Can anyone tell me how to have a variable which can store leading zero's. I am using this variable and part of a string and want it to be able to store and calculate numbers such as 0005 at the moment if such a number is entered it sees it as 5. At the moment I have declared the variables as integers but clearly this is incorrect.
View 9 RepliesI am trying to make sense of quite an elaborate macro built by someone else. This has the following line of code
Code:
Public Sub readOperation(rowNumber As Integer)
Dim rowOff As Integer
rowOff = rowNumber - 1
'other arguments and conditions
End Sub
What I am buggered about is that I cannot see the the variable rowNumber being declared anywhere but it seems to have a value of 1. I should mention that Operation is a class and I am very new to classes.
Using excel 2003
What is the proper declaration for a decimal, I’ve been using currency because it has two decimal points i.e.
Dim x as Currency ...
I have a worksheet that has 2 sheets. I want to declare a variable that can be accessed for reading and/or overwriting by both of those sheets. Where do I declare it and how do I access it from Sheet1 for example?
View 4 Replies View RelatedIs it possible to declare n variable names dynamically in a macro? For example: Cell A2 in Sheet1 contains the number of variables to be considered in the macro (n). I would like all the variables to take names in the macro from node1 to noden using the dim statement. I tried running a for loop:
View 14 Replies View RelatedPrior to declaring a variable i used this code and it worked:
Sheets("442000ON-1+6").Range("C7").formula = "my formula"
range(C7).select
Selection.AutoFill Destination:=Range("C7:N7"), Type:=xlFillDefault
Than i declared a variable b/c i have a number of formulas i need to use but still needed it to fill the formula in a series after the formula ran. I started getting an error.
Fix was:
Dim formula1 As String
formula1 = "=SUMIF(Pivot!$A$6:$A$108,'442000ON-1+6'!$C$3,INDEX(Pivot!$B$6:$BP$106,0,MATCH('442000ON-1+6'!$B$1,Pivot!$B$5:$BP$5)))"
Sheets("442000ON-1+6").Range("C7").formula = formula1
Range("C7").Select
Set SourceRange = Worksheets("442000ON-1+6").Range("C7")
Set fillRange = Worksheets("442000ON-1+6").Range("C7:N7")
SourceRange.AutoFill Destination:=fillRange
Users select a row number which then opens up a Userform. Comboboxes and Textboxes on this Userform are then populated with coloumn values (dependant on the row initially selected). If the row number was the same each time I could accomplish this by the following.
Private Sub TextBox1_Enter()
TextBox1.Value = Range("a1")
End Sub
but as its a variable I'm trying the following (which I think should work)
Private Sub TextBox1_Enter()
TextBox1.Value = Range("a" & edi & "")
End Sub
I think I need to declare the variable 'edi' as Public. If so where should this be? I've tried 'Genereal Declaration'
what i want to do is input a range of numbers into a cell "L12" from 1 to 450
though when in excel i have formated the cell to "number" so when i want number 001 it turns to 1
what i what to do in the macro is after
Dim sNum As Integer
Sheets("FFR").Select
sNum = Range("L12").Value
if the number 1 is in the cell "L12" the number 1 will be in the variable sNum, though i want the number to be 001!
would i have to count the number of numbers in the variable and then say for example if there is only "1" number in the box, use an "add 00" function to get the number in the variable to be 001! I have an idea what to do though no idea where to start!
I have a column of about 13,000 10 digit numbers. I need to add four zero to the beginning of each row of numbers so I can make it 14 digit numbers. Is there a way to do this without cutting and pasting four zero's for each row of numbers.
View 10 Replies View RelatedI am trying to insert a leading zero for single digits. A3 contains a date, i.e. 01/10/08
d = Range("A3")
dDay = Format(d, "dd")
'The result is '10'
dPrevDay = dDay - 1
'The result is '9'
dPrevDay = Format(dDay - 1, "dd")
'I anticipated the result of this to be '09', but it is '08'
How do I get the result of '09'?
I want to know how to index a drop down list to be used for calculations.
Up until now I was using
Range("B1").Select 'the cell where the drop down list is
ActiveCell.Formula = SiteID 'site id
But for whatever reason it trims a trailing zero from SiteID when setting it in the second line. SiteID is a VBA string.
Indexing it would work, as would preserving the zero so help on either one is appreciated. Auto Merged Post Until 24 Hrs Passes;Correction, I lied. I was using this line to set it.
Range("B1").Select 'the cell where the drop down list is
ActiveCell.FormulaR1C1 = SiteID 'site id
where the number of rows and columns depend on other variables?
