"Masking" Out Non Alpha Characters From A String
Jul 20, 2009
I am comparing to columns of data from MS Project using Excel. In one column are the resource names for the project tasks. In addition to the names are the designations for % utilized. So the column's data will look like this:
John Jones[15%],Mary Smith, Fred Arguello[240%].
I want to compare this column with another resource names column which will never have utilization values - only the names.
In order to do that I need to "mask" the non alpha characters out of the first string.
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Apr 24, 2009
Attached spreadsheet - the cell highlighted in yellow.
This is the formula I currently have, but it isn't giving me the results I am looking for:
=IF(TYPESVC="CompanyX", COUNT(Companies!I:I), " ")
Basically, IF the Companies tab, last column has 'CompanyX' written in it - then I want to count the number of responses provided in the Q2N column.
Same formula would be copied over to the other cells to the right as well (for Q5, Q6, Q7, etc.)
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Aug 23, 2007
I have a problems here. The problems is attached in the file. I wanna extract alpha/char from a string. Example: I wanna extract the words "(M)" with the bracket from the string "Toothbrush (M)" in column A. After extracting the (M) out, I wanna do a validation to compare the (M) in column B with another data in column C, if the (M) is same as the data called "Medium" in column c, the validation will return "Match" in the column d!
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Mar 6, 2007
I have columns and rows that are populated with one of three letters: P, S, & T. At the bottom of the column and at the end of the row, i'd like to assign a numeric score to the entire column/row that is based on converting the characters to a numeric eqivelant. P = 3, S = 2 and T = 1. I'm guess a case statement would be used, but not too sure here. So, I'd need the code behind the worksheet as well as the formula(s) used for the score. I've attached an example.
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Jul 24, 2009
I am trying to capture alpha characters entered into a textbox. If a character is (something) then a variable is (something).
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Nov 3, 2009
I've got a worksheet here that i need to update every week. The problem i'm having is that i have a table of values that's drawing values in from another larger table. For example in B9 the cell is referenceing the I2 cell in another sheet. When i pull down the formula in B9 i want the cell below to reference J2 and so on. In other words, I only want the alpha characters to increment. Tried messing around with dollar signs but it doesn't seem to be doing what i want.
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Jan 7, 2010
Have a spreadsheet that contains a column of 3 digit numbers as well as 3 digit numbers with 2 trailing alpha characters.
Example:
376
377
421
376AB
376XY
377NC
421GQ
421EF
Need to sort by this column, but, with the parameter of sorting first by the numeric only, and then by numeric with alphas. So, the above list would look like this sorted properly:
376
376AB
376XY
377
377NC
421
421EF
421GQ
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Sep 19, 2012
I have a log that I need to number starting in cell A1, as follows:
A-0001
A-0002
A-0003
etc.
I've put this formula in A2 to try an increment it by 1, but it just replicates the string in A1:
=LEFT(A1,3)&MID(A1,2,5)+1&RIGHT(A1,2)
with the proper syntax?...
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Sep 27, 2011
Problem: String is broken into 2 parts within a delimeter.
Goal: To keep each String/Segment intact regardless of Alpha/Numeric.
I have a .csv file with 26 segments (commas). This file contains customer data: PO#, Order#, Carton ID, Address 1, Address 2, Address 3, etc.
I've written code to capture all 26 segments as: Input #1, Seg1, Seg2, ... ,Seg26. The variables work fine until it encounter a string with Numeric first then Alpha within the same segment.
For this example we have a string such as (...,187 Main Street, PO Box 369,...)
Seg4 = Address
Seg5 = PO Box
The Segment Variables in Input #1, get shifted when it encounters the numeric portion of the address...so the result becomes:
Segment4 = 187
Segment5 = Main Street
Segment 6 = PO Box 369.
So on my next loop when ReadLine is executed...all the variables are shifted and I can't focus on the specific segment that I need to do something to it.
It delimits when it encounters Numeric then Alpha within the string, but accepts the entire string into the variable when its Alpha then Numeric within a delimeter.
How I can keep the entire string in tact within each delimeter?
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Jan 7, 2009
I have another problem with this damn address file. Column H and I have data in them that is often mixed. As shown below, I have used A and B below, but its normaly in Column H and I. I would be greatul if some could write a macro to split the data into the two columns.
Rows 2-8 is what Im presented with. I would like them to look like 11-17
Note that the number in row 8 does not match, so is left for manual intervention....
