=IF((OR(B14=1,2,3,12,15,16)),"A",IF(OR(B14=4,5,6,7,8,9,10,11,13,14,21,40,41,42,43,44,45,46,47,50,51, 52,53,54,55,56,59,60),"B",IF(OR(B14=20,30,57,58),"C",IF(OR(B14=33,31,32,34,35,22),"E F OR G",IF(OR(B14=36),G,"ERROR")))))
I am trying to write a formula that will satisfy the following:
C1 and G1 are number values.
IF (cell E1 does not contain any text) AND (G1-C1-12.5>=0), then output (G1-C1-12.5), otherwise output nothing (""). BUT, IF (cell E1 DOES contain text) AND (G1-C1-13>=0), then output (G1-C1-13), otherwise output nothing.
I have a sales ladder which ranks my people by the % difference between budget and sales to date, but not everyone has made a sale yet and the % difference is zero for 6 people. These 6 people all have a rank of 75. Where this happens, I want to then rank only those 6 people, based on their budget figure.
My current formula reads: =IF(F83=0,75,RANK($G83,$G$9:$G$83,0)) where F is the sales value and G is the % difference. Budget figures are in column D.
=If(isError(find("-";a1));mid(a1;3;9);mid(left(a1;search("-";a1)-1);3;9)) where: a1=AN03048-12 and its result I wanted is the following: 03048 (great! ) But... what if I'd have ANN03048-12? Then the result would be N03048...
How can I obtain only 03048 or whatever (but only numbers) avoiding previous letters? How can I only pick numbers without letters starting from the left beginning of the record? I'd like to get only numbers before the "-" symbol. I think I should add a function before or instead of the "3" number (which I highlighted in red) in the second mid() function
I would like Excel to look at column A, and if there is a number0, count it and go to the next row. If it's =0, then go to column B and see if THAT number is 0. If it is, count it; if not, go to C. So my data looks like:
A B C 0 2 3 4 0 0 0 0 0
I only want it to count one time per row, so right now I am using =IF(COUNTIFS(A2:A30,"0",B2:B30,"0")0,COUNTIFS(A2:A30,"0",B2:B30,"0"),IF(COUNTIFS(B2:B30,"0",C2:C30,"0")0,COUNTIFS(B2:B30,"0",C2:C30,"0"),0)))
I also tried it with a SUMPRODUCT to simplify but both formulas are getting me the wrong answer. I'm using Excel 2007.
I have 12 teams(rows) and would like a cell(A21) to show the team name after determining the max value of the column(O). Is there another way to do it besides "ifs", I've maxed out the function at 7, but there are 12 teams
If I could get this figured out it would be great, and a seperate question/addition problem I would also like to do is have the cell come up the same color as it is above.
I am currently having trouble with what I thought was a simple IF statement. As you will see from the formula I want to complete a statement for every month of the year but Excel will not let me go past July. Is there a limit to the number of arguments in an IF statement and how do I overcome this? =IF($A$3="Jan'08", SUM(C7),IF($A$3="Feb'08",SUM(C7:D7),IF($A$3="Mar'08",SUM(C7:E7),IF($A$3="Apr'08",SUM(C7:F7),IF($A$3="May'08",SUM(C7:G7),IF($A$3="Jun'08",SUM(C7:H7),IF($A$3="Jul'08",SUM(C7:I7),"n/a")))))))
I am having trouble evaluating two conditions with nested logical operators to produce the output I need.
For example Condition 1 has 5 choices (A,B,C,D,E) and Condition 2 has 3 choices (a,b,c).
