I want to assign a value to a character or string
Like I have formula p2p3= (n-1)*p +(2*e)
I want to assign values(number) to n,p,e.............so that i can get p2p3....like want to assign 'n'=4
I don't want to use cell number for calling values of n,p,e
I can't work out how to strip the hyperlink address in cell rRecordID(1,11).
Code:
Private Function GetRecord(lRow As Long)
Dim i As Long
Dim vMyCopy As Variant
[Code].....
What am I missing here. The following code fragment
strTestString = In_Wrksht.Range("A" & i)
strNameString = Trim(Mid(strTestString, 6))
Debug.Print strTestString & " uuu"
Debug.Print strNameString & " eee"
In_Wrksht.Range("B" & i) = strNameString & " XXX"
Debug.Print Trim(In_Wrksht.Range("B" & i)) & "ggg"
returns these results:
7/ 31 FIDELITY SHORT TERM BOND uuu
FIDELITY SHORT TERM BOND eee
ggg.
strNameString is not being assigned to B&i. Why Not?
I'm currrently using column I and col J
in col I are all the units of measurement: KG, PKT, BAG
in ColJ is the formula to return:
KG as 9999999
PKT as 8888888
BAg as 7777777
if(i2=kg, 999999999,"false!")
i was thinking of using if....but triple if formulas would be long isn't it?
PART2 of this would be using:
=IF((SUMPRODUCT(--(db!$A$2:$A$36000=$B$1),--(db!$F$2:$F$36000=C$5),--(db!$G$2:$G$36000=C$6),--(db!$E$2:$E$36000=$A7),--(db!$D$2:$D$36000=$B7),db!$I$2:$I$36000))=9999999,"KG","Invalid")
to check 5 values and if it is 999999999 it'll return KG
8888888 PKT
7777777 BAg
I'm looking for some VBA code that would look at a column of data, look at each cell value in that column and if the cell value starts with the letter 'G' and the 5th character in that cell is not 'Z' or 'X' I would like to highlight that cell. Example:G123-123 would be highlighted whereas G123Z-123 would not.
View 4 Replies View RelatedI would like to get the nth character from a string. For example, let's say there is a string "jupiter", and I would like to get the 3rd character of this string, "p". Is there a function in excel vba that would allow me to do this?
View 9 Replies View RelatedI have a VBA program which is running very slowly on one of my computers, but none of the others.
Here's a piece of code which illustrates the problem, which is that assigning a null string to a cell is very slow.
Option Explicit
Public Sub test()
Dim objSh As Worksheet
Dim I As Integer
Set objSh = Worksheets("Sheet1")
MsgBox "test1"
For I = 1 To 1000
objSh.Cells(1, 1) = ""
Next
MsgBox "test2"
For I = 1 To 1000
objSh.Cells(1, 1) = " "
Next
MsgBox "done"
End Sub
If I change this to assign a space instead it is very fast (about 1,000 times faster).
This slow machine is not normally slow; an ACER Aspire 9410Z with 2GB RAM, running Vista Ultimate.
Other machines run this code OK on a mix of Windows XP, 2000 and Vista Business. with Excel 2003, 2000 and 2007.
Ultimate seems to be the only unique factor of the machine where it runs slowly.
I have this data and want to extract the character after the letter Y if the string has a Y in it.
Example data Output
AU 2013 OD ANR B24 Y2 2
AU 2013 OD ANR B24 Y4 4
AU 2013 OD ANR B24 Y5 5
AU 2013 PD HLD NOV B SPA
AU 2013 PD HLD NOV C SPA
AU2013OD ANR B25 Y1 1
AU2013OD ANU B25 Y5 5
AU2013OD WCR FPVN B49
AU2013OD Y6 FPVN B49 6
AU2013OD WCR FPVN B40
AU2013OD WCR FPVN B43
How can I evaluate just the first part of these stirings so I can just do something like Left("Ca",2)?
View 2 Replies View RelatedHow do I split the below character or similar strings into 2 columns of 25 characters each without cutting a word off?
BONE CURETTE-RVERSE ANGLE 5.5MM WIDTH-MEDIUM/BAYONETED
I have a web query that returns a city and state, but the last character of the state is lower case. I need VBA code to change the last char to upper case. Here is what I have so far:
Code:
tmp = Cells(4, 1).Value
Mid(tmp, Len(tmp), 1) = UCase(Right(tmp, 1))
Cells(4, 1).Value = tmp
Is there any easier way to do this without 3 lines of code?
I have some columns in the excel file:
/path1/xyxxx/cccccc/filename12.txt
/path1/bxgdgg/gfdfacc/filenameeee8.txt
/path1/tttwrw/ccefecc/ddddd/filename56.txt
And I would like to delete everything before the LAST slash(just filenames)
filename12.txt
filenameeee8.txt
filename56.txt
I have a column that has various codes such as "E123" and "X456" and "S345". I just want to extract the numbers and leave the letters in each cell. How do you write a formula using the LEFT function to extract the last three numbers?
