Macro To Split String Returns Type Mismatch
Aug 5, 2013
My code below returns a type mismatch? It is looking at the values in column B which are formatted as text and the output is in column J. An example of a value is 2.1.15 I want to extract 1 (i.e. the central character between two ".").
VB:
Sub ConvertLineNo()
Dim r As Long, TempStr As String
For r = Cells(Rows.Count, "B").End(xlUp).Row To 1 Step -2
TempStr = Cells(r, "B")
TempStr = Split(TempStr, ".")
Cells(r, "J").Value = TempStr
Next
End Sub
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Jul 6, 2013
I have a bit of code that builds a formula and uses a variable store the range:
VB:
Sheets("CONTROL").Select
lastRow = Cells.Find(What:="*", After:=[A1], SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row
[Code].....
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Feb 23, 2014
I get a Type mismatch from this line:
x = Application.WorksheetFunction.Lookup(2, 1 / (Range("G7:P7") = "A"), Range("G7:P7"))
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Jul 19, 2007
With the following procedure, I am using a Part ID number to look up that part's location in a worksheet. To do this, I am using the DGET function which now works, thanks to all who helped with those issues.
But now I'm trying to harness the outcomes from that function.
--It displays #VALUE! if the part ID number was not found in my worksheet and therefore the function can't return a location.
--It displays # NUM! if the part ID number was found in multiple records/rows in my worksheet and so it has multiple corresponding locations.
I am trying to construct an IF section that will clarify what these mean to anyone running this macro. I want to replace #VALUE! with "Not Found" and #NUM! with "Numerous".
The issue arises when I compare the result of the function with the #VALUE! or #NUM! strings. I've tried StrComp and a simple equals sign (as below) I've even tried having Option Compare at the top, though I'm not familiar with how that would change things. But I am getting "Type Mismatch Error 13" all the time. I also get that error when set my DGET function = to a variable (Dim'ed as string)
Variables to point out:
---Sheeti is a Publically defined Worksheet
---'CriteriaRange : Publically defined Range that is empty (until assigned criteria for my DGET function later within my loop)
---'InventoryRange : Pubically defined Range that contains inventory data that I look through with my DGET function (Items in the inventory are identifyable by a string I call "sItem" and each has a location in a corresponding column that I am looking for with my DGET function)
Public Sub LoopThruParts()
Dim y As Integer
Dim sItem As String
Dim ValueError As String
Dim NumError As String
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Mar 12, 2014
I am attempting to concatenate several columns and I am getting the Type Mismatch error. I understand why I am getting this error, but I do not know any other way to accomplish what I am seeking.
[Code] ......
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Jul 14, 2014
"Type Mismatch error" in the macro below. I am trying to implement logic, where if value in column F, equals "1ma+89", then extract 89 only in column G. I also have other values in column F, where I have set specific rules for them, to extract numbers.
I have attached a worksheet with example data and highlighted red cells, represent incorrect output from the macro.
test2_14July.xlsm
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May 4, 2007
im making this macro code for my cell that will have a conditional formula but im always getting an error pop up message: TYPE MISMATCH.
here is my code
Sub ACCOUNTFINDERCODE()
Dim LastRow5 As Long
LastRow5 = Columns(7).Find("*", searchdirection:=xlPrevious).Row
If Sheets("working file").Range("g11:g" & LastRow5) = "F1212014000" Then
Sheets("working file").Range("k11:k" & LastRow5) = "='Account LookupSheet'!R4C3"
End If
If Sheets("working file").Range("g11:g" & LastRow5) = "F1212015000" Then
Sheets("working file").Range("k11:k" & LastRow5) = "='Account LookupSheet'!R5C3"
End If
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Nov 4, 2006
I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:
- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)
- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)
Etc.
The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the
Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............
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Aug 21, 2014
I am getting a type mismatch with the following:
HTML Code:
Private Sub Export2Pdf()
Dim sFileName As String
'Create file name
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")
[Code] ........
something to do with this:
HTML Code:
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")
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Feb 14, 2009
I have used this code previously and it worked however I now get a type mismatch error in the line coloured red..
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Feb 24, 2014
The line I first used was:
var all_spans = document.getElementsByTagName( 'SPAN' );
for( var i =0,skip =0 ; i [code].....
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Jul 1, 2009
I am getting error Type mismatch error the moment i enter value in Cell T54 and CLICK "DAILY" on Daily button.Waiting for the solution.
I am attaching the file.
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Aug 25, 2009
I have four columns of data and 25 rows (A1:D25). I wish to add this to a multi-column list box in my user form. My userform is called FundSelect, and my listbox is called FundList. The ColumnCount property is set to 4. When I use the command:
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Feb 8, 2010
I'm trying to write a pretty simple macro which invokes a built-in DDE function to retrieve some data, then when the data is retrieved, just show a msgbox. When the data is finished being retrieved, cell(20,11) in the sheet "Historical Data" will automatically have "FINISHED" placed in it. So while the retrieval is taking place, I'm simply looping and checking the contents of this cell waiting for it to read "FINISHED". My problem is the 'Do While Sheets("Historical Data").Cells(20, 11) <> "FINISHED"' line generates a "Type Mismatch Runtime Error 13", which I can't for the life of me understand why.
