I'm trying to automate the attached schedule so that the formulas in H stop increasing once the amount in column J equals zero. So far everything I've tried either gives me a circular reference error or ends up giving me the same result as if I depreciated the asset an additional month.
View 3 RepliesI request a help:
A1 = 01-Apr-2009
B1 = 02-Apr-2009
C1 = 03-Apr-2009
D1 = Blank
E1 = 05-Apr-2009
F1 = 06-Apr-2009
What is the best suitable formula to find "First blank cell", then "date difference" between today and its previous cell's (i.e today minus "C1" in this case).
I need to calculate the amount of time between two dates, and show it in the number of hours and minutes. My dates are formatted to show the time in Zulu time. So 1406 = 2:06PM.
Here is what I have:
A1 = 6/4/08 1406Z
B1 = 6/5/08 0402Z
For this example, the formula should return a result of 13 hours and 58 minutes. With the result, there is no need to desingate Zulu time with a 'Z'. But I need the result in a format that will allow me to calculate an average for all my data.
I'm looking for a macro or formula that can calculate the difference to the lowest of col C based on option in colB. See attached. I complete what it should look like in F. Basically, this can be done by sorting the data by colB and using this formual for every group. =C2-MIN($C$2:$C$4). This is not ideal because I have many of these to do and you have to adjust the min range for every group. Plus group sizes will vary.
There has to be a better way. Ideally, I would not like to have to sort the data, unless a macro did it for me....
I have 2 columsn with data that looks like this:
Creation DateResolved DateDifference in days7/1/2011 4:221/9/2012 14:587/1/2011 8:567/1/2011 13:517/1/2011 11:438/3/2011 17:157/1/2011 11:597/14/2011 14:077/3/2011 22:477/5/2011 11:037/4/2011 1:399/15/2011 15:207/4/2011 8:367/5/2011 9:357/5/2011 7:047/6/2011 9:107/5/2011 9:177/6/2011 10:007/5/2011 10:471/9/2012 14:37
I am trying to figure out what formula to use to calculate the difference between the creation date and resolved date in hours and days. That is, In once column I would like to see the difference in 'hours' and in another column I would like to see the difference in 'days'.
This is more of a query on date dif
I was trying to calculate the difference between two dates on excel
I had a look through the search message board and searched the web generally where I came across the datedif function
I had found that in order to get the number of years it was
=datedif(startdate,enddate,"Y")
for months same formula"YM" and for days use "MD" in place of "Y" in the original formula
My question is when using datedif to calculate the number of days between two days it initialy gave me the right answer
Number of days between 01/08/2008 - 22/08/2008 - Answer 21 days
Using date dif gave me 21 days but when i did
01/08/2008 - 01/09/2008 - this gave me 0
Am I entering the formula wrong or does datedif simply not pick the difference if the days havent changed even though the month has ?
I then found i could simply minus one from the other , which then had me asking what is the point of date dif
is anyone aware of a formula/macro that can calculate (in days, hours and minutes) how much time has elapsed between two date and time stamps?
For example [30/07/2008 00:30] and [01/08/2008 01:45], so in days hours and minutes it would look somewhat like this: 02:01:15
Example.xlsx
how to calculate the difference in value of an item between two dates on a pivot table. I have one table that feeds the Pivot Table and it has three fields:
Data as of Date
Item
Value
So each day, the Data as of Date is updated to the current day and the items are the same but the values are different. I need to calculate the difference in value between the most recent date and x days ago. I cannot figure out how to do this via Pivot Table.
I'm just trying to calculate the difference between dates in two columns and applying conditional formatting based on if it is a positive or negative number. But when there is a null value in either of the date columns I don't want anything returned.
So far I'm either getting a 0 or a FALSE.
Column A = Date 1 Column B = Date 2 Column C = Formula
=IF(NOT(ISBLANK(B2)), B2-A2, )
I am trying to determine the average reduction amount of appraised property values. I have two columns in my spreadsheet. Column H has appraised value of property. Column I has the accepted value of the property. Sometimes the accepted value is the same as the appraised value, sometimes it is reduced, and sometimes it is rejected.
I want to be able to find the average reduction amount when the accepted value is less than the appraised value and is not rejected.
Column H always shows a numerical value (i.e. $250,000), but Column I may have a numerical value or show "rejected".
I am currently usins Excel 2007 and would like to calculate the diferrence in hours and minutes (ideally in decimal e.g 4:30 should be reflected as 4.5) between two date and time groups, excluding the non-working time between 17:00 and 09:00, weekends and holidays. An 8 hour working day is to be used. I have attached a spreadsheet were I tried to achieved the above with little success.
View 2 Replies View RelatedFrom the below example, I would need to know the difference between date & time of Received and Resolved in number of days. Meaning - time difference should also be calculated in days
CELL ACELL BCELL CCELL DCELL E - REQUIRED OUTPUTReceived
DateReceived
TimeResolved
DateResolved
TimeTurn Around Time - IN DAYS20-Jan-122:43:00 PM23-Jan-124:50:00 PMDifference between Resolved date & time and Received date & time
I have a number which consist of 12 digits such as 765432123345. The first two digits denotes the year. I need to create a formula in the next column to calculate the difference in years by comparing to the current year of 2013. In this scenario, the difference will be 37. Is there a way to do this?
View 5 Replies View RelatedI have a huge two column spreadsheet. The first column is a list of times in the format: dd-mm-yy hh:mm:ss and the second column is a status of either START or STOP
Every time there is a START, I want it to count the difference between that time, and the next STOP time, and display the results in column C
Sometimes there will be multiple START's in a row or multiple STOP's in a row, but I am only interested when the status actually changes from the first START to the first STOP. It then resets until there is another START.
