Is it possible to make VLOOKUP look to the left?
Imagine following arrangement of data:
Address Name PIN
A-street Abe 4587
B-street Bob 8214
V-street Val 9657
I want to know the name of the person who has PIN 4587. Is it possible to do this without rearranging the columns?
I have a simple VLOOKUP that I can't manage to give the right answer. The contditions must be 'FALSE' as the the stock report database has so many similar numbers in it.
View 2 Replies View RelatedI ahve got the below range.what I want is if the first chracter starts with any of the below corresponnding value to be shown.I am using left and abs for this . but when the chracter stars with "N" or "E" . i am getting and error.
6Connect
NExplore
1Entry
3Connect
2Entry
5Live
EAchieve
7Live
8Live
9 connect
trying to return a value left of a column instead of from the right.
ex
A B C D
1103013v2200172b
I want to lookup a value in column C and return the value from column A
What I need is to find a max value within a range and then tell me what the row value in Column A is. Usually use VLOOKUP for this but this doesn't like minus numbers.
I think it has something to do with Match and Offset but can't get it to work properly.
I have attached an example, where the max of the total is 4,435 and belongs to Steve but how do I get this to do using formulas
generally vlookup function gives a value from the right side cell. is it is possible to display a cell from the left side. in the attached excel file i want the numbers against the cell which contains mom.....
View 2 Replies View RelatedFunction sequence giving me "N/A": =VLOOKUP(LEFT(C6,5),H:I,2,FALSE)
Basically, I have numbers that each start with a unique sequence. The first 5 numbers of that sequence represent a certain cell carrier.
What I want to do is have the function look up the first 5 characters of a cell and depending on the 5 characters, I want it to return a certain value.
My idea with the vlookup was to have the lookup value be the first 5 digits and then in my table, it would take only those 5 digits and return a value I have specified in the second column.
LEFT(C4,3)
VLOOKUP(C4,C4:D38,2,FALSE)
VLOOKUP(LEFT(C4,3),C4:E38,2,FALSE)
I combined the first two formulas into one (the third one) but it is not working. I get an N/A result.
I have a issue with VLOOKUP and LEFT STRING ETC I have a lookup table see below
AB10 Grampian
AB12 Grampian
AL8 Anglia West
AL9 Carlton LWT
B1 Central West
B10 Central West
B11 Central West
B13 Central West
B14 Central West
B15 Central West
Code: =VLOOKUP((LEFT(C4,6)),'Data from 7500'!$B$16:$G$195,6,TRUE)
And it works great, except that the data returned is off by one row. For example, the correct value for the sample name in B107 is located in G107, but the formula returns the value in cell G106. I've tried changing the TRUE to FALSE and that returns #N/A.
I am trying to obtain price of an item using vlookup() function on the identifier 0003128 (7 digits) stored with custom format 0000000 in one worksheet. However in other worksheet, the identifier is stored as 000312 (6 digits) with text format without the last digit 8. I tried using the left(A,6) function on 0003128 but instead of returning 000312 it returns 3128 and Im unable to use the vlookup() function.
View 6 Replies View RelatedI have a workbook which has data from 2 different time points (6 and 12 months) and this is signified by a prefix to an ID number which is a letter (A or B) and a number:
I need to analyse data separately so I'd like to create 2 separate workbooks, once which imports all of the 6 month data (1 row per case) and one for the 12 month data.
I thought that this would be based around a VLOOKUP of the first 1 or 2 characters but I can't work out how to integrate this with an 'IF' and link it to another workbook.
In the attached sheet I am trying to use the formula below but am getting a #NA error. I have narrowed the problem down to the use of the SEARCH and LEFT functions that I am using to determine the lookup value of the VLOOKUP formula.
what I am doing wrong? If I substitute the SEARCH and LEFT function with the number "14" it works just fine. You can find examples of both in cells B29 and C29 on the rename tab.
I have a large table with data to which I want to retrieve a name to the left of a certain cell.
Clear as mud so far!
I've put together a small example of what I'm after. In cell F9 is the MAX of cells F2:F7. In cell H3 I then want a formula that will find the MAX of F2:F7 and return the text five rows to the left of that cell. In this example it would be Fred.
The second part of this question is how could I get it to display if more than one person had the same total....
XL 2003
I want to combine these three functions
=VLOOKUP(e4,AGTNAME!$A$1:$E$3086,5,0)
=LEFT(E4,FIND("/",E4)-1)
and iserror
I have a sheet that a VLOOKUP is looking at, and what I need is, if that VLOOKUP finds what it is looking for I need it to look at the cell 2 cells to the left, how is that done?
I am thinking something like:
Formula:
[Code] ......
I just don't know the offset part.
