ce.Offset(, 4) = "=" & ce.Offset(, -1).Address & "*" & ce.Offset(, 4).Column & "25"
If X29 were equal to ce.Offset(,4) then the value in that cell should be set to
"=S29*X25"
Currenctly it is returning "=S29*2425"
(FYI - ce is just a variable to capture a particular range/cell that is dynamic and used within a For Next Loop)
Is there a way to get the column Letter, instead of Number?
like in A1 Column() would equal 1 in B1 Column() would equal 2
I would like
in A1 Column() to equal A and in B1 Column() to equal B
is there a way to make the following code return the letter of the column instead of the number? currently if the 'String' value that is in 'ColumnFind' is in column B this code returns a value of 2. i Need the 'B' for later code to work.
ColumnLetter = ColumnFind.Column
I want to apply Data Validation to a cell, so that only the following combination of letters and numbers can be entered.
Letter Letter Number Number Number Number Number Number Letter.
e.g AB123456C.
I need to convert a column letter to a column number for the following line of code in my VBA application:
VB:
strAverageBaseFormula = "=AVERAGE(D" & Trim(Str(lngFirstRowOfIncrement + 1)) & ":K" & Trim(Str(lngFirstRowOfIncrement + 1)) & ")"
I am inserting a formula into a cell using VBA, but the problem is that I don't know the letter value of column "K" (used in the middle of the line); instead, I know it as column number 11. Is there a simple way to convert the column number 11 to the column letter "K"?
Can column() return a letter instead of a number? I am planning to use it with INDIRECT? Is that possible?
=INDIRECT(row() & column())?
Some bits of code I have learned use column numbers and some bits use column letters.
Can someone share a line or two that I could add to my macro that will convert the F representing column F into a 6, and vice versa, so that I can continue using my pre-existing bits?
When using the formula '=COLUMN()' in cell A1, it returns the number of the column - in this case, '1' (for column A). Is it possible to affect this formula so that it returns the column letter (in this case, 'A')?
I can obtain the columns numbers but I cannot get the letters. Is there anyway to convert from a number to a letter?
eg. somefunction(1) gives me column(A) as an answer?
How to return column number (not letter)?
View 5 Replies View RelatedI wanted to know if there was a way to either make a variable hold a column letter or else automatically convert a column number to a letter. This would be for use in the Range property.
All I could find is some complicated technique requiring division by 26 that I will never remember let alone code quickly.
Or if you have a variable holding a column number, is the only way to use it with Cells?
Is there a function that will output the column letter? For example there's one I know of: =COLUMN(), which outputs column number, but not the letter. And if not, can a formula be written to output it without converting the spreadsheet to R1C1 style or using the lookup function that refers to a separate table within the spreadsheet?
View 3 Replies View Relatedhave thousands of rows and the cells look similiar to this:
FAKE NAME PARTNERS FTA048
some other combos could be FTB039 or BCL048 ETC
whats the best way of looking down a column
and moving any 3 letter 3 number combos to another column
so that FAKE NAME PARTNERS and FTA048 are in seperate columns
In my spreadsheet the formula
=count(k:k)
gives 8 which is correct.
But I know ONLY that the column is 11 (that is 11 th column). Then how do I write the above count formula wilthout using column letter k.
in a macro i have this: col=cell.column 'suppose col=16384. then i need to place in a cell this formula =(XFD2708*100/XFD2597)-100 so i'm looking for "something" that can convert 16384 in XFD.
View 2 Replies View RelatedI have a variable, ColumnX. I want to use VBA to generate some formula referencing ColumnX. For example: I want to sum the values in A1 to A10. ColumnX has been set to "1" which is the number of column A.
Range("A11")= "=sum("A1:" & ColumnX & "10)"
Obviously the above code doesn't work because I'm putting a number where VBA expects a letter. How can I rewrite my code so that A11 will entered with formula that sums A1 to A10?
I need code to change a letter such as A into a column number i.e 1. Everything i can find is to do with changing column numbers into letters, surely you can do it the other weay round aswell? So when the macro is given the letter AA it returns the column number as 27 etc, but i need it as a defined variable such as "i = column number" so i can use this information further on in my code.
View 2 Replies View RelatedIs there an easy way (without writing my own conversion function) to get the column letter from a range object, as opposed to the column number?
View 5 Replies View RelatedI am having troubles finding a row number, using it to specify a range and then counting the cells containg values in that range.
This is what I have
Code:
Private Sub TextBox1_Change()
Dim test1 As String
Dim FoundRom As Range
Dim i as String
Dim abc1 As Range
Dim Core1 As String
test1 = TextBox1.Value
[Code] ........
