My question is about converting a Literal String to Character Code. I'm using the following coded InputBox. And it prompts the user for what characters to search for in a string.
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For icount = 1 To LenComputername
valComputername = Asc(Mid(UserComputername, icount, 1))
Next icount
If the computer name is NAMTOK-PC Then the LenComputername is 9. Does that mean then that the valComputername is equal to 78?
Junior Fit Softstyle T-Shirt
Antique Cherry Red
Junior Fit Softstyle T-Shirt
Antique Cherry Red
Softstyle T-Shirt
Antique Heliconia
Softstyle T-Shirt
Antique Heliconia
Softstyle T-Shirt
Antique Heliconia
This is column a and b. Looking at b I am looking for a formula that will pull the first capital letter out of each word like ACR to create color codes.
I would like to be able to record keystrokes in a macro that mimicks the keystrokes, not the contents of the cells.
Like this:
I select a random cell, start the macro, and the macro should: ....
I'm looking for some VBA code that would look at a column of data, look at each cell value in that column and if the cell value starts with the letter 'G' and the 5th character in that cell is not 'Z' or 'X' I would like to highlight that cell. Example:G123-123 would be highlighted whereas G123Z-123 would not.
View 4 Replies View RelatedI would like to get the nth character from a string. For example, let's say there is a string "jupiter", and I would like to get the 3rd character of this string, "p". Is there a function in excel vba that would allow me to do this?
View 9 Replies View RelatedI was wondering if it was possible to do something like this:
x = 15
test = "x"
MsgBox (test)
with the message box saying "15" instead of "x". I guess more specifically what I want is:
x = 15
test = Range("A5").Value 'Range("A5").value = "x + 2"
MsgBox (test) 'I want "17" to be outputted
Is this possible? Somehow convert the string test into an integer and read the variable?
I have this data and want to extract the character after the letter Y if the string has a Y in it.
Example data Output
AU 2013 OD ANR B24 Y2 2
AU 2013 OD ANR B24 Y4 4
AU 2013 OD ANR B24 Y5 5
AU 2013 PD HLD NOV B SPA
AU 2013 PD HLD NOV C SPA
AU2013OD ANR B25 Y1 1
AU2013OD ANU B25 Y5 5
AU2013OD WCR FPVN B49
AU2013OD Y6 FPVN B49 6
AU2013OD WCR FPVN B40
AU2013OD WCR FPVN B43
I want to assign a value to a character or string
Like I have formula p2p3= (n-1)*p +(2*e)
I want to assign values(number) to n,p,e.............so that i can get p2p3....like want to assign 'n'=4
I don't want to use cell number for calling values of n,p,e
How can I evaluate just the first part of these stirings so I can just do something like Left("Ca",2)?
View 2 Replies View RelatedHow do I split the below character or similar strings into 2 columns of 25 characters each without cutting a word off?
BONE CURETTE-RVERSE ANGLE 5.5MM WIDTH-MEDIUM/BAYONETED
I have a web query that returns a city and state, but the last character of the state is lower case. I need VBA code to change the last char to upper case. Here is what I have so far:
Code:
tmp = Cells(4, 1).Value
Mid(tmp, Len(tmp), 1) = UCase(Right(tmp, 1))
Cells(4, 1).Value = tmp
Is there any easier way to do this without 3 lines of code?
I have some columns in the excel file:
/path1/xyxxx/cccccc/filename12.txt
/path1/bxgdgg/gfdfacc/filenameeee8.txt
/path1/tttwrw/ccefecc/ddddd/filename56.txt
And I would like to delete everything before the LAST slash(just filenames)
filename12.txt
filenameeee8.txt
filename56.txt
I have a column that has various codes such as "E123" and "X456" and "S345". I just want to extract the numbers and leave the letters in each cell. How do you write a formula using the LEFT function to extract the last three numbers?
I'm currently trying to copy a dynamic range based on the row number of a selected listbox item. I'm able to get the row number of the selected listbox item from the data tab in my file. I, however, am stuck when it comes to copying a fixed column / varying row range from this tab and copying it over to another tab.
Private Sub CommandButton2_Click()
Dim ID As Long
Dim Row As Long
Dim Cnt As Long
Dim SearchTermsStr As String
Dim SearchTermsRng As Range
[Code] ....
SearchTermsRng is returing "Nothing" but the SearchTermsStr returns "F3:O3"
Is there any way in VBA to convert a Variant into a String? This code doesn't seem to be valid:
Dim vName As Variant
Dim sName As String
vName = "John"
sName = CStr(vName)
I have a cell that has approx 22000 characters. I'm trying to remove a specific character string from a cell by doing a find and replace with "". It works for characters in the first part of the cell but not for characters in the last part of the cell.
Example: I do a find/replace for the characters 21242 to "" in column A and I get the expected results. I do a find/replace on 69294 to "", again I get the expected results, but if I do a find/replace on 85203 to "", I get "Excel cannot find what I am searching for" (but its there!)