For example: In sheet 1, I have mentioned A = 2 and B = 3.
In the macro, I declare A and B to be integers. Then I try to declare a 2D array as follows:
Dim AB(A, B) As Integer
During compiling, it gives me an error: "Compile Error: Constant Expression Required" with the above line highlighted. What am I doing wrong?
Also, when I declare an array AB(4, 7), 4 is the number of rows and 7 is the number of columns, right?
I tend to use alot of sub but am finding I need to declare variables each time
for example
Sub Macro1
Dim i as integer
i = 10
some other code...
end sub
Sub Macro2
Dim i as integer
i = 10
some other code...
end sub
I'm having trouble creating a macro that will look at a single URL, and based on what text is in a cell, replace that name and put it into a specific location in the URL. Then the URL will open and the rest is a macro I've written already. This will then be done as many times as need as long as there is text in the column.
So I'm looking to declare the text in these cells as different variables, then have something call these variables into a specific location in a URL, then have that URL (which is a worksheet location) open up. This is because I have many URL worksheet locations on an external website, I'd like for my macro to look at the cells in column A, check "A2" and whatever that name is, and have it placed into the URL. I assume some type of loop would be useful, since I do not want them to open up all at once, but one by one based on the text or variable in the column. Then the URL will open.
Then I can run my macro code which will include copying and pasting, closing and saving. Then go the next cell, check "A3" then repeat the process. The URL for all the worksheets are all the same, except for one specifc name, which is what im looking to replace one by one.
i got this at the top of my module:
Option Explicit
Public intLRow As Integer
Public strNetDrive As String
Public strDocName As String
Const strNetDrive = "\DriveDocuments"
Then i have this as a macro to test it:
Sub test()
Range("A1").Formula = strNetDrive
End Sub
When i run the macro i get this error:
how do you declare public variables? In one of my forms I declare the variables but for some reason can not access them in other forms.
Public Rm_new As Integer
Public Angle_new As Integer
Public Pl_new As Integer
Public Sub cal_graph_Click()
'Stating variables
Rm_new = text_rm.Text
Angle_new = text_angle.Text
Pl_new = text_length.Text
I'm trying to create an array of arrays (a jagged array). According to Microsoft's VB developer center I can declare in the following ways: ...
View 6 Replies View RelatedRight now in cell AE1 the value = "SUM", but the word "SUM" floats in row 1
I'd like a macro that looks through row1, and gives me the column letter that the word "SUM" resides in
sCol_1 As String
sCol1 = (Where ever the word "SUM" is located in row 1)
not sure if this is the best way.
i'm trying to develop an array that is populated when a userform is activated. The userform has a command button that when pressed, will cross check the information filled out in the userform with the entries in the array. If there are no matches then the array is ReDim and the new information is added to the array. Once all the entries have been made. The array is then transposed to a sheet titled "Database". My problem is that vba is not allowing me declare a public array.Below is the first part of the code. Which is when the userform is activated.
Private Sub UserForm_Activate()
With Sheets("Resources")
cbZIP.List = .Range("A2", .Range("A" & Rows.Count).End(xlUp)).Value
cbBED.List = .Range("B2", .Range("B" & Rows.Count).End(xlUp)).Value
cbBATH.List = .Range("C2", .Range("C" & Rows.Count).End(xlUp)).Value
cbSTABRV.List = .Range("G2", .Range("G" & Rows.Count).End(xlUp)).Value
End With
[code]....
I am trying to compare two workbooks and am running into the problem that since I declared my two workbooks, I am limited in the methods that I can use. Here is all of the code so far.
Option Explicit
Sub UpdateMasterFile()
Dim wbMaster As Workbooks
Dim wbEmailed As Workbooks
Dim wsPC As Worksheet
Dim Master As Long
Dim Emailed As Long
Dim intMaster As Integer
Dim intEmailed As Integer
Set wbMaster = Workbooks("Master Info.xls").Sheets("PlantsCom")
Set wbEmailed = Workbooks("EmailedData.xls").Sheets("NewInfo")
Master = Workbooks("Master Info.xls").Sheets("PlantsCom"). Range("a65536").End(xlUp).Row
Emailed = Workbooks("EmailedData.xls").Sheets("NewInfo").Range("a65536").End(xlUp).Row..............
