Get Error When Declaring A Jagged Array?
Jan 13, 2010I'm trying to create an array of arrays (a jagged array). According to Microsoft's VB developer center I can declare in the following ways: ...
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Declaring A 2D Array
Jan 21, 2007where the number of rows and columns depend on other variables?
For example: In sheet 1, I have mentioned A = 2 and B = 3.
In the macro, I declare A and B to be integers. Then I try to declare a 2D array as follows:
Dim AB(A, B) As Integer
During compiling, it gives me an error: "Compile Error: Constant Expression Required" with the above line highlighted. What am I doing wrong?
Also, when I declare an array AB(4, 7), 4 is the number of rows and 7 is the number of columns, right?
Declaring Public 2 Dimensional Array In Userform
Apr 22, 2014i'm trying to develop an array that is populated when a userform is activated. The userform has a command button that when pressed, will cross check the information filled out in the userform with the entries in the array. If there are no matches then the array is ReDim and the new information is added to the array. Once all the entries have been made. The array is then transposed to a sheet titled "Database". My problem is that vba is not allowing me declare a public array.Below is the first part of the code. Which is when the userform is activated.
Private Sub UserForm_Activate()
With Sheets("Resources")
cbZIP.List = .Range("A2", .Range("A" & Rows.Count).End(xlUp)).Value
cbBED.List = .Range("B2", .Range("B" & Rows.Count).End(xlUp)).Value
cbBATH.List = .Range("C2", .Range("C" & Rows.Count).End(xlUp)).Value
cbSTABRV.List = .Range("G2", .Range("G" & Rows.Count).End(xlUp)).Value
End With
[code]....
VB Error - Declaring Strings
Jul 18, 2008i got this at the top of my module:
Option Explicit
Public intLRow As Integer
Public strNetDrive As String
Public strDocName As String
Const strNetDrive = "\DriveDocuments"
Then i have this as a macro to test it:
Sub test()
Range("A1").Formula = strNetDrive
End Sub
When i run the macro i get this error:
Slicing And Dicing CSV Files - Involves Arrays And Jagged Arrays
May 8, 2013I am retrieving a CSV file from the net. In this file there are 'x' amount of row data and 7 columns. I only care about the values in the 7th column for each row. I also don't care about the entire first row. A graphical version would be represented something like this, with the values I want colored in orange:
|---,---,---,---,---,---,---|
|---,---,---,---,---,---,---|
|---,---,---,---,---,---,---|
|---,---,---,---,---,---,---|
|---,---,---,---,---,---,---|
|---,---,---,---,---,---,---|
|---,---,---,---,---,---,---|
.
. extending until the end of the data set
.
I've managed to dice this thing into a jagged array by first splitting it using vbLf as a delimiter, and therefore adding those to an array called Lines(). Then I split Lines() up using commas as the delimiter and threw those into a jagged array, let's call it Breadcrumbs()(). I want to throw all the values from Breadcrumbs(i)(6) into an array of its own. Here's my code so far:
Code:
Public Sub CSVparser(file As String)
Dim Lines As Variant
Dim j As Integer
Lines = Split(file, vbLf)
ReDim breadCrumbs(UBound(Lines)) As Variant
For i = 1 to UBound(Lines) - 1
breadCrumbs(i) = Split(Lines(i), ",")
Next i
End Sub
Declaring Variables
Aug 23, 2007I tend to use alot of sub but am finding I need to declare variables each time
for example
Sub Macro1
Dim i as integer
i = 10
some other code...
end sub
Sub Macro2
Dim i as integer
i = 10
some other code...
end sub
Declaring Variables And Implementing Into URL
Jul 17, 2014I'm having trouble creating a macro that will look at a single URL, and based on what text is in a cell, replace that name and put it into a specific location in the URL. Then the URL will open and the rest is a macro I've written already. This will then be done as many times as need as long as there is text in the column.
So I'm looking to declare the text in these cells as different variables, then have something call these variables into a specific location in a URL, then have that URL (which is a worksheet location) open up. This is because I have many URL worksheet locations on an external website, I'd like for my macro to look at the cells in column A, check "A2" and whatever that name is, and have it placed into the URL. I assume some type of loop would be useful, since I do not want them to open up all at once, but one by one based on the text or variable in the column. Then the URL will open.
