IF(ISNumber): Returning A Value For The Alpha-numberics That Begin With DMR
Jan 28, 2010
See attached file...I'm having trouble returning a value for the Alpha-numberics that begin with DMR, which should return 'Dishwasher'. All other values are correct, I'm sure it has to do with the character range but I'm a little stumped.
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Jan 20, 2009
we query SAGE, and have account codes begining xx-xxx. We use the project ledger which attaches a letter on the end depending on the works, i.e. 00-001A, 00-001B, etc
I need to set a paramater to say any that any that begin/contain (i.e. LIKE %) 00-001 filter out, regardless of the letter.
I know the basics of [paramater] or ?, but the ? doubles as a wildcard in the like criteria. Whenever I try to put a paramter value in it shows nothing. I can get it to work for exact, >< etc but not contains or begins. Even if I play with the SQL, nothing!
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Dec 30, 2009
I have a spreadsheet that contains private information, but I'm hoping this is a simple request. If the cell in column A does not contain text that begins (starts) with the letter "L", the row needs to be deleted. The rows that will be deleted usually start with "A2008..." "A2009..." "E2009..." etc. The row I need to keep always starts with "L", then a space, then more text.
I'm looking for VBA code that I can implement into a macro program I have already done so that once I open up a file, I can click a button and not have to do this part manually anymore.
[Code]....
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Aug 18, 2012
I am preparing one macro and to make below macro more easier.
My Data is not constant. Everyday it get change.
In my data i am trying to delete all rows which begin with "MEANING".
I have prepared below macro but problem here is in range i am taking maximum rows i.e 65000 as i am not sure how many rows will be there in my data which begin with Meaning.
I just wanted to know what is the coding we use to go down untill data end if we are not sure about the range.
Selection.AutoFilter Field:=1, Criteria1:="=MEANING*", Operator:=xlAnd
Range("A3:A65000").Select
Selection.SpecialCells(xlCellTypeVisible).Select
Selection.EntireRow.Delete
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Nov 21, 2012
I am trying to create a formula that sums all the cells that have numbers that begin with 12. For example, here are the numbers in cells A1 through A6 (my actual spreadsheet is much larger):
12
1200
13
1
120
112
I want to pull the 12, 1200, and 120 for a total of 1332.
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Jul 25, 2006
in excel how do I count cells that begin with specific text. Ex: in a
column with 100 entries, I want to count the number of cells that have the
letters "app" from the word approved as the first three characters in the cell
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Sep 3, 2008
I am trying to write a piece of vba that clears the contents if the first character in the cell is not #.... if I use "#"*, I get a syntax error
Just figured my syntax needs a slight adjustment to be recognized...
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Mar 31, 2009
I have a column that has values ranging anywhere from 1 to 999,999 and I need a way in vba to take whatever value is in the specified cell and place a decimal point at the far left. Example:
change 175526.34 to .17552634
change 376.1 to .3761
change 22987.254 to .22978254
when the code is run I need the selected number to begin with the decimal point.
See, the tricky part is that the length of the number varies and I cant just divide by X to shift so many places to the left..
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Nov 12, 2008
Im using ISNUMBER in a spreadsheet to automatically add a ref number to an entry in the spreadsheet, this is based on the value of a set column. To give you an idea the values are bus services, i.g. 6, 123, 56 etc, when the column has a bus service number entered it auto produces a ref number.
Now the problem is now some service numbers have letters in e.g. X14 X12 36A etc, now these are not recognised and therefore no ref number is given, is there a way of changing my formula to recognise this.
The formula at the moment is as follows
In the ref column (which is locked) =IF(V4=1,COUNTIF($V$3:V4,V4),"")
In column V (which is locked and hiden) =IF(ISNUMBER(D4),1,"""")
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Jul 24, 2009
The following formula:
=IF(ISNUMBER(F35)="TRUE","",IF(ISNUMBER(E35)="TRUE","X",IF(ISNUMBER(D35)="TRUE","XX","XXX")))
is returning XXX when copied down, where I expected it to return XXX as well as XX, X and " ".
Has anyone got a clue what I'm missing (might be a friday afternoon thing...).
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Apr 21, 2006
I am faced with the daunting assignment of adjusting a payroll report using infrequently exercised logical expressions. I've been careful to try and build my formula adjustments in intermediate steps, so I could test the results, but I can't seem to get past a dual test. I need to create a commission calculation if there are no values in the two columns immediately left of my active cell,col N79, i.e., if L79 OR M79 contain a value, then do nothing, otherwise, multiply contents of G79 * the commission rate contained in named cell "Split3".
