Mismatch Errors With Variables In Functions

Jul 24, 2013

I have set variable A and B up as integers

When I input the variables into the function

Code:
Rows(A:B).EntireRow.Hidden = True

I get a mistmatch error. I've used a MsgBox to confirm that both variables are indeed returning integers.

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String Functions Errors While Trying To Late Bind

Dec 7, 2006

I’m developing an application that will be distributed amongst several clients all running different versions of Excel.

I am trying to employ Late Binding, but am runing into an issue with some string functions (like Mid, Right and UCase) and am getting a ‘Can’t find project or library’ error.

These functions work as expected in a blank project.

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Using Variables In Macro Functions?

Jun 27, 2014

My goal is to write an equation that allows me to total all of the numbers in a column until the value = 0.

When I write the following equation using actual cell references, I am able to get the results I am looking for:

=IF(LEFT($E$78,6)=" Expe",SUM($J$78:INDEX($J$78:J1000,MATCH(0,J78:J1000,),0)),0)

When I try to write it in a macro using variables, I get all messed up:

Selection.Offset(1, 0).Select
Selection.Font.Italic = True
ActiveCell.FormulaR1C1 = " Expense"

[Code].....

(Possibly unnecessary information: This is for a budget spreadsheet I am creating. Ideally when I am finished with the macro it will allow me to add a line item under a specific program and update the total amount spent. The budget is broken out by month, rather than program. When a new program begins the amount in column J will always be zero, hence the Sum until 0 is reached.)

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Passing Array Variables In Functions?

Sep 15, 2012

What I am trying to do is to automatically build a "tree" diagram representing the links in a huge model which is dynamically configured. What I have a problem with is the following:

The tree consists of layers, I start off with the top layer and for each entry in the top layer I can add all its subsidiary layers and draw links between them, this uses a function which takes as its arguments the node name and its layer number (how far down the tree it is) and the number of items in that layer so far.

So I start at the first item in Layer 1 and there are as yet no layers below it. I start at the first one and add the first item in layer 2 then I kick the function off again and that adds the first item connected to item 1 in layer 2 in the layer below (3) starting at the first one, and so on. When I reach the bottom I go up one layer and add the second item in the bottom layer and so on. When I have added all the connctions to the first item in the next to bottom layer I go up one layer and add the second item connected to the first item in that layer and then add all the items connected to it and so on and so on.

In this way I build up the network exhaustively (to make things more complex more than one item in a layer may connect to the same item in the layer below).

I can do almost all that, the issue I am struggling with is I need to keep track of how many items there are in each layer (as some layer 1 items connect to 1, 2, 3 ...8 layer 2 items and so on). my idea is to keep a running total of these in an array LevelCount(1), LevelCount(2) etc. so when I add a new item to a layer I know where to put it. However I cant workout how to do this final step.

Currently I have a function that draws the nodes below a specified node this and takes the correct value from the array LevelCount(n) by passing Levelcount(n) (where n represents how far down the tree you are) into the function and the function then updates the value of LevelCount(n) (ByRef) so that next time I use it it is correct. That is fine but what I want to do is to is to call the same function from within itself when it adds each node which would make it work automatically - it would keep calling instances of the function until it reached bottom and then go back one step at a time to the top but I cant work out how to reference the right value in the array to pass into the second (and subsequent) instances of the function.

I don't think I can simply pass (n) into the function and in the body of the function set LevelCount(n) = LevelCount(n)+1

I also dont know ahead of time how many layers the model will have, nor can I tell which layer a node sits in as it depends on the links that are dynamically configured.

Beyond this a node can also be subsidiary to nodes in more than one level so it needs to sit at the lowest level - but I suspect if I can work out how to do the first bit i can do this too.

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Syntax For Using Variables Within VBA Formula Functions?

Dec 3, 2003

correctly using variables within functions used in formulas specified by VBA. Here's an example:

I want to place a formula within a workbook file called "Books 2003.xls" that goes to the version of the file for the previous year (or whatever year is specified) and does a Sum of a particular range (where that range is also specified as a variable) so it sums up the Total for the previous year for the same number of months that have data in them to date for the current year. Once VBA places the formula where it belongs, it should be able to always provide a running comparisson with the current year to date total and the totals for the same period for the previous year. Here's an example of the intent of this simple formula:

ActiveCell.FormulaR1C1 = "=SUM('[Books 2002.xls]Income Summary'!R4C2:R8C2)"

The workbook files will all be named the same way: Books 2002.xls, Books 2003.xls etc.... The range to be summed will always start at R4C2, but could then end anywhere from R4C2 (same as B4) up to R15C2 (same as B15).