So I have this list (I made it a little bit shorter).
So what you see is two different tasks (01 and 02) and three different conditions (A, B and C). In column B you see the result I would like to have. '/Searchtask_01.html' in A1 belongs to conditions A, because it is in session A. However, '/Searchtask_01.html' in A10 belongs to conditions B, because it is in session B.
How to get the results in B with a formula?
I have a cell that has approx 22000 characters. I'm trying to remove a specific character string from a cell by doing a find and replace with "". It works for characters in the first part of the cell but not for characters in the last part of the cell.
Example: I do a find/replace for the characters 21242 to "" in column A and I get the expected results. I do a find/replace on 69294 to "", again I get the expected results, but if I do a find/replace on 85203 to "", I get "Excel cannot find what I am searching for" (but its there!)
My cell size is within the max size of 32,767 characters so not sure why its not working.
Attached a sample worksheet.
I would like to find the position of the last occurrence of a character in a string. For example, I have a string with the following:
"c:wwgpeToolbidsTest File.GP$".
I would like to find out the position of the last '' in the string because I want to pull the filename, 'Test File.GP$' into a variable. I would like to avoid writing code to do this. Are there some Excel functions I can use for this?
I have a macro that asks the user to enter a file name and have written a small function to search the name given to the file to find any invalid characters, trouble is I must be doing something wrong as I doesn't work. Everytime I write something in the box I'm told it's invalid, regardless of weather it actually is or not.
Function -
I am trying to work out how to get nth position of a character in a string. For example in this
Code:
kjishdfiuayigdscka
if I use the formula
Code:
=FIND("i",I$1),
it will give me answer 3. But I want the position of 3rd "i" in the string. The answer should be 12. How can I change this formula to get the correct result?
In cell A1 contains a string, how do I get the number of position of the last numeric character from right to left (this value will be in cell B1).
Example: 12543AR3372C31WWW (In Cell A1)
4 (In Cell B1)
The barcode lablels all have the following format: A318639....that is a letter followed by six numbers.
When I scan the barcodes into any cell, a dollar sign "$" appears in the front of the barcode string that is entered into the cell. The dollar sign is not a relevant part of the string of characters in the barcode label.
What I am looking for is a solution where upon scanning a barcode into any cell, the dollar sign is removed from the front of my string and I am left with just the seven character string which is shown above.
I have experimented with the Data Validation tool by trying to limit the number of characters that are allowed in a cell to seven characters, but that has not actually removed any characters from my data string.
For icount = 1 To LenComputername
valComputername = Asc(Mid(UserComputername, icount, 1))
Next icount
If the computer name is NAMTOK-PC Then the LenComputername is 9. Does that mean then that the valComputername is equal to 78?
on the web I've found this formula, which returns the postion of the last occurrence of the character in cell B1 in the string in cell A1:
=MAX((MID(A1,ROW(INDIRECT("A1:A"&LEN(A1))),1)=B1)*ROW(INDIRECT("A1:A"&LEN(A1))))
How do I turn this into a VBA function?
I am doing a Regular Expression search on a string variable assigned to the HTML content of a Wikipedia search. However I am currently manually going to Wikipedia, searching for the term, saving the html page, opening the saved page with Notepad and then copying the content into a cell.
Can the above process be automated with VBA, how to assign the html content of a Wikipedia search to a string variable.
i want to extract a value from a column into another column in excel.
this first column contains text and i want to extract a value that in located between the characters 'FOR' and 'MTHS'.
how do i do that?
the situation is the same for all the rows; the value that i want is just located between these characters.
is there a simpler way other than using the MID functn? because everytime i use it i need to count the no. of characters and its quite difficult to keep up with the numbers.
Title should read: Finding the nth Occurrence of a character within a text string
I have a very long text string that is delimited by about 50 "/" to segment certain values within the text string. I want to be able to extract the text between the 33rd and 34th occurrence of "/". How to do this?
I have a code which displays the values of R2, S2, T2, and U2 in one cell (J2). R2, S2 and U2 are all letters, but T2 is a 2 digit number. If there is a leading zero in T2, then in the display of J2, the leading zero is gone. so if the value of R2 is K, S2 is M, T2 is 01 and U2 is S, then I would want it to display KM01S, but it is only displaying KM1S.
View 1 Replies View RelatedI've spent way too much time trying to figure out this simple thing. Doh! I have a text string that may have one or more CR and/or LF characters on the right. Unfortunately, RTrim doesn't remove CR/LF characters.
Is there an easy way to do something similar to the following that will remove the CR/LF characters?
[Code] .....
How do you find if the last character in a string is a quotation mark?
View 9 Replies View RelatedNeed formula to count the number of times a particular character is found in a string I have been experimenting with the likes of
View 5 Replies View RelatedMy question is about converting a Literal String to Character Code. I'm using the following coded InputBox. And it prompts the user for what characters to search for in a string.
View 4 Replies View Related