Vba : Error Returning Validation Object

Apr 14, 2007

I am trying to read Formula1 from the the Validation object. If the cell does not contain a Formula1 - I get on object error.

In:
http://www.ozgrid.com/forum/showthread.php?p=95521

Derk suggested "That error occurs when the activecell has no validation. Some of the properties return as "codes" so you will need to figure out what say -1 means for alertstyle." I do not know how to test for this.

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I have problems with setting Validation input title and message. When in column "C" I type product code, data validation of corresponding cell in column "D" changes to list of diameters allowed for that product. That works fine. But i also want to set validation message to show allowed diameters.I set it in VBA using named ranges.
But for every second line (13, 15, etc on attached file) I get an application-defined or object-defined error. The rest (14, 16 etc) works ok.

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How do I add multiple worksheets at once after opening a new workbook? I was able to go to Insert>Workbook but it only adds one sheet at a time. I I need to add 50 woorksheets, I don't want to really click 50 times.

Insert a new worksheet
To add a single worksheet, click Worksheet on the Insert menu.
To add multiple worksheets, hold down SHIFT, and then click the number of worksheet tabs you want to add in the open workbook. Then click Worksheet on the Insert menu.

When I hold down the shift button and enter 50 i get the "%" and ) sign entered on the open workbook and then I try to click worksheet from the insert tab and it is greyed out.

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Code for the dictionary build has been included below. I have attached the Excel file which contains the appropriate module which calls that function

VB:
Option Explicit[ATTACH]46705[/ATTACH]
Function DictAppTable(Loop_Range As Integer, Key_Range As Range, Dim_1 As Range, Dim_2 As Range)
Dim DictTable As Dictionary
Dim AppElement(0 To 0, 0 To 1) As Variant
Dim iD As Integer
Dim strAppID As String

[Code].... the previous post, as the pared down excel file which I posted had a slight error which prevented it from running

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Code:

Sub Copy_NationalAccounts_Rows()

Const Message As String = "Select the entire range containing National Account Y flags, then press Enter or click OK."
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Dim rngSource As Range
Dim rngDest As Range
Dim r As Range
Dim c As Integer
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[Code] ........

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I am having difficulty getting a form to work the way that I would like it to work. I have a form that is used to display questions that my students will be answering. The form also is used to put the answers into a worksheet. I have 2 sheets. Sheet2 has the questions, student answers, and correct answers. Sheet1 is used to indicate correct answers and to keep track of percentage correct. I am fairly new to VB. I have 2 pieces of code that I am going to post. The first one works and the second one doesn't.

This is in the "This Workbook" section and it works.
Option Explicit
Public intNoQ As Integer
Public strNoQ As String
Public NumberofQuestions As Integer
Dim StudentName As String
Dim InputBoxAnswer As String
Public Sub Workbook_Open()
Application.Visible = False 'Hide Excel
Load Questions
Load NumberCorrect
NumberofQuestions = Worksheets("Sheet1").Range("K3").Value
For intNoQ = 1 To NumberofQuestions
strNoQ = VBA.CStr(intNoQ)
If intNoQ = 1 Then
Questions.Controls("QuestionNumberBox").Value = "Question#" & strNoQ
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Next intNoQ...............

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[URL]

If I go any of the cells in that column, the VBA code page opens up and I get the following message:

Compile Error:
Ambigous name detected: Worksheet _SelectionChange

and the following vb code is hightlighted:

Private Sub Worksheet_SelectionChange(ByVal Target As Range

The code I have used is:
Private Sub Worksheet_SelectionChange(ByVal Target As Range)
If Target.Count > 1 Then Exit Sub
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Else
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End If
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VB:
Sub GetRangeName()
Sheets("TOTAL").Select

[Code].....

use code tags around code. Posting code without them makes your code hard to read and difficult to be copied for testing. Highlight your code and click the # at the top of your post window.

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Dim filepath As String
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MsgBox ("File Appended")
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On using the same on a worksheet I'm getting a #VALUE! error and for the life of me am not able to pinpoint the problem area.

Public Function CBOList(Rng As Range, App As String, OutRng As Range) As Variant

Dim Func As WorksheetFunction, UniqueVals As New Collection
Dim cnt, who
Dim ctr As Long, lst As String
Dim myarr() As Variant

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Application.Volatile...........................

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VB:
rivate Sub Btn_Edit_Click() ' code for Edit Function
Dim findvalue As String
Dim FileName As String

[Code].....

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HTML Code:
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Jul 28, 2007

Sub Macro2()
'
' Macro2 Macro
' Macro recorded 7/28/2007 by i8ig
'

If Target.Column = 1 Then
If Target.Value = "Med" Then
Rows(Target.Row).Interior.ColorIndex = 4
Range("H3").Select
ActiveCell.FormulaR1C1 = "=IF(RC[3]="""","""",RC[3]-3)"
Else
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Rows("4:4").Interior.ColorIndex = 44
Range("H4").Select
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Else
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Range("H5").Select
ActiveCell.FormulaR1C1 = "=IF(RC[1]="""","""",RC[1]-2)"
End If
End If
End If
End If
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I continue to receive an error '424' object required and I cant find it

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Nov 3, 2009

I have two worksheets one called "invoice" and one called "tenants"
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I have put the following macro in

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Dim res As Variant
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but get the following error - "object required"

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cr = vbCrLf
quot = Chr(34) 'quotes

Dim l As FileSearch
Set l = Application.FileSearch

s = InputBox("Search", " Enter the text you're looking for.")

With l
.NewSearch
.LookIn = "D:FinancialNews"
.SearchSubFolders = True
.FileName = "*.xls"
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Jan 20, 2007

Private Sub Worksheet_SelectionChange(ByVal target As Range)
If programmatic Then Exit Sub
selectionChange (target) ' 424 occurs on this line
End Sub

Private Sub selectionChange(target As Range)
' sub implementation here

I can't see anything wrong with my sub call that would cause a 424: Object Required.

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Sub CIT_SLA()
'Name and size the range CIT_SLA so the Word file (EOM Report) can pick only the relevant cells
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End Sub

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using Excel = Microsoft.Office.Interop.Excel;
using Office = Microsoft.Office.Core;
...
...
Excel.Application xlApp;
Excel.Workbook xlWorkBook;
Excel.Worksheet xlWorkSheet;

xlApp = new Excel.ApplicationClass();
xlWorkBook = (Excel.Workbook) xlApp.ActiveWorkbook;
xlWorkSheet = (Excel.Worksheet) xlWorkBook.Worksheets.get_Item(1);

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TextBox5.Text = Cells(rngFind.Row, 2)

Option Explicit
Sub locate(Name As String, Data As Range)
Dim rngFind As Range
Dim strFirstFind As String
Dim Find As String
With Data
Set rngFind = ActiveWorkbook.Sheets(1).Cells.Find(Name, LookIn:=xlValues, LookAt:=xlPart)
If Not rngFind Is Nothing Then
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Do
If rngFind.Row > 1 Then
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