I am thinking that I have my "Dim"'s wrong or something but I cant figure out how to define the range including the found row number and then count the number of cells containing data within that range...
i want to fill down a column and instead of my formula changing from A6 to A7 i want it to change to B6.
View 9 Replies View Relatedi'm running out an option, i must use offset or index function but there are problem found: 1.Offset function cannot use a dynamic height or number of columns and the result are #NAME?, here is the code
VB:
Private Sub CommandButton1_Click()Dim k As Variant
Dim b As Variant
Range(Me.RefEdit1).Name = "item"
[Code]......
For the below formula is it possible to replace the B's (column location) with a cell Say Z146 which contains the letter B (or a number if thats easier and someone can tell me the numbers for each column).
When the formula is dragged into the next cell (down) it takes its column reference from Z147 and then my life becomes so much easier.
=IF(INDEX('Overs-Unders'!B:B,MATCH($C145,'Overs-Unders'!$A:$A,0))"",INDEX('Overs-Unders'!B:B,MATCH($C145,'Overs-Unders'!$A:$A,0)),"")
I am having some difficulties using a combination of IF and the OFFSET function to display a range of cell values from another column based on a simple condition. The values I need to display at the destination cells should be offset by 8 columns to the right and "X" rows down from the reference column. The value "X" is to be determined via the IF function to check for the row index number.
For example, if Index value "X" = 8, then display the value of B2 in cell I9. IF X = "9", display B2 in cell I10 etc.
I have attached a sample worksheet that provides some examples.
I am trying to work out how to nest offset in a code using search replace. The goal is to find a value from cell A1 (example) and replace the values in the cells next to the cell containing samuel and the cell containing samuel.
A sort of search and remove data tool if you like So for example:
[QUOTE]A1: "samuel" (the search criteria)
Search range is: B1:D400
(for example)
Cell B40 = samuel
C40 = Driver
D40 = year
So, the macro is activated and finds "samuel" in B40 and I would like C40 & D40 replaced with "" The code I'm using is below: (this is just replacing the cell containing the search criteria with "test". I would like to nest offset(0,2) & offset(0,3).Value = ""
Sub Macro1()
Range("B1:D400").Select
Selection.Replace What:=Sheets("Sheet1").Range("A1").Value, Replacement:="test", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
End Sub
I would like to change a number to a letter and then drop a digit from the end.
Say my data in A1 reads 81234568, and I would like it to display in cell A2 as h123456.
I have letter and number combination code in two collumns and they differ for 10.000 numbers:
BAM98314
BAM88314
BAM90000
BAM80000
As you can see the left code is for 10000 numbers higher. the letters are allways the same. In the event that this isn't so, if difference between codes in same row is more or less than 10000 numbers. I was thinking on making conditional formating so the cells with wrong difference would be marked red, but I do not know how to make formula for this difference.
How to translate a specific number into a specific letter related to the number itself.
I have lots of different numbers for example all going down a specific cell (These numbers I want to separate into 3 different catagories. The positive numbers I want to be calculated as the same Letter that is next to that row directly over to the left of that cell.
So if the letter
B / cell / cell / +9 / Then I want if its a positive number like +9 to answer in the formula with the same letter (B) listed to the right in the same row in a different cell of course
B / cell / cell / -6 / Then I want if its any negative number like -6 to answer in the formula as the opposite Letter of (P) listed to the right in the same row in a different cell of course
P / cell / cell / +17 / Then I want if its a positive number like +17 to answer in the formula as the same letter (P) listed to the right in the same row in a different cell of course
P / cell / cell / -3 / Then I want if its a negative number like -3 to answer in the formula as the opposite Letter of (B) listed to the right in the same row in a different cell of course
and thirdly if its a (0) zero and only (zero's) Then I want the answer to stay (0) zero.
The number can be any numbers it doesn't matter. Only distinction is that positive number of +1 and up repeat and stay the same letter that the cell on the far left is already stated.
and all the negative number of -1 amd below all reverse the letter to the opposite letter of (B to a P) or (P to a B) listed to the right in the same row in a different cell of course
and of course (0) zero would be listed as a positive number and only return a (0) zero as the result of the formula.
I am using the Column() Function for referencing purposes... what I want this function to do is return the "letter form" of the column position rather than the "number Form"... is there anyway to change this without switching to R1C1 form?
i.e. Column(B4) yields "2"
I want it to give me "B"
I have this macro below and would like the code changed to find the "Customer Number" column by name rather than by column B. Note that the "Customer Number" column will always be somewhere in row 1.
View 12 Replies View RelatedIs there any way to name cells with same letter but different number?
e.g i need to name the first row A1 to A100.
