Numeric String Manipulation Query

Dec 23, 2009

I have a sizable spreadsheet, which has one column where the cells are mostly numeric strings of up to 6 numbers - there are variations, which I will mention.

What I need to do, is to treat the numbers as individual figures, and add them, then divide by the number of figures. e.g. cell value '123456' I need to process as (1+2+3+4+5+6)/6.

The variations are that '0' has to be added as 10, and any letters need to be added as 12. '-' and '/' which are the only non-alphanumeric values should be ignored.

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VBA String Manipulation

Sep 1, 2009

I need to be able to take someones name which is in a single cell in the format "First Middle Last" (could be more than one middle name) and then split it up so that it fits the following format:

Last name (must be 50 characters)
Middle name (must be 15 characters)
First Name (must be 15 characters)

I'm unsure on the right combination of operators to use to variably concatenate strings in this way. I'm confident I can figure out how to add the white spaces after a name to make it fit the character requirement but I don't know how to split the initial name up into it's 3 parts. Names longer than the character requirement will just be truncated.

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Jul 23, 2009

I have a macro that loops through a column of text and removes all text after a hyphen. Example: AU9929-PK becomes AU9929. I need to set up some exceptions that when it processes certain text it does not truncate it. Example: AU9929-ASST stays as AU9929-ASST. So far there are twelve exceptions but this could increase.

Note: The list which includes shop number, description, sku, sku description, quantity, unit price and more is sorted in a particular order as other operations are performed on it that requires it be in a specific order.

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Aug 1, 2008

I am trying to let the user call my subroutine in the following 5 ways but am lost using string manipulation -

Call FindReplaceAll(“C”, “123”, “1.23”) ‘ In Col C replace 123 with 1.23
Call FindReplaceAll(“2”, “123”, “1.23”) ‘ In Row 2 replace 123 with 1.23

Call FindReplaceAll(“C:E”, “123”, “1.23”) ‘In Col C-E replace 123 with 1.23
Call FindReplaceAll(“2:4”, “123”, “1.23”) ‘In Rows 2-4 replace 123 with 1.23

Call FindReplaceAll(“C9:E19”, “123”, “1.23”) ‘In region C9-E9 replace 123 with 1.23

Here is what I am trying to do in psudo
Sub FindReplaceAll(sType As String, sFind As String, sReplace As String)
If sType does not have a colon in it then
If sType = “A-IV” or sType = “a-iv” only then
Columns(sType &”:”& sType).Select
If sType = “1-65000” then
Rows(sType &”:”& sType).Select
Else

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Dec 5, 2008

i have a worksheet called 'week 1' and want to write vba code so that a new sheet called 'week 2' can be created. However i want to write code so that it doesn't matter what sheet i am on, a new sheet would be created with the name week and the next number up. ie. the last worksheet is 'week 7' then the code should be able to create a new worksheet called 'week 8' ect. I currently have this code but it keeps returning an error message. anyone know how i could do this???

Sub nSheet()
Dim nm, i As Long
nm = Worksheets(Worksheets.Count).name
i = 1
Sheets.Add
Do While WorksheetExists(Left(nm, Len(nm) - 1) & i)
i = i + 1
Loop
ActiveSheet.name = Left(nm, Len(nm) - 1) & i
End Sub

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Oct 22, 2009

I am trying to do is extract the volume size of products in 'ml'
from 10k plus products from a description field cell.
this description field could also contain the weight of the product in grams
so I cannot just do a search for a numeric string ,
it has to be associated with the milli-litres statement .

is is possible to do a sort of ' *ml ' search and then select and copy to another cell ???

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Dec 6, 2006

I am trying to slim down my database results in Excel via MS Query by searching for Part ID's that are numeric (we have parts that also contain letters....I want to weed those out).

In all my searching on the web, I thought the ISNUMERIC() function should be the function for this, but I keep getting an ORA-00904::"ISNUMERIC":invalid identifier....

