I am using =randbetween(1,100). however everytime i enter a new number elsewhere on the sheet, a new ndom number is made. Could you make a button (or something) that, when pressed, creates a random number in a certain cell?
View 8 RepliesI am currently working on sheet that i need to have print out user names and random passwords for as many people that entered on the sheet to a text file for email. I am running into a few issues.
1. When i try to print to a .txt file of the text from column G on sheet 'Review and Generate', all the text appears on one line. I have been trying to use the Char(10) to create line spaces, but that has not worked out for me. How do i get excel to export text from a cell to a .txt file with correct line spaces?
2. I have a random password function running on column F, however i am trying to get it only produce one result and not keep calculating random values. How do i have the cell calculate only once?
I have one worksheet which comes out of an online application (for the purposes of this example I will call it "Online Sheet"). The column headings in this sheets are always named the same but could theoretically appear in any column address. For example, the column header "Completed" could appear in column "X", or "AT", or "ZZ".
On a second sheet (called "Code Sheet") I have to unscramble all of this data into a standardize layout. Each row value has a unique ID which appears on both the "Code Sheet" and the "Online Sheet". However, in the "online sheet" the unique ID could also appear in any column. Like the "Completed" column this column also has a unique column heading ("Unique ID").
Using Match I can calculate the column number in which the "Completed" column appears in this instance of the online data. For example, "Completed" = Column "25". However, I now need to use some lookup function on this column based on the row in which my "Unique ID" appears of the "Online Sheet" (which could of course be in any column in the "Online Sheet").
For example, if "Completed" is in column "25" and the "Unique ID" which I am referencing on the "Code Sheet" appears on row 14 in the "Online Sheet", then the lookup formula must return the value of column 25 row 14 on my "Code Sheet".
I am looking for a template where I can have the Gap between Demand and Supply of Resources. This is to plan taking up new opportunities or not based on the supply.
View 2 Replies View RelatedMaybe the title shouldn't be simple or I am missing something starring me in the face.
I am trying to make a supply and demand graph, with the following table,
wage supply demand
45,000 200,000 325,000
40,000 220,000 310,000
35,000 250,000 300,000
30,000 290,000 290,000
25,000 310,000 275,000
20,000 320,000 250,000
I can make either a supply or a demand graph without problems, however no matter where I place the vaules, ie wage first, demand, then supply or demand, wage, supply, the graph will not work or look right. The wage must be on the left had side so that the graph complies with standard Supply and Demand. I also need to be abble to make another graph showing what happens with a wage cap.
I can do it on graph paper, put I can not find a way to do it using Office 2007 Word and inserting a graph option and using Excel.
I have a spreadsheet which uses MS Query to import data from our MRP System. This Spreadsheet has all new orders and qtys required per sales order etc. Each Part number may have several sales orders and different qtys for each. I am looking for help to write a fomula which looks the required qty`s for each sales order & part and check another sheet which has all the avaliable stock to sell on it and populate a column next to the qty req`d with what if anything is available.
Both the orders sheet and the stock sheet are MS Queries which refresh at a given interval so cells may change position.
Cutdown Example of Orders Sheet.
Sales Order No. ¦ Part ¦ Qty Req`d ¦
--------------------------------------
1234 ¦ Apple ¦ 12 ¦
6777 ¦ Apple ¦ 16 ¦
7989 ¦ Pear ¦ 4 ¦
cutdown Example of Stock Sheet.
Part ¦Qty in Stock ¦
----------------------
Apple ¦ 12 ¦
Pear ¦ 3 ¦
Now the fomula should bring back the following
Sales Order No. ¦ Part ¦ Qty Req`d ¦ Qty Avaliable ¦
----------------------------------------------------
1234 ¦ Apple ¦ 12 ¦ 12 ¦
6777 ¦ Apple ¦ 16 ¦ 0 ¦
7989 ¦ Pear ¦ 4 ¦ 3 ¦
Once you have created the supply and demand numbers and have put them in a graph or on a chart, how do you find the equilibrium point? Also, how do you show the equilibrium point on a chart.
View 4 Replies View RelatedI am currently using the following formula to calculate the average weekly demand of a product:
=SUM($G8:$CF8)/COUNTIF($G8:$CF8,">=0"))
It works fine, but sometimes the data I'm analysing doesn't span the full horizon (78 weeks). What I therefore want, is for the COUNTIF part to recognise the last populated Cell in the array, and to use the length of the array up to that point to calculate the average. Put another way, if I only have 52 weeks of data (the last populated Cell is $BF8), I want the COUNTIF to calculate based on 52 weeks and not 78 weeks.
How do I make a row of 5 random numbers in A2:A6 that are not the same as each other. It's basically for a Bingo card. I have a formula that can calculate the random numbers =INT(RAND()*15)+1 under the B's for example, but I can't seem to figure out how to make it so they are not the same.
How can I make sure that I can generate random numbers that don't repeat using the rnd function in VBA.
View 14 Replies View Relatedhow to Make a forecast for the demand for the time periods shown....
View 9 Replies View RelatedFor an economics assignment I would like to graph price elasticity with price on the 'y' axis and units on 'x'. I have not found a way to do this in Excel, can someone assist?