Breaking it down, [Condition 1] option "A" always applies and should give "Yes" (No matter [condition 2], "A" always gives "Yes") [Condition 2] option "c" always applies and should give "Yes" (No matter [condition 1], "c" always gives "Yes")
[Condition 1] option "D" never applies and should give "No" (No matter [condition 2], "D" always gives "No")
[Condition 1] options "C" and "B" only apply if [condition 2] is "b" (if so, the answer is "Yes")
What I need is the equivalent of:
if ((([condition 1] == A) || ([Condition 2] == c)) || (([condition 1] == B || C) && ([condition 2] == b)), "Yes", "No")
I am trying to make a multiple nested spreadsheet. I get as far as the first 2 and then can't seem to get the data validation to work. I tried several different formulas (indirect(vlookup)) ones but must be doing something wrong. I have the "lists" on the second sheet to be referenced for the first sheet as drop down menus.
I do building material appraisals and this sheet will be to help me with the inspections if I ever get it done. It is supposed to work like this - Area - Item - then depending on the item - three consecutive dropdown lists with further information.
I am aware of the following topic in the VBA Help file:
"Using Microsoft Excel Worksheet Functions in Visual Basic You can use most Microsoft Excel worksheet functions in your Visual Basic statements. To see a list of the worksheet functions you can use, see List of Worksheet Functions Available to Visual Basic.
Note Some worksheet functions arenít useful in Visual Basic. For example, the Concatenate function isnít needed because in Visual Basic you can use the & operator to join multiple text values."
And I'm aware of how to call Excel funcitons from within VBA; e.g., answer = Application.WorksheetFunction.Min(myRange)
However, not only are some Excel functions not useful; the fact is they cannot be used because VBA has a native function that does exactly the same thing and you have to use that native VBA function to achieve your goal. It is these overlapping functions that I am especially interested in. I want to know what I should use directly in VBA and what I need to go to Excel for.
My objective is to replace a text string with a numeric variable. The string has text values such as US, Canada, Germany, France etc, There are about 15 such words in total. Each row will have a different one of the 15 text strings.
Each text string has a corresponding number, which I want to use in various formulas throughout the spreadsheet. The numbers are located on a separate worksheet (ďMatch RateĒ), within the same workbook. I obtained the numbers from a formatted report, which I simply pasted into the second worksheet. Due to the complexity of the report, I canít reformat the numbers to allow use of the VLOOKUP function.
I created the following function, but unfortunately it doesnít work. Can you help, please?
Iíd like to stay with a VBA solution, since a simple if/then sequence such as this is an excellent introduction to the powerful world of VBA... (it just doesnít work, yet). I suspect the problem is in the calls to the Match Rate Worksheet.
Ok. Here's what I'm trying to do. I have a drop down menu of certain providers located on cell F5. Each one charges different rates per day located on another sheet. Here's the kicker two of those providers charge different rates depending on the amount of days. Those two are UASC and CMA. For the First 5 days they charge one rate and after the 5 days they charge an increased rate.
I'm trying to have one cell located on the first sheet display this information with all the proper calculations. The below formula gives me a false value. I'm not even sure if it works. I know a little bit of excel through some intro courses in college but I'm not sure if a formula like this would work. I know laugh it up.... : ) but I'm not too saavy with formulas....
I'm building a macro and need to know how to add a nested if-then statement. I need to create a formula in a new column whose value extends to the last row of the database. My base formula is sumproduct(--((A2:A:last row which I need to calculate&B1:B same thing)=A2&A2))
I'm trying to build this formula and I'm only half way through it and it already isn't working. Column D - can be 1, 2, 3, or 4 Column E - can be any number
If column D is 1 or 3, then the VLOOKUP should look up column E and point to the answer in column 4 on another worksheet (Companies in this case). If column D is 2 or 5, then the VLOOKUP should look up column E and point to the answer in column 5 on another worksheet (Companies in this case). This is what I have so far, just trying to get it to recognize if it is a 1 or 2:
I am trying to create a nested IF function (has 5 IF statements), however, every time I put the brackets at the end of the function, it puts a little . next to the false answer, removes the brackets and comes up with an error message?
This is only happening on one particular PC, when I create the same formula on other pC's, it works fine so I know my formula is correct.