Is this function supposed to work or is there another function that will do this

This is my SQL statement so far, which works to get parts that are 6 characters long only:

SELECT PART.ID
FROM SYSADM.PART PART
WHERE (LENGTH(PART.ID)=6)
When I change it to this to get parts that are numeric, it gives the error above:

SELECT PART.ID
FROM SYSADM.PART PART
WHERE (LENGTH(PART.ID)=6) AND (ISNUMERIC(PART.ID)=1)

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Aug 6, 2014

Given 5 rows in column A, I have strings that has the word 'Qty' and some none. For any string that has the word 'Qty', I want the numeric value before it. For string that doesn't have the word 'Qty', I want it to be 1. My question is, how should I added the numeric string without a helper column?

Column A
Desired Qty to Take

some string name and ended with (4 Qty)
4

some string name without the word Qty
1

[code]....

In the above example, I would like to have an answer in say cell B1 to be 15

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Oct 1, 2008

I am trying to create what should be a unique string.

I figured the easiest way to do this would be to use the value given by Now().

However I can't find out how to actually get the result of Now() as a number.

If on a spreadsheet I put in a cell: =Now() and then format that cell as 'General' it gives me the number I am trying to get programatically.

I tried:

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Apr 22, 2009

IDMacro Out Put
X11891189
cdecde
CONFRCONFR
175175
D0101101

I ahve a sheet having two column one is "ID" and other is "Macro Out Put" as shown above , is that possible with VBA code that it give the same result as i shown above in column "Macro Out Put". for reference i also attch the file

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Feb 3, 2006

say I have a string that looks like this

C:Documents and Settingsme[test 2-2006.xls]Sheet1

I want to extract the DATE prior to .xls. I can get to this:
C:Documents and Settingsme[test 2-2006

It is possible that the filename would have numbers in it prior to the date.

I'm trying to figure out a way to get to the last SPACE in the string.

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Nov 26, 2013

I have the following data.

Column A is for ID and column B is for Notes.

I need find a formula that will extract the number that is highlighted in red and place it in column C. Would this be possible?

ID
INTERNAL NOTES

355104

[Code] .......

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Jan 5, 2005

My colleague has a problem where he needs to Extract numbers from alphanumberic strings. Here is the formula he is using:

=MID(B7,MATCH(TRUE,ISNUMBER(1*MID(B7,ROW($1:$297),1)),0),COUNT(1*MID(B7,ROW($1:$297),1)))

It works if alphabetic and numbers are clustered together such as scs987
It works if alphabetic and numbers are not clustered together such as scs987dtg

Problem: It does not work when numbers are not clustered together such as scs987dtg1234

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Jul 13, 2009

I need to be able to locate a date in a spreadsheet bassed uppon a user input date. I am looking for the week that contains the user's date. However it seems even if I initialize the value as Date, it still reads the user's input as a string.

Is there an easy way make sure the system automaticaly recognizes the user's input as a date, or is there a way to quicly convert the string to a date?

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Feb 6, 2012

I’m wanting to extract the numeric values & piece of text from the end of a text string. Example data set starting in A1;

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Result wanted :
Column B1 : Big Box
Column B2 : 40*20
Column B3 : 40 x 30

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Aug 23, 2012

How do I copy the numeric part(11 Digits) of a cell

EG. A1 = "GL CREDIT DDA07 60291627599 ZFT"

I Require "60291627599" in A2

Descr
ANSWER

GL CREDIT 62180577391@DDA ZFT
62180577391

GL CREDIT 62300192854 62300192854 DDA06 ZFT
62300192854

GL CREDIT ACC REC 62273991367 ZFT
62273991367

The numeric 11 digit number is not always in the same position in the cell.

