I have data (strings) which looks like this:
000000000001000
000000000392000
000000000003000
no I want to write a routine which delets all zeros from left to right untill the first "normal" number appears.
Result:
1000
392000
3000
I need to add 2 to 6 zeros to the end of string of numbers beginning in A2:
01
011
0111
0112
011901
The end result, all numbers must be 8 characters long.
I have a list of about 1,400 numbers ranging in different lengths. What I'm trying to accomplish with a formula is to remove the single letter at the end of each number (not all numbers have them) and in addition to removing all zeros at the beginning of the number (again not all numbers have them).
Here is an example...say I have the following 5 numbers:
8014554
45678456
87451245
0008014554b
0008014554c
And what I need my formula to do provide is the following results instead:
8014554
45678456
87451245
8014554
8014554
So far I have started with the following =LEFT(A1,LEN(A1)-1), but that will always remove the last character (number and letter).
I have a code which displays the values of R2, S2, T2, and U2 in one cell (J2). R2, S2 and U2 are all letters, but T2 is a 2 digit number. If there is a leading zero in T2, then in the display of J2, the leading zero is gone. so if the value of R2 is K, S2 is M, T2 is 01 and U2 is S, then I would want it to display KM01S, but it is only displaying KM1S.
View 1 Replies View RelatedI need to add zeros to the beginning of string of numbers in column A (given below), for e.g., 000029, 002562, 015096:
A
29
2562
15096
286
1
I have a summary worksheet consisting of columns that are referenced to other sheets within the same workbook.
If the cell in the 'referring' (original) sheet is blank then the forumula returns a zero instead of a blank in my summary worksheet, which is messing up some other calculations.
Is there a way to make these cells truly blank, or possibly into string variables instead, so that they do not interfere with my calculations?
I have a daily worksheet that will always have 9 columns. The end of the data contains some rows that contain all zeros. The number of rows will vary from day to day. Is there a way to specify that "if the cells in columns A:I contain a zero, delete the entire row"?
View 4 Replies View Relatedi need a macro that will select 0's in columns h-j.
View 7 Replies View Relatedwith the data in the attached sheet, I create several different pivot tables that need show the count of the information in the columns M:DU. My issue is that the data is sent to me from a third party and the columns contain zeros that cause the counts to inflate.
What I would like to be able to do is run a macro that will search out any zeros in M:DU and replace them with a blank cell.
Unfortunately the number of rows increases with every monthly reporting cycle so the macro would need to be able to accommodate for that.
Working with a scheduling report and trying ultimately to get it down to a line item report with the associate information and their earliest start and latest end for the week. Already made a lot of fixes to the formatting involving junking empty cells and trash data, but running into a road block on some of the trash data.
Here is the format of the report at this point. Names have been changed to protect the innocent.
Agent: 2366 Bacon, Kevin
Date
Start
End
[Code].....
So what I need is something that will iterate through the report...such as an while and find the cells in column A that start with "Agent:" It needs to compare that cell to a stored value to see if this "Agent:" is a repeat. If it is then it needs to delete that row and the next one and shift up. If it is not then it overwrites this "Agent:" with the previous one in the stored value and continues the while.
I know what I want to do...but not shure on the code cause I am not great at VBA.
Oh...if it matters probably need to allow for about 10k line items to iterate through...right now report is at 6k...but allow room to grow.
I’ve created a formula for this statistic and I’m happy with the results. Because I’m working with formulas, my only problem is the unwanted zeros. How do I hide zeros that show up automatically (i.e. #3 [blank] and Nov 09-June 10)? I can hide the numbers, but if I enter a zero to one of my future statistics it will not appear and I don’t want that to happen. Is there a way to hide those automatic zeros without affecting my real zeros?
Vendor’s Name
Jul 09
Aug 09
Sep 09
Oct 09
Nov 09
Dec 09
Jan 10
Feb 10
Mar 10
Apr 10
May 10
June 10
1
Vendor1
20
5
15
3
0
0
0
0
I am currently using this macro for deleting a row if a string is found:
[Code] .....
But I would like to be able to not delete that row, but also to delete the 13 row above that row, including that row too.
ROW 1
ROW 2
ROW 3
ROW 4
ROW 5
ROW 6
ROW 7
ROW 8
ROW 9
ROW 10
ROW 11
ROW 12
ROW 13
ROW 14 - NO MONEY
All this from No Money up to Row 1 will be delete, and loop.
I want a macro to look at column G and if a cell in column G does NOT contain "Test Case" anywhere in the cell then delete the row. So for example G5 might be "Test Case/Others" - I would not want this row deleted.
View 3 Replies View RelatedI have some columns in the excel file:
/path1/xyxxx/cccccc/filename12.txt
/path1/bxgdgg/gfdfacc/filenameeee8.txt
/path1/tttwrw/ccefecc/ddddd/filename56.txt
And I would like to delete everything before the LAST slash(just filenames)
filename12.txt
filenameeee8.txt
filename56.txt
I trying to search for a string in Excel and then delete that row. The code below will do that but I am also looking to delete the next row line out as well. .
Dim ws As Worksheet
Dim lRow As Long
Set ws = ThisWorkbook.Sheets("DSS")
[Code]....
VBA code to delete all rows that have the day string of Wednesday
The weekdays are in column C2:C?????
