I am curious can we chose random number out of numbers if they are in one cell separated by coma
Example:
*A111, 12, 14, 18, 19
Is there any formula so Random number can be selected from cell A1
When the entry in a cell is of the format e.g 3,4 is there any way to find the value 3 or 4 in that cell?
Attempts like:
Cells(i, 1).Value = variable (e.g variable=3)
or
Set cell_found = Cells.Range("A1:A10").Find(variable, lookat:=xlWhole)
do not find the cell with the 3 (or 4). The above work fine when 3 or 4 are alone in the cell. Is there anyway to find these values in the cell?
I have the following syntax in B1: "1,2,3,5,6". and I need VBA to take the very last number out of that list, and increase by four in single steps. For example: before the code: "1,2,3,5,6" and then after it "1,2,3,5,6,7,8,9." The code must be flexible, though, because it will be running within another Macro, and it must work whether the last number in the list is 1 digit ("...4,5,8"), 2 digit ("...34,35,36") or 3 digit ("...111, 113, 114"). Those three examples would be changed into "...4,5,8, 9, 10, 11" "...34,35,36, 37, 38, 39" "...111, 113, 114, 115, 116, 117".
View 4 Replies View RelatedI need to generate 8 (random) numbers which should range between 0 to 80 and the sum of those generated 8 numbers should be 80.? How can I achieve this.
View 14 Replies View RelatedI have build a system that needs a lot of random numbers generated to work.
I have used what I thought would work to generate me these numbers like this example:
VB:
Lastrow = ThisWorkbook.Sheets("RPlay").Range("A" & Rows.Count).End(xlUp).Row
RPlayerNum = Int((Lastrow - 2 + 1) * Rnd + 2)
This would generate a random number into RPlayerNum variable, based on the list in sheet RPlay, missing off row 1 as the header.
However we have noticed a massive flaw in this code.... It works as long as the excel file is open, each time run it gives a different random number. However if you close the excel file and open it, then run it, it ALWAYS gives the same number first run, every time.
I wanted to generate 11 random numbers between 1 and 10, which added up to 100 every time I pressed F9...
View 9 Replies View RelatedI need excluding text from a cell and come out with a random number up to 3 numbers. Please see the attached image;
If you notice in column D there is text and a number that starts with a decimal, for example on the first row is .437 the next row is .215 next row is .63 etc... Is there a way to come out with a random number mixing it up to 3 digits and output those number on column "E"? Im only interested in filtering and coming out with the random number i mentioned .437 .215 .63 etc... not the +/-.010in.
There is no right or wrong number, i just need to come out with random number using up to 3 numbers up.
Maybe for .437 three numbers up could be .440 for the next row .215 maybe a number up .216..etc..
Hope there is a way to do this, my excel file is too long to type a number manually.
I vant to get a random number i a cell whenever my file is opened, but the random function is not working well for me as I always get the same number.
Sub Auto_Open()
MyValue = Int((99 - 1 + 1) * Rnd + 1) ' Generate random value between 1 and 99.
Range("A1").Select
Selection.Value = MyValue
End Sub
I basically need to grab all the numbers going down in a row and get them into one cell in Text format with a comma between them.
A1
5293
5294
5295
5296
5299
5300
5301
5302
5303
5304
5305
B1
What I need in Text format
5293,5294,5295……
I need to set up a formula to choose 2 job titles from a single column. There can be 2 to n job titles (non-repeating) and I want to find the title at random. I have no problem finding the first job title using index and randbetween, but I want the second title to meet the same criteria, just not equal to the first job title.
View 3 Replies View RelatedI'm using the prob() function, and it works for no more than 61 random numbers. Does anyone know of a limit on the number of random numbers used in the function, and whether it's possible to use more numbers in the function? My formula is:
=PROB($C$11:$C$71,$L$11:$L$71,G11,H11)
I want to create a long list of 10,000 random numbers between -100 and +150, but do it so that the average of all the random numbers equals 20.
View 9 Replies View RelatedCell(i,1)have 3 Numbers
Each Number Not Allowed Greater Than 10
Each Number In Cell(i,1) Will Be Added 1 In Cell(i,3) And Cell(i+1,3)....
How Can I Seperate Numbers And Make Three Variables To Run Macro
A
1,3,10
2,5,9
C
2,3,10
1,4,10
3,5,9
2,6,9
2,5,10
I am working on a Random Cycle Count Generator that provides random SKU#s based on 3 separate columns of SKU listings. The user clicks a button to generate the SKU#s to cycle count for that day. What I would like to see is a date stamp in the columns next(B,D,F) to the referenced SKU listing(A,C,E) based on which SKU#s are generated. This will let me see the last date that the SKU was generated. I would also like it to automatically save after generating.
View 2 Replies View RelatedI have what seems to be a pretty complicated situation involving random numbers and letters. I need to generate random sets of this combination of 2 letters follows by 6 numbers (ex. AB123456). I need the final product to be randomly generated and non-repeated.
I have played with various methods of producing random numbers and random letters both repeated and non-repeated. The closest I can get would be a cell of randomly generated letters adjacent to a cell of randomly generated numbers which so far has been useless.
VBA or excel functions are both okay.
If I have, in one cell (call it D1):
EH,DR,HU
and in a lookup table on another sheet:
A B
1 ED T
2 EH F
3 DR G
4 HU H
5 SE E
6 YU E
I need to be able to lookup the values in D1 on the table and return the values in column B to a single cell (say E1), also comma separated...
eg...
F,G,H
I have 25 random numbers and I would like to get a possible 5 digit combinations of these numbers. Can anybody help me with the possible formula?
