Lookup Function Returns Type Mismatch?
Feb 23, 2014I get a Type mismatch from this line:
x = Application.WorksheetFunction.Lookup(2, 1 / (Range("G7:P7") = "A"), Range("G7:P7"))
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Setting Range Returns Type Mismatch?
Jul 6, 2013I have a bit of code that builds a formula and uses a variable store the range:
VB:
Sheets("CONTROL").Select
lastRow = Cells.Find(What:="*", After:=[A1], SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row
[Code].....
Macro To Split String Returns Type Mismatch
Aug 5, 2013My code below returns a type mismatch? It is looking at the values in column B which are formatted as text and the output is in column J. An example of a value is 2.1.15 I want to extract 1 (i.e. the central character between two ".").
VB:
Sub ConvertLineNo()
Dim r As Long, TempStr As String
For r = Cells(Rows.Count, "B").End(xlUp).Row To 1 Step -2
TempStr = Cells(r, "B")
TempStr = Split(TempStr, ".")
Cells(r, "J").Value = TempStr
Next
End Sub
Error '13' Type Mismatch In Function Code
Oct 6, 2006while the code works fine by itself in the sample file, when inserted into my other file which contains another set of algorithms, it generates a run time error '13' type mismatch whenever the 'Hide' button is clicked.
this line of the following function: b = x / tpi
Function range(x)
tpi = 2 * 3.1415927
b = x / tpi
a = tpi * (b - Int(b))
If (a < 0) Then a = tpi + a
range = a
End Function
Type Mismatch '13' On Passing Function Result To Variable
Aug 11, 2006I have the following codes in my spreadsheet, they are pretty much the same and both used to work perfectly. However, now the first code returns a Type Mismatch '13' on line beginning mynum= and the second one works perfectly.
Sub addtasks()
Application.DisplayAlerts = False
myrow = Cells. Find(" Total P&C Estimate").Row - 3
mycell = Cells(myrow, 2)
mynum = Right(mycell, Len(mycell) - InStr(mycell, "#")) + 1
With Range(Cells(myrow, 2), Cells(myrow + 2, 2))
.EntireRow.Copy
.EntireRow.insert Shift:=xlDown
End With
Application.CutCopyMode = False
Cells(myrow + 3, 2) = "Task#" & mynum
Application.DisplayAlerts = True
End Sub
Type Mismatch Error Message Comparing Value To Cell Error "Type Mismatch"
Nov 4, 2006I'm trying to write a Macro that, in the active sheet (which contains plenty of data), deletes rows according to several criteria, for example:
- if cell(i, ar1(j)) = ERROR, delete row i and shift 1 up
(ar1 is an array of column numbers)
- if cell(i, ar3(j)) = 0, delete row i and shift 1 up
(ar3 is another array of column numbers)
Etc.
The problem is that, when I run it, I get a "Type Mismatch" error message, and I don't understand why. Here is the
Sub Delete_invalid_rows()
Dim i%, j%
Dim Nr%, valid As Boolean, BYPdata As Boolean
Dim ar1, ar2, ar3, ar4 As Variant
Nr = 1379
ar1 = Array(11, 14, 19, 20, 22, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 64, 65, 66, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 104, 106, 107, 109, 112, 116, 126, 127, 128, 129, 131, 133, 134, 135, 136, 137, 138, 139, 140, 142, 143, 145)..............
Match Function In Vba Returning Error "type Mismatch"
Nov 30, 2007I am trying to use a match function in VBA to return a value when a number of values in a row match a certain criteria (I have tried the Find approach on the Ozgrid help pages but it is not what I am after). My problem using a match function of course is that when there is no match the code returns a type mismatch error. I have tried to circumvent the error problem using an "On error resume next" but this then delivers a match for all rows. Anyone have any thoughts about how I can get around this problem?
Sub DataSum()
Dim strData As String
Dim i As Integer
i = 0
Sheets("Sheet1").Activate
Range("B4", Range("B4").End(xlDown).Offset(0, 0)).Select
For Each cell In Selection
If cell.Value = 0 Then
i = i + 1
Else
strData = Sheets("Sheet1").Range("$B$4").Offset(i, 0)...........................