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Aug 22, 2013
I have a string of letters in cell column L20 through L3019.
The letters are A, B, C, and R . No other letters.
I wanted to find out if it is possible to remove any duplicates when starting in cell L20 going downward.
For example:
L20 = B
L21 = A
L22 = A
L23 = B
L24 = C
L25 = C
L26 = C
L27 = C
L28 = B
L29 = R
L30 = A
L31 = C
L32 = C
L33 = C
L34 = R
L35 = R
L36 = B
L37 = B
In the range L20 through L37 all the letters have appeared so my goal is to create a formula where the outcome is BACR. Starting with the first letter B in cell L20
Cell range L20 through L37. Looking for the next letter which would be either A,C, or R. Since we already used the letter B. In this case it's the letter A
ABCR
Cell range L20 through L37. Looking for the next letter which is the C or R. In this case it's the letter C
CBRA
Finally range L20 through L37. Looking for the letter R which is in cell L29.
RACB
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Aug 8, 2009
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
If intASCIIVal >= 97 And intASCIIVal <= 122 Then
RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1)
End If
Next intLoopCounter
End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
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Sep 28, 2013
I have an index of 80,000 names from an index. Some names appear in multiple volumes and on multiple pages within a volume. While the name is the same, they are different people. The Roman numeral is the volume and the numeric is the page number.
Example of original data: Joe Shmoe V-225, 310 VIII-22, 86, 110
I have separated the data into separate columns. Now I have:
Col 1 Col 2 Col 3 Col 4 Col 5 Col 6
Joe Shmoe V-225 310 VIII-22 86 110
At this point, I want to combine the Roman numeral in Col 2 with Col 3 and 4 and combine the Roman numeral in Col 4 with Col 5 and 6.
There are way too many records for me to manually enter the Roman numeral where missing.
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Dec 22, 2013
I have the following type of info in A1,A2,A3...
Code:
nameGaryage40cityPittsburgheight190
age30height150
ameLindacityMichigan
citySan Jose
ameHarryheight180age50
My goal is to get as close as possible to this,so it will be easier to sort and manage
Code:
nameGaryage40cityPittsburgheight190
nameLindaage30cityMichiganheight150
nameHarryage50citySan Joseheight180
I can't use the "" sign as delimiter to separate them into different columns because the age,city,name and height fields are in random positions on different cells.The good thing is person's name will always come after "name" string, age is alwals followed by "age" string, so it cannot be like nameheight40Michigan180
I think the following would be the easiest method(not for me tho).If on B1 I had a formula that said "find the string "name" and write anything after it until you reach the next "" character".On C1 field I could have a formula "find the string "age" and write anything after it until you reach the next "" character.On D1 I would have the same for "height" string,then on E1 for city string.
My question is somewhat similar to this one
Extract A String Between Two Characters
Formula which outputs the data between 3rd and 4th instances of the "_" character.Can we substitute "3rd and 4th" with a specific strings like "age" or "height" ?
Code:
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",3))+1,LEN(A1)),"_",REPT(" ",LEN(A1))),LEN(A1)))
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Feb 17, 2014
i have 8 digit invoice numbers. Each 8 digit number starts with one of three 4 digit ID codes. Depending on the first 4 digits, I want a different "company" to show up.
First seems to work fine.
=IF(E6>"1NCC","North Carolina",IF(E6>"2ALA","Alabama",IF(E6>"3SCC","South Carolina")))
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Feb 24, 2014
I have variable length strings, as shown in the sample cells below
TopographyTAB_FormatSP9200
TopographyTAB_FormatSP9400
OS_DataLandline
ITNTileTabTQ2286
I want to select any record where 5th and 6th character from the right hand end of the string which = either "SP" or "TQ". Where this is the case I'm then looking to truncate the string to remove the last 7 chacters.
None of what I have so far found using mid or right string appears to be particularly applicable.
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Dec 26, 2009
I'm trying to remove everything after a specific character in a string.
