I made in a macros this formula :LEFT(RC[-1],(LEN(RC[-1])-2))
is removing from left side an index , like in this example '
9117 - 570-65CE49D-B4-7 to obtain 9117 - 570-65CE49D-B4
so here is my code,
is with an userform, but it gaves me an error, that my procedure is invalid
I want to remove varying amounts of periods that appear at the end of my strings. For instance, ABCEDFGH......., DEFGH.., FG.... etc. Do I have to test each char to see if it's a period, and then use that count of chars to LEFT out the string that I want? Or is there an easier, quicker way to do this?
View 3 Replies View RelatedI need a formula that can remove all characters to the right of "]" for example, if a1 = abcdefg]1234, I want b1 to return the value: 1234. I tried =RIGHT(a1,FIND("]",a1)-1), but that didn't really work. It returned: fg]1234
View 4 Replies View RelatedI need a formula for left coulmn lookup (using index and matching function) and lookup array has duplicate value.
View 1 Replies View Related=INDEX([ipathfall07shoes.xls]Sheet1!$B$2:$W$139,MATCH(C17,0),1)
View 9 Replies View RelatedI'm having a bit of a block with an index/match formula that I am trying to create for the attached spreadsheet. i.e. I need to populate cell J3 with the info the corresponding letter contained in the table to the far left. The numbers of reference to match are the 'zones' in H3 and J2.
View 2 Replies View RelatedAssume someone typed the hereunder date ad TEXT.
The Formula bar shows: ="01/01/2009"
The cell presents: 01/01/2009
I need to remove the equation sign as well the two inverted-commas.
I am familiar with the "Text to Column" feature, the use of SUBSTITUTE Function, a short macro and also the Find&Replace is also a good idea but, as far as I understand,
it must be run Twice(!)
I am looking for a way to use Find&Replace in "One! shot" - meaning, to put the TWO different(!) characters [ the '=' and the " ] in the 'find what' window,
leaving the 'replace with' window empty.
I know that something similar to that can be done in a "Word" document - but can it be accomplished in Excel?
I believe I should use the INSTR function, but I simply dont understand its use very well. I have a string in a cell, "MEAS/SPHERE,F(QUA_1),5", the characters I need start at the "(" and end at the closing ")", ref: (QUA_1). The start and end will always be the same, the length of characters and the spelling of characters be anything. Thus, QUA_1 can be CAL_1, CAL_2, SOMEOTHERTEXT_1 or 187bgo_199, etc, always enclosed in "( )". I wish to place the characters and the closing "( )" into a variable as a string.
View 5 Replies View RelatedCALIB/SENS,S(S5a90b-90),FA(CAL_15)
This one has two sets of quotes, with the information from the noted post I can retrieve the string "S5a09b-90", now that I have a double set of brackets "( )" how do I get the value for the second set of brackets, "CAL_15"?
In the quoted string, CALIB/SENS,S, is constant. The first set of brackets are constant (string length is not), the second set of brackets are constant (string length is not).
I need to some spaces to the end of a string to make it up to 36 chars.
The original string can vary in size based on the courier name.
i.e. : business direct invoice 40617 = 29 chars
i.e. : TNT post invoice 4061755 = 24 chars
Can someone point me in the right direction to be able to concat' some spaces on the end to make it up to 36 chars.
Would this be easier done using VB?
I have just done a vba project of striping chars (QOOO1=) from each cell
and then sorting the records on column6/question6
however i have been able to do this and display results in second worksheet(Results2)
I feel there is a better way to do it and display the results on same worksheet
Could anyone take a look at the file and help.
IMPORTANT:Place curse on "Results2" worksheet and run the macro:Pres
Do not run the macro on main sheet all data will be lost and will have to download again.
File:[url]
I have two words of differing character lengths separated by a space.
How can I remove the first word... essentially, all the charcters to the left of the space AND the space itself?
I'm looking for a formula which returns the longest consecutive series of occurrences of 2 chars in a text string.
In the case I'm trying to count the longest consecutive number of nine-spares (9/) in a bowling game.
For example:
|7/|X|9/|9/|9-|9/|9/|9/|9/|X8/|longest series of 9/ would be 4.
|9/|9-|9/|9/|7/|9-|(8)/|X|7/|9-|longest series of 9/ would be 2.
|9/|(8)1|X|X|72|63|7/|8/|8/|9/9|longest series of 9/ would be 1.
I have a file of names that has some undisplayable characters. I am trying to match against a different file. It works if I overtype the "blank" fields with a space. How can remove these trailing problem characters whatever they are? I tried CLEAN and TRIM and the mystery characters are still there.
View 2 Replies View RelatedI am having problems with a macro I am writing and I need some guidance on where I am going wrong (I am still a noob at VBA).
I have pasted the code below (not the most efficient use of code I know).
I have a list of departments and codes from the Intranet at Work. Now this contains a Department Code, Department Description and within the Description is a number in brackets showing how high up the organisation hierarchy they are....
I'm using excel 2003 and I have have a dynamic string of data separated by 19 commas ",". I think 19 (the # of commas) is one of the few fix numbers...
What I'd like to do is from Right2Left return the 5 characters immediately to the right of (before) the 11th "," comma (i.e. 22.59 for the 1st string on Excel Cell A2) OR from the Left2Right return the 5 characters immediately after the 9th comma "," comma, which is also 22.59
Example of some of the strings I've been trying to work with...the list is much longer...but for example sake I've limited to 4...
I have a 2010 excel sheet containing 14 columns and 45082 rows in total. I am quite illiterate when it comes to writing macros but I know that what I need can be achieved with a set of codes.
