the number of Characters to as required.
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Jul 7, 2008
way to remove a varible number of characters in a cell? My example is in cell range A1:Z1 and each cell could have a different number of characters.
Smith, Sally 5348
Jones, Johnathan 7893
Doe, Mike 2223
What I would like to do is remove the second space and the numbers that follow to get a result of
Smith, Sally
Jones, Johnathan
Doe, Mike
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Aug 8, 2009
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
If intASCIIVal >= 97 And intASCIIVal <= 122 Then
RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1)
End If
Next intLoopCounter
End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
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Mar 13, 2008
I have a cell (B2) I would like to apply multiple data validations to.
I know I need to use the custom formula option but don't know how to write the formula.
I don't even know if it is possible, but here is what I'm after
I need to make sure the cell is 4 digits long
I need to make sure the cell starts with a zero (Because the cell starts with a zero I have it as a text cell)
I need to make sure the 2nd number is not 0 if A2 begins with 5 (A2 is also a text cell).
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Jun 12, 2014
I have the following two columns, and would like to obtain for each individual Company, the corresponding Country values excluding duplicates as text in a single cell.
Company 2Country B
Company 2Country C
Company 3Country C
Company 3Country C
Company 5Country A
Company 5Country C
Company 5Country C
For example:
- For Company 2, a cell containing "Country B, Country C"
- For Company 3, a cell containing "Country C"
- For Company 5, a cell containing "Country A, Country C"
I've approached generating an array using an IF statement, as in =IF(INDEX(A1:A8="Company 5",,),INDEX(B1:B8,,)," "), which returns the following array: ={" ";" ";" ";" ";" ";" ";" ";"Country A";"Country C";"Country C";" ";" ";" ";" "}.
The question is: how do I get that array to produce, as text in a cell: "Country A, Country C". Note that the duplicate Country C has been removed.
There are a few "StringConcat" User-defined functions that I've found elsewhere on the internet, but they don't seem to be able to handle to conditionally generated IF Index array, which I would think is key to parsing between Countries corresponding to each Company in the list.
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Aug 14, 2008
I pasted in 1369 characters (including spaces) to a cell, and NO MATTER what I try, all characters will not print.
If I have the cell up for formatting on the function line, all text can be seen, but for some reason it cuts off the last sentance or more and will not show it in print preview.
I've tried all kinds of cell text formatting, cell merging, etc. with no luck. The only work around I found is to just have the "missing text" on the following row.
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May 6, 2009
This is very similar to my previous post, which was solved. Now that I've extract the numbers, I need to extract the text for the specific work activities, for example 13Z or 9GGG. I'm assuming some variation on this formula:
=LOOKUP(9.99E+307,--MID(C4,MIN(FIND({1,2,3,4,5,6,7,8,9,0},C4&1234567890)),ROW(INDIRECT("1:"&LEN(C4)))))
is the solution, but I'm struggling with making the correct alterations.
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Aug 8, 2007
This should be simple, but I am struggling with finding a way to use the search or find function to identify text characters. This is my situation, I have for example a cell that contains FW023 or D1234. I need to be able to count the number of characters that are text.
i would think I would be able to do it with the search or find function, but can't figure out how to get it to just count the number of text characters with in it.
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Nov 18, 2008
a formula that will count the txt chars in a cell example ie "aa99" result would be 2 or "aa99aa" equals 4
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Mar 27, 2008
I have some cells in a spreadsheet that contain unique numbers as the beginning of the cell (these numbers are always ten characters). In the rest of the cell there is text. the data would look something like this:-
SGGHNVT561 - 3yr Maintenance
I also have some cells which dont have the unique number at the begging, so the data would just look like:-
3yr Maintenance
In another table I have a list of the unique numbers and the name that they correspond to, for example (this is the 2 columns)
SGGHNVT561 - Dave
HUKIDO8946 - Stuart
HJUTIFHE78 - Graham
I have ben trying to construct a formula that only searches the beginning of the cells to see if it containts one of the unique numbers and if it does to put the name of the person beside the cell. If the unique number is not there to return a value like 'Check'.
i tried vlookup but then i ran out of ideas :/
this is what i came up with so far:-
=IF(P7="","",VLOOKUP(P7,'[Master List.xls]Sheet1'!$B$2:$C$5,2))
The only problem i can see that this is looking for the full cell to be within the master list - but its really just the first 10 characters I want it to check
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Jun 5, 2008
let's say row 2 has data that looks like
apple (kg), apple (g), orange (kg), orange (g)
it is possible to remove the (kg) and (g) tags so that it'll become
apple, apple, orange, orange
using VB code?
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Apr 27, 2006
May I know how to remove character like
1) full stop
2) spacing
3) Dash
4) Hyphen
5) Left and Right Slash
For example:-
016-2733(LS-800E)
MS12-FS4/2M
1/4"GTR
Output:
0162733LS800E
MS12FS42m
14GTR
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Feb 27, 2014
In an active cell I have this value : " Hello.xlsm"
I need a MACRO code that will take out the characters ".xlsm".
I am trying to focus on the active cell and not a range.
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May 28, 2014
I have a cell which contains the following information:
01E4R3; 01W5; 01M4G3; 01W5
I want to sum up just the numbers in that cell. In this example, the answer should be: 30
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Sep 2, 2008
Is there a way to specify if there are 46 characters in a cell, to apply text wrap, indent the second line, and resize the row height to 25.5?
For example, I always will have text on merged cells B7:C7. I'd like to have a macro that determines if the text goes over C7 (I figured that it would take 46 characters to do this), that the merged cells will be text wrapped, then row 7 will be resized to 25.5.
I know how to record a macro that will text wrap and resize the row height but am not sure how to do the "if" condition.
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Feb 1, 2008
I wish to limit the number of text characters in a cell and have excel prevent the entry of additional characters after limit is reached. I have tried the Data Validation but it does not preven the entry of additional characters. I want to be able to show the error immediately when the limit is reached and no additional characters are permitted.
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Dec 26, 2009
I'm trying to remove everything after a specific character in a string.
I.e. change a website address to the hostname
http://www.excelforum.com/newthread.php
http://usa.excelforum.com/forum/new
to
excelforum.com
usa.excelforum.com
I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A2,"www.",""), A2,"http://",""), A2, "/*", "")
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Feb 19, 2008
I have to manually go through about 9,000 workbooks. In cell E43 of a certain sheet called "list" I have to delete underscores(_) and replace them with a single space. and remove the Rev** after each name
In example: company_name_t45671000_RevA2
Will look like this when I'm done: company name t45671000
Now I've tried to make a Macro that will delete the underscores and the Rev which worked fine except that it replaced the names with the the name that the macro was recored under.
IE: The first sheet I done worked fine when I hit the keyboard shortcut command which was company_name_t45671000_RevA2.
The second workbook sheet of "list" got fixed but had the name of the one I fixed before it: company name t45671000, where it should have been "company name s6743245.
Is there a way around this?
Also sometimes the sheets are protected, is there a way to incorporate "unprotect sheet" when it needs to be unprotected and then after the file has been corrected, re-enable protection again?
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Mar 6, 2013
I always seem to have trouble with the Find() and MID() function when used together. I try to following the syntax but it keeping erroring...
I'm trying to remove all the characters before the first non-zero number.
e.g. ABC263080 becomes 263080
PROGO0123 becomes 123
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May 26, 2009
i need a macro to do the following,
1. Remove all commas from activeworksheet ( i notice i cant see the commas in excel, but when i open notepad i have commas in empty rows)
2. Remove all characters such as = + # ( ) $ from Column 5
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