View 6 Replies View RelatedI have build a system that needs a lot of random numbers generated to work.
I have used what I thought would work to generate me these numbers like this example:
VB:
Lastrow = ThisWorkbook.Sheets("RPlay").Range("A" & Rows.Count).End(xlUp).Row
RPlayerNum = Int((Lastrow - 2 + 1) * Rnd + 2)
This would generate a random number into RPlayerNum variable, based on the list in sheet RPlay, missing off row 1 as the header.
However we have noticed a massive flaw in this code.... It works as long as the excel file is open, each time run it gives a different random number. However if you close the excel file and open it, then run it, it ALWAYS gives the same number first run, every time.
How to generate random 50 number with 10 group..
View 6 Replies View RelatedIs it possible to use the =randbetween() function to generate a random number between 0.8 and 1.2.
View 4 Replies View RelatedIf I generate a random number in cell A1 ranging from 1 to 3. Can I count how many times the result is equal to 2 if I was to run it 100 times and then show the results in cell A3.
View 9 Replies View RelatedI have a formula to generate a random number between 0 and 10.
View 10 Replies View RelatedI need a macro that will select a random number between 1 and 6. ie select the number of a dice. It needs to input 1 random value into one cell and another random value into another. Like the dice values of a monopoly game.
View 9 Replies View Relatedis if there is a way to generate random numbers between 0001 and 9999. I always need to always have 4 digits. The first couple of numbers can be 0 so that I can maximize the number of variations.
random number selection...
i have a list of 200 items (rows) and i would like to "randomly" select 30 of them...(next month i will get another 200...)
I get the following error whenever I try running a Monte Carlo simulation with iterations in excess of 64000 (The MC simulation calls the 'NormSInv' worksheet function at least once per iteration, and the argument to the 'NormSInv' function is always a standard normal RANDOM number also generated by Excel VBA): Run-time error '1004': Unable to get the NormSInv property of the WorksheetFunction class
Why do I inevitably encounter this error ONLY when the number of iterations exceeds 64000, for instance? Simulations with iterations < 64000 run smoothly without a glitch.
I am using the data analysis add-in to generate a random number (using the random number generation) using a normal distribution. The problem is, i want it to recalculate these numbers every time the worksheet is recalculated but the numbers seem to be values only.
View 2 Replies View Relatedi have worked in access using vba procedures. i can easily create a form in access that generates a random integer number between 0 and 20 and the user will guess the number between 1 to 20 if the random number is 16 and the user enters 14 the program will display a msg box saying too low or too high. here is the code .
Option Explicit
Private Const MAX = 20
Private Const MIN = 1
Private iKey As Integer
Private lTries As Long
Private Function Random() As Integer
Random = CInt(Int((MAX - MIN + 1) * Rnd() + MIN))
End Function
Private Sub cmdGuess_Click()
Dim lGuess As Long
now i have to do the same thing in excel create a program that will ask the user to enter numbers between 0 to 20 and see if the random number and user guess is same or not. but i have never worked in excel using vba procedures how can i achieve the same thing in excel using a vba procedures.
I have a random number generater but it creates a new random number whenever I recalculate the sheet or enter something in another cell. I would like it to choose a random number once and not do it again until a condition, specificaly a date, is met.
View 6 Replies View Relatedhow to put time delay on my program?
like it will generate again every 9 minute?
Private Sub CommandButton1_Click()
Dim x As String, i As Byte
Randomize
x = Format$(Int(Rnd * 1899) + 1, "0000")
For i = 1 To Len(x)
Me.Controls("TextBox" & i).Value = Mid$(x, i, 1)
Next
End Sub
is there any rule for random number to be picked up? Any Rule, Any Formulae, Any Calculation Anything, Any authentic routine which may guess what would be the next random number? for example if first random number is 825587 then what would be the next?
View 4 Replies View RelatedI have the following formulae to pick up a random number from 0 to 9999.
=TEXT(RANDBETWEEN(0,9999),"0000")
I want to start this random search from a specified number. for example if i press F9 it should show 3456 at first press and then onward.
I understand how RAND and RANDBETWEEN work, but have a slightly more complicated random number generation problem that requires a number that isn't solely between two numbers.
I have one cell that is randomly generating a number between 0 and 350 (we'll call this value A) and another randomly generating a number between 0 and 15 (value B). Then, I have a third cell (value C) that equals 15 minus B. Where I am having trouble is with a fourth cell (value D). This cell I want to have randomly generate a number between 0 and 350 but it needs to be D less than the value in A or C more than the value in A. Is there an advanced random number generation technique that can solve this?
I have a spreadsheet of 1000+ companies and I want to take a random sampling of 100 of them. I would assume this could be accomplished by auto-filling a numerical value to each line of data (which I did), then scrambling only the column with the numbers (which I can't figure out), and then selecting the entire text and resorting it to put the numbers back in order and then just work with the first 100 rows (which I can do, if I knew how to make the numbers random).
I have taken on a project that is would seem is far out of my league right now, but need to deliver.
I have attached the example spreadsheet what I am trying to achieve, which is basically a random automated number allocator.
Look forward to receiving your replies,
Example.xlsx