Split from Count Of Groups Where Last Character Is Unique
The A1 B1 C1 were not the data items in the table, but the cell addresses. The new title of the thread does not reflect what I am asking either. The focus of the question is the counting of groups, not counts of cell contents.
Formula to count the number of consecutive zero starting from the last cell with non zero value.
View 14 Replies View RelatedI need to count the maximum amount of consecutive crosses that appear in a list. For instance:
x
x
x
x
x
x
x
x
x
the result would be 4, because the highest amount of consecutive crosses in this list is 4 times.
Would anyone mind providing me with a formula for this, please? The list is from C5:C52.
I have a daily column of numbers of approx 600 rows and the number is either a 0 or 1 and the 0 or 1 are in a random order in each row like:
1
1
1
0
1
0
0
0
1
0
0
1
I would like to find the min number of rows with 1, the max number of rows with 1, the totals of consecutive rows with 1 ie 3 consecutive rows of 1 appear 4 times, 4 consecutive rows appear 6 times etc and the average of the consecutive rows with 1.
I have to calculate bonus payments for people working O/S. I have a 5 year calendar in month blocks (60 months/columns). In each month there is a percentage 'time O/S' figure.
If an employee is O/S for 3 consecutive months they get bonus 'A', 6 consective months bonus 'B', etc. How can I evaluate the 60 columns, returning the number of times 100% occurs in 3 consecutive months/columns. I have found examples of similar solutions but they will return a value of 3 if there are 5 consecutive months of 100%...
ie. 100 100 100 100 100
= 100 100 100 *** ***
& *** 100 100 100 ***
& *** *** 100 100 100
= 3
but I need it to equal 1
I'm looking for a VBA code or formula that will count consecutive values in a column.
Please look at my example sheet.
I'm trying to use this formula to count consecutive values but somehow it doesn't work properly.
Does anyone see what's going wrong here or is there a better formula to this?
I'm trying to come up with an array formula to count the consecutive declines or increases from the last value in a column, going from bottom to top. The real world application is a list of daily stock prices down a column, and counting from the most recent day, how many consecutive days the price declined or increased.
I got some hints in the following post but can't get it evaluate the resulting logical array in reverse order (which is needed since column addresses are evaluated top to bottom, not bottom to top).
Count consecutive increase in values
Example for consecutive increases leading to last value
49
50
51
52
53
49
55
56
I need a formula to return 2, the number of increases from 49 to 56.
I am a remodeling contractor trying to monitor trips my employees are making to the lumberyard. I am able to export to excel from our accounting program a column of dates that invoices are made and another column that tells me whether trips were made before 8:30, between 8:30 and 3:30, after 3:30, or whether materials were delivered involving no trip. So I can count "time of day" trips. I also want to know if multiple trips were made in a single day, or if trips were made 2, 3, 4, 5, etc. days in a row.
Column 1 Column 2
Monday, July 6 2009 Before 8:30
Monday, July 6 2009 Between 8:30 and 3:30
Tuesday, July 7 2009 Between 8:30 and 3:30
Wednesday, July 8 2009 Before 8:30
Friday, July 10 2009 After 3:30
Monday, July 13 2009 Before 8:30
Wednesday, July 15, 2009 Before 8:30
In this example, I have 2 trips made on a single day; 1 instance of trips made 3 days in a row; 1 instance of trips made 2 days in a row (Friday, and then again on Monday since we don't work weekends) and 1 instance of 1 trip made on an isolated day. Additionally, we have 4 trips made before 8:30; 2 trips between 8:30 and 3:30 and 1 trip made after 3:30. Columns for a single job could range to 30 or 40 trips or more, and we have 6-12 jobs running at any one time, so I could be looking at data for all of those jobs once a month if I can figure out how to make it easy to do. I have figured out how to count up the time of day trips (but included the example here for a fuller picture of what I'm trying to do) but cannot figure out how to count the number of 2,3,4,5 etc.-day-in-a-row trips that are being made.
I have a range of binary numbers and would like to count the number of times the value of 1 appears BUT there must be at least 4 consecutive 1's.
Here's an example:
1
1
1
1
1
1
0
1
0
1
1
1
The final count should be 6.
I have a daily column of numbers of approx 600 rows and the number is either a 0 or 1 and the 0 or 1 are in a random order in each row like;
1
1
1
0
1
0
0
0
1
0
0
1
I would like to find the min number of rows with 1, the max number of rows with 1, the totals of consecutive rows with 1 ie 3 consecutive rows of 1 appear 4 times, 4 consecutive rows appear 6 times etc and the average of the consecutive rows with 1.
