this formula was working great since 12-08, but someone came to me yesterday saying there is a flaw in the formula between Company A and Company B
If you note that 10.125.239.0/24 is overlapped with 10.125.236.0/22, yet is marked FALSE ...
How well does Excel / VBA deal with data in a binary format? I am working on a Base64 decoder, which in basic terms means I will have 4 numbers, which I need to convert into their binary representations (6 bits each). I then need to combine these binary groups together, and then divide them up differently to give me 3 numbers (made of 8 bits each).I'm just wondering if anyone has any examples on how best to work with binary in Excel? Also if there are an gems of builtin library functions?
View 4 Replies View RelatedI'm receiving this statement when trying to save:
"One or more formulas in this workbook are longer than the allowed limit of 8192 characters. To avoid the limitation, save the workbook in the Excel 2007 Binary workbook format."
The longest formula is 29 characters long. Even if I add the number of characters in every formula in the workbook, it only adds up to 1664.
Does anyone know how to convert a 4 digit number to binary in excel? I used the =DEC2BIN formula, but it only works on a 3 digit number that is smaller than 512.
View 9 Replies View Relatedcell A1 contains the numeric value: 3961.3
cell A2 contains the follwing: ="z equals "&B3-3933.7
which i would expect to give me: "z equals 27.6"
BUT, it gives me: "z equals 27.600000004"
which is awefully strange becos the 4 comes form nowhere...
what makes some sort of sense is that if the value in A1 is changed to 3961.4 or 3961.5, then the final decimal 4 in A2 changes into a 3, and then a 2.
when the value in A1 is changed to xxxx.7 the number in cell A2 becomes what one would expect it to be.
how do i get rid of these strange decimals???
(formatting cells, setting number of significant figures does not work. i naturally already tried that)
Is there anyway to convert excel sheet into a file with binary format?
Or maybe export them into binary files?
I want to change my database type to binary from text..
Problem is my database is Huge, it's a 1044x1044 matrix..
The previous .txt database is exported using macro, into 1044 files that contain 1044 values each. I want to do the same except with binary format...
I have 70 sequences of binary coded variables each, which I would like to compare in terms of overlaps for the number "1", e.g.,
a1 1 0 0 0 0 1
a2 0 1 1 1 0 0
a3 0 1 1 0 1 0
.
.
.
a70 0 1 0 0 0 0
How can I do a pairwise comparison in Excel for the number "1" (ie how often does the number "1" occur at the same place for two sequences?).
I thought about a correlation matrix (that compares sequences a1-> a2, a1-> a3, a1->a4, ...., a1-> a70; a2->a3, a2-> a4, ...., a2-> a70; .....; a69-> a70), but am looking for an easy way to compute this in Excel.
I am running into one of the strangest issues I have seen in a long time. I have a user defined type that I utilize in VB6 and write out to a binary file....
View 7 Replies View RelatedI was reading this Binary Conversion from Decimal on this site, however i am unable to reply to the thread. This code is exactly what i was looking for but have the need for it to be able to give the result as a number of bits eg. i would like the result to be dispalyed as 13 bits. I have tried modifying the code without any success and would like to be able to use it in this form. Public Function Dec2Base( Num As Long, base As Long, length as long) As String
View 3 Replies View RelatedI want to convert Hex to Binary. I want the Binary in 8 different cells.The hex input would be lets say A1 I would want to convert that to eight different cells Bit7 G10, Bit6 G12, Bit5 G14, Bit4 G16, Bit3 E10, Bit2 E12, Bit1 E14 and Bit0 E16.
Then I want another Hex input on A2 and convert that to eight diferent cells.
Bit7 K10, Bit6 K12, Bit5 K14, Bit4 K16, Bit3 I10, Bit2 I12, Bit1 I14 and Bit0 I16.
How would I do This?
I have written a little test sub which reads the contents of a binary file, which is approximately 0.2 Mb in size, into a byte array.
My sub is as follows:
[Code]...
It works just fine, BUT, it is incredibly slow (it spends 80 seconds in the For loop!!!!!)
How can I speed this up?
Note that the binary file can be of arbitrary size.
I tried using a string buffer filled with zeros, and it works!
I read the thread Converting from Hexadecimal to Binary and what I need to do is convert the following hex number to binary; 9E6799CF. The function in that thread doesn't seem to handle that large of a hex value. Is there anyway of doing that with a HexToBin function, short of chopping it up converting the smaller numbers and recombining it in binary?
