I need a formula that can remove all characters to the right of "]" for example, if a1 = abcdefg]1234, I want b1 to return the value: 1234. I tried =RIGHT(a1,FIND("]",a1)-1), but that didn't really work. It returned: fg]1234
View 4 RepliesI made in a macros this formula :LEFT(RC[-1],(LEN(RC[-1])-2))
is removing from left side an index , like in this example '
9117 - 570-65CE49D-B4-7 to obtain 9117 - 570-65CE49D-B4
so here is my code,
is with an userform, but it gaves me an error, that my procedure is invalid
I have two words of differing character lengths separated by a space.
How can I remove the first word... essentially, all the charcters to the left of the space AND the space itself?
I have a 2010 excel sheet containing 14 columns and 45082 rows in total. I am quite illiterate when it comes to writing macros but I know that what I need can be achieved with a set of codes.
To be more clear, I inserted two tables below. The first one represents the current data structure, and the second one is the way I want my data to look like.
Current data structure looks like
Variable 1
Variable 2
Variable 3
[Code].....
I am having trouble filling a formulae series to the left on one spreadsheet, the fomulae being references to another sheet.
For example, I have two sheets 'Mtce Options' and 'Base Case'. In 'Mtce Options' I have the following formulae
A B C
1='Base Case'!A15='Base Case'!D15='Base Case'!G15
I want to fill to the left, incrementing the column references by a factor of 2 each time, eg. next two should be ='Base Case'!J15 and ='Base Case'!M15.
However, if I autofill to the left by highlighting A1, B1 and C1 or just B1 and C1 all I get is an inappropriate reference such as ='Base Case'!D15 or ='Base Case'!F15, respectively, in D15.
I want to grab everything left of the last occurrence of "." in a string, and in the next cell everything right of the last occurrence of "."
so say the string is 111.111.1.222
column 1
111.111.1
column 2
222
my current code (which works, but its messy) for the first cell is
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
If intASCIIVal >= 97 And intASCIIVal <= 122 Then
RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1)
End If
Next intLoopCounter
End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
I have a column that is giving unwanted value . dont know the reason as that excel file has been created by some other guy and I just started working on it .
My Question is how to move to 2 cells left(A for example) from from that unwanted value column. and check if
A is equal to cell above it , means B Cell(Row above A but same column).
As my excel file is totally based on Forms, Macros, I am not quite familiar with macros.
Is there any way to put if condition in one cell (column) and drag it all the way down which should work for all the values in these 3 column.
And also if A=B then I want to make that unwanted value cell="".
I have a set of data in an Excel 2007 spreadsheet and want to move it to Sheet2. I move all that I need except for one column which needs some work done to it and I keep receiving errors. Sheet1 Column 12 is comprised of six digits, space, six digits, space, and four more digits. What I need is the first twelve (12) digits, less the space, moved to column1 on Sheet2.
The code I am attaching does the following:
The year 2009 to Sheet2 Column2
Column6 + Column7 to Sheet2 Column3
Column8 + Column9 to Sheet2 Column4
Column6 + Column7 + Column8 + Column9 to Sheet2 Column5.
In cell A1, suppose I have a string "Forrest Gump", how can I get the "Forrest" part out using left() or any other function?
View 10 Replies View RelatedI have a cell and I only want to look at the word after the first 4 characters of every cell. I do not know the word size so right(...) didn't work for me, I just know the first 4 characters I do not need and the word follows.
View 9 Replies View RelatedHow can I use Len and Left together to ensure a workbook name begins with Order?
I've tried using Left("Order", 5) and didn't work.
Len(Activeworkbook.Name, 5) didn't work either.
I have a table with a range of numbers inputted as text (ie. 200-400, 300-500, 65-90, etc.) that I am extracting. I made a formula that works for pulling out numbers if they are in the triple digit range but don't want to rejig if they go down to double-digits, or up to quad. (too tedious to change the right and left count function midway if data suddenly changes)
The values that I am extracting are separated by -'s and when i use the formula below i end up with negative numbers if one of the pairs is less than 3 digits (ie. 2)
=VALUE(RIGHT('NAIC Spread 2007'!D11,3))
how can i work in a Len function to deal with this issue?
