Picture 2 rows and 4 columns.
The top row is just 0, 1, 2, 3
The bottom row is something like: 850, 790, 200, 250
Here's the problem: I want to find the midpoint of the data set in row 2, based on the values in row 1. So, the sum of the data in row 2 in this example is 2090, meaning the midpoint is 1045.
If we were traversing along the top row as a line, we'd find that midpoint somewhere in the 0.3 range... but how do we get that value?
We are trying to find the median of a large set of numbers to calculate the median income in 2010. For an example we have 8,379k people with $2500 average income, 9,783k with $7500 average income and so on. How can I calculate the median average income of such a large amount of entries?
View 8 Replies View Relatedhow to find the median for a list of numbers using =median(). But what if I have a list of prices for different types of say cars.
Car Type Price
A $10000
B $15000
A $20000
C $30000
Is there a macro that will return
Car Type Median
A $
B $
C $
I have two columns of data, one is the price per unit, the other is the quantity sold at that price. I'm trying to find the median selling price, but MEDIAN doesn't work correctly and I'm not sure how to tell the function to count each price the actual number of times it was sold.
I actually believe I've found a work-around for this problem - I sort by price and use a SUM function to figure out where the middle is...I just feel like there should be an easier way (for the future).
How to find Median,Mode in a excel sheet which contains more than 255 rows of data?
View 6 Replies View RelatedI am working on a spreadsheet for my farm. I have two sets of data I am working with. A very basic example is below:
What I am trying to do is find the actual median stud fee (i.e. if you had another column with $5000 listed 22 times, $6500 listed 34 times, etc. then you could find the median from there).
Seems like an easy thing, but I'm not sure if an array formula is what I need to use or something simpler. I don't have a lot of data right now (only a page) but will have much more soon.
with the following formula.
I need to find the median of Column C and Column H and then divide the median sum of Column C by the median sum of Column H. My data contains blanks so I obviously need to count cells with data only. I am trying to avoid hard coding any cells and am looking for a single formula.
So what I have is a large list of items, and each item has the price of the product, and a product type.
What I want to do is find the median price for each specific product type, using a formula, without having to sort or filter my large list of products.
I've read several threads about using Median(If, and I have success with one criteria, but not with three. Here's the setup:
I have a log of phone calls, and I want to find the median call length for calls in a certain month or set of months (i.e. a quarter, three months). In Calls!B I have the date of the call, in Calls!C I have the call length in minutes (i.e. "34"), and in Calls!A I'm using Concatenate and Text to return month/year (i.e. "Aug06").
With one criteria, it calculates the median correctly. With three, it only returns #NUM. Yes, I hold control+shift and hit enter. Here's my formula:
=MEDIAN(IF(Calls!$A$2:$A$500=Scores!B8,IF(Calls!$A$2:$A$500=Scores!C8,IF(Calls!$A$2:$A$500=Scores!D8,Calls!$C$2:$C$500)))))
Where Scores!B8,C8,D8 hold "Oct06" "Nov06" and "Dec06" respectively. What am I doing wrong? Is there another approach I should use instead?
Median Indirect: I would like to find the median in a range of cells and then bring back the 2 adjacent cells
Range...............Adj Cell 1............Adj Cell 2
1.......................L1......................L2
2.......................P3......................P4
3.......................O9......................010
So the median of the range is 2, thus we would want the formulas to bring back P3 and p4
Column 1..............Column 2
P3...........................P4
I now have a XY scatter graph with 109 individual points (representing schools) and a macro that tells you the plot details when you hover over. It's ok if you want to know which school is down the bottom but if you don't know where the desired school is in the first place, it's a lot of trial and error before you find it.
What could I look to add that gives the user the option to have a single data point highlighted (on selection?) so they don't have to manually look for it?
workhorse.xlsx
This is part of the bigger excel sheet. I would like to write a macro to find the column D6 based on the location of text 'committed total' . Then addup all numbers from E6 to V6 and write total in W6. Then add d6 and w6 and place it in X6.
I'm trying to create a macro that when run, scans Row 12 (only after column E), Finds the first empty cell, then inserts the cell value from Sheet4 CellE8. Then the hard bit begins. I need it to insert cell info in all the cells below it, from different locations...