This formula works on a single column test:
=IF(ISNUMBER(M79)," ",G79*Split3)
But I can't seem to construct a formula to test both column cells. I have tried this unsuccessfully:
=IF(OR(ISNUMBER(L79),ISNUMBER(M79)," "),G79*Split3)
The above formula is accepted, but I get: #VALUE, with the explanation:
"A value used in the formula is the wrong data type"
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Sep 27, 2007
I need to create a formula (Sumproduct) that will look at two criteria then total a third column IF the value in the cell of the third column is a number.
The sumproduct will look at one range A1:A100 and see if it matches initials in cell D1, and it will look at the year in column B1:B100 and see if it matches the year in D2. Then it should total the amount in column C1:C100. But the column C to be totaled includes both dollar values and “N/A”. So If I use something like:
=SUMPRODUCT((A1:A100=D1)*(B1:B100=D2)*(C1:C27))
I get the #NAME? I believe because some of the values are N/A instead of numbers. So can I say something like:
=SUMPRODUCT((A1:A100=D1)*(B1:B100=HD2)*(ISNUMBER(C1:C100)*(C1:C2100)))
(I know this probably isn’t even close, but I hope you can see what I want to do)
I know I can create a separate column to show only the dollar values from column C and use the sumproduct to total that column, but is there a why to skip that step?
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Nov 28, 2007
Can someone tell me how to have 2 options using isnumber.
I'm using ISNUMBER(SEARCH("SUBMITTED",N156)) but I'd like to have "SUPPLY" & "SUBMITTED"
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Oct 17, 2008
Here is some of my code. It does not seem to work though. can you fix it?
Dim Madrid As Integer
Dim Paris As Integer
For n = 7 to 17
Madrid = Application.WorksheetFunction.IsNumber(Sheets(3).Value("P" & n + 1).Value)
Paris = Application.WorksheetFunction.VLookup(Sheets("Sales").Value("$E:$I"), 3, False)
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Jan 8, 2009
I have this formula, I have 2 cells that i eneter times in, I would like to have the formula do this..
I would like to have it only display if there is a value in the cell. If value is in both cells then it would display both cells
=TEXT(Inbound!AP25,"h:mm AM/PM") &" / "&TEXT(Inbound!AP40,"h:mm AM/PM")
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May 28, 2006
Can anyone identify the error in my looping? My IsNumber(f) is not working. If I enter a string, an error message will pop up, but if I enter a number (e.g 4 or -4), the same error message pops up too...what can I do?
I cant really set the inputbox to Type:=1, because I want this inputbox to be optional to the user, i.e If user does not enter anything, it will return a 2.
Sub frequency2()
'Get the frequency of coupon payments per year
frequency = Application.InputBox("Please enter the frequency of the coupon payments", _
"Frequency of the coupon payments", , , , , 1)
'If c = 0 Then 'If it is a zero-coupon bond, set the frequency of coupon payments to 0
'frequency1 = 0
'Debug.Print frequency1
'ElseIf frequency = False Then
'frequency1 = 0
'Else
frequency1 = determinefrequency(frequency)
Debug.Print frequency1
'End If
End Sub
' This function automatically sets the value 2 to the Frequency of Coupon Payment of the Bond if the user
' did not enter anything when prompted.
' It also validates if the user entered negative numbers
Function determinefrequency(Optional ByVal f As Variant) As Variant
Dim testt As Boolean
Do
' If values have been entered into the inputbox and
' the userinput is a number
If Len(f) > 0 And WorksheetFunction.IsNumber(f) Then
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Jul 14, 2009
I have recorded the below code, is it possible to adjust this so that instead of using "USD" the macro will reference whatever currency the user inputs into say sheet1 cell A1?
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Dec 20, 2011
formula to check a range for any text entires by error.
Example: I have a range of numbers on column A1:A1000, at the end of this range on A1001, I have been trying to use the following formula...
=isNumber(A1:A1000)
if like on A7 it had "525a" instead of "525".
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Jan 24, 2007
I have a problem with isnumber giving me two different results. One time it will evaluate the following as true:
ISNUMBER(0)
and in the same sheet it will evaluate the same as false.
I need ISNUMBER to NOT recognise "0" as a number all the time.
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Feb 21, 2010
I've been trying to use excel's Isnumber or Istext function to evaluate a range of cells, but have been unsuccesful so far. Is it even possible? or is the formula just restricted to evaluating only single cells?
For example, if I do, Isnumber(A1:A10), is there any way to make that work?
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Jan 13, 2005
I am trying to create code that deletes lines in a spreadsheet when the first column is either blank or has text in it. However, when writing the VBA code, ISNUMBER and ISTEXT do not work. Amazingly, ISBLANK does work.
