I'm trying to use match function to find the max value that is less than a given value. look at my file. I think it should return F as the value, why is it returning G?
View 11 RepliesI am having some trouble getting a formula to work. I am building a report that pulls figures from a pivot table in another workbook. I am using a vlookup with match function to get the column index to find the relevant data I want. Where I need to add two columns together I am using sum, with the vlookup & match formulas nested in them e.g.:
=SUM(VLOOKUP(F13,'[PIVOT 156.xlsx]PIVOT'!$C:$AQ,MATCH("FAID",'[PIVOT 156.xlsx]PIVOT'!$C$6:$AQ$6,0),FALSE),VLOOKUP(F13,'[PIVOT 156.xlsx]PIVOT'!$C:$AQ,MATCH("COMM",'[PIVOT 156.xlsx]PIVOT'!$C$6:$AQ$6,0),FALSE),VLOOKUP(F13,'[PIVOT 156.xlsx]PIVOT'!$C:$AQ,MATCH("BPCM",'[PIVOT 156.xlsx]PIVOT'!$C$6:$AQ$6,0),FALSE),VLOOKUP(F13,'[PIVOT 156.xlsx]PIVOT'!$C:$AQ,MATCH("COMD",'[PIVOT 156.xlsx]PIVOT'!$C$6:$AQ$6,0),FALSE))
Where:
F13 = Employee number
Column C on the pivot 156 workbook is where the employee number is based.
The Match formula is then getting the column index from the column headings of the pivot table ie. "FAID"
This in itself works fine, as long as it finds a match in the column headings. This is where i get the error as in the above function "COMD" is not in the pivot table. However I need to keep it included as it may appear on a future pivot table. Is there a way of getting the sum function to complete even though later in the formula it can't complete the vlookup? So it will ignore it, or assume the value is zero if it can't find it? The formula probably needs to do this for all the vlookups as some headings may drop off in future pivot tables.
I am trying to match data from 2 independent sets, formatted slightly differently so not sure which function would work best for me. From the attached file, I am trying to match the date and time stamp (in cell A1) with that from the other data (in this example in cell E1) and return the data (from cell F1) to cell C1. So basically any date and time stamp before 04/03/09 04:00 will return a value of 44 (this value should appear, therefore in cells C1 - C30)
View 2 Replies View RelatedBasically where the columns say 2011 or 2012 AND 1, 2, 3. I want to be able to have it index the number below based on the GL number on the left and both the year and period on the top. I think that you can do with using the sumproduct function with the binary, but the computer is a little dated and it takes a while to run those calculations.
2011
2011
2011
2012
2012
2012
[code].....
Another interesting dilemma to solve. Using this formula:
View 2 Replies View Relatedlet me start by saying that I know an example workbook would be useful here, but the part I'm struggling with is the [managementroster.xlsm] file, and there is A. no way I can release it to the internets and B. its so huge/complicated I couldn't even begin to reproduce a portion of it, scrubbed of data, and hope to maintain its functionality in a meaningful manner.
[Code]....
This formula checks a staff number on this spreadsheet, and then goes and looks at the staff number on the roster. Once found, it returns that staff members roster, but changes any manager codes in the MRC list to Mgr, and changes all other roster codes to Free.
I now need this formula, before altering roster codes to Mgr or Free, to only return codes that are a match for another table (or after really. I don't particularly care, so long as only codes are shown that match data from another table). I think an index/match function would do the trick, but this forumula is already at the edge of my excel ability, nesting another function within it is completey beyond me. The relevant cells for the index/match function would be:
This first Match function targets the column. $E3 is the date required, $BA$1:$DN$1 is the range the dates are entered in
Match: Lookup value = $E3
Lookup array = '[ManagementRoster.xlsm]Vacancies!'$BA$1:$DN$1
match type = 0
This second Match function targets the row. $A$4 is the department name, $B$434:$B$452 is the range where all departments are entered
Match: Lookup value = $A$4
Lookup Array = '[ManagementRoster.xlsm]Vacancies!'$B$434:$B$452
match type = 0
Index: array = $BA$434:$DN$452
So I think my final function is
[Code] .....
But I have absolutely NO idea where it would fit within my first formula, or how to code it so that my original formula only reproduces results that are found in both sheets, or anything.
=MATCH(9.999999E+307,B12:Y12)-1
=MATCH(9.999999E+307,B18:Y18)-1
So what is this pulling and how does it change depending on the data?