I need a formula that will bring up the Model type of a product based on its Material code. All the models I need to generate have a "root" number in them (the first 6 digits define model type). This is what I need to fill out:
View 2 Replies View RelatedI have a 2010 excel sheet containing 14 columns and 45082 rows in total. I am quite illiterate when it comes to writing macros but I know that what I need can be achieved with a set of codes.
To be more clear, I inserted two tables below. The first one represents the current data structure, and the second one is the way I want my data to look like.
Current data structure looks like
Variable 1
Variable 2
Variable 3
[Code].....
See the attached example for an illustration of my problem. Essentially, I am trying to reference the first two numbers of an account number when using VLOOKUP. The function then references a table with account classifications based upon the first two numbers of each 10 digit account. This seems so basic, but is driving me up the wall!
View 3 Replies View RelatedI am having trouble filling a formulae series to the left on one spreadsheet, the fomulae being references to another sheet.
For example, I have two sheets 'Mtce Options' and 'Base Case'. In 'Mtce Options' I have the following formulae
A B C
1='Base Case'!A15='Base Case'!D15='Base Case'!G15
I want to fill to the left, incrementing the column references by a factor of 2 each time, eg. next two should be ='Base Case'!J15 and ='Base Case'!M15.
However, if I autofill to the left by highlighting A1, B1 and C1 or just B1 and C1 all I get is an inappropriate reference such as ='Base Case'!D15 or ='Base Case'!F15, respectively, in D15.
I want to grab everything left of the last occurrence of "." in a string, and in the next cell everything right of the last occurrence of "."
so say the string is 111.111.1.222
column 1
111.111.1
column 2
222
my current code (which works, but its messy) for the first cell is
I have a column that is giving unwanted value . dont know the reason as that excel file has been created by some other guy and I just started working on it .
My Question is how to move to 2 cells left(A for example) from from that unwanted value column. and check if
A is equal to cell above it , means B Cell(Row above A but same column).
As my excel file is totally based on Forms, Macros, I am not quite familiar with macros.
Is there any way to put if condition in one cell (column) and drag it all the way down which should work for all the values in these 3 column.
And also if A=B then I want to make that unwanted value cell="".
I have a set of data in an Excel 2007 spreadsheet and want to move it to Sheet2. I move all that I need except for one column which needs some work done to it and I keep receiving errors. Sheet1 Column 12 is comprised of six digits, space, six digits, space, and four more digits. What I need is the first twelve (12) digits, less the space, moved to column1 on Sheet2.
The code I am attaching does the following:
The year 2009 to Sheet2 Column2
Column6 + Column7 to Sheet2 Column3
Column8 + Column9 to Sheet2 Column4
Column6 + Column7 + Column8 + Column9 to Sheet2 Column5.
In cell A1, suppose I have a string "Forrest Gump", how can I get the "Forrest" part out using left() or any other function?
View 10 Replies View RelatedI have a cell and I only want to look at the word after the first 4 characters of every cell. I do not know the word size so right(...) didn't work for me, I just know the first 4 characters I do not need and the word follows.
View 9 Replies View RelatedHow can I use Len and Left together to ensure a workbook name begins with Order?
I've tried using Left("Order", 5) and didn't work.
Len(Activeworkbook.Name, 5) didn't work either.
I have a table with a range of numbers inputted as text (ie. 200-400, 300-500, 65-90, etc.) that I am extracting. I made a formula that works for pulling out numbers if they are in the triple digit range but don't want to rejig if they go down to double-digits, or up to quad. (too tedious to change the right and left count function midway if data suddenly changes)
The values that I am extracting are separated by -'s and when i use the formula below i end up with negative numbers if one of the pairs is less than 3 digits (ie. 2)
=VALUE(RIGHT('NAIC Spread 2007'!D11,3))
how can i work in a Len function to deal with this issue?
I have a Vlookup which I want to modify so that it can become dynamic as the table array part of the vlookup will change.
So the basic vlookup is as follows:
=VLOOKUP($R$3,ATTRIBUTION_FACTSET!$M$60:$P$73,2,0)
but the data I am looking for wont always be in the range M60:P73.
So I tried to make it dynamic by doing the following:
=VLOOKUP($R$3,INDIRECT("ATTRIBUTION_FACTSET"&"!M"&U1&":P"&V1),2,FALSE)
The idea being that U1 and V1 would be numbers that can change so in this case U1 would equal 60 and V1 would equal 73
This vlookup is giving me #N/A and no matter how I modify it I cannot get it to work.
Obscure lines of info which I'm trying to break up into pieces. Being able to find from the right instead of left would be REALLY handy. See attached example with details and example!
View 3 Replies View Relatedi have this issue, i named column J. now it says instead of using Social Security numbers as a unique identifier, they are considering using an ID of the first 3 letters of the last name (L Name) followed by the first letter of the first name (F Name). If the last name is fewer than 3 characters, the letter Z replaces each missing character.
View 3 Replies View Related