View 2 Replies View RelatedI am taking a decimal degree (longitude) and converting it to binary then to hexadecimal. The value I am using is a Binary Angle 32 bit structure that will be translated into an 4-byte hexadecimal (with two characters per byte i.e. "20" is one byte and results in spaces).
This is what I have:
Input of 359.999999916 (in cell A2)
Cells B2 through AG2 I have converted A2 into binary (using formulas like "=IF(A2-180>0,1,0)" for cell B2, "=IF(A2-180*B2-90>0,1,0)" for cell C2, "=IF(A2-180*B2-90*C2-45>0,1,0)" for cell D2, and so on)
I then concatenated all of the results into one cell using the following formula:
=CONCATENATE(B2,C2,D2,E2,F2,G2,H2,I2,J2,K2,L2,M2,N2,O2,P2,Q2,R2,S2,T2,U2,V2,W2,X2,Y2,Z2,AA2,AB2,AC2,AD2,AE2,AF2,AG2)
To get a result of (located in cell A4):
11111111111111111111111111111110
However, when I attempted to use the BIN2HEX conversion on A4, I get a "NUM!" error. Here is the formula that I was using in cell A5:
=BIN2HEX(A4,8)
I am trying to convert 14 to 15 digits lengthy Binary value to number.
The formula =BIN2DEC(A2) is giving error #NUM
101111100001010
101111100001010
101111100001010
101111000011100
101111000011100
101111000011100
110001000001010
I have a lot of outputs being spat out in csv files.
I need to get some of the data from set columns and copy this over into a master tracker. Columns are not sequencial and may need to copy change at a later date. Example attached.
Some data fields will have letters in them as well. Some are varying in length in terms of the amount of data within a cell. eg. "AB389238923589Y234HI" or just "A-GT6"
I don't know where to start VBA wise but it must be possible rather than open copy paste.
The tracker has a set name but will change quaterly.
The Output CSV files are new files with a number (no date) for titles.
How do I graph this data? I am plotting the test results (Column A is the employee number, B is the Employee name, then each of the questions are Columns D through DX with DY being the total correct by each employee) (Rows are employees and then the Ratio that the question was answered correctly) The goal is to find questions that are routinely answered in correct or that have a problem with the question.
I was hoping to graph the correct and incorrect questions so those that are either high frequency correct, incorrect or not answerd identified I can improve the test.
Example of the spreadsheet. I am using =COUNTIF(D3:D15,"1")/12 for the ratio answered correct - this should also see the ones not answered as incorrect. 1 = correct answer 0 = incorrcet null=not answered
NO
Employee Name
Question
1
2
3
[Code]...
How can I graph these results to answer which questions have a high frequency of incorrect answers? I am thinking some kind of scatter plot.
I want to create the chart below. I have data that is coded with a binary flag (0 = red, 1 = blue) that is also ordered. For example, the data I would use to hypothetically create the left hand column below looks like this
Binary Flag
Rank
0
1
0
2
1
3
0
4
1
5
1
6
I've set up a binary matrix, such that I have 421 unique headings repeated twice: once in each column and once in each row (i.e., in the matrix the headings for row 5 and column 5 will trace back to the same description in the column headings and in the row headings).
I need to fill in 1s (case satisfied) or 0s (not satisfied) in this 421X421 matrix. Where my problem lies is in finding the exact row-column cell combination in which I need to enter the 1s. Descriptions that belong to the same group or category will be marked by these 1s in the matrix. For example, if I have descriptions 5, 9, 13, and 17 belonging to the same group I need to enter a 1 in each possible combination of these numbers: {5,9} {5,13} {5,17} {9,13} {9,17} {13,17}. I need a quick formula that will compute all possible combinations for inputted descriptions AND will enter a 1 into the cells, which correspond to these combinations.
I have a very large dataset (~5000 points in a 2D array) which I need to plot and fit a linear trendline to. There are 90 subjects each of which has a daily binary event checked over its lifespan. eg:
Day: 1 2 3 4 5 6 7 8 9 10
subj 1 0 1 0 0 0 (dead)
subj 2 1 1 1 0 1 0 1 0 0 0(dead)
subj 3 0 0 1 0(dead)
I simply averaged the number of events per day per subject and plotted them but near the long-lived end of the data the variability gets really high. I have normalized the lifespan for each subject such that instead of the event occurring on day 10, it occurred at 0.2 of its total lifespan (dying on day 50). Now that my data is in this format, I want to create an average for all subjects over the domain 0-1 representing birth-death.
