Redim An Array Within An Array
Aug 17, 2009
Can I redim an array that is held within an array? I have (for example) 3 worksheets, and from each one I want to load 2 columns into an array. However I also want (I think) those 3 arrays to be contained within one array so that I can step through them easily. The code below will not run, but might better show what I am wanting;
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Apr 28, 2014
I iterate through a list and store the data in an array.
[Code] ..........
This works fine, but I tried to have 2 dimensions to the array and It no longer works!
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Nov 16, 2007
Currently I am building a class to keep track of entries I have made during the macro execution. Thus far I have:
Private Type Memory
MemoryArray() As Variant
End Type
Private Sub Class_Initialize()
Redim MemoryArray(0) As Variant
End Sub
Public Property Let AddToMemory(Object As Variant)
'memory is empty
If UBound(MemoryArray) = 0 And MemoryArray(UBound(MemoryArray)) = "" Then
MemoryArray(0) = Object ..............
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Sep 20, 2012
I have an array that is going to have a variable length every time the macro is run. I set a really high length at the beginning and when I want to unload the data, I want to redim the array to only the amount of data that was loaded into the array.
I am getting an error of "Array already dimensioned" when use the redim function near the end of my code below.
Code:
Private Sub Trend_Click()Dim GraphRow As LongDim TodaysYear As Integer,
Adjustment As Integer, EndYear As Integer,
StartYear As IntegerDim X_Axis_Array(1 To 100) As VariantDim SelectedStmt As StringDim X_Axis_ArrayEnd As IntegerTodays
[Code] ........
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Apr 1, 2014
I've written this function to re-dimension an array based on the size of the range it is storing. Originally all my variables were simply declared as:
Code:
Dim XLRecOutput() as Variant
I then wrote a function which took the variable and the range as follows:
Code:
Function LoadRangeToArray(dataArray() As Variant, selectedRange As Range, Optional blnLoadData As Boolean = True)
With selectedRange
ReDim dataArray(1 To .Rows.Count, 1 To .Columns.Count)
End With
If blnLoadData Then dataArray = selectedRange
LoadRangeToArray = dataArray
End Function
To call the function, it's simply:
Code:
XLRecOutput = LoadRangeToArray(XLRecOutput, Range("XLRecOutput"))
Now I've created a class and set up Get/Let properties for the variables instead, but the above function fails with a Compile error on the call - 'Type mismatch: array or user-defined type expected' and I can't get my head around how to resolve it.
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Jul 20, 2009
I found quite a few posts about this problem, but none of the answers was any use to me. I need to redimension a 2 dimensional array in a Sub. I deleted all the code that is not of interest:
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Jul 30, 2012
in C a string is nothing more than an Array of characters ending with a null character.
in VBA this does not seem to be the case.I am trying to use the BlowFish code from David Midkiff for some encryption, however the code sometimes fails:
When encrypting a string a string of a specific length should be returned. however sometimes one of the characters of the encrypted string is a null character, and the returned encrypted string (with a embedded null character) is causing me problems. I want to check for the null character and if present redo the encryption. But how do I check for the presence of this null character in a unicode (double-byte) string?
Checking with Len(encrypted) gives the correct length (!) but trying to move each (unicode)character into an array fails when using the Mid() function past the null character in the string.
Now I can use
byteArray() = StrConv(unicodetext,vbFromUnicode)
to get the lower byte of each character into an array easily, but how do I do this for both bytes of the unicode characters?
Using an integer array does not work other than through
intArray(j) = CInt(AscW(Mid(Outp, j, 1)))
which fails on the nullstring in my encrypted text.
I have tried with variants but so far no luck. I thought if the string was entered into a variant then I could also address the variant as an array of bytes, but that does not seem to be accepted by VBA.
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Sep 9, 2012
I am trying to populate many arrays with the same code using something like this. For this test, assume the following data in A1.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
Code:
Sub populate()
Dim firstArr(5), secondArr(5), thirdArr(5), fourthArr(5), fifthArr(5) As Integer
Dim r, c, num As Integer
[Code]....
The above code does not work of course and falls over. I am unsure whether I should try and concatenate with something like this eg "" & arrName(i) = Cells (r,c) or go down a different route.
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Dec 20, 2013
I need to export this to Xcelsius which doesn't support any macros/vba. Btw I can;'t use Row() in xcelsius too.
[Code].....
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Oct 2, 2008
I have a class module with several private variables, including one that is an array of a user-defined type. I am trying to set the values of a single element of this array with "Property Let ..." from a string array:
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Apr 7, 2009
Say I have 3 columns of data: A1:C10 and I want to run a Match() function on them all together to see if I get a match any one those cells, say the value of have in X1.
Since, Match only allows a One-Column lookup array.. is there a way to "concatenate" or "append" the 3 columns together within a formula so now I would be looking to Match in an array that is 1 column * 30 rows?
Basically want to convert =Match(X1,A1:C10,0) to =Match(X1,A1:A30,0) without moving around the raw data in the sheet.
And I want to avoid doing an AND or OR formula that uses 3 separate MATCH() for each column.
