How To Delete All Rows Which Begin With MEANING
Aug 18, 2012
I am preparing one macro and to make below macro more easier.
My Data is not constant. Everyday it get change.
In my data i am trying to delete all rows which begin with "MEANING".
I have prepared below macro but problem here is in range i am taking maximum rows i.e 65000 as i am not sure how many rows will be there in my data which begin with Meaning.
I just wanted to know what is the coding we use to go down untill data end if we are not sure about the range.
Selection.AutoFilter Field:=1, Criteria1:="=MEANING*", Operator:=xlAnd
Range("A3:A65000").Select
Selection.SpecialCells(xlCellTypeVisible).Select
Selection.EntireRow.Delete
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Dec 30, 2009
I have a spreadsheet that contains private information, but I'm hoping this is a simple request. If the cell in column A does not contain text that begins (starts) with the letter "L", the row needs to be deleted. The rows that will be deleted usually start with "A2008..." "A2009..." "E2009..." etc. The row I need to keep always starts with "L", then a space, then more text.
I'm looking for VBA code that I can implement into a macro program I have already done so that once I open up a file, I can click a button and not have to do this part manually anymore.
[Code]....
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Dec 30, 2009
I have a spreadsheet that contains private information, but I'm hoping this is a simple request. If the cell in column A does not contain text that begins (starts) with the letter "L", the row needs to be deleted. The rows that will be deleted usually start with "A2008..." "A2009..." "E2009..." etc. The row I need to keep always starts with "L", then a space, then more text.
I'm looking for VBA code that I can implement into a macro program I have already done so that once I open up a file, I can click a button and not have to do this part manually anymore.
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Feb 9, 2007
The following code was posted in another thread:
Private Sub UserForm_Initialize()
Dim a, v, x, ws As Worksheet
Set ws = Sheets("Scheduled Courses")
a = ws. Range("a2", ws.[a65536].End(xlUp)).Value
With CreateObject("scripting.dictionary")
For Each v In a
If Not IsEmpty(v) And Not .exists(v) Then
.Add v, Nothing
End If
Next
x = .keys
End With
With Me.ComboBox1
.Clear ' clear the listbox content
.List = x
.ListIndex = 0 ' select the first item
End With
End Sub
How are the brackets used in the 4th line? I have not seen this notation before. Is this some kind of a shorthand for a Range("A65536") reference?
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Jul 15, 2009
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Sep 25, 2012
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Apr 16, 2014
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see the desired result tab in the sheet to get an idea of what I am looking for as the end result.
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May 22, 2008
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Feb 20, 2008
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123456 | 1.001 | Paul Jones | Project Manager | 20/02/2008 | 3.5
[Code]....
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May 10, 2012
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Sep 30, 2008
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123456 | 1.001 | Paul Jones | Project Manager | 20/02/2008 | -2.5
123456 | 1.001 | Paul Jones | Project Manager | 20/02/2008 | 3.5
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123456 | 1.001 | Jo Brown | Developer | 20/02/2008 | -7.5
123456 | 1.001 | Sam Smith | Architect | 20/02/2008 | 7.5
Should be processed and come out like this:.......................
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Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1 As Variant
Dim ar2 As Variant
Dim ar3 As Variant
Dim ar4 As Variant
Nr = 20
ar1 = Array(11, 14, 19, _
20, 22, 25, 26, 27, 28, 29, _
30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, _ .................
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Mar 5, 2008
This sheet has A:K columns and 1:3212 rows. There are 'page headers' that are in the text file that I want to delete (the text file was exported from an AS400 program). The first row that starts the page header has SA341 in column 1. Each page header has 5 rows. I used this code from one of the other threads on deleting rows, but I obviously do not understand the code as it deleted all rows that contained SA341.
Sub DeleteRows()
Column_To_Check = 1
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Next Row_Counter
End Sub
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