Using Excel 2007, I'm trying to figure out (and not succeeding!) on how to declare worksheet and range - in order to:
input a formula to cell xfd1, then copy down to xfd2:xfd100 - and here's what I've been playing about with
Code:
Sub filldownxfd()
Dim src As Range, out As Range, wks As Worksheet
Dim sRangeName As String
Workbooks.Item(1).Sheets.Item ("Sheet1")
Dim example As Range
Set example = Range("xfd2:xfd100")
[code]....
I have formatted the cells to be '0000' (showing the leading zero) however when my VBA code runs it copies the cell value into a string but when I stop the code running to check the value the leading zero(s) are gone. I can see they are the same on both worksheets in the correct format. I've tried a few others like integer and long but same same.
View 3 Replies View RelatedI have a CSV file I'm importing into Excell that contains leading zeros in a number field. I cannot get the zeros to display in Excel, but the user of the report needs to see them. Is there a way to dsiplay the leading zeros on a number field?
View 10 Replies View RelatedI have cells where the formual is this: =D17/SUM(D17:E17). The result is always going to be a three-digit decimal, less than 1. .546 .345 .678 etc. Excel, of course, places a zero in the front: 0.546 0.345 etc. Is there a way to remove this?
View 5 Replies View RelatedSample data:
1234
234
123
0304
304
7685
0123
0076
687
I need to be able to use formulas on the above numbers to perform look-ups and comparisons(=IF(A1>1000,"Yay","Boo")). My issue is the leading 0. To use formulas the above fields HAVE to be in a number format. Converting to typical number format removes the leading 0. All of the help files I can find show how to preserve the leading 0 either require a set number of 0s or require a set length. Unfortunately my data cannot match those rules. Is there any way I can convert these cells to a number format AND preserve any existing leading 0(s)?
How do I keep leading zeros in this code? I am incrementing a value with in a string.
TextBox1.value = "PRO 001"
I've been tasked at work with created a daily CSV upload file for a new system. Typically, the format the raw data comes in is .xls and very untidy (direct from SAP).
As such I have created a small macro which tidys up the spreadsheet, and saves it as a CSV. However, I have only just noticed that for the product codes we have which have a leading zero, the .xls file displays the leading zero without a problem, but in the resultant CSV file they are gone.
The macro I use, is as follows:
Code:
Sub SamplesUpload()
'
' SamplesUpload Macro
'
'
Range("A:A,G:G").Select
Range("G1").Activate
Selection.Delete Shift:=xlToLeft
[Code] .....
As you can see, it's very crude (I'm a complete nubie when it comes to this) - the Application.Run "PERSONAL.xlsm!CSV" is a small macro which puts double quote marks around all content of any populated cells in column B and the Application.Run "PERSONAL.xlsm!SaveAsCSV" is a small macro which saves the current sheet as a CSV file - code for those as below:
Code:
Sub SaveAsCSV()
Dim DTAddress As String
Dim FileName As String
Dim FullyQualifiedFileName As String
'Get the path to the desired save location
[Code] ........
Code:
Sub CSV()
Dim arrB As Variant: arrB = Intersect(ActiveSheet.UsedRange, [B:B]).Value
Dim R As Long
For R = 1 To UBound(arrB, 1)
arrB(R, 1) = """" & arrB(R, 1) & """"
Next R
Intersect(ActiveSheet.UsedRange, [B:B]).Value = arrB
End Sub
So, why the leading zeros are not in my CSV file, and how to get them back?
The line which I use to get the leading zeros is:
Selection.NumberFormat = "[>9999]000000;General"
And this is because the only codes which have a leading zero are 6-digits long. Could I maybe add a single ' to the beginning of each cell in column A to make them text, and thus keep the leading zero?
To confirm, the column which contains the product codes is column A.
Trying to manipulate basketball statistics copied from websites ... each cell has a leading space before the number(s) ... is there any way to globally eliminate the leading space from the cells
Tried find/replace, finding [space] replacing with 0 (which would then be disregarded ... didn't work
Tried converting all cells to number format, didn't work
I have two, technically unique text values, with leading zeros, countif is including them in the count for each.
D17 = 01234
D18 = 1234
formula in column "C"
=IF(D17<>"",COUNTIF('Part Numbers'!B:B,D17),"")
=IF(D18<>"",COUNTIF('Part Numbers'!B:B,D18),"")
both countif's are resulting in 2, whereas they should be 1 since they are textually unique. The cells themselves, on both the source and counting side are formatted as text.
I have received an attachment of a .csv file from a client and one of the fields is a tenant ID number that sometimes begins with 1 or more zeros. When I open the attachment it is opening in Excel and dropping the zeros. How can I open that up and keep the zeros. I need those leading zeros.
View 3 Replies View Related