I'm using the match function to tell me in which column the first positive/non-zero number appears. However, the formula is returning the # of columns in the range. Here is what I'm using:
=MATCH(1,H6:CA6,TRUE)
I'm getting 72 back as a result, which is the number of columns between column H and CA.
Any ideas why this is the case?
I have the below code sent in by a MR Excel forum user
Public Function BigMatch(rngIndexColumn As Range, varMatchValue As Variant, rngMatchRange As Range) As Variant
Dim lngCol As Long
Dim rngCell As Range
lngCol = rngIndexColumn.Column
For Each rngCell In rngMatchRange
If rngCell.Value = varMatchValue Then
BigMatch = Cells(rngCell.Row, lngCol).Value
End If
Next rngCell
End Function
when using the BigMatch Function = BigMatch(any cell in the column you want to pull from, the value you want to match, where you want to find that value)
I am using 2 different sheets, Technology & Lessons learnt: when I try the BigMatch Function
=BigMatch(Technology!C17,'Lessons Learnt'!A46,Technology!W17:AD27)
Instead of returning 'Technology'!C17 its returning the value from Lessons Learnt C17,
I have a very long function I created. But I need to edit it in a matter I have never done before.
Below is my function and i will like to add a new condition to it.
IF the text value in cell C7 is equal to any text value in Workbook2 B10:K10 and the value underneath that cell (I.e if B10 then B11 etc..) is Deleted then I want to have one of the conditions of my function below display "Deleted".
=+IF(AND(E7<=0,J7<>0,Y7<=0,AO7<=30),"Check Inventory",IF(AND(E7<=0,J7<>0,Y7<=0,AO7>=60),"Delete Listing ",""))
Using the address function to find the exact cell of a unique string text.
I'm using the following command to find the address of a string i have in a different cell.
=ADDRESS(MATCH("*$H$1*",A:A,0),1)
The string text is in cell H1, H2, H3.......(or on another sheet). The goal is to find the address of a cell containing the unique string text from cell H1, H2, H3.....(that entire column) in a sheet with 13,000 lines. Basically, searching for a specific cell address of a string text referenced from another cell.
=IF(ISNA(INDEX($D$3:$D$100,MATCH(G19,IF($C$3:$C$100="DF",$A$3:$A$100),0)),"",(INDEX($D$3:$D$100,MATC H(G19,IF($C$3:$C$100="DF",$A$3:$A$100),0)))
what i'm trying to do is to replace #N/A with blank. Taken the above from vlookup examples but does not seems to work.
MATCH("b",{"a","b","c","b"},0) returns 2
how about if I would like to have the return result as 4 since I have another "b" within that same array?
is there anyones know what's the meaning of 1 in this formula
MATCH(1,('Data Issues'!$A2=Sheet1!$A$2:$A$68)*('Data Issues'!B2=Sheet1!$B$2:$B$68),0)
In Sheet 2 i have a 1000 of data contains the birth date of following customers
The result i want in Sheet 1 is
particular on todays (Say on 27-11-2008) date how many customer are having birthday, supoose there 10, or 8 wahtever should show me the list.
I tried this formula
=INDEX(Sheet2!$B:B,MATCH($B$3,Sheet2!$H:$H,0))
but by this formula it only show one customers birthdate what i want if there 10 differenrt customer those same birthdate it should display all the 10 date and name in diff rows
I'm trying to create a formula that would return the value of the column next to it. Looking at the below example, in a new cell I would want to be able to return the value 7 based on the fact that it is in category b.
I would think an if/offset/match function would do this but I can't seem to figure it out as it may require nesting.
categoryvalue
a1
a2
a3
a4
a5
a6
b7
I have one column full of duplicate names, column A. I have another 2 columns's E & F which contain the unique number and corresponding name to that number. I want to create a formula which i can put in column B which will match every name in A to the name in F but will enter the value as the unique number.
ie
A1 will contain Joe. E1 = 1 F1 =Joe. When I enter the formula in B1 it will show as 1. How would I write this as a formula?
I have a column of values (text) to choose from. I need to randomly assign them to names.
There are more values then names.
Each name has to have a value.
Each value has to be used only one time.
Not every value has to be used.
Column B contains names, column Q contains values.
Now. So far I've come up with below:
Code:
Sub randomize()
Dim Random As Integer[code].....
"Random" returns exactly the amount of values in column Q, so this works ok.
"i" counts iterations correctly, meaning as many times as names in column B.