I am preparing a attendance sheet. I am using 1 & 0 for present(=1) & absent(=0). I want to find out if a student has been absent for three consecutive days and if there is three consecutive 0 then the formula should return the value 0 ( the student gets 0 if he is absent for 3 consecutive days ) otherwise it should add all the 1s in the row. i.e
1 1 1 0 0 1 1 0 = 5
10 0 0 1 1 0 0 = 0
I'm looking for a way to count groups of alternating rows of "TRUE" values across 3 columns. There will never be an occurrence of more than one "TRUE" value per row. In the sample below, alternating TRUE values occur in rows 4 through 7, so this would be counted with the groups of 4.
1Column 1Column 2Column 3
2FALSEFALSETRUE
3FALSEFALSETRUE
4FALSE TRUEFALSE
5 TRUEFALSEFALSE
6FALSE TRUEFALSE
7 TRUEFALSEFALSE
8FALSEFALSETRUE
9FALSEFALSETRUE
10FALSEFALSETRUE
I have an excel spreadsheet to record employee holiday and sickness figures.
It is set on as a grid e.g. column A stores all the dates and then employee names are used as column header.
One of the triggers I need to use is where, an employee has been absent 28 consecutive days. When an employee is absent I simply enter 'ABSENT' against there name.
Countif will count the number of time absent appears in the column however I need it to only recognise it if it is only 28 days in a row.
I need a formula that will calculate the most recent consecutive years.
The actual data has multiple ID# and the consecutive years need to be matched to the ID#
So far I have =COUNTIFS(ID_NUMBER, A2, EXPIRATION_DATE, ?????)
A friend of mine suggested that I count backwards from the most recent date and stop counting when there is a break of one year. That is where I get stumped. It doesn't need to be a year day and date, I just need to compare the YEAR portion of the date.
The example data is provided below the consecutive year value on the sheet was calculated by hand and is the correct value that needs to be returned.
ID # Transaction Date Transaction Type Registration Package Amount Paid Expiration Date Years Paid Inspected Consecutive Years 57 8/8/1996 NEW SHIRT+DISC $15.00 8/8/1997 8 Y 3 57 9/3/1997 RENEW DISC $15.00 8/8/1998 8 Y 3 57 9/8/1998 RENEW SHIRT $15.00 8/8/1999 8 Y 3 57 6/13/2001 RENEW SHIRT $15.00 6/13/2002 8 Y 3 57 5/6/2005 RENEW DISC $15.00 5/6/2006 8 Y 3 57 5/12/2009 RENEW DISC $15.00 5/12/2010 8 Y 3 57 3/7/2010 RENEW DISC $15.00 5/12/2011 8 Y 3 57 1/4/2011 RENEW SHIRT $20.00 5/12/2012 8 Y 3
I have a user form with 125 checkboxes and if checked would like them to display one message box containing a specific message for that the checkbox slection, but all messages in one message box.
I have one command button that will list each message box individually, using code like this -
If CheckBox12 = True And CheckBox5 = True Then MsgBox "You would need to see your manager"
Each message box individually is time consuming and it would be better if they all displayed in one box. Of the 125 check box options, 7 or 8 will only be selected at any given time.
I need an equation that will return a 1 in column F if data is available (cell is populated) in 2013 or last two years (2012 & 2013) or last three years (2011 & 2012 & 2013) or last four years or last five years. A zero counts as data.
Data is set up as:
Years in columns
2009
2010
2011
2012
2013
Count
product 1
34
32
33
31
35
1
[Code] ......
The formula in column B counts the number of values that are
View 9 Replies View Relatedcreate a formula that counts consecutive rows that have wins and losses.
A B
1 Game 1 Win
2 Game 2 Win
3 Game 3 Win
4 Game 4 Lose
5 Game 5 Lose
6 Game 6 Win
7 Game 7 Lose
So Consecutive wins = 3
Consecutive losses = 2
I have a spreadsheet with employees performance results for the last 12 months. Column A contains name, columns B to M contain text "Gold", "silver" or "bronze". I need to count how many consecutive months thay have achieved "Gold" status BUT must include latest month.
So, if column M contains "silver" or "bronze", the consecutive answer (column N) would be 0. If col M = "Gold" but L doesn't then N = 1. If M and L = "Gold" then N = 2 etc etc.
Is there a formula I can use in column N for this without doing 12 "if" functions?
I think this needs to be an array formula but the ones I've tried I can't get to work.
I want to count the number of groups of 3 adjacent cells in a horizontal range (C5:EV5) in which any cell in the group of 3 has a value in it (as opposed to all the cells being blank or containing "0"). For example, if any or all of the cells in C5:E5 have a value in it, it would count as 1, and if any of the cells in the group F5:H5 have a value, it would also count as 1, and so on. Is there a way to use COUNTIF for this?
View 5 Replies View RelatedI'm looking at test results and would like to know how many times in a row correct answers were given before getting one incorrect. The way I have this currently set up, is if a student has the answer correct it returns a "TRUE" value, and a "FALSE" value for an incorrect answer. A typical test may have 50 questions, so I would have either "TRUE" or "FALSE" values in rows A1 through A50.