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Aug 23, 2012

How do I copy the numeric part (11 Digits) of a cell ,

E.G. A1 = "GL CREDIT DDA07 60291627599 ZFT" in only want "60291627599" in A2

Descr
ANSWER

GL CREDIT 62180577391@DDA ZFT
62180577391

GL CREDIT 62300192854 62300192854 DDA06 ZFT
62300192854

GL CREDIT ACC REC 62273991367 ZFT
62273991367

11 digit not always in same position in cell.

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Jan 3, 2013

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example:

X3PP2 1200 U

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Jan 29, 2009

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4 (In Cell B1)

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Jul 31, 2009

I'm trying to extract alphanumeric data before and after a numeric string. The numeric string is in the middle of a URL, which is a varying distance from the start and end.

Here's a sample of my data:

URL Page ID Headline Section quiz.impression-http://www.stuff.co.nz/2677193 2677193

http://www.stuff.co.nz/travel/267779...flying-JetStar 2677794 Why-I-hated-flying-JetStar travel http://www.stuff.co.nz/technology/di...eo-a-smash-hit 1675213 Wedding-dance-video-a-smash-hit technology/digital-living http://www.stuff.co.nz/national/crim...ce-in-Auckland 2678248 Man-shot-by-police-in-Auckland national/crime http://www.stuff.co.nz/sport/rugby/s...it-for-Blackie 3674350 NZRU-set-to-bend-it-for-Blackie sport/rugby/super-14

I start with just column A and generate the other three from that.

I'm using some excellent code from a Mr Excel guru (thanks again Peter) to extract the 8-digit numeric string in column B, I just need C (after) and D (before).

That macro is:
Dim Bits
Dim c As Range
Dim i As Long

For Each c In Range("A4", Range("A" & Rows.Count).End(xlUp))....................

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May 24, 2006

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May 23, 2007

I have some code where I need to check if the first five char are numbers and not letters.

I have in a column for example
12345-someone is here
23456-someone else is here
someone is here too

I need to get all of the ones that have 5 digits and not pull in the other into a new list.

I have tried Left(CPHierAll. Cells(CPHierAllRow, 1),5) which will get me the fist 5 char. and then i need to check to make sure that they are all numbers and not char.

if Left(CPHierAll.Cells(CPHierAllRow, 1),5) = "#####" then
But this does not bring anything in.

I also tried if CPHierAll.Cells(CPHierAllRow, 1),5) = "#####" then

I have 3 column that i am checking for different thinks the first two work just find and seperate out on the check but the last one with the numbers is being a pain.

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Dec 31, 2007

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Sep 27, 2011

Problem: String is broken into 2 parts within a delimeter.
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I have a .csv file with 26 segments (commas). This file contains customer data: PO#, Order#, Carton ID, Address 1, Address 2, Address 3, etc.

I've written code to capture all 26 segments as: Input #1, Seg1, Seg2, ... ,Seg26. The variables work fine until it encounter a string with Numeric first then Alpha within the same segment.

For this example we have a string such as (...,187 Main Street, PO Box 369,...)
Seg4 = Address
Seg5 = PO Box

The Segment Variables in Input #1, get shifted when it encounters the numeric portion of the address...so the result becomes:
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Segment5 = Main Street
Segment 6 = PO Box 369.

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It delimits when it encounters Numeric then Alpha within the string, but accepts the entire string into the variable when its Alpha then Numeric within a delimeter.

How I can keep the entire string in tact within each delimeter?

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Jun 20, 2014

I want to strip only the leading set of numbers from a string. Trailing numbers should stay.

Logic rule would be:
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Code:
Original string Desired string
42114DEP DEP
050114OP2OP2
0514OPOP
050214BKCKSBKCKS
05214CKCK
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050214CKSACKSA
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50214PSCASH1PSCASH1
050214PSCKSPSCKS
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only the first 7 characters won't change. The number part could be 2 or 4 digits, and the NewInfo portion could be anything.

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Currently, they connect using a Visual FoxPro ODBC driver. We setup the connection when we made the queries. Now that they are in on the worksheets, I want to be able to edit them with VBA instead of using the script editor (which is very slow).

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