I tried useing Match to rule out already used value but this code returns "unable to get Match property of the WorksheetFunction class" error.
I've been working on a payroll program for my small biz. I'm close to done BUT...When I use the Index Match function in a cell it works great. However I need to copy it down a column to work for pay periods going forward. When I copy it down of course it puts zeros or N/A.
Columns:
Gross Fed FICA Medicare State Net
F G H I J K
Gross is user input. FICA Medicare State and Net are simply calculated on the sheet. But to get Fed Income tax I use the Index Match function and it works perfectly. The rows increment properly with each new user input.
My question: Fed Income tax is dependent on what the Gross is in order to look up the tables with the Index Match function. How do I get the result of the function into column G? Can I increment up Column G and ignore the zeros that dragging the function down G creates?
I have a variable called LU which I am trying to use to do a match function in a macro.
OwnerOldRow = Application.WorksheetFunction.Match("C" & LU, "Owners1!$A2:$A65")
What I am hoping to do is find the row associated with column C and row value from LU. I have a stop on the line and LU is properly valued but it won't do the match. Is my syntax wrong. I am leaving the match type blank as it defaults to 1 which is the value I want anyway.
its says unable to get the match property
Me.doj.Value = Application.WorksheetFunction.index("A4:H574", Application.WorksheetFunction.Match("A4:A574", Me.id.Value, 0), 6)
I have column A with 1000 cells tall with a bunch of random whole numbers from 1-100. In cell B1 I enter the formula:
=MATCH(25,A1:A1000,0)
This goes through the data and outputs the location of the first instance of "25". However my data has 8 instances of "25", and I want to know all of them. So basically in B2, B3, B4, ... I want to enter:
=MATCHsecond(25,A1:A1000,0)
=MATCHthird(25,A1:A1000,0)
=MATCHfourth(25,A1:A1000,0)
...
Obviously MATCHsecond isn't a real function, but that should explain what I'm looking for.
On sheet1, I have numbers and names. These names are also contained in Comments on sheet2, and i would like a function in Column M that matches the numbers with the names in the comments. Cell M1 I have manually filled for demonstration purposes.
Can this be done with a function or is this a VBA task?
I have the following equation programed in Excel, (see file attached). I do not understand while the match funstion is not working the lookup value is the on in cell N1 the array is from B1:F1. The return value should be 3 but I get #NA instead at the begining I was thinking that the values were different but then I compared cell =D1=N1 and the result was TRUE, meaning that they are equal
View 4 Replies View RelatedI have attached an extract from a Conveyor drum design document.
Cell E7 contains a relatively simple formula to extract data from the supplied table. I have tried time and again to make this work, but the best i can come up with is the formula shown, which returns an incorrect value.
I am having many difficulties getting conditional formatting using the match function to work correctly in my excel document.
What I would like to accomplish is as follows in the 3Q09 tab. If a subdivision name is found in C-62 through C-70 and a match is found for the subdivision name in AB-24 to AB-66 I would like it so the AB-24 to AB-66 Subdivision name is bolded for every match. I removed the function formulas from the 3q09 tab I used to have since they didnt work and I do not want to confuse anyone.
This is correctly done on the "Working Correctly" Tab included in the same file, so please view this for clarification if you need it. Why it works on one tab and not the other simply baffles me.
Been trying to figure out whats wrong with my formula. The 4th column doesn't seem to produce the intended result. I have attached here for reference.
View 4 Replies View RelatedI have multiple sheets within one Excel file. Each sheet is structured the same way. Column B lists Client's last names, which differ from sheet to sheet, though some clients may be repeated in several tabs. I have a column K which displays either the number 1 or 0. This is consistent between sheets.
I have created a formula that will look at the last name in a specific cell in column B of sheet 2 (FY 07) and search sheet 1 (FY 06) column B for the same last name.
=IF(MATCH($B5,'FY 06'!$B$5:$B$24,0),1,0)
If the same last name exists and if column K of sheet 2 and sheet 1 display a "1", I want it to place a 0 in the formula cell.
So, if there is a client that is in both sheets and has a "1" in both columns K of each sheet, I want the formula to let me know.
I am trying to write a formula that says if a name is in a column of names put a 1 otherwise put 0. Should be a simple If, match function. I have attached a simple example.....
View 5 Replies View RelatedI would like to have an Index & match function in my userform.
I know that i must use it like this Application.WorksheetFunction but i am not able to do it.
User select a code and then in next text boxes, description and price should appear.