ISERROR At End Of IF Statement Returns A #VALUE!

Nov 21, 2008

I've written (with help from here) and IF statement, as below;
=IF('Raw - NUS'!G45="","",VALUE(TRIM(CLEAN('Raw - NUS'!G45))))

The issue is, that not all cells in my array are "" or a value, some are " " and some are " " which gives a FALSE to the arguement and returns a #VALUE! in the cell. Is there a way I can add an ISERROR to the FALSE, VALUE(TRIM(CLEAN('Raw - NUS'!G45))), result make this blank? I've tried OR, but it doesn't work.

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Column B D E F
Cases Case Pack Reg Price VPR Price
1 14 2.25 0.00
1 14 1.75 2.00

When the value of F is zero, I want the formula to be B1*D1*E1, when the value of F is not zero, I want the formula to be F1*D1*B1. I can figure this part out. The problem is I have these values on a certain number of rows and I want a grand total at the bottom, but the rows that do not have values in them are giving me a #VALUE! error, which is messing up the grand total. I am not sure how to write the formula with the IF AND and ISERROR functions.

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if Statement A: =IF(M4>$B$17,0,LOOKUP(M4,$AA$20:$AB$29)*$B$15/12) works very well

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now I am trying to say

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Code:

Private Sub worksheet_change(ByVal Tar As Range) On Error Resume Next
If Tar.Column = 1 Then
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[Code]..

but when i use Cells instead of Range ,Find command returns perfect result

Code:

Private Sub worksheet_change(ByVal Tar As Range) On Error Resume Next
If Tar.Column = 1 Then
Set f = Sheets("Sheet2").Cells.Find(Tar(1, 1), LookAt:=xlWhole)
If f.Column = 11 Then Sheets("Sheet1").Cells(Tar.Row, Tar.Column + 1).Value _
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would be come

=IF(ISERROR(INDEX('Characs Single'!$B$1:$C$100,MATCH('1Report'!$B12,'Characs Single'!$B$1:$B$19,0),2)),"",INDEX('Characs Single'!$B$1:$C$100,MATCH('1Report'!$B12,'Characs Single'!$B$1:$B$19,0),2))

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