I am having trouble writing a Macro to delete multiple periods at the end of each cell. Each cell looks simiar to this: Blah Blah Blah................... I am using the InStr function to find the first period but it returns a 0 everytime. Here is the code I used to find the period. I want it to delete everything after the first period and store the value back in the same cell. Right now it just stores blanks.
Sub PeriodRemover()
Dim NewContract As String, Contract As String
Application.Calculation = xlManual
i = 2
Sheets("Product Listing by Contract").Select
Contract = Range("A" & i).Value
Do Until Contract = Empty
NewContract = Left(Contract, InStr(Contract, "."))
Range("A" & i).Value = NewContract
i = i + 1
Contract = Range("A" & i).Value
Loop
Application.Calculation = xlAutomatic
End Sub
I have fixed headers on row 16, from columns A-AC.
I want to be able to delete the entire column, if the row has a certain string, such as "Chart ID" .
I also want to expand it to include other strings such as "Month" and "Source" . So if it contains any of these words, the columns should be deleted. It should be an exact match (as other headers contain the word "month").
I am trying to delete part of a text string for a range of cells. The code I have so far deletes the first set of letters but is looking in every cell in the range.
Ideally I would like it to only look in the cells of col B where there is data then only delete the first 10 letters if the cell begins with "Service ID"
Sub DeleteServiceID()
Dim c As Range
For Each c In Range("B1:B1000")
c.Value = Right(c.Value, 10)
Next c
End Sub
I want to delete a specific words from string but i have a problem with the code below. For example, i wan to delete the word "Inc" only but the problem with my code is that it is deleting from "Incorporated" too and i want only the code to delete only if it finds the word "Inc" only.
View 11 Replies View RelatedFind part of string and delete. I have the following type of string:
View 4 Replies View RelatedI'm looking to loop through a worksheet with over 1000 columns and would like to delete columns containing a percent sign (%) in the header row which is row 4. Column range to search would begin at column 12.
View 4 Replies View RelatedI am interested in some sort of macro or formula that will strip all of the characters in a cell that come after that last space. My difficulty lies in that the string isn't a constant character count nor is the string always the same.
American Legion Post 8754 Hartford
YWCA Canton
I would like for it to say:
American Legion Post 8754
YWCA
There are probably simple solutions to these problems but I'm fairly new to Excel and i have spent far to much time trying to figure this out.
I need a macro that will delete rows that do not contain the string "QC"
Only column A is populated and "QC" is always at the start of the string followed by a space then more characters.
I would also like to delete the contents of the remaining cells (cells that do contain "QC") with the exception of the 5 characters (inc space) immediately after "QC"
For example, these 3 cells:
QC 4860 MF 25/01/08 1713 DateUtilsAH F 25Jan2008 VbV defect 4842QC 4529
Would become:
QC 4860
QC 4529
I need to write a macro that will search column A and find the word hospital or HOSPITAL and if found delete the entire row. The code I have below will do this ONLY if hospital or HOSPITAL is the only word in the cell. However in my column A there are numerous words in each cell i.e Saint Mary's Hospital.
Sub KillRows()
Dim rngNew As Range
Dim rngDelete As Range
Dim aCell As Range
Dim lastrow As Long
Set rngDelete = Nothing
Set rngNew = Worksheets("Sheet1").Range("A1", Range("A65536").End(xlUp))
rngNew.Select
For Each aCell In Selection
Select Case aCell.Value...........
I am looking for a formula to delete information from the middle of a text string. I have ~ 1,000 lines of data. Each text string is composed of the same way. The data I am looking for is two parts of the string (1) all the text up to and including the first “%” character (2) the last six characters.
Raw Data
CARDINAL HEALTH 5.5%13CARDINAL 5.513 CARDINAL HLTH 5.5 061513
UST BILL 0%09US TREAS BILL 0%09 UST BILL 0.0 092409
WORLD SAVINGS 4.125%09WORLD 4.125%09 WORLD SVGS 4.125 121509
JP MORGAN 5.375%12JP 5.375%12 JPMORGAN CHS5.375 100112
Desired Result
CARDINAL HEALTH 5.5% 061513
UST BILL 0% 092409
WORLD SAVINGS 4.125% 121509
JP MORGAN 5.375% 100112
I need A VBA that will delete a cell if it contains a specific text string
As long as the cell content is deleted, I can do the rest that needs to be done.
I have 2 columns A and B. The data is in column B.
What I'm trying to do is delete entire rows from my current selection if they do not begin with mailto:
I'm using a query that dumps information into Excel. The query automatically creates a formula in each each cell. For instance if the first value in the query showed FUNSTUFF, after dumping it into Excel, the contents of the cell would show ="FUNSTUFF". I can just use a find and replace to get rid of the leading =", but sometimes the values of the cells are supposed to have a quotation mark, so using the same method to remove the trailing quote won't work. I need a way to search each cell, check if the last character in the string is a quote, and if it is, delete it.
View 5 Replies View RelatedI have an excel file, and on some rows, the "B" column contains the text " Total:" (it does have a leading space). I would like to loop through the first 200 rows (maximum length of the file) and delete all the rows that contain " Total:" in column "B". I have tried:
For i = 1 To 200
range("B" & i).activate
If range("B" & i).value = " Total:" Then
rows(activecell.row).select
selection.delete shift:=xlUp
End If
Next i
When I step through that code, it just skips over the IF function as if B1 does not equal " Witness:"