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Mar 23, 2012
I have a while loop that counts backwards in a seriescollection to find the last value with data. In one particular case, I had to use an IF formula in the source data where it would output NA() if the statment was false, so instead of loop through empty strings until the loop finds a number, it loops through #NA until it finds a number.
This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.
Code:
Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long
[Code]....
(P.S. why I would have "NA" as an output, its because it won't graph, where putting "" for my false condition did)
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Jan 16, 2013
I am using this code:
Code:
With wshvar
.Range("A16") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) - 1)
.Range("A18") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) + 1)
End With
but receiving a 'Type mismatch' error with the highlighted code.
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Feb 23, 2013
I tried to find value on the other workbook. Gives me error "Type mismatch"
Below is the code in my VBA project
Code:
Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub
[Code] .......
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Jan 16, 2007
This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch
dim c as Range
...
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
MatchCase:=False)
ActiveCell is a single cell on an unhidden sheet - cell A279.
I can Control-F at this point in Excel, and it finds "LIQ" just fine.
Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.
Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)
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Feb 19, 2007
I have a piece of VBA code that acts weird. For brevity I am doing a function call like this:
val=MyFunc( [D1] )
and
Function MyFunc(mean As Double)
D1 is a named range which is a single cell. It contains a double.
The problem occurs when the value is zero, I get a type mismatch on the function call. If it is non-zero all is well.
What would cause this? I could see if zero was invalid inside MyFunc() that some calculation might blow, but it nevers gets into the function. Looks like the compiler is stopping it.
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May 18, 2007
Range("C1:C" & x).Value = WorksheetFunction.Transpose(Result)
I'm trying to run it in 2007. It works in earlier versions.
I get Type Mismatch error. Result is dimmed as variant type.
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Dec 14, 2008
I have some code which i trialled in a blank workbook and was fine. when i pasted it into the workbook i am working on, i get runtime error 13 type mismatch.
Sub Trackj()
Dim a As Long
For a = 1 To Sheets.Count
If InStr("master", Worksheets(a).Name) < 1 Then
Worksheets(a).Cells(40, 6).NumberFormat = "hh:mm"
Worksheets(a).Cells(41, 6).NumberFormat = "hh:mm"
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(40, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("B52:B80").PasteSpecial (xlPasteValues)
End If
If Hour(Worksheets(a).Cells(41, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(41, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("D52:D80").PasteSpecial (xlPasteValues)
End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
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Jan 9, 2009
what i know what's actually type mismatch and how do i solve it?
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Jul 24, 2009
When my macro runs through the above code, I get a type mismatch error. All of the cells are formatted at Date only.
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May 16, 2014
When I run the following code I get a (Run-Time error '13': Type mismatch). When I click debug it highlights line 41
[Code].....
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Jul 15, 2014
I am trying to accomplish the following: iterate through rows of a selection, delete row if the first column cell is empty or the second column cell equals 0.
So far I have:
[Code] ........
I am getting a type mismatch error at my if statement.
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Aug 18, 2014
i have written a vba code to open excel file saved at network server. The issue is code opens the file but gives "Runtime Error 13 Type mismatch"
Code :
<code>
Sub test_opening()
Dim filepath As String, filename As String, completename As String
Dim hurray_macros As Workbooks
[Code].....
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Jan 30, 2009
I seem to have some type mismatch in my macro...
The error appears every time i insert or delete a row in the worksheet.
This is the ....
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Jun 16, 2009
I made this case statment below to look at a cell in Q and if the cell value is "Large Area" then the cell in P same row should be 1 if the case is Varsity then it would be 2 however I keep getting a Type Mismatch. I tried Picker.Text and Picker.Value as well I didn't get errors but it didn't work either.
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Aug 6, 2009
I have attached a sample file for you to easy reference. So when the code run until the loop function, it will prompt an error message.
The idea is to open the selected file and the copy the data from the selected to this master file by searching the column A. Column A has the identical text in all the files that are to be copied from.
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Oct 16, 2009
I am trying to only have the option 1, 2, or 3 be entered. I have that part down, but if someone clicks cancel or just closes the input box i get the type mismatch I believe because no integer was found....is there a way around this?
Dim intResponse As Integer
intResponse = InputBox("Choose One" & Chr(10) & Chr(10) & "1 - Lease Lock" & Chr(10) & "2 - Upgrade" & Chr(10) & "3 - Lease Lock & Upgrade", "Contract(s) sent out")
If inResponse <> 1 Or strResponse <> 2 Or strResponse <> 3 Then
MsgBox "Must choose (1,2,3)"
Exit Sub
End If
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