Setting Range Returns Type Mismatch?

Jul 6, 2013

I have a bit of code that builds a formula and uses a variable store the range:

lastRow = Cells.Find(What:="*", After:=[A1], SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row


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Lookup Function Returns Type Mismatch?

Feb 23, 2014

I get a Type mismatch from this line:

x = Application.WorksheetFunction.Lookup(2, 1 / (Range("G7:P7") = "A"), Range("G7:P7"))

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Macro To Split String Returns Type Mismatch

Aug 5, 2013

My code below returns a type mismatch? It is looking at the values in column B which are formatted as text and the output is in column J. An example of a value is 2.1.15 I want to extract 1 (i.e. the central character between two ".").

Sub ConvertLineNo()

Dim r As Long, TempStr As String
For r = Cells(Rows.Count, "B").End(xlUp).Row To 1 Step -2
TempStr = Cells(r, "B")
TempStr = Split(TempStr, ".")
Cells(r, "J").Value = TempStr
End Sub

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Type Mismatch Error Reading From Range

Oct 5, 2006

I went to rerun an old macro that i ran fine before and it is now working not so fine and was wondering if anyone could lend me a hand in figuring it out because i know it's something stupid and simple.

this code

Workbooks("SUMMARY OF LSC.xls").Activate
For i = 2 To lastrowA
If Range("F" & i & "").Value = "Y" And Range("AR" & i & "").Value <> 0 Then
Sheets("FACILITY DATA IN EUR").Range("A" & i).Copy
Sheets(" lookups").Select
Sheets("lookups").Range("A" & lastrow1 + 1).Select
Sheets("lookups").Range("E" & lastrow2 + 1).Select

is giving me a Run-time error '13': Type mismatch and i have no idea why it would be. any suggestions? the variables are set to double.

the values in column F is either Y or N and in column AR is either 0.00 or a number like 11111.11.

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Type Mismatch Error On Range Change

Mar 7, 2007

I've been getting a type mismatch error with my code (upon using multiple cells) and I can't quite figure out why. I have the following

Sub Quicky()
If Worksheets("Daily").Range("B13").Value = 4 Then
Range("B13:H13"). Merge
Range("B13") = "Due " & Range("B13").Value & " times"
End If
End Sub

This code works just fine, but if I change Range("B13") in the first line to Range("B11:B13") that's when I get a type mismatch error.

Also, I'd like to be able to make it not have to use the value 4, but use whatever value is in the range, but that's a secondary issue. I hope that is not too close to a second question as I am attempting to follow the rules.

This was also posted at ....

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Type Mismatch Error In Returning Range Element

Dec 31, 2009

For some reason get a type mismatch error on when I try to determine the rth member of summation range. I have highlighted the relevant part of the code in bold. It is strange as I can obtain the address.

If ((All_nurse_names(r, 1) = nurse_name) And (All_status(r, 1) = status)) Then
Debug.Print "test " & r & " " & summation_range(r).Address & " " & val(summation_range(r))

total_hours_in_shift = total_hours_in_shift + (summation_range(r))
End If

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Type Mismatch When Transposing 65556 Size Array Into Range

Feb 22, 2014

I was looking for a worksheet with vba to do FFT beyond the Excel internal 4096 limit. I wanted to try my hand at writing code to do it faster. The attached does just that.

Everything worked fine until I went beyond 32k samples. The next higher 2^n value for data size to feed the FFT is 65556. When I tried this quantity of samples I got Runtime Error (13) type mismatch when attempting to write the array back to the worksheet using the "transpose" method.If I remember correctly, 32k worked.

Is there some limit to the size of the array that can be transposed and placed into a range? If so, is there another way to do this?

I do not need to re-write the data, but I use this same method elsewhere to write the FFT output. It it fails writing the input data back, it will probably fail when writing the FFT results.

Attached File : FFT.xlsm‎

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Type Mismatch Error Message Comparing Value To Cell Error "Type Mismatch"

Nov 4, 2006

I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:

- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)

- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)


The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the

Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............

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VBA Type Mismatch

Aug 21, 2014

I am getting a type mismatch with the following:

HTML Code: 

Private Sub Export2Pdf()
Dim sFileName As String
'Create file name
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")

[Code] ........

something to do with this:

HTML Code: 

sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")

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Type Mismatch

Feb 14, 2009

I have used this code previously and it worked however I now get a type mismatch error in the line coloured red..

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Type Mismatch IF Statement?

Feb 24, 2014

The line I first used was:

var all_spans = document.getElementsByTagName( 'SPAN' );
for( var i =0,skip =0 ; i [code].....

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Error 13,Type Mismatch

Jul 1, 2009

I am getting error Type mismatch error the moment i enter value in Cell T54 and CLICK "DAILY" on Daily button.Waiting for the solution.

I am attaching the file.

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Type Mismatch For RowSource

Aug 25, 2009

I have four columns of data and 25 rows (A1:D25). I wish to add this to a multi-column list box in my user form. My userform is called FundSelect, and my listbox is called FundList. The ColumnCount property is set to 4. When I use the command:

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Type Mismatch Error 13

Feb 8, 2010

I'm trying to write a pretty simple macro which invokes a built-in DDE function to retrieve some data, then when the data is retrieved, just show a msgbox. When the data is finished being retrieved, cell(20,11) in the sheet "Historical Data" will automatically have "FINISHED" placed in it. So while the retrieval is taking place, I'm simply looping and checking the contents of this cell waiting for it to read "FINISHED". My problem is the 'Do While Sheets("Historical Data").Cells(20, 11) <> "FINISHED"' line generates a "Type Mismatch Runtime Error 13", which I can't for the life of me understand why.

