i need to calculate the median of numbers in column m. which numbers i want to include will be calculated by checking their number in their row in column a.
so.. column a is ages of surveyees, column m is how long they sleep per night. i want to calculate the median sleep per night of 9 year olds.
We are trying to find the median of a large set of numbers to calculate the median income in 2010. For an example we have 8,379k people with $2500 average income, 9,783k with $7500 average income and so on. How can I calculate the median average income of such a large amount of entries?
View 8 Replies View Relatedhow to find the median for a list of numbers using =median(). But what if I have a list of prices for different types of say cars.
Car Type Price
A $10000
B $15000
A $20000
C $30000
Is there a macro that will return
Car Type Median
A $
B $
C $
In A2:A9 are text "time" numbers which may cross midnight
1941
1852
0130
2347
0242
2326
0028
2257
Looking for formulas to place in A10:A11
which can return the average & median of the times in the same text "time" format
It's probably best if you open up the attached example spreadsheet that contains sheets "Before" and "After" otherwise it might be pretty difficult to understand what I'm talking about.
So I have this spreadsheet where I have part numbers in column B, status of the orders in Column I and lead times in Column M. What I want to achieve is to get of Mode (col N), Median (col O) and Average (Col P) values of each part number and each of its status using the lead times in Column M. If possible I would only like this on the top lines of each of these. I have done the formulas manually on sheet After so if you click on the formula you can see the range's it covers.
I did create a concatenation in column K (conc of column B and I) as helper column because in theory this might make things a little bit easier.
Now going into second part. I would also like to do something very similar but only using the part number and status "Finished" and get the values in columns T,U, and V on the top row of each part number. I made some blue boxes and arrows to kind of point out the idea.
The solution can be either formula based or macro, it really doesn't matter, however I will intent to use it within macro either way.
I have long series of data in 8 columns (B, F, J, N, R, V, Z, AD) starting at row 5 down to row 86404. I want to find the total median for each row, where a condition is met for that row. The condition is if number>10 and the number is located in row 3 for each column (i.e., B3 for column B). So, if B3, J3, R3 are all >10, then I want to find the median for all the numbers in the columns B,J,R.
I assume there is an array formula that could do this? I've tried a few solutions with no luck.
I have a list of part numbers which repeat when there are multple prices they were sold at. For each unique part number I need one median price. The list if of about 500 parts but with the various different prices the file is 3700 rows. How can i do this quickly? For each unique part number I need one median price.
View 3 Replies View RelatedI am trying to find the median of a set of numbers on a column that correspond to dates on the left column. I want a monthly median average of the numbers on the right which correspond to the dates on the left. So for example. I want to make an equation that gives me the median of all the numbers on the right if they fall within the range of a certain month(in this case October). I've tried These:
=IF(COUNTIFS(A:A,">=10/1/12",A:A,"
I work for a charity and I have to cancel the donations of people whose credit card donations have been declined in three consecutive months.
If in Column A I have a list of donor IDs whose credit cards were declined in Jan 2008, in Column B I have a list of donor IDs whose credit cards were declined in Feb 2008 and in Column C I have a list of donor IDs whose credit cards were declined in Mar 2008, is there a way of showing in a fourth column which donor IDs were common (repeated) in Columns A, B and C? I would have a title for each column in A1, B1 and C1, and also the column where the repeated donor IDs would be displayed.
I need to compare two colums by number decription for example m344 in one column and fsh344-1 in another. All I want to match is 344. In column a I want to indcate the match by placing an X by each match. View my attachment for reference. I don't know if it makes a difference but the columns are centered in my original spreadsheet.
View 8 Replies View RelatedI have a database of employees with 7 different variables [Year, JobFunction, PreviousIndustry, PreviousRegion, Degree, Experience, CollegeMajor] of which I would like to be able to select any number of and find their median/max/min/etc salary.
For example, I may need to know the median salary of all employees who started in Year 2006, who work in accounting, and have an MBA.
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Rather than copy and paste my 7 variable AVERAGEIFS function, I'm just going to use a two variable example here to keep things simple.
I had no trouble doing what I need with this 2 variable AVERAGEIFS function like so;
{=AVERAGEIFS(Salary,File,$A$3,JobFunction,$A$6)}
...where Salary, File and JobFunction are the names of a cells in another worksheet and $A$3 is a drop down menu that I can select the File Year and $A$6 is a drop down menu where I can select the JobFuction.
Now I would also like to have the same kind of conditional "IFS" filtering with the MEDIAN function, but I have been unable to figure it out since Excel doesn't have a MEDIANIFS function. This is what I've tried so far;
{=MEDIAN(IF(AND(File=$A$3,JobFunction=$A$6),Salary))}
but this just returns "0" which obviously means I'm doing something wrong, can anyone help me out here?
Note: I was able to get it to work with just a single variable just fine like so;
{=MEDIAN(IF(File=$A$3,Salary))}
but trying to add the second [and eventually 3rd, 4th, 5th, 6th, and 7th] conditions is the problem.
Is there a good/easy formula to use when trying to find the mean, median and mode for a column? If so, can someone post it? I'd like to make it as easy as possible (obviously!).
View 6 Replies View RelatedI have 5 numbers (can be with decimals) in column A (A1:A5). For these
numbers, I want all combinations as well as the median of these
combinations.
I'm pretty far already. However, the median seems to be calculated
wrong.
I have a list of hotel IDs in one column of my spreadsheet. In the next few columns, I have ratings that customers gave the hotel for cleanliness, location, room, etc.
What I need to do is calculate the median of all the ratings for each specific hotel, in a separate column.