My cell size is within the max size of 32,767 characters so not sure why its not working.
Attached a sample worksheet.
I would like to find the position of the last occurrence of a character in a string. For example, I have a string with the following:
"c:wwgpeToolbidsTest File.GP$".
I would like to find out the position of the last '' in the string because I want to pull the filename, 'Test File.GP$' into a variable. I would like to avoid writing code to do this. Are there some Excel functions I can use for this?
I have a macro that asks the user to enter a file name and have written a small function to search the name given to the file to find any invalid characters, trouble is I must be doing something wrong as I doesn't work. Everytime I write something in the box I'm told it's invalid, regardless of weather it actually is or not.
Function -
I am trying to work out how to get nth position of a character in a string. For example in this
Code:
kjishdfiuayigdscka
if I use the formula
Code:
=FIND("i",I$1),
it will give me answer 3. But I want the position of 3rd "i" in the string. The answer should be 12. How can I change this formula to get the correct result?
In cell A1 contains a string, how do I get the number of position of the last numeric character from right to left (this value will be in cell B1).
Example: 12543AR3372C31WWW (In Cell A1)
4 (In Cell B1)
The barcode lablels all have the following format: A318639....that is a letter followed by six numbers.
When I scan the barcodes into any cell, a dollar sign "$" appears in the front of the barcode string that is entered into the cell. The dollar sign is not a relevant part of the string of characters in the barcode label.
What I am looking for is a solution where upon scanning a barcode into any cell, the dollar sign is removed from the front of my string and I am left with just the seven character string which is shown above.
I have experimented with the Data Validation tool by trying to limit the number of characters that are allowed in a cell to seven characters, but that has not actually removed any characters from my data string.
on the web I've found this formula, which returns the postion of the last occurrence of the character in cell B1 in the string in cell A1:
=MAX((MID(A1,ROW(INDIRECT("A1:A"&LEN(A1))),1)=B1)*ROW(INDIRECT("A1:A"&LEN(A1))))
How do I turn this into a VBA function?
I have a problem in converting text to columns for a string that has 1000+ entry's. Excel bumps me out after 851 using the Split function.
The data I can only download in a text format has >1000 fields that are seperated by ",". Not a problem so far but when I attempt to convert to columns there is a maximum limitation of 851.
Data1,Data2,Data3,Data4...................Data1000,Data1001,Data1002 etc...
I have tried:
Sub Split_Delimeter()
Dim Words() As String
Words = Split(Cells(2, 4), ",")
MsgBox "String contains " & (UBound(Words) + 1) & " words"
End Sub
I have a set of letters in a single row DISATAGFOORCBORDQFINFCOBBKIEHDSMCNRSKARDFCJSLCQCECFVSBCBOYKPVYKC. I want to distibute them across 5 columns such that each letter occupies one cell. I might want to specify a different column width later on so the solution should be flexible.
View 5 Replies View RelatedI am trying to check my sheet names to see if they convert to a valid date format. If it doesn't, then I want it to check for the next criteria (ex - if it equals "Page2"). With the code below I keep getting an error of type mismatch. Code is below.
[Code] ......
I need to be able to locate a date in a spreadsheet bassed uppon a user input date. I am looking for the week that contains the user's date. However it seems even if I initialize the value as Date, it still reads the user's input as a string.
Is there an easy way make sure the system automaticaly recognizes the user's input as a date, or is there a way to quicly convert the string to a date?
I have a spreadsheet that has 3 different dates in 3 different cells:
B4 - 3/24/2014
B5 - 4/6/2014
B6 - 4/14/2014
From that information I need once cell to display "Mar 24 - Apr 6 paid Apr 14"
Reason being is that I am importing journal entries into an accounting program and I am allowed one cell each row for the description. This would let me change the dates only and my descriptions will fill out before import. It is important that the months are abbreviated to 3 letters as I am limited on how many characters the description can be.
I have a function that will be used across 10K+ records at a time, so I was taking a look at optimizing it a bit. At the start of the routing I have a string with a 9 to 15 digit numeric value in it. I wanted to load each individual digit into a byte array. I started out using:
byVal = StrConv(sVal,vbFromUnicode)
But that actually loads the ASCII Character codes into the array not the digits themselves. From there I considered looping through the array applying CByte(Chr$(byVal(i))) but then I wondered if it would make more sense to just load the array with Mid$(sVal,i,1)... Does anyone have tested knowledge on which performs better? Is there an option C I have missed?
I have hit an issue when tranfering a string date from VBA to excel, excel thinks the string is US format and swaps around the days and months even though the system and excel are setup for UK date format:
Simple example of the problem:
Sub test()
Dim testy As String
testy = Now
'testy will equal 04/10/2007 17:20
Range("A1").Value = testy
'A1 will equal 10/04/2007 17:20
End Sub
Now I know in this example that if I used DateValue(testy) it would work, but our situation is a bit more complex as we are running this is a loop testy is not always a date.