Lookup Function Returns #N/A Or #REF
Apr 23, 2007Im trying to do a lookup but when I drag the formula down it returns the wrong values and also returns #N/A or #REF (which I think means it's refering to a wrong range and cant find the data???). How can I do a look up function by dragging the formula down a long column of data eg. 65,000 rows in excel, that returns the correct text. I have attached a simple example- see attached.
View 4 Replies View RelatedNested LOOKUP Function Returns Incorrect Data
Apr 22, 2008I setup this function to pull my staff's schedule an auto generate the forms i need however the lookup function works properly sometimes and improperly others i checked the syntax and it is correct how ever the wrong data is continually returned. I have attached the file if anyone can help. the VISUAL PLAN tab is the one contaning the formula and it pulls data from PLAN, CURENT SCHEDULE, AND CATAGORY SUMMARY however the only formulas hat i have a problem with are the ones referencing CURENT SCHEDULE.
View 9 Replies View RelatedLookup Type Function Returning Multiple Values
May 23, 2007I have attached a sample spreadsheet which describes my problem.
In C2 and C3 under the first business coalitions column, I have written in text what I would like to be displayed automatically with a formula. The trouble is that, as you can see, Abbott Laboratories is a member of 3 business coalitions. Therefore, a simple vlookup doesn't work because that would only return 1 result.
VBA Type Mismatch
Aug 21, 2014I am getting a type mismatch with the following:
HTML Code:
Private Sub Export2Pdf()
Dim sFileName As String
'Create file name
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")
[Code] ........
something to do with this:
HTML Code:
sFileName = Range("employeename").Value & " - Payslip" & " - " & _
Format(Range("enddate").Value, "dd mm yyyy")
Type Mismatch
Feb 14, 2009I have used this code previously and it worked however I now get a type mismatch error in the line coloured red..
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Feb 24, 2014The line I first used was:
var all_spans = document.getElementsByTagName( 'SPAN' );
for( var i =0,skip =0 ; i [code].....
Error 13,Type Mismatch
Jul 1, 2009I am getting error Type mismatch error the moment i enter value in Cell T54 and CLICK "DAILY" on Daily button.Waiting for the solution.
I am attaching the file.
Type Mismatch For RowSource
Aug 25, 2009I have four columns of data and 25 rows (A1:D25). I wish to add this to a multi-column list box in my user form. My userform is called FundSelect, and my listbox is called FundList. The ColumnCount property is set to 4. When I use the command:
View 4 Replies View RelatedType Mismatch Error 13
Feb 8, 2010I'm trying to write a pretty simple macro which invokes a built-in DDE function to retrieve some data, then when the data is retrieved, just show a msgbox. When the data is finished being retrieved, cell(20,11) in the sheet "Historical Data" will automatically have "FINISHED" placed in it. So while the retrieval is taking place, I'm simply looping and checking the contents of this cell waiting for it to read "FINISHED". My problem is the 'Do While Sheets("Historical Data").Cells(20, 11) <> "FINISHED"' line generates a "Type Mismatch Runtime Error 13", which I can't for the life of me understand why.
View 2 Replies View RelatedWhile Loop With Type Mismatch?
Mar 23, 2012I have a while loop that counts backwards in a seriescollection to find the last value with data. In one particular case, I had to use an IF formula in the source data where it would output NA() if the statment was false, so instead of loop through empty strings until the loop finds a number, it loops through #NA until it finds a number.
This ALMOST works. In Debug mode, the loop actually returns a value of 141, which is what I want, but it won't store it in a variable.
Code:
Dim arrRedLimit As Variant
Dim dblRedLimit As Double
Dim i As Long
[Code]....
(P.S. why I would have "NA" as an output, its because it won't graph, where putting "" for my false condition did)
Getting Type Mismatch Error
Jan 16, 2013I am using this code:
Code:
With wshvar
.Range("A16") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) - 1)
.Range("A18") = Application.Index(wshcore.Range("A:A"), Application.Match(.Range("A17"), wshcore.Range("A:A"), 0) + 1)
End With
but receiving a 'Type mismatch' error with the highlighted code.