I have a hunch that the MMULT or MMULT/TRANSPOSE functions are involved, but can't seem to get it right.
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May 2, 2013
I'm only starting to get to grips with arrays. I have what I consider to be a lot of data that I need to 'cut' into separate workbooks. I have written some code that does this by simply looping through each line, 250k+, checking against a variable and copying the row into a separate sheet. This took longer than it would have doing it manually. It was suggested to me that I use arrays to speed up the process. I have managed to store the test data into an array but am struggling to find a way to loop through and pull out an entire 'row' from the array based on a variable. I have looked for 2 days in various places to find some way to loop through the data held in the array, but to no avail.
That code will appear here from about 8am GMT tomorrow. I know that once I've cracked this I'm on the road to some very significant time saving and comprehensive report writing.
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Aug 5, 2014
I want to pass an array to Offset in the "Height" parameter, without having to type the array.
{=MAX(SUBTOTAL(9,(OFFSET(A1,ROW(1:5),,{1,2,3,4,5}))))}
I can't seem to figure out how to build the {1,2,3,4,5}. I've tried another ROW(1:5) and have tried nesting that like N(ROW(1:5)) but nothing works.
How I can get the {1,2,3,4,5} without having to type it out (so that I can expand this to a larger list)??
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Aug 26, 2009
I am trying to filter an array (the longer one) using the shorter array as the criteria. I am currently doing this using the following method
IF(LOOKUP(lookup cell, array)=lookupcell, lookupcell, "FALSE")
I then copy and paste 'values' and filter out the 'false' to get my final result.
This has worked in the past, but for some reason that I simply can't figure out, the formula isnt working! I've attached the example, and I've highlighted a number in blue (cell E522 and C103), (that should be being found in the 'LOOKUP' function) but is returning a "FALSE". I have looked over the code and simply can't figure out why Excel isn't returning the right value.
This is obviously happening for a quite a few of my numbers, as my filter result is returning an array that is about 1500 shorter than it should be. I have highlighted E522 as the 'example cell' to look at.
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Jun 21, 2014
wondering is there a VBA equivalent of --() in excel that turns trues and falses to 1's and 0's?
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Nov 6, 2013
Is there anyway to recreate this formula w/o it being an array ?
{=IF(C3="","",IFERROR(INDEX('Master List'!$B$1:$B$2000,MATCH(TRUE,ISNUMBER(SEARCH('Master List'!$A$1:$A$2000,C3)),0)),"ADD TO MASTER"))}
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Nov 15, 2007
=CORREL(C1:C10,C12:C21) at H1
=CORREL(C1:C10,C23:C32) at H2
=CORREL(C1:C10,C34:C43) at H3
etc
can i have a macro that first array remain the same, and second array always 11 cells added. drag it down also can
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Mar 22, 2007
I've tried to multiply each element in a 6x6 array by a similar 6x6 array, both on the same sheet, and it worked.(see Macro2 and attached xls file "Test").Then I got more ambitious and tried to do the multiplication from a standard array in sheet "TestA", with the result on the same sheet, by each array in sheet "TestB" and failed.How do I solve this problem? Pgualb PS:I'm using the R1C1 style.
Sub Macro2()
For y = 29 To 34
For x = 2 To 7
Cells(x, y) = Cells(x, y - 27) * Cells(x, y - 18)
Next x
Next y
End Sub
Sub Teste12()
'Multiplica matriz em TestB por matriz padrão em TestA com _
'resultado na matriz em TestA correspondente à matriz em TestB
'
Dim x, y As Integer
For y = 2 To 7.............
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Aug 15, 2014
Assume that I have in Sheet2 a list of CUSTOMIZED name.
[Code].....
Now in Sheet1, I have data in column A that has strings consist of the customized name.
For example
[Code] .....
What function should I use that could give me the result of the CUSTOMIZED name?
I was thinking of a formula i.e.
[Code] ......
Obviously, the above formula give me error. Even if it works, it'll not give me the customized name ...
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Nov 28, 2011
I'm new to arrays. They seem promising for what I want to do though...
Heres where I'm at. I have some data like this:
items freq 1 0.5 2 0.5 3 0.5 4 0.25 5 0.25 6 0.125
Now, I've created a 2 dimensional array, as such:
Code:
Sub testarray()
Dim arr1 As Variant
Dim rng1 As Range
Dim lngX As Long
Set rng1 = [A2:A6]
ReDim arr1(1 To rng1.Count, 1 To 2)
For lngX = 1 To rng1.Count
arr1(lngX, 1) = rng1.Cells(lngX, 1)
arr1(lngX, 2) = rng1.Cells(lngX, 2)
Next
End Sub
Now, what I need to do, is create an array for each freq of all the items that share that freq. Essentially I need this:
0.5 {1,2,3} 0.25 {4,5} 0.125 {6}
Now, I was thinking, if I could create a dictionary object and make the key the freq (so my keys would be 0.5,0.25,0.125) then I could assing the "item" an array (or another dictionary) holding the items that apply to that freq.
