Sum First Character Of List Of Values

May 13, 2013

I'm looking for a formula that can sum the first character of a list of values together, based on the cagegory.

Example below:

Column A = The category (or name of a person)
Column B = The status, I'm interested in the first character of the status (which is always a number)
Column C = The sum of the status based on the first character of the status for that specific person

James
1.0 Not Started
8

James
1.1 Not Ready
8

[Code] .....

I want to do this without adding another column (i.e. I can get the result adding a column with formula "=value(left(B2,1))", but I don't want to add the extra column)

I'd also prefer to avoid doing this with a macro, as this part of the formula is only a smaller part in a larger formula.

I tried to look for an entry in this forum, but couldn't find one that matches what I need.

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1 2 3 4 5 a b 6 ....

after combin (x,3) i want to list me this: 123........but each number must be in separate cell (1-one cell, 2 -one cell, 3 -one cell)

124
125
12a
12b
126
234
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An error occurs when a Model Number list box item is selected but not when a product ID is selected.

The difference between the two are AlphaNumeric vs only numeric.

USBLT15CMB - Product Description 1
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the code is:

Private Sub CommandButton1_Click()
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[Code]...

The macro stops on the ID = line

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Good
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Does the list need to be alphabetized?

Could it be something that is entered into the data validation box? This spreadsheet has data validation in 35 columns.

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code as below... be grateful for your help

Sub measure1()
Dim list As String, pos As Integer, refl As String, refr As String, newlist As String
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Refers to:
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Dim row As Range
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[Code]....

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This is how the table looks like.

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4" AB1 AB2 AB3
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Sample data Required Output
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I currently have a formula that seems to work for this purpose but I don't know how to add the condition in #2 (below)

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Here is the formula I currently use which serves #1 (above):

[Code] .....

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Example of desired results:

Column A | Column B
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DD | CC
AA | DD
CC |
DD |
DD |
IC |
IC |

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My formulaic solution is thus: .....

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