I already have a routine that captures the value for the variable CurrentYear in the form "2003" and thus have another variable for PrevYear (= CurrentYear -1), and so then have a way to correctly specify the variable "BookName" to get the correct filename needed. I also have a variable for the CurrentMonth in the form of "1 through 12", and can use that to specifiy the correct RowNum needed to determine the end of the range (RowNum = CurrentMonth + 3).

I've tried to substitute the variables "BookName" and "RowNum" into the above formula with various combinations such as what follows, but I'm not getting the correct syntax with the right number of quotes etc...:

ActiveCell.FormulaR1C1 = ""=SUM('[" & BookName & "]Income Summary'!R4C2:R" & RowNum & "C2)""

This doesn't work, and I'd love to learn the correct rules for syntax when inserting variables into situations like this.

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Type Mismatch Error Message Comparing Value To Cell Error "Type Mismatch"

Nov 4, 2006

I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:

- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)

- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)

Etc.

The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the

Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............

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Unzip Code - Works Without Variables, Breaks With Variables...

Feb 5, 2009

Unzip Code - Works without Variables, Breaks with Variables.... This has been driving me bananas...

I have the

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Functions Compared With VBA Functions

Mar 14, 2008

I am aware of the following topic in the VBA Help file:

"Using Microsoft Excel Worksheet Functions in Visual Basic
You can use most Microsoft Excel worksheet functions in your Visual Basic statements. To see a list of the worksheet functions you can use, see List of Worksheet Functions Available to Visual Basic.

Note Some worksheet functions aren’t useful in Visual Basic. For example, the Concatenate function isn’t needed because in Visual Basic you can use the & operator to join multiple text values."

And I'm aware of how to call Excel funcitons from within VBA; e.g., answer = Application.WorksheetFunction.Min(myRange)

However, not only are some Excel functions not useful; the fact is they cannot be used because VBA has a native function that does exactly the same thing and you have to use that native VBA function to achieve your goal. It is these overlapping functions that I am especially interested in. I want to know what I should use directly in VBA and what I need to go to Excel for.

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Function Back Variables: Function Give Two Or More Output Variables

Jul 27, 2006

Can a Function give two or more output variables. e.g.

Sub a()
x = 5
result = Y(x)
End Sub

Function Y (x As Integer) As Integer
Dim B
B = ... * x
Y = ... * B

this will give back Y as a result. But if I want to get 2 or more output variables (let's say I need to get also B into sub) from one function, how should I do that?
I need this because function works with large matrix and I want to extract some values appeared in between.

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VBA Type Mismatch

Aug 21, 2014

I am getting a type mismatch with the following:

HTML Code: 

Private Sub Export2Pdf()
Dim sFileName As String
'Create file name
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")

[Code] ........

something to do with this:

HTML Code: 

sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")

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Type Mismatch

Feb 14, 2009

I have used this code previously and it worked however I now get a type mismatch error in the line coloured red..

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Type Mismatch IF Statement?

Feb 24, 2014

The line I first used was:

var all_spans = document.getElementsByTagName( 'SPAN' );
for( var i =0,skip =0 ; i [code].....

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Error 13,Type Mismatch

Jul 1, 2009

I am getting error Type mismatch error the moment i enter value in Cell T54 and CLICK "DAILY" on Daily button.Waiting for the solution.

I am attaching the file.

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Type Mismatch For RowSource

Aug 25, 2009

I have four columns of data and 25 rows (A1:D25). I wish to add this to a multi-column list box in my user form. My userform is called FundSelect, and my listbox is called FundList. The ColumnCount property is set to 4. When I use the command:

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Type Mismatch Error 13

Feb 8, 2010

I'm trying to write a pretty simple macro which invokes a built-in DDE function to retrieve some data, then when the data is retrieved, just show a msgbox. When the data is finished being retrieved, cell(20,11) in the sheet "Historical Data" will automatically have "FINISHED" placed in it. So while the retrieval is taking place, I'm simply looping and checking the contents of this cell waiting for it to read "FINISHED". My problem is the 'Do While Sheets("Historical Data").Cells(20, 11) <> "FINISHED"' line generates a "Type Mismatch Runtime Error 13", which I can't for the life of me understand why.

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While Loop With Type Mismatch?

Mar 23, 2012

I have a while loop that counts backwards in a seriescollection to find the last value with data. In one particular case, I had to use an IF formula in the source data where it would output NA() if the statment was false, so instead of loop through empty strings until the loop finds a number, it loops through #NA until it finds a number.

This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.

Code:
Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long

[Code]....

(P.S. why I would have "NA" as an output, its because it won't graph, where putting "" for my false condition did)

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Getting Type Mismatch Error

Jan 16, 2013

I am using this code:

Code:
With wshvar
.Range("A16") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) - 1)
.Range("A18") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) + 1)
End With

but receiving a 'Type mismatch' error with the highlighted code.