I.e. change a website address to the hostname
http://www.excelforum.com/newthread.php
http://usa.excelforum.com/forum/new
to
excelforum.com
usa.excelforum.com
I'm using this formula, which strips the http:// and the www., but does not replace the characters after the first remaining "/" as the wildcard is not recognized.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A2,"www.",""), A2,"http://",""), A2, "/*", "")
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Feb 11, 2009
Replace characters in a string. I have this macro:
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Feb 21, 2010
I'm importing data from the internet. The cell I'm trying to get is B8 on "Temp_Data" onto cell E3 on "Other Data". When it imports the cell into Temp_Data for some reason the cell expands, and I can't have that. I would manually copy and "Paste Special", text, into the proper cell, and that works. I can also copy the fist 7 letters in the string from B8 and paste them into E3. My code currently looks like this:
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Aug 21, 2012
I'm having difficulty figuring out how i can Trim the last 3 characters from this string
Code:
FeatureCode1 = Split(errorChecker.lstErrorMessage.List(0), " [")(0))
I tried
Code:
FeatureCode1 = Left(Split(errorChecker.lstErrorMessage.List(0), " [")(0)), 3)
But that only SHOWS the last 3 characters... how i can just cut off the last 3 characters?
I'm guessing something to do with TRIM, but not sure how to implement it?
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Dec 30, 2008
I am trying to count the characters in a string in one cell. For example, I want to count the number of "-"'s in the cell. The version number of part numbers is always the last two characters if the value contains at least one "-". However the parts have a non standard number of characters.
444444 = 0
444-44 = 1
44-44-44 = 2
There can be 0,1 or 2 "-" in the string. I can use the substitute formula to get the root part number, but I was wondering if there is an easier way. The raw data is from our ERP system, so I multiply the value by 1 to get a number if there are no "-" for the vlookup in another formula to work....
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Dec 22, 2009
Is it possible to format a character in a string using vba?
For example if i had a string of GGGFF, and i wanted to make the G's appear as Green font and the F's as Red font.
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Nov 16, 2006
I have a string like: AAJDGYE030000460. How can I remove the first character in a macro? I need to look at the second,third, and forth character
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Dec 21, 2006
I have a set of data in column a that consists of email addresses. These email addresses all have underscores after them, ie "abc@hotmail.com_______". It will be a different amount of underscores everytime and I don't want underscores to be removed that are actually part of the address. I had been using the find replace function through vba, ie
Range("A:A").Select
Selection.Replace What:="_", Replacement:="", LookAt:=xlPart, _
SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _
ReplaceFormat:=False
however this ofcourse removes from actual parts of the email address. Is there a way to do this?
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Apr 11, 2007
I have a string, specifically a file path, and I want to take the last 5 characters of the string. How would I got about doing this?
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Jan 22, 2008
I've come across multiple times where I have to do this same sort of task, and I don't think I am doing it the most efficient way.
What I need to do is take a variable which holds a string and remove the last 9 characters from it. Don't need to know what the last 9 characters are, all I care about is knowing what the other characters are in the string. I know this can be done through thingslike susbstrings, but I don't think VBA has a substring function.
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Oct 24, 2012
I want to get only unique characters in a text. For ex. ozgrid.com. I should get ozgrid.cm (o is already came). another one. For ABCEABC the result will be ABCE. So I have written an UDF. Unfortunately there was "Argument is not optional" error in "UNIQUECHARS = Join(JoinT.Item)".
How could I get rid from this error and get my result?
Below is my code.
VB:
Public Function UNIQUECHARS(chtxt As String)
Dim c() As Variant
Dim JoinT As New Collection
Dim sp As String
cchtxt = Application.WorksheetFunction.Substitute(chtxt, " ", "")
[Code] ......
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Aug 2, 2006
I am trying to remove all characters that aren't letters or numbers from a string. Is there any way to differentiate between a non-alphanumeric characters and alphanumeric characters? I'm thinking of something like "ISTEXT()" that I could use on one character at a time. Or are there any wildcards I could use in the Replace function?
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Dec 23, 2008
I'm using Excel 2007. I want to write a formula that will list all characters in a string to the left of a "-". See below example. What formula would I use?.......
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Jul 11, 2014
Is it possible to find the location of different characters in a string (using VBA)? Normally I would use InStr of InStrRev option in VBA but my situation is a little more complicated.
The character I am looking for is not always the same, sometimes it is a , or a . or a : or a "blank" etc
I tried to do it like:
dim strChar as string
strChar = "[,.? /]"
SearchPosition = InStr ("cell location", strChar) (searchposition is the name of the function I am trying to make)
This works if I define only 1 character, this way it gives me a 0 as outcome
I have tried to change it to strChar = "[,]" or strChar = "[.]" or strChar = "[ ]" but this doesn't work.
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