The trouble is that now each subject's domain has different intervals between points (eg. 0.1 for subjects living 10 days and 0.006993 for those living 143 days). How to now space out the cells (somewhat) automatically so I can average the columns? My array is 90 x 150 so doing it manually is not really possible. Or, alternatively, is there a way to create a continuous average rather than a discrete one? Some sort of function that goes through each infinitely small (or even a discrete really tiny interval) point of the domain (0-1) and averages the binary y-value?
I am trying to do a query against my database using MsQuery, but I am having a problem with it...
One of the tables in my database stores information as Binary (Bits) instead of actual text.... When I create the Query in MsQuery, the text is displayed as desired...but when I send it to Excel that column is not displayed..
Does anyone have any ideas on how I can get it to send the column to Excel?
See attached for what I mean. The Bits column shows in MSQuery, but not in Excel.
I have a problem with the code below. The code pastes values into column c, depending on values in Column A.
The problem is that, at the end I want it to go to column d and execute the R1C1 formula, but the lastrow1 variable is always set to 1 ( I went through the code pressing F8) so the formula won't go down the column.
Code:
If Range("A" & i).Value = 2 Then
Worksheets("deacc").Activate
Call SelectRndRow
Worksheets("sheet1").Activate
Range("c1").Select
Selection.End(xlDown).Select
[code]....
why my datedif function is not working.
View 3 Replies View RelatedI currently have a workbook (Unconfirmed Application Audit 02) which is the result of an audit of applications on PCs. I have come up with a macro which will insert new columns into the sheet and fill those columns with data, should the application listed, have a replacement specified in the AppRM file. The macro works fine for column G, in that it pulls through the new software manufacturer name but column H should pull through the new product name and I should display the new product version and they don't. To me, it looks like the exact same formula in each column apart from the column reference to get the information from.
View 7 Replies View RelatedI'm trying to use a formula for column F, starting in cell F6, for column M, starting from M26. The formula works in Column F but after I tried to use it in column M with adjustments, it doesnt work. Attached is the file.
View 3 Replies View RelatedI have a Age calculating formula in an excell cell, which calculates the age as on another date.
The forumala is =IF(E4="","",IF($C$1="","",ROUNDDOWN(($C$1-E4)/365,0))) where E4 is the date of birth and C1 is the date in which I want the age calculated to be.
The above formula works very well on my computer, but does not on any other computer. If I access it from my sent items or from a shared drive, it works perfectly on mine, but not on any other computer!!! I get a #value error message on all other computers.
I have tried the foll:
If i enter =ISNUMBER(C1) where the age has to be calculated, I get #Name?
If I enter =ISNUMBER(E4), i get TRUE
The above is on the sheet where it does not work ( on others computer ) and i get TRUE for both on mine. Also both have the same date formats and same time zones...
where the issue with the following formula is?
=IF(AND($E$2="N",$AA$550),"BT1",IF(AND(Z5="F",Y5>=0),"CLEAR",IF($AA$5
Yesterday (13/03/2007) was the 9th working day of the month (basing a week on Mon – Fri) – today is the 10th working day
Is there any formula, or mix of formula’s I can use to automatically calculate this?
I am trying to use a countif and formula but can't get it to work. This part of the formula works fine =COUNTIF(J:J,"
View 9 Replies View RelatedI am trying to create a formula to work out the last working day of each month, but I can't come up with anything that is less than the 1,024 formula limit. I am using a UK calendar so the only two holidays to effect the last working day of the month will be Easter and the last Monday in May.
This is the formula I am using which takes account of Easter, the checking for the last Monday in May is simple enough in another column, but I would rather keep it in one column, just wondering whether there is a simpler way of doing this.
A1 is a specified date and then I would like to work out the last working day of the month, on a new row, for up to the next 50 years....
I have a column of numbers ranging from 0000-9999. They are not in order and multiple numbers are used more than once. I would like to know how many times the numbers in the range of 4000-4999 appear. I am trying to use the formula =COUNTIF(F4:F500,"=4????") or =COUNTIF(F4:F500,"=4*") but neither are working. If I do a single number like this =COUNTIF(F4:F500,"=41420"), it will count them for me.
View 9 Replies View Related