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May 18, 2007
I just wanted to concatenate a few cells using an array formula like this:
{=SUM(IF(B2:J2="";0;B2:J2))}
Well, this does not work. I have no idea why it fails. Any solution to this without scripting?
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Jun 30, 2006
i need to replicate what i did using array formulas with VBA macro (array variable). to make things clear and simple i created an example for illustration only. look at it & u will find what i did & what i need to do ,much of it
in writing so that i accurately describe my problem. attached is my example
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Jul 11, 2007
On one sheet (KPI) I have either the values "x" or "" in the range A84:A89 to mark wheter to use the corresponding project in the range B84:B89. On the sheet X-ref I have the same project names in range T4:Y4 and a corresponding target value in T8:Y8
What I want is the sum (or average) of the marked-projects target-values. The result should end up in KPI!G31.
In other words I want
=sumif(A84:A89;"x";'X-ref'!T4:Y4)
but it doesn't work since the first range is an column-array and the second range is an row-array.
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Feb 11, 2008
I'm trying to use an array to carry out string function on a range of excel cells.
Here is the code I am using
Dim arrXl As Variant
arrXl = ws.Range("F1:F" & ws.Range("D1").End(xlDown).Row)
For i = LBound(arrXl) To UBound(arrXl)
MsgBox (LBound(arrXl))
'If 1st char is different from 3rd char then remove all of string after 1st char
If Left(arrXl(i), 1) <> Mid(arrXl(i), 3, 1) Then
arrXl(i) = Left(arrXl(i), 1)
End If
'If 1st char is different from 7th char then delete string after 5th char
If Left(arrXl(i), 1) <> Mid(arrXl(i), 7, 1) Then
arrXl(i) = Left(arrXl(i), 5)
End If
The lbound function returns the value of 1 as the lower bound, I do not have "Option base 1" set so I was expecting the lbound value to be 0. The first 2 cells in the F column are blank so this may have something to do with it, I am unsure if cells in excel can be null if they can be null one cell may be null and the other may be a zero length string but I am unsure about this.
The ubound function returns a value of 487.
The code breaks when I try to access an element in the array so it breaks on the line:
If Left(arrXl(i), 1) <> Mid(arrXl(i), 3, 1) Then
and returns the "Subscript out of range" error message.
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Aug 6, 2009
I need to multiply an array of logical results ( returned as {1,0,0,0,1,0 et.}) with a text array (a reference column) and return the text in the reference column in case the value in the logical array is 1.
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Mar 31, 2014
I am trying to do a sort of index match thing using VBA. What I am attempting to do is to use the prefix of a long number and try to find that exact prefix in a string array, and output that string array value. So this is what I have so far as a test:
[Code].....
So I can match the text exactly so if I put PREFIXB in cell A1 in this example, i will get the msg box saying "YES", but if I make it PREFIXB1231k4j3jj1kj32cj, it will display "NO". I want to get it so that PREFIXB will be displayed in the cell that I put the formula in. So if A1 = "PREFIX1AAA100CF" and cell B1 = "=ABC(A1)", cell B1 will display "PREFIX1AAA".
Now the thing is that these prefixes can have different lengths, but will never encompass the exact prefix of another. So if I had a prefix of: PRE1AB, I won't have a prefix of PRE1A.
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Aug 25, 2006
I am trying to copy or edit a cell thats has the following formula (see below), I keep getting this message "You cannot change part of an Array!"
=If(ROW($A2:$A8)-ROW(A2)+1>COUNT(W2:W8),"",INDEX($A:$A,SMALL(W2:W8,ROW(INDIRECT("1:"&ROWS(A2:A8))))))
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Nov 16, 2005
how to use Array formulas in Excel. I can Sum, Count
etc. I am wondering if you can return an array of data with an array formula
Example:
Name Replied?
Bob N
Brian Y
Robyn N
Rachel Y
From the table above if I test for "N" I'd like the formula to return a list
of names, in this case Bob and Robyn.
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Aug 17, 2007
I need to create an array within an array (or loop within a loop). First loop works fine as
x = 0
Dim DirArray(0 To 80) As String
Dim intI As Integer
For intI = 0 To 80
DirArray(intI) = Range("start").Offset(intI, 0).Value
Next
For x = 0 To 80
lob = DirArray(x)
Range("lob") = lob
Calculate
Sheets("WBB LOB Summary").Select
ActiveWindow.SelectedSheets.PrintOut Copies:=1, Collate:=True
Next
At the 'start' point (cell A1), first loop works downward through rows. Second loop (starting in cell B1) would work across columns in each row within the first loop. I will have to use a variable for 'y' (the across value) b/c the number of cells containing data can vary between 3 & 9, but I have a COUNTA in each row setup to use as the variable.
So spreadsheet data would look like this with X data being the 'start' cell:
X 1 2 3
Y 1 2 3 4 5 6
Z 1 2 3 4
I need to pickoff X1, X2, X3, Y1, etc, picking up every sub-category on the sheet.
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Apr 15, 2008
1) after I have made an filled an array with data.
Dim orders(100000 To 200000) As Double
I want to then sum the orders above and below a number, lets say
orders>orders(150000)
and
orders
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