View 9 Replies View RelatedI would like to ask if there's a way to generate a random 4 characters in one cell and the specific random 4 characters that has been generated will be copied until the last cell of my preferred choice?
The format that I want is that:
yymmdd / random 4 characters that has been generated / 4 numbers that will increment sequentially
For example:
in A1: 140330QWER0001
in A2: 140330QWER0002
in A3: 140330QWER0003
.
.
.
.
.
But here's the catch, the file that I am using when closed then opened again will generate another random 4 characters with the same format. If i opened this file tomorrow:
for example the date for tomorrow is March 31, 2014, the file will do:
in A1: 140331TYUI0001
in A2: 140331TYUI0002
in A3: 140331TYUI0003
.
.
.
.
.
I tried to record it, the Rand() function when copied will generate another 4 characters.
I have a range of cells that have values from 1 to 7 in them. What I would like to do is to have the next column generate a random number from 1 to 7 that does not generate the number that the cell next to it has. for example if cell A1 has 6 in it, I would like cell b1 to generate a random number other than 6 in it. if cell A2 has 3 in it then cell B2 would generate a number other that 3 (1,2,4,5,6, and 7).
View 9 Replies View Relatedi have a list of customer codes each seperated by a space. In the column next to them i have a percentage. (see attached file before tab). I would like to be able to split the cell of customer codes and transpose them so that there is one cell per customer code with the appropriate % applied (please see attached file after example tab).
At the minute a manual process is completed of sorting in length order, using the text to column function then copy paste and transpose, then copy the % in. Its quite manual process, is there an easier way?
For example the cell contains 1,M2,M7,M1,M8:2,M15,M9,M4,M5:3,M3,M6,M14,M11,M12:4,M10,M13 and I need to create M1, M2 , M3 ..etc columns and attach the coresponding number to each one of them. For instance M2,M7,M1,M8will get 1 and so forth and so on. I was acutally thinking using the Notepad to replace the , with a TAB space and paste them back in to my data set and create some IF statements. On the other hand running VBA scrip would make it even easier. However I would preffer to use a function (that I am not 100% familiar with) and leave the VBA scrip out of the question for the moment.
View 12 Replies View RelatedI have a spreadsheet that has two numbers separated by a backslash in one cell, like below:
F/P KR EVERYDAY TOWELS 6P (72)276SFT SC 015836
3 / 3
1 / 1
3 / 3
1 / 1
[Code]....
What I want to be able to to is separate the two numbers into a different cells like below:
F/P KR EVERYDAY TOWELS 6P (72)276SFT SC 015836
F/P KR EVERYDAY TOWELS 6P (72)276SFT SC 015836
3
3
[Code]...
Because I have about 50 columns, I don't want to use Text to Columns. Is there a formula or macro I could use? It doesn't have to be as clean like I layed it out (in regards to the column title) but I just to really separate the two numbers into two cells.
I have a sheet with a list of cost values and I need to be able to total each set. Each set begins with the word "COST" and ends with empty cells. Some sets have no values, just the word "COST"
There are currently about 500 cost sets, from row 1 thru row 2194.
Here is an example of what Id like to accomplish:
BEFORE:
I have column of cells containing entries such as V1, V3 and V7. I'm trying (and failing) to come up with a formula to separate the numbers from the letters and add them together: V1, V3 and V7 would together give 11.
I can use the MID worksheet function to separate my numbers from my letters on a row-by-row basis, but I can't work out how to do the whole thing in one fell swoop. =SUM(MID(A1:A10,2,2)) doesn't work, for example.
I have a listbox populated with a number followed by description. How do I write code to extract the number and description to different cells. Listbox example: "1234ES - Project Description". Now I want "1234ES" in one cell and "Project Description" in cell left of number.
View 2 Replies View RelatedI have a huge data file that must unfortunately be mandatorily downloaded in a single column format, with coma delimitation for each separate piece of data instead of a space, as follows: 08/04/2009,158,7,1849,1184,824451,403711
What I need to do is put each of the bits of data (coma separating each bit) into a separate column, so that each piece may be further processed. Is there a simple way to do this? Would be happy just pasting the data to a new worksheet, if there was a simple way to remove the coma, create a space between each number, and automatically place each piece of data into a separate column.
Basically...here's what I'm trying to do...
I have 7 numbers. The numbers are going to be grouped in threes.
(Ex. 123,124,125,126,127,134,....)
I want to assign column/range for each number...
1=A2:A100, 2=B2:B100, 3=C2:C100...
So for 123 the formula would be...
sumproduct(--(A2:A100>criteria),--(B2:B100>criteria),--(C2:C100>criteria))
It would be awesome to have the formula automatically calculated based on the numbers I choose.
i have a problem in that i need to generate a random 6 digit number preceeded by an X if the data in column B is either blank or 0. This needs to be filled in if the adjacent cell in column C has data in. i am a moderate macro writer and am finding this part quite challenging.
i am ussing excel 2007.
"A1" has a number containing "1000"
I want column "B2" to choose the next number in sequence,(1001) so long as "A2" contains these letters "EHT". if it does not contain "EHT" i dont want excel to insert the number "1001"
But if cell A3 contains, "EHT" I want the next number in sequence to be instered automatically... (1001, 1002, 1003")
Is there a simpler formula I can use that combines IF and COUNT functions. CountIf, maybe?
I have, let's say, 17 items and I want to choose 5 items out of them. Each time I pick one I am told how many I have chosen. When I reach 5, I am told that I have chosen too many.