So I've been trying to figure out a formula that counts the number of times "TRUE" rows repeat 'consecutively' in a given column, in this scenario column A. The formula would need to check the current row and if "TRUE" check the row immediately after, if that row is also "TRUE" then check the row immediately after that, until it runs into a "FALSE" string, then display that total count of consecutive "TRUES" in another cell. I understand there may be duplicate results but I'm only really interested in the longest value, so duplicates can be ignored.
If it makes the formula easier, each possible result can be assigned to it's own cell. Let's assume the test has 50 questions. So if a student got all 50 questions correct the result count would be 50 in cell B50, or if they got 25 correct before the first incorrect answer, cell B25 would say 25, etc. I'm guessing I could then easily query this column for the largest value to come up with what I need at a glance.
I have a sheet that lists customers in column A and then each customers Distribution & Sales over a period of time. The spreadsheet then flags if the customer has sold out in any month. I now require a count of maximum consecutive sellouts for each customer. For example:
Customer A S/O S/O nil nil S/O
Customer B S/O S/O S/O nil nil
Customer C nil S/O S/O S/O S/O
In the above example Customer A would have 2, B 3 and C 4 sellouts. I'm looking at about 10K customers I require for each product.
I have a range of data but the important pieces are
Column B - list of employee IDs.
Column C - Date
I have sorted the data by column B with secondary sort for column C oldest to newest date.
I want to know the number of instances where an employee has 3 consecutive days in column C. Only count 3 consecutive. If the consecutive days go over 3 (such as 4 or 5 days) I do no want to count these.
I have a table of data as below recording daily foreign exchange rates.
Column A = Time and date
Column B = USA
Column C = UK
Column D = Aust.
Column E = Japan
Column F = Euro
Time and date USA UKAust.JapanEuro
04-Jan-20060.68390.39180.924379.470.5693
05-Jan-20060.68660.39050.918779.720.5666
06-Jan-20060.68710.39150.919579.720.5675
Then in column H i have a formula that works out if the rate has exceeded a specified base rate, if it has i display Threshold Exceeded and if it hasn’t i display No Action Required.
OK from here i want to count the number of times in the month the Threshold has been exceeded. I can do this by using the countif formula.
Now this is the section i need help on
For a specified time, say a month, i want to count the maximum number of times the Threshold has been exceeded consecutively.
E.g
Threshold Exceeded
Threshold Exceeded
Threshold Exceeded
Threshold Exceeded
Threshold Exceeded
No Action Required
No Action Required
Threshold Exceeded
Threshold Exceeded
Threshold Exceeded
Result = 5 (max number of consecutive Threshold Exceeded” for a specified time frame)
I have a .csv open in Excel 2007 that looks like the following
Code:
1 566
1 566
1 566
2 341
2 341
3 566
3 566
3 566
3 566
...
There is a one-to-one relationship between Column A and B, but B is not unique (but can only take a small set of valid values). I wish to query how many id's (Column A) contain a particular property (Column B). If the example above ended before the "...", I would like to get as the output:
Code:
566 2
341 1
because the property 566 is owned by two id's (1 and 3) and the property 341 is only owned by the id 2.
What I am trying to is to count the number of times a certain number or character appears (either on its own or in a batch of consecutive cells containing that number/character) in a column.An example might clarify things (for reasons of brevity I will write the columns in rows):
If a column looks like (each 1-digit numbers / characters being a consecutive cell) 0 0 X X 0 0 X and I am counting for X, then I should get 2. If my column is X X 0 X X 0 X 0 0, then I should get 3. If my column is 0 X X 0 0 X 0 then I should get 2. If my column is X X 0 X X 0 X then I should get 3. Is there a formula to perform that calculation?
I couldn't figure out how to change this function to allow for weekends.
Function to count consecutive dates as one occasion
=--((NETWORKDAYS(SUM(c1)*(B1=B2),c2)-1)>1)
Column A Column B Column C Column D ( I would then use this column in a pivot table to calculate)
pat name pat id date of service # Admissions
[code]....
Let's say I have a column A with the following values.
30
40
30
60
-20
-10
-50
-60
-70
120
320
20
-40
-30
40
How can I have 2 cells display:-
i)highest streak of positive numbers = 4
ii)highest streak of negative numbers = 5?
Also, how can I have another 2 cells display:-
iii)the sum of the highest streak of positive numbers = 160
iv)the sum of the highest streak of negative numbers = -210
I'm trying to use logic to identify trends...in each of the strings below, I want to count the occurrences of the left most character appearing consecutively. The answer is to the left
I'm trying to do this via a formula vs. vba if possible
BBBBBBBBBBBBBBBBBBB - 19
BBBDUDUUUUDDBBBBBBB - 3
UUDUDDUUUDUDBBBBBBB - 2
UDUDDUDUUUDDBBBBBBB - 1
[Code] .....