An example of what I have: ...
Is there any way to do a weighted median in Excel?
Consider this example: ....
I have two columns of data, one is the price per unit, the other is the quantity sold at that price. I'm trying to find the median selling price, but MEDIAN doesn't work correctly and I'm not sure how to tell the function to count each price the actual number of times it was sold.
I actually believe I've found a work-around for this problem - I sort by price and use a SUM function to figure out where the middle is...I just feel like there should be an easier way (for the future).
Is there a way to get median for a subtotal?
median(SUBTOTAL(1,G7:G1747)) is not working.
I have a list of ages 10-65 and then different number of participants associated with each age, ie: 10 - 5,071, 11 - 6,069, 12 - 8,465, etc. to age 65. I am try to calculate the median age of all participants.
View 9 Replies View RelatedThe following is a sample data. Col A has years, Col B has values. I want in Col C, median for each of 1 year, 2 year, 3 year. Currently I am sorting the data on Col A and then enter the Median formula in Col C for each range (1 year, 2 year etc..). What I would is to have a formula in Col C that automatically calculates the median without having to sort Col A. The formula should work if the data in Col A changes ...
View 9 Replies View RelatedI have a sheet of many rows a small sample attached. Column A list 3 races at times4.05,4.40 and 5.10...col b contains the names and col c a number for each name.
In col d from d2 to d11 in each cell I need the median number of col c for the race at 4.05...in d12 to d24 I need the median number of the race at 4.40 etc...My sheet has thousands of races..
Hi, Im using a array in Excel VBA, i got a method which looks at a element no of the array as as a return for that array, i have got it to sort the array, i just need some help to find the middle number (median) of the array.
View 6 Replies View RelatedPicture 2 rows and 4 columns.
The top row is just 0, 1, 2, 3
The bottom row is something like: 850, 790, 200, 250
Here's the problem: I want to find the midpoint of the data set in row 2, based on the values in row 1. So, the sum of the data in row 2 in this example is 2090, meaning the midpoint is 1045.
If we were traversing along the top row as a line, we'd find that midpoint somewhere in the 0.3 range... but how do we get that value?
I am trying to calculate the median difference between two dates but I am running into trouble. Here is sample data:
A B
1/1/13 2/1/13
1/2/13 2/5/13
1/4/13 1/25/13
1/7/13
1/10/13 1/18/13
I want to be able to type notes into column B such as "closed" or simply "X" (so i can keep track):
A B
1/1/13 2/1/13
1/2/13 2/5/13
1/4/13 1/25/13
1/7/13 X
1/10/13 1/18/13
I tried this:
in column c, use "datedif" function then calculate median from column C values.
problem: if left blank, value in row 4 comes up as #NUM!. if text is entered, value comes up as #VALUE!
I also tried this array: =median(abs(B5:B1-A5:A1))
Should i be trying the medianif function?
I have a nifty formula that conditionally tots lots of figures up, and conditionally tots up another set of figures up and divides them to create a percentage
=SUMIFS(INDEX(MATRIX!$S$1:$BC$5933,0,MATCH($D$2&$D$3,MATRIX!$S$1:$BC$1&
MATRIX!$S$2:$BC$2,0)),MATRIX!$N$1:$N$5933,$H12,MATRIX!$L$1:$L$5933,$D$5)
/SUMIFS(INDEX(MATRIX!$S$1:$BC$5933,0,MATCH($D$2&$D$3,MATRIX!$S$1:$BC$1&
MATRIX!$S$2:$BC$2,0)),MATRIX!$L$1:$L$5933,$D$5)
There are 4 conditions in the first part of the formula and 3 conditions in the second one. A division and a neat little percentage.
What I would like to do is add a median to this.....
Essentially I want the formula to 1. Calculate the same as above (as I need the median to be based on the percentages) and then there should be 18 figures that I would like to median
Is a nested sumif and a median possible?
how would I find the median of a group of numbers? I have a database with a group of numbers associated with a part number. I need to find the median of each part. Here is what I have tried, but it doesnt work =MEDIAN(IF(A:A=A2,B:B))
View 5 Replies View RelatedI have a list of properties with dates of purchase and sold, i need to find the median of a range subset with it that have an sold value equal to S. I cannot see to get the date range and sold value S in the subset so I can calculate the median, this is what I have but I dont think it is right.
=MEDIAN(IF(Sheet1!$H:$H>=F165,Sheet1!$G:$G))
where H is the date column, G is the price, I have F column for the sold value, not sue how to put it all together.
I am looking to asign values of +/- above and below the median of a range of numbers, then calculate the results.
worksheet attached
excel macro and i would like to ask u if i want to calculate a median of column of data and then the result i need to put in a new column with row by row....i need how to write the coding?
View 3 Replies View RelatedI am really new to VBA programming and I have to automate an excel sheet which has the columns Closed Qtr, Apps Bucket and Res Time.
Closed Qtr has the following entries: Q107,Q207,Q307,Q407,Q108,Q208,Q308,Q408.
Apps Bucket has the following entries:
BU Apps,Global Apps,Quality,others
I have to find the median of the Res Time data based on grouping by Closed Qtr and Apps Bucket, i.e., for BU Apps in Q107, BU Apps in Q207 and so on.
Is it possible to submit the MEDIAN() function as an array (ctrl + shift + enter)?
I.e., I would like to submit a function similar to this SUM() function:
{=SUM(IF(("a"=$A$1:$A$7),$B$1:$B$7,))}
However, when I submit
{=MEDIAN(IF(("a"=$A$1:$A$7),$B$1:$B$7,))}
it does not give me the intended result.