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While Loop With Type Mismatch?

Mar 23, 2012

I have a while loop that counts backwards in a seriescollection to find the last value with data. In one particular case, I had to use an IF formula in the source data where it would output NA() if the statment was false, so instead of loop through empty strings until the loop finds a number, it loops through #NA until it finds a number.

This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.

Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long


(P.S. why I would have "NA" as an output, its because it won't graph, where putting "" for my false condition did)

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Getting Type Mismatch Error

Jan 16, 2013

I am using this code:

With wshvar
.Range("A16") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) - 1)
.Range("A18") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) + 1)
End With

but receiving a 'Type mismatch' error with the highlighted code.

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Find Value - Type Mismatch

Feb 23, 2013

I tried to find value on the other workbook. Gives me error "Type mismatch"

Below is the code in my VBA project

Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub

[Code] .......

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Type Mismatch From VBA .Find

Jan 16, 2007

This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch
dim c as Range
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
ActiveCell is a single cell on an unhidden sheet - cell A279.

I can Control-F at this point in Excel, and it finds "LIQ" just fine.

Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.

Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)

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Type Mismatch Error When The Value Is Zero In VBA

Feb 19, 2007

I have a piece of VBA code that acts weird. For brevity I am doing a function call like this:

val=MyFunc( [D1] )


Function MyFunc(mean As Double)

D1 is a named range which is a single cell. It contains a double.
The problem occurs when the value is zero, I get a type mismatch on the function call. If it is non-zero all is well.

What would cause this? I could see if zero was invalid inside MyFunc() that some calculation might blow, but it nevers gets into the function. Looks like the compiler is stopping it.

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2007 Type Mismatch

May 18, 2007

Range("C1:C" & x).Value = WorksheetFunction.Transpose(Result)
I'm trying to run it in 2007. It works in earlier versions.

I get Type Mismatch error. Result is dimmed as variant type.

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Run Time 13 Type Mismatch

Dec 14, 2008

I have some code which i trialled in a blank workbook and was fine. when i pasted it into the workbook i am working on, i get runtime error 13 type mismatch.

Sub Trackj()
Dim a As Long
For a = 1 To Sheets.Count
If InStr("master", Worksheets(a).Name) < 1 Then
Worksheets(a).Cells(40, 6).NumberFormat = "hh:mm"
Worksheets(a).Cells(41, 6).NumberFormat = "hh:mm"
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(40, 6)) = Minute(Now()) Then
Worksheets(a).Range("B52:B80").PasteSpecial (xlPasteValues)
End If
If Hour(Worksheets(a).Cells(41, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(41, 6)) = Minute(Now()) Then
Worksheets(a).Range("D52:D80").PasteSpecial (xlPasteValues)
End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:

If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then

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VB Enquiries - Type Mismatch

Jan 9, 2009

what i know what's actually type mismatch and how do i solve it?

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TimeDiff Type Mismatch

Jul 24, 2009

When my macro runs through the above code, I get a type mismatch error. All of the cells are formatted at Date only.

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Run Time Error - Type Mismatch?

May 16, 2014

When I run the following code I get a (Run-Time error '13': Type mismatch). When I click debug it highlights line 41


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Basic Syntax / Type Mismatch

Jul 15, 2014

I am trying to accomplish the following: iterate through rows of a selection, delete row if the first column cell is empty or the second column cell equals 0.

So far I have:

[Code] ........

I am getting a type mismatch error at my if statement.

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Runtime Error 13 Type Mismatch?

Aug 18, 2014

i have written a vba code to open excel file saved at network server. The issue is code opens the file but gives "Runtime Error 13 Type mismatch"

Code :

Sub test_opening()
Dim filepath As String, filename As String, completename As String
Dim hurray_macros As Workbooks


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Runtime Error 13 Type Mismatch

Jan 30, 2009

I seem to have some type mismatch in my macro...

The error appears every time i insert or delete a row in the worksheet.

This is the ....

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Case Statement Getting A Type Mismatch

Jun 16, 2009

I made this case statment below to look at a cell in Q and if the cell value is "Large Area" then the cell in P same row should be 1 if the case is Varsity then it would be 2 however I keep getting a Type Mismatch. I tried Picker.Text and Picker.Value as well I didn't get errors but it didn't work either.

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Run Time Error - Type Mismatch

Aug 6, 2009

I have attached a sample file for you to easy reference. So when the code run until the loop function, it will prompt an error message.

The idea is to open the selected file and the copy the data from the selected to this master file by searching the column A. Column A has the identical text in all the files that are to be copied from.

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Type Mismatch Error On InputBox

Oct 16, 2009

I am trying to only have the option 1, 2, or 3 be entered. I have that part down, but if someone clicks cancel or just closes the input box i get the type mismatch I believe because no integer was there a way around this?

Dim intResponse As Integer
intResponse = InputBox("Choose One" & Chr(10) & Chr(10) & "1 - Lease Lock" & Chr(10) & "2 - Upgrade" & Chr(10) & "3 - Lease Lock & Upgrade", "Contract(s) sent out")
If inResponse <> 1 Or strResponse <> 2 Or strResponse <> 3 Then
MsgBox "Must choose (1,2,3)"
Exit Sub
End If

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