Find Value - Type Mismatch
Feb 23, 2013I tried to find value on the other workbook. Gives me error "Type mismatch"
Below is the code in my VBA project
Code:
Private Sub Worksheet_Change(ByVal Target As Range)
Application.ScreenUpdating = False
Dim ResVal As Variant
Dim FindId As Range
If Range("Cnst") 1 Or Target.Row = 1 Then Exit Sub
[Code] .......
Type Mismatch From VBA .Find
Jan 16, 2007This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP.
Run-time error '13':
Type Mismatch
dim c as Range
...
Set c = .Find(what:="LIQ", _
LookIn:=xlFormulas, _
LookAt:=xlPart, _
SearchOrder:=xlByRows, _
SearchDirection:=xlNext, _
After:=ActiveCell, _
MatchCase:=False)
ActiveCell is a single cell on an unhidden sheet - cell A279.
I can Control-F at this point in Excel, and it finds "LIQ" just fine.
Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange.
Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.)
Type Mismatch Error When The Value Is Zero In VBA
Feb 19, 2007I have a piece of VBA code that acts weird. For brevity I am doing a function call like this:
val=MyFunc( [D1] )
and
Function MyFunc(mean As Double)
D1 is a named range which is a single cell. It contains a double.
The problem occurs when the value is zero, I get a type mismatch on the function call. If it is non-zero all is well.
What would cause this? I could see if zero was invalid inside MyFunc() that some calculation might blow, but it nevers gets into the function. Looks like the compiler is stopping it.
2007 Type Mismatch
May 18, 2007 Range("C1:C" & x).Value = WorksheetFunction.Transpose(Result)
I'm trying to run it in 2007. It works in earlier versions.
I get Type Mismatch error. Result is dimmed as variant type.
Run Time 13 Type Mismatch
Dec 14, 2008I have some code which i trialled in a blank workbook and was fine. when i pasted it into the workbook i am working on, i get runtime error 13 type mismatch.
Sub Trackj()
Dim a As Long
For a = 1 To Sheets.Count
If InStr("master", Worksheets(a).Name) < 1 Then
Worksheets(a).Cells(40, 6).NumberFormat = "hh:mm"
Worksheets(a).Cells(41, 6).NumberFormat = "hh:mm"
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(40, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("B52:B80").PasteSpecial (xlPasteValues)
End If
If Hour(Worksheets(a).Cells(41, 6)) = Hour(Now()) Then
If Minute(Worksheets(a).Cells(41, 6)) = Minute(Now()) Then
Worksheets(a).Range("B2:B30").Copy
Worksheets(a).Range("D52:D80").PasteSpecial (xlPasteValues)
End If
End If
End If
End If
Next a
End Sub
And the line that gets hilighted in the editor is:
If Hour(Worksheets(a).Cells(40, 6)) = Hour(Now()) Then
VB Enquiries - Type Mismatch
Jan 9, 2009what i know what's actually type mismatch and how do i solve it?
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Jul 24, 2009When my macro runs through the above code, I get a type mismatch error. All of the cells are formatted at Date only.
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May 16, 2014When I run the following code I get a (Run-Time error '13': Type mismatch). When I click debug it highlights line 41
[Code].....
Basic Syntax / Type Mismatch
Jul 15, 2014I am trying to accomplish the following: iterate through rows of a selection, delete row if the first column cell is empty or the second column cell equals 0.
So far I have:
[Code] ........
I am getting a type mismatch error at my if statement.
Runtime Error 13 Type Mismatch?
Aug 18, 2014i have written a vba code to open excel file saved at network server. The issue is code opens the file but gives "Runtime Error 13 Type mismatch"
Code :
<code>
Sub test_opening()
Dim filepath As String, filename As String, completename As String
Dim hurray_macros As Workbooks
[Code].....
Runtime Error 13 Type Mismatch
Jan 30, 2009I seem to have some type mismatch in my macro...
The error appears every time i insert or delete a row in the worksheet.
This is the ....
Case Statement Getting A Type Mismatch
Jun 16, 2009I made this case statment below to look at a cell in Q and if the cell value is "Large Area" then the cell in P same row should be 1 if the case is Varsity then it would be 2 however I keep getting a Type Mismatch. I tried Picker.Text and Picker.Value as well I didn't get errors but it didn't work either.
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