Then I can run my macro code which will include copying and pasting, closing and saving. Then go the next cell, check "A3" then repeat the process. The URL for all the worksheets are all the same, except for one specifc name, which is what im looking to replace one by one.
Declaring A Variable With Leading Zero's
Oct 29, 2008Can anyone tell me how to have a variable which can store leading zero's. I am using this variable and part of a string and want it to be able to store and calculate numbers such as 0005 at the moment if such a number is entered it sees it as 5. At the moment I have declared the variables as integers but clearly this is incorrect.
View 9 Replies View RelatedDeclaring Variable In Sub Statement?
Nov 23, 2011I am trying to make sense of quite an elaborate macro built by someone else. This has the following line of code
Code:
Public Sub readOperation(rowNumber As Integer)
Dim rowOff As Integer
rowOff = rowNumber - 1
'other arguments and conditions
End Sub
What I am buggered about is that I cannot see the the variable rowNumber being declared anywhere but it seems to have a value of 1. I should mention that Operation is a class and I am very new to classes.
Declaring A Variable As A Decimal
May 2, 2008Using excel 2003
What is the proper declaration for a decimal, I’ve been using currency because it has two decimal points i.e.
Dim x as Currency ...
Declaring A Global Variable
Oct 20, 2006I have a worksheet that has 2 sheets. I want to declare a variable that can be accessed for reading and/or overwriting by both of those sheets. Where do I declare it and how do I access it from Sheet1 for example?
View 4 Replies View RelatedDeclaring Public Variables
Apr 19, 2007how do you declare public variables? In one of my forms I declare the variables but for some reason can not access them in other forms.
Public Rm_new As Integer
Public Angle_new As Integer
Public Pl_new As Integer
Public Sub cal_graph_Click()
'Stating variables
Rm_new = text_rm.Text
Angle_new = text_angle.Text
Pl_new = text_length.Text
Declaring Variable Names Dynamically
Jun 11, 2007Is it possible to declare n variable names dynamically in a macro? For example: Cell A2 in Sheet1 contains the number of variables to be considered in the macro (n). I would like all the variables to take names in the macro from node1 to noden using the dim statement. I tried running a for loop:
View 14 Replies View RelatedDeclaring Columns Based On Location Of Value
Jun 14, 2012Right now in cell AE1 the value = "SUM", but the word "SUM" floats in row 1
I'd like a macro that looks through row1, and gives me the column letter that the word "SUM" resides in
sCol_1 As String
sCol1 = (Where ever the word "SUM" is located in row 1)
not sure if this is the best way.
Fill Series :: Declaring A Variable
Jul 28, 2009Prior to declaring a variable i used this code and it worked:
Sheets("442000ON-1+6").Range("C7").formula = "my formula"
range(C7).select
Selection.AutoFill Destination:=Range("C7:N7"), Type:=xlFillDefault
Than i declared a variable b/c i have a number of formulas i need to use but still needed it to fill the formula in a series after the formula ran. I started getting an error.
Fix was:
Dim formula1 As String
formula1 = "=SUMIF(Pivot!$A$6:$A$108,'442000ON-1+6'!$C$3,INDEX(Pivot!$B$6:$BP$106,0,MATCH('442000ON-1+6'!$B$1,Pivot!$B$5:$BP$5)))"
Sheets("442000ON-1+6").Range("C7").formula = formula1
Range("C7").Select
Set SourceRange = Worksheets("442000ON-1+6").Range("C7")
Set fillRange = Worksheets("442000ON-1+6").Range("C7:N7")
SourceRange.AutoFill Destination:=fillRange
Declaring An Object As A Workbook Is Limiting The Methods I Can Use.
Jun 18, 2006I am trying to compare two workbooks and am running into the problem that since I declared my two workbooks, I am limited in the methods that I can use. Here is all of the code so far.