For example
A
B
C
D
[Code].....
In the above sheet, I need it to go to cell D2 and insert the values from Sheet4 CellE8, Then proceed to D3 and insert data from Sheet3 D4, then to cell D5 and insert data from Sheet1 A7, etc etc
I dont mind doing each cell individually, but they will always be in the same column (and row 2 "Value" will always be the one that determines the next empty column).
I have multiple tables like the one in the picture and have to duplicate this code for different known ranges.
View 11 Replies View RelatedMy data is set out in columns, where alternate columns provide day numbers for given years (we can call these type 1 columns), with adjacent columns containing values which correspond to those type 1 column day numbers (we can call these type 2 columns). There are about a hundred columns in total (50 of each type). I would like to get excel to return the three largest numbers within each type 2 column, but I want to exclude data within the type 2 column above the point which is adjacent to a specific (varying) day number in the type 1 column. The location of this point varies for all the type 1 columns, according to a third row of numbers (the look up start point), which are currently listed below the dataset in every type 1 column. So, for the type 1 column "year 1", I would want Excel to ignore the values 0 and 1, which are listed next to day numbers 78 and 79, and begin looking for the three largest values down the column starting from the value which is adjacent to 81 (which is a 2). In type 1 column "year 2", excel would start looking for the largest values from the cell adjacent to 78, so it would ignore the 18 at the top of the column,and would return 2 and 12. And so on.
Year1
Value
Year2
Value
Year3
[Code]...
look up startpoint
81
78
62
83
I have a pivot table as shown below which is pretty straight forward however I am trying to create a macro that will automatically change the point name to match the point name in column E then copy that resulting dispaly to another sheet then pick the next point name in line and do the same thing and repeat for 50 rows, so my end result will be 50 pivot tables ready for printing. I can do this manually but I am trying to make it automatic...BTW the point names in column E change everyday but the pivot table supports the name changes.
Option Explicit
Sub PointName()
Dim Ws As Worksheet
Dim Rng As Range, Cel As Range
Set Ws = ActiveSheet
Set Rng = Range(Cells(2, 7), Cells(Rows.Count, 7).End(xlUp))
For Each Cel In Rng
Ws.PivotTables("PivotTable1").PivotFields("Point Name").CurrentPage = Cel & " "
Ws.Columns("A:B").Copy
Sheets.Add
With ActiveSheet
.Paste
.Name = Trim(Cel)
.Range("A1").Select
End With
Next
Ws.Activate
End Sub
I turned it off for a while and when I turned it back on I am getting an error
Unable to set the _Default property of the PivotItem class
Debugger is highlighting
Ws.PivotTables("PivotTable1").PivotFields("Point Name").CurrentPage = Cel & " "
I am trying to find the median of a set of numbers on a column that correspond to dates on the left column. I want a monthly median average of the numbers on the right which correspond to the dates on the left. So for example. I want to make an equation that gives me the median of all the numbers on the right if they fall within the range of a certain month(in this case October). I've tried These:
=IF(COUNTIFS(A:A,">=10/1/12",A:A,"
I have an interesting problem (I hope you find it interesting too). I'm trying to find the historical "high" day of the week for a particular stock I follow. I searched for several hours but was honestly unable to make any progress. Normally I do my own formulas, so other than pasting a rare macro, that's pretty much the extent of my (lack of) experience, ie please assume I am a novice....
View 9 Replies View RelatedI have a database of employees with 7 different variables [Year, JobFunction, PreviousIndustry, PreviousRegion, Degree, Experience, CollegeMajor] of which I would like to be able to select any number of and find their median/max/min/etc salary.
For example, I may need to know the median salary of all employees who started in Year 2006, who work in accounting, and have an MBA.
------------------------------------------------------------------
Rather than copy and paste my 7 variable AVERAGEIFS function, I'm just going to use a two variable example here to keep things simple.
I had no trouble doing what I need with this 2 variable AVERAGEIFS function like so;
{=AVERAGEIFS(Salary,File,$A$3,JobFunction,$A$6)}
...where Salary, File and JobFunction are the names of a cells in another worksheet and $A$3 is a drop down menu that I can select the File Year and $A$6 is a drop down menu where I can select the JobFuction.