Obscure lines of info which I'm trying to break up into pieces. Being able to find from the right instead of left would be REALLY handy. See attached example with details and example!
View 3 Replies View RelatedI have a simple VLOOKUP that I can't manage to give the right answer. The contditions must be 'FALSE' as the the stock report database has so many similar numbers in it.
View 2 Replies View Relatedi have this issue, i named column J. now it says instead of using Social Security numbers as a unique identifier, they are considering using an ID of the first 3 letters of the last name (L Name) followed by the first letter of the first name (F Name). If the last name is fewer than 3 characters, the letter Z replaces each missing character.
View 3 Replies View RelatedWhat is wrong with this formula? It results in #Value error.
View 3 Replies View RelatedI've been trying to figure out how to tell my left footer to automatically use the value of whatever "L2" is. How do I do this?
View 7 Replies View RelatedI am trying to use the left function to include only the first account number, for example if a cell has "120122 280000" (there may be many spaces between the two numbers), I only want 120122.
So far my programming only returns the 280000 into the cell.
I am working with cell values in column "K".
Is it possible to make VLOOKUP look to the left?
Imagine following arrangement of data:
Address Name PIN
A-street Abe 4587
B-street Bob 8214
V-street Val 9657
I want to know the name of the person who has PIN 4587. Is it possible to do this without rearranging the columns?
Is there any auto sorting available to sort w/in rows left to right?
View 9 Replies View RelatedI have one field that contains a city, state and zip. I need to extract only the city. I need the proper function to ask Excel to go to the cell and return all the text beginning the first place on the left, continuing until it reaches a comma. The number of places in the city will always vary.
I ahve got the below range.what I want is if the first chracter starts with any of the below corresponnding value to be shown.I am using left and abs for this . but when the chracter stars with "N" or "E" . i am getting and error.
6Connect
NExplore
1Entry
3Connect
2Entry
5Live
EAchieve
7Live
8Live
9 connect
trying to return a value left of a column instead of from the right.
ex
A B C D
1103013v2200172b
I want to lookup a value in column C and return the value from column A
i know the forumla, using left and find to get the value of a cell to the left of the first space. (i.e if the cell said [url] click here then im looking for just [url]
however, when I try and use this in vba I cant get it to "find".
im trying to get the value of a textbox, before the first space
i am having one excel spreadsheet where there are data in matrix of 365 rows X n columns. columns are not fixed.(but will always be less than 125). now i want to add blank column after every column through VBA
e.g.
a--b--c--d--e (these are columns)
date--scrip1--scrip2--scrip3--scrip4
now i want data to be rearrange as
a--b--c--d--e--f--g--h--i
date--scrip1--<blank>--scrip2--<blank>--scrip3--<blank>--scrip4--<blank>
means one blank column after every scrip idea is to calculate %return in that new added blank column
What I need is to find a max value within a range and then tell me what the row value in Column A is. Usually use VLOOKUP for this but this doesn't like minus numbers.
I think it has something to do with Match and Offset but can't get it to work properly.
I have attached an example, where the max of the total is 4,435 and belongs to Steve but how do I get this to do using formulas
I need to move characters from the end of a string to the beginning.
I have a list of Exact stings that are allowed. I need to move this allowed string to the beginning.
JAN
JANS
JANTX
JANTXV
If "TR" or "T/R" are at the end of the allowed Exact string, I need that removed completely.
i.e.
JANTR = JAN
JANT/R = JAN
JANTXT/R = JANTX
PN
Desired result
1N3595UR-1JANTX = JANTX1N3595UR-1
1N4992JAN = JAN1N4992
2N1711JANS = JANS2N1711
1N4148UR-1JANTXVTR = JANTXV1N4148UR-1
this formula as a result =IF(LEFT(A3,1)="0",RIGHT(A3,LEN(A3)-1),A3) It worked great to strip the left most zero from a string of text numbers in the cells where the formula was applied.
However, now I need to put the zero back in lol!
So...how would I adjust the formula (or write a different one) to insert a zero as the first digit of a string of text digits?
generally vlookup function gives a value from the right side cell. is it is possible to display a cell from the left side. in the attached excel file i want the numbers against the cell which contains mom.....
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