Option Explicit
Sub UpdateMasterFile()
Dim wbMaster As Workbooks
Dim wbEmailed As Workbooks
Dim wsPC As Worksheet
Dim Master As Long
Dim Emailed As Long
Dim intMaster As Integer
Dim intEmailed As Integer
Set wbMaster = Workbooks("Master Info.xls").Sheets("PlantsCom")
Set wbEmailed = Workbooks("EmailedData.xls").Sheets("NewInfo")
Master = Workbooks("Master Info.xls").Sheets("PlantsCom"). Range("a65536").End(xlUp).Row
Emailed = Workbooks("EmailedData.xls").Sheets("NewInfo").Range("a65536").End(xlUp).Row..............
#N/A ERROR In Array Formula
Jan 30, 2008How do you suppress the #N/A error in the array formula below:
J$2:$J$1201,MATCH(1,($B14=Datasheet!$I$2:$I$1201)*($E$13=Datasheet!$G$2:$G$1201),0)))
Array UDF Returning #VALUE! Error
Mar 23, 2008I have come up with the following array UDF to help me split a large list of values into list of smaller groups.
The function takes the 3rd input argument to to understand how many smaller lists it needs to split the bigger range.
The 2nd argument simply specifies a seperator, either "," or ";"
On using the same on a worksheet I'm getting a #VALUE! error and for the life of me am not able to pinpoint the problem area.
Public Function CBOList(Rng As Range, App As String, OutRng As Range) As Variant
Dim Func As WorksheetFunction, UniqueVals As New Collection
Dim cnt, who
Dim ctr As Long, lst As String
Dim myarr() As Variant
Set Func = Application.WorksheetFunction
CBOList = ""
Application.Volatile...........................
Array Fx Is Giving Me A #NAME? Error
Feb 4, 2009I have a CSE formula that's been working great since day one.
In B202 I have the name Magnecraft.
In Row9 I have all the possible sources for this item starting in D9:CB9.
The fx in C202 is as follows:
{=SUBSTITUTE(MCONCAT(IF(INDEX(D202:CC202,MATCH(B202,B202:B202,0),0)="X",","&$D$9:$CB$9,"")),",","",1)}
I have an "x" in E202 and I202.
C202 should then show (in this case) Abacus and A/E as the 2 sources available.
I'm getting an #NAME? error.
And if I insert a new row, all the data in each cell in C"C turns to #NAME?.
Average Array #DIV/0 Error
Nov 18, 2006I am using the following array formula to give the average number of days aging on overdue reports for my staff where Manager and Aging_on_Overdue are named ranges in my input data: {=AVERAGE(IF((Manager="Joe Smith")*(Aging_on_Overdue>0), Aging_on_Overdue))}
This works fine as long as Joe Smith has Overdue reports, but returns a # DIV/0 if he has none. How do I get a formula to return 0 if he has no overdue reports? I need this because I have to do a weighted average of the group and my SUMPRODUCT formula returns a #DIV/0 for the group if any member of the group has no overdues.
Excel 2007 :: Declaring Worksheet And Range As Variables
Dec 22, 2011Using Excel 2007, I'm trying to figure out (and not succeeding!) on how to declare worksheet and range - in order to:
input a formula to cell xfd1, then copy down to xfd2:xfd100 - and here's what I've been playing about with
Code:
Sub filldownxfd()
Dim src As Range, out As Range, wks As Worksheet
Dim sRangeName As String
Workbooks.Item(1).Sheets.Item ("Sheet1")
Dim example As Range
Set example = Range("xfd2:xfd100")
[code]....
Variable Declaring. Textbox On Userform To Show Value Of A Cell
Sep 25, 2006Users select a row number which then opens up a Userform. Comboboxes and Textboxes on this Userform are then populated with coloumn values (dependant on the row initially selected). If the row number was the same each time I could accomplish this by the following.
Private Sub TextBox1_Enter()
TextBox1.Value = Range("a1")
End Sub
but as its a variable I'm trying the following (which I think should work)
Private Sub TextBox1_Enter()
TextBox1.Value = Range("a" & edi & "")
End Sub
I think I need to declare the variable 'edi' as Public. If so where should this be? I've tried 'Genereal Declaration'
Subscript Out Of Range Error In Array
Mar 21, 2012I am pasting the VBA code below:
Public No_of_Sims As Variant
Public Sim_No As Variant
Public Ground_Up_Agg As Variant
Public UseSelfInsuredVehicle As String
Public Option_Name(1 To 12) As String
[Code] .....