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Aug 11, 2014
I'm trying to develop a formula that can incorporate the search function in amongst a countifs formula. I have a column that contans the string "2.3 Manage Project Delivery" in a single cell. However, a single cell could also contain this text string in amongst other text and be in there multiple times - E.G; "2.1 Manage Customer Support, 2.3 Manage Project Delivery, 2.4 Close Program, 2.3 Manage Project Delivery" etc
My formula currently looks like this: =COUNTIFS('RDC Register'!$AW:$AW,"Not Overdue",'RDC Register'!$C:$C,"2.3 Manage Project Delivery") but it's not counting the cells that have 2.3 Manage Project Delivery in it more than once.
So basically I need to modify my formula to search for this text string in the cell and add all occurrences to the final count.
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Jan 14, 2009
the attached document. I wish to try and conditionally format Sheet1!D:D depending on if Sheet2!E:E displays a particular letter, when; Matching Sheet1!A:A to Sheet2!A:A Matching Sheet1!B:B if <11 to Sheet2!B:B where cell equals text "Small (7-10)" if Sheet1!B:B is >10 then where Sheet2!B:B equals text "Mid - Large (11-16)"
Matching Sheet1!C:C if cell contains "Hcap" to Sheet2!C:C where cell equals "Handicaps". If Sheet1!C:C doesnt contain "Hcap" match to Sheet2!C:C where cell equals "All Races".
To use an example, if E:E in the cell adjacent to all the matches above equals N then the cell in Sheet1!D:D turns red. Cell D52 would become red. D88, D91, D92, D93 and D96 would also become red. Here was my attempt at the formula, no idea if I was close to the answer.
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Jul 23, 2008
If A1= 5 ; C1= #N/A ,F5= 7 and E7= 8
Any formula which can average if isnumber A1,C1,F5,E7 ?
it shall ignore errors in this case.
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May 25, 2007
I have this search function that works well: =IF(ISNUMBER(SEARCH("which is < ",E9)),"test ok", "not ok") my E9 cell contains the phase: "I have a number which is < 9, and which is positive..." E9 has "which is < ", then i get back "test ok"
My question is.... how can I do this multiple times within the same function/cell. i.e. if I wanted to search "which is < " and/or "positive" in the same cell, then i get back "test ok", "positive number") I keep trying all combinations to no avail, like: =IF(ISNUMBER(SEARCH("which is < ",E9)),"test ok", "not ok"), =IF(ISNUMBER(SEARCH("positive",E9)),"positive number", "no good")
Keep in mind I am using a numeric example, although I am using this function to check if part of a cell matches specific text...
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Jun 8, 2007
I am using the ISNUMBER formula to verify if specific text is found in a string of text.
This formula worked when I only needed to find 1 particular brand name:
=IF(ISNUMBER(SEARCH(""BrandB"",RC[6])),""B"",""C"")
Now I need to have 2 different brand names ("BrandB" and "J & B") that need to return a "B" and all others should return a "C".
I found a thread regarding this same topic, but I could not get their solution to work for me.
They recommended using:
=IF(ISNUMBER(SEARCH("BrandB",RC[6])),"B","C")&", "&IF(ISNUMBER(SEARCH("J & B",RC[6])),"B","C")
The fact that my second brand name is written with spaces ("J & B") could be adding to the problem, I don't know. I thought replacing the "C" with another "IF(ISNUMBER" function should work, but I have been unsuccessful at writing a formula that doesn't cause run-time errors.
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Jan 26, 2014
I am checking whether or not two different cells contain a number or the error #NA.
If one of the cells contains a number then the result will be that number.
If both cells contain #NA then the result should be “99â€
Example:
Formula in Column C
The values are in columns A and B.
If the value in cell A is a number the result is A.
If the value in cell B is a number the result is B.
If the value in cell A and B equal #NA the result is 99
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Mar 24, 2009
I have 4 cols, x rows. I need Column C to check Column B for a numerical value, and if true, return the value in B, and if not true, then return value from A. Column B are functions formatted as general. The reference made by Sheet2!B is numbers formatted as text as to retain leading zeros. Here is what I have so far
=IF(ISBLANK($B10),$A10,$B10)
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Nov 5, 2008
I want to use the SumIf function to sum cells when other cells begin with certain characters.
I've toyed with a few ideas of how this could work, but i don't know how to specify that the cells need to begin with certain characters. The cells that would be the criteria and the ones that would be summed come out of an Oracle database (and i have no control over the way they're pulled out - yet) so the beginning characters are connected to extremely unique information, so i dont want that to be included in the if part, for obvious reasons.
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Dec 30, 2009
I have a spreadsheet that contains private information, but I'm hoping this is a simple request. If the cell in column A does not contain text that begins (starts) with the letter "L", the row needs to be deleted. The rows that will be deleted usually start with "A2008..." "A2009..." "E2009..." etc. The row I need to keep always starts with "L", then a space, then more text.
I'm looking for VBA code that I can implement into a macro program I have already done so that once I open up a file, I can click a button and not have to do this part manually anymore.
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