Now I would also like to have the same kind of conditional "IFS" filtering with the MEDIAN function, but I have been unable to figure it out since Excel doesn't have a MEDIANIFS function. This is what I've tried so far;
{=MEDIAN(IF(AND(File=$A$3,JobFunction=$A$6),Salary))}
but this just returns "0" which obviously means I'm doing something wrong, can anyone help me out here?
Note: I was able to get it to work with just a single variable just fine like so;
{=MEDIAN(IF(File=$A$3,Salary))}
but trying to add the second [and eventually 3rd, 4th, 5th, 6th, and 7th] conditions is the problem.
Is there a good/easy formula to use when trying to find the mean, median and mode for a column? If so, can someone post it? I'd like to make it as easy as possible (obviously!).
View 6 Replies View RelatedI have 5 numbers (can be with decimals) in column A (A1:A5). For these
numbers, I want all combinations as well as the median of these
combinations.
I'm pretty far already. However, the median seems to be calculated
wrong.
I have a list of hotel IDs in one column of my spreadsheet. In the next few columns, I have ratings that customers gave the hotel for cleanliness, location, room, etc.
What I need to do is calculate the median of all the ratings for each specific hotel, in a separate column.
An example of what I have: ...
Is there any way to do a weighted median in Excel?
Consider this example: ....
Is there a way to get median for a subtotal?
median(SUBTOTAL(1,G7:G1747)) is not working.
I have a list of ages 10-65 and then different number of participants associated with each age, ie: 10 - 5,071, 11 - 6,069, 12 - 8,465, etc. to age 65. I am try to calculate the median age of all participants.
View 9 Replies View RelatedThe following is a sample data. Col A has years, Col B has values. I want in Col C, median for each of 1 year, 2 year, 3 year. Currently I am sorting the data on Col A and then enter the Median formula in Col C for each range (1 year, 2 year etc..). What I would is to have a formula in Col C that automatically calculates the median without having to sort Col A. The formula should work if the data in Col A changes ...
View 9 Replies View RelatedI have a sheet of many rows a small sample attached. Column A list 3 races at times4.05,4.40 and 5.10...col b contains the names and col c a number for each name.
In col d from d2 to d11 in each cell I need the median number of col c for the race at 4.05...in d12 to d24 I need the median number of the race at 4.40 etc...My sheet has thousands of races..
Hi, Im using a array in Excel VBA, i got a method which looks at a element no of the array as as a return for that array, i have got it to sort the array, i just need some help to find the middle number (median) of the array.
View 6 Replies View RelatedI am trying to calculate the median difference between two dates but I am running into trouble. Here is sample data:
A B
1/1/13 2/1/13
1/2/13 2/5/13
1/4/13 1/25/13
1/7/13
1/10/13 1/18/13
I want to be able to type notes into column B such as "closed" or simply "X" (so i can keep track):
A B
1/1/13 2/1/13
1/2/13 2/5/13
1/4/13 1/25/13
1/7/13 X
1/10/13 1/18/13
I tried this:
in column c, use "datedif" function then calculate median from column C values.
problem: if left blank, value in row 4 comes up as #NUM!. if text is entered, value comes up as #VALUE!
I also tried this array: =median(abs(B5:B1-A5:A1))
Should i be trying the medianif function?
I have a nifty formula that conditionally tots lots of figures up, and conditionally tots up another set of figures up and divides them to create a percentage
=SUMIFS(INDEX(MATRIX!$S$1:$BC$5933,0,MATCH($D$2&$D$3,MATRIX!$S$1:$BC$1&
MATRIX!$S$2:$BC$2,0)),MATRIX!$N$1:$N$5933,$H12,MATRIX!$L$1:$L$5933,$D$5)
/SUMIFS(INDEX(MATRIX!$S$1:$BC$5933,0,MATCH($D$2&$D$3,MATRIX!$S$1:$BC$1&
MATRIX!$S$2:$BC$2,0)),MATRIX!$L$1:$L$5933,$D$5)
There are 4 conditions in the first part of the formula and 3 conditions in the second one. A division and a neat little percentage.
What I would like to do is add a median to this.....
Essentially I want the formula to 1. Calculate the same as above (as I need the median to be based on the percentages) and then there should be 18 figures that I would like to median
Is a nested sumif and a median possible?