The code highlighted in BOLD is where I am getting runtime error 9 (Subscript out of range).
Subscript Out Of Range - Array Error
Dec 30, 2012When I run my code it comes up with Error 9. I clicked debug and took a look at it and couldn't find out why it wasn't working.
Code:
Private Sub Hundred_Day_MA()
'Sets Last Trading Day's Date
Dim LastDate As Date: LastDate = ThisWorkbook.PreviousBusinessDay(Now, 1)
[Code]....
Error On Function Applied To Array
Jul 20, 2009I have the following code (below) which calls a function to return the sum of values in a specific part of the array.
I haven't set the function up correctly as it is causing an object not defined error(424), but I can't see where and have been going round the houses changing it. I'm wondering if it's my confusion over when to use By Val?
Sub getDataIntoArray()
Dim arrDataTot()
Application.ScreenUpdating = False
Application.DisplayAlerts = False
Application.EnableEvents = False
On Error Resume Next
ReDim arrDataTot(1 To 1)
Error Filling Array With Only Few Values Within Loop
Feb 26, 2014I am trying to fill an array with only a few values within a loop (when XspacingA is 0.5, add the value of the Line to the array) and keep getting the error "Subscript out of range".
View 3 Replies View RelatedRedim Function - Array Already Dimensioned Error
Sep 20, 2012I have an array that is going to have a variable length every time the macro is run. I set a really high length at the beginning and when I want to unload the data, I want to redim the array to only the amount of data that was loaded into the array.
I am getting an error of "Array already dimensioned" when use the redim function near the end of my code below.
Code:
Private Sub Trend_Click()Dim GraphRow As LongDim TodaysYear As Integer,
Adjustment As Integer, EndYear As Integer,
StartYear As IntegerDim X_Axis_Array(1 To 100) As VariantDim SelectedStmt As StringDim X_Axis_ArrayEnd As IntegerTodays
[Code] ........
String Limit In Array - Querytables - Error 13
Jun 23, 2007I need understanding what is the maximum length of string data type. I read that is 63K characters... but, in my case... maximum value is 253. I don't know why happens this. here is some code from one of my buttons.
Private Sub btn_procesare_Click()
Dim intUnit As Integer
Dim strBuffer As String
Dim contor, var_else, cale, dest, dest_final, masca, filtru, **** As String
Dim vntbuf As Variant
Dim sql As Variant
For i = 0 To Me.ListBox2.ListCount - 1
Application.Worksheets(1). Range("A" & i + 2).Value = Me.ListBox2.List(i, 0)
Next...........................
when watch for x, the value is maximum 253 characters. I get error Data Type Mismatch - Error 13 with this.
Runtime Error 381 - Invalid Property Array Index
Apr 21, 2014When I try to populate a worksheet with the data from a multicolumn listbox on a userform.
I have references which list index is to go to which cell on the worksheet, however if there is no entry in this list index it is giving me this error.
As the listbox could have 1 line or up to 10 lines populated, I think I need to put an error handling on so that if the entry in listbox index is "" then resume next, or something like that. However everything I have tried doesn't work and I keep getting this error.
Here is the code I have to populate the worksheet from the listbox. There are 7 columns and 10 rows.
How to handle this error?
[CODE]
Private Sub cbPrint_click()
Call Error_Handling_VBA_On_Error_Resume_Next
Dim ws As Worksheet
Set ws = Worksheets("Invoice Copy")
With ws
.Range("B11") = CusName.Value
[Code] ......
Wrong Data Type Error In Simple Array Formula
Jun 30, 2013I am trying to use FIND and an array formula to find the position of text in a range of cells (A2 and A3 in the example) which could be one of a number of options (C1:D1 here). But the array formula throws up the following error: "A value used in the formula is of the wrong data type". The simplest illustration of the problem is as follows. The formula in B2 is
Code:
{=FIND(($C$1:$D$1),A2)}
and $C$1:$D$1 contain REF and ATM respectively. [/CODE]
REF
ATM
203047 05AUG 08.55 OKEHAMPTON ATM
#VALUE!
CO-OP GROUP 380611 REF 191 7553375222 BCC
22
We see that B2 has a #VALUE! error - wrong data type. But for some reason B3 is ok returning 22!