To be more clear, I inserted two tables below. The first one represents the current data structure, and the second one is the way I want my data to look like.
Current data structure looks like
Variable 1
Variable 2
Variable 3
[Code].....
I am having trouble filling a formulae series to the left on one spreadsheet, the fomulae being references to another sheet.
For example, I have two sheets 'Mtce Options' and 'Base Case'. In 'Mtce Options' I have the following formulae
A B C
1='Base Case'!A15='Base Case'!D15='Base Case'!G15
I want to fill to the left, incrementing the column references by a factor of 2 each time, eg. next two should be ='Base Case'!J15 and ='Base Case'!M15.
However, if I autofill to the left by highlighting A1, B1 and C1 or just B1 and C1 all I get is an inappropriate reference such as ='Base Case'!D15 or ='Base Case'!F15, respectively, in D15.
I want to grab everything left of the last occurrence of "." in a string, and in the next cell everything right of the last occurrence of "."
so say the string is 111.111.1.222
column 1
111.111.1
column 2
222
my current code (which works, but its messy) for the first cell is
I have found a very useful UDF for removing non-alpha characters from strings. (See below, Credit for posting to Stanley D Grom - Ozgrid post ´Removing Non-alpha Characters From Text´).
Option Explicit
Private Function RemoveCharacters(InString As String) As String
Dim intLoopCounter As Integer
Dim intStringLength As Integer
Dim intASCIIVal As Integer
intStringLength = Len(InString)
InString = LCase(InString)
For intLoopCounter = 1 To intStringLength
intASCIIVal = Asc(Mid(InString, intLoopCounter, 1))
If intASCIIVal >= 97 And intASCIIVal <= 122 Then
RemoveCharacters = RemoveCharacters + Mid(InString, intLoopCounter, 1)
End If
Next intLoopCounter
End Function
Two requests:
1. Could the UDF be modified such that any part of a string contained within brackets is also removed (e.g. "NLGA High Street (West-Enfield), EN6" becomes "nlgahighstreeten")?
2. Can an argument be added to the format of the UDF, such that numbers (0 to 9) are either included or excluded (e.g. RemoveCharacters(A1,1) where the argument ´1´ would include any numbers (0 to 9), so "NLGA2003 High Street (West-Enfield), EN6" becomes "nlga2003highstreeten6")? ´blank´or ´0´would exclude these numbers, i.e. would return "nlgahighstreeten"
I have a column that is giving unwanted value . dont know the reason as that excel file has been created by some other guy and I just started working on it .
My Question is how to move to 2 cells left(A for example) from from that unwanted value column. and check if
A is equal to cell above it , means B Cell(Row above A but same column).
As my excel file is totally based on Forms, Macros, I am not quite familiar with macros.
Is there any way to put if condition in one cell (column) and drag it all the way down which should work for all the values in these 3 column.
And also if A=B then I want to make that unwanted value cell="".
I have this table
.......A.....B.....C....D
1.....I......a.....d.....g
2.....II.....b.....e.....h
3.....III....c.....f......i
As you can see, the number I has a,d,and g, II has b,e,and h, and III has c, f, and i
I want to make formula that if I make the input g it would return I, f would return III, and c would return III, and so on
I want to make four formulas by using VLOOKUP, INDEX, MATCH, INDEX&MATCH separately.
I have a set of data in an Excel 2007 spreadsheet and want to move it to Sheet2. I move all that I need except for one column which needs some work done to it and I keep receiving errors. Sheet1 Column 12 is comprised of six digits, space, six digits, space, and four more digits. What I need is the first twelve (12) digits, less the space, moved to column1 on Sheet2.
The code I am attaching does the following:
The year 2009 to Sheet2 Column2
Column6 + Column7 to Sheet2 Column3
Column8 + Column9 to Sheet2 Column4
Column6 + Column7 + Column8 + Column9 to Sheet2 Column5.
In cell A1, suppose I have a string "Forrest Gump", how can I get the "Forrest" part out using left() or any other function?
View 10 Replies View RelatedI have a cell and I only want to look at the word after the first 4 characters of every cell. I do not know the word size so right(...) didn't work for me, I just know the first 4 characters I do not need and the word follows.
View 9 Replies View RelatedHow can I use Len and Left together to ensure a workbook name begins with Order?
I've tried using Left("Order", 5) and didn't work.
Len(Activeworkbook.Name, 5) didn't work either.
I have a table with a range of numbers inputted as text (ie. 200-400, 300-500, 65-90, etc.) that I am extracting. I made a formula that works for pulling out numbers if they are in the triple digit range but don't want to rejig if they go down to double-digits, or up to quad. (too tedious to change the right and left count function midway if data suddenly changes)
The values that I am extracting are separated by -'s and when i use the formula below i end up with negative numbers if one of the pairs is less than 3 digits (ie. 2)
=VALUE(RIGHT('NAIC Spread 2007'!D11,3))
how can i work in a Len function to deal with this issue?
Obscure lines of info which I'm trying to break up into pieces. Being able to find from the right instead of left would be REALLY handy. See attached example with details and example!
View 3 Replies View RelatedI have a simple VLOOKUP that I can't manage to give the right answer. The contditions must be 'FALSE' as the the stock report database has so many similar numbers in it.
View 2 Replies View Relatedi have this issue, i named column J. now it says instead of using Social Security numbers as a unique identifier, they are considering using an ID of the first 3 letters of the last name (L Name) followed by the first letter of the first name (F Name). If the last name is fewer than 3 characters, the letter Z replaces each missing character.
View 3 Replies View Related