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Find Value - Type Mismatch

Feb 23, 2013

I tried to find value on the other workbook. Gives me error "Type mismatch"

Below is the code in my VBA project

Code:
Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub

[Code] .......

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Type Mismatch From VBA .Find

Jan 16, 2007

This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch
dim c as Range
...
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
MatchCase:=False)
ActiveCell is a single cell on an unhidden sheet - cell A279.

I can Control-F at this point in Excel, and it finds "LIQ" just fine.

Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.

Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)

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Type Mismatch Error When The Value Is Zero In VBA

Feb 19, 2007

I have a piece of VBA code that acts weird. For brevity I am doing a function call like this:

val=MyFunc( [D1] )

and

Function MyFunc(mean As Double)

D1 is a named range which is a single cell. It contains a double.
The problem occurs when the value is zero, I get a type mismatch on the function call. If it is non-zero all is well.

What would cause this? I could see if zero was invalid inside MyFunc() that some calculation might blow, but it nevers gets into the function. Looks like the compiler is stopping it.

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2007 Type Mismatch

May 18, 2007

Range("C1:C" & x).Value = WorksheetFunction.Transpose(Result)
I'm trying to run it in 2007. It works in earlier versions.

I get Type Mismatch error. Result is dimmed as variant type.

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Run Time 13 Type Mismatch

Dec 14, 2008

I have some code which i trialled in a blank workbook and was fine. when i pasted it into the workbook i am working on, i get runtime error 13 type mismatch.

Sub Trackj()
Dim a As Long
For a = 1 To Sheets.Count
If InStr("master", Worksheets(a).Name) < 1 Then
Worksheets(a).Cells(40, 6).NumberFormat = "hh:mm"
Worksheets(a).Cells(41, 6).NumberFormat = "hh:mm"
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(40, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("B52:B80").PasteSpecial (xlPasteValues)
End If
If Hour(Worksheets(a).Cells(41, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(41, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("D52:D80").PasteSpecial (xlPasteValues)
End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:

If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then

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Jan 9, 2009

what i know what's actually type mismatch and how do i solve it?

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Jul 24, 2009

When my macro runs through the above code, I get a type mismatch error. All of the cells are formatted at Date only.

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Dec 5, 2009

In cells BS8 I have the following =100*SUBSTITUTE(BR16,"metres","") to get centremetres from cell BR8 and in cell BT8 I have the following

=IF(BS8,ROUND('Under 6 Boys'!D11*(BS8-'Under 6 Boys'!E11)^'Under 6 Boys'!F11,0),"") I get a #Value error

I have also tried
=ROUND('Under 6 Boys'!D11*(BS8-'Under 6 Boys'!E11)^'Under 6 Boys'!F11,0)
In BT8 but I get same error

I have used it in another sheetsheet and it works I don’t understand why is is happening ...

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#n/a Errors

Jul 4, 2008

I am using a combination of validation, vlookup and simple formulas to lay out a workorder. If I leave something blank in one of the feilds then everything that comes after say #n/a and won't allow the calculation to complete. Is there a way I can set a default value or something so to make calculate all the feilds that ARE filled in?

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Defining Variables Using Variables

Apr 27, 2006

I'm trying to loop through a range in excel from access, checking where the titles (in Excel row 1) match with the fields (in a recordset in Access that is passed to the function) - and where they do, I want to dimension a variable to hold the column number - I'm not sure it's possible, but I'd be interested to know either way. The line I'm asking about is at the bottom of the code - the rest of the code is just to give context...

Sub ImportGeneric(rsImported As ADODB.Recordset, rsConfirmed As ADODB.Recordset)
Dim fd As FileDialog
Dim xl As New Excel.Application
Dim wb As Excel.Workbook
Dim ws As Worksheet
Dim iFilePicked As Integer
Dim strFilePath As String
fd.Filters.clear
fd.Filters.Add "Excel files", "*.xls"
fd.ButtonName = "Select"
iFilePicked = fd.Show
If iFilePicked = -1 Then
strFilePath = fd.SelectedItems(1)
Else ..................

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Architecture Mismatch Between Driver And Application

Feb 16, 2012

Last week I was having no problem accessing the company's Database using Excel 2010. Thursday, my computer was replaced during an upgrade to Microsoft 7. Now, I am getting this Microsoft [ODBC Driver Mismatch] error. The exact message is:

[Microsoft][ODBC Driver Manager] The specified DSN contains an architecture mismatch between the Driver and Application.

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Run Time Error - Type Mismatch?

May 16, 2014

When I run the following code I get a (Run-Time error '13': Type mismatch). When I click debug it highlights line 41

[Code].....

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Basic Syntax / Type Mismatch

Jul 15, 2014

I am trying to accomplish the following: iterate through rows of a selection, delete row if the first column cell is empty or the second column cell equals 0.

So far I have:

[Code] ........

I am getting a type mismatch error at my if statement.

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