Here's an example of how I'd want it to function:
13-06-13 01:22:13 START
13-06-13 01:22:16 START
13-06-13 01:22:20 STOP 00:00:07
13-06-13 02:20.01 STOP
13-06-13 02:21.03 START
13-06-13 03:22.04 STOP 01:01:01
I can do this manually, but of course there is too much data to do that, so I'm looking for an automated solution that looks at the status.
I want to calculate time difference from two columns,
00:00:18:4400:00:28:44
00:00:19:2400:00:29:24
00:00:34:7700:00:44:77
00:01:05:3200:01:15:32
00:01:05:3200:01:15:32
wanting the difference between col B and col a.
Sum doesn't work
I have two Rows of data. Each row contains a unique Name column and separate columns for Date, Hour and Minute. I would like to calculate the Time difference in Days, Hours and Minutes between the two Dates. I’m not sure if the way I’ve set it up is the most practical. I’ll attach the spreadsheet to better explain.
View 4 Replies View RelatedI am working on an employee weekly schedule and would like to be able to calculate the amount of hours an employee is scheduled each day. For example; if you worked from 7am to 4pm, I want to have a formula that can determine that (7am to 4pm= 9 hours) then sum the total amount of hours for all employees scheduled that day.
Mon Tue Wed Thrs Fri Sat Sun Total
Employee 1 7-4 7-4 8-5 off 2-10 5-10 off 40
Employee 2 8-5 11-8 off 7-4 1-8 off 8-5 43
Hours 18 18 9 9 15 5 9 83
On some Military computers the Add-ins were not installed, therefore the WEEKNUM function cannot be used.
The task is to calculate the time interval (in whole weeks) between two dates.
(Every start date is to be calculated as a whole week – same for the End date).
I tried but the most but came up with the incorrect formula in the attached workbook.
i've two time constraints with 22:00~6:00 and 6:00~22:00. i'll apply time span to two constraints,calculate time covering on two constraints. it will start at anywhere of 00:00~24:00, time span will be 00:00 ~24:00. i add some formula, a3=start time, b3=end time. time constraints with 22:00~06:00:
=IF(AND(A3<=22/24,B3>=6/24,A3>B3),8/24,IF(AND(A3<6/24,OR(B3>22/24,AND(B3>0,B3<6/24,A3>B3))),IF(B3>=22/24,(B3-22/24)+A3-6/24,(B3+1-22/24)+MOD(6/24-A3,1)),IF(AND(OR(A3>=22/24,A3<B3,A3=0),B3<=6/24),IF(OR(A3=0,A3=1),B3,IF(A3>B3,B3+1-A3,B3-A3)),IF(AND(A3<=22/24,B3<=6/24),MOD(B3-22/24,1),IF(AND(A3>=6/24,B3<=22/24,A3<B3),0,IF(AND(A3>=22/24,B3>=6/24),(1-A3)+6/24,IF(AND(A3<=22/24,B3>22/24),B3-22/24,6/24-A3)))))))
time constraints with 06:00~22:00. :C$3=start time,$B4=end time...............................
I am setting up a time and attendance system.
What I want to do is calculate the overtime that someone has worked but in multiples of 15 minutes.
Example, if someone worked 20 minutes over they would be paid for 15 minutes overtime.
If someone worked 31 minutes over they would be paid 30 minutes overtime.
The possible overtime someone could work in one day is 6 hours.
I want it to return the overtime in decimal numbers (e.g 0.25 for 15 minutes overtime).
I have attached a sample spreadsheet.
I would prefer this to be done in VBA if possible?
I'm trying to do some calculations involving times. I'm using the format [=A2+(A1>A2)-A1] in order to calculate times from one day to the next which avoids negative numbers. This is working well. My problem is now that I'm trying to develop my spreadsheet and am trying to embed this inside an IF statement as the [value_If_True]and I get an error because it doesnt like the leading equals sign inside the IF statement.
View 6 Replies View RelatedI have a pivot table and I created a formula that says:
=jobCompletedDate-jobCreatedDate
and so for example, I have
3/31/2014 7:21AM - 3/31/2014 6:33AM
and that difference is giving me: .03367
I'm not sure what this value represents......the difference in dates, converted to ??
Time arithmetic, I have two cells representing a time range.
The first one (say: X1) is formatted using the custom format [h]:mm and contains a certain number of hours and minutes. It gets its value by summing up other cells in the same format. A typical entry could be 98:35 to represent a duration 98 hours and 35 minutes.
The second cell (say: X2) is formatted as a number with 4 decimal places after the comma, and similarily gets its value by summing up other cells in the same format. It also represents a time duration as a number of hours. A typical entry could be 202.7500 to represent a duration of 202 hours and 45 minutes (because 0.75 of an hour is 45 minutes).
I would like to calculate the hour difference between these cells, and display it as hours and minutes. In the example given, the result should be negative, i.e. -104:10.
My first approach was to use the formula X1-X2 and format the result as [h]:mm, but this gives me a #VALUE! error.
I need to calculate the date difference between two dates and get the result in the number of years and proportion of months ie;
20/09/99 to 01/02/02 is 2.33333333 years. I can use the DATEDIF function to get 2 years 4 months as the result but for the calc I'm doing I need it in the format of 2.33333333. Thinking I just need to tweak the DATEDIF a bit but just can't work it out!
So I am running in to a large brick wall! I have a single pivot tablet with a column for items received and then a column for items shipped. I would like to create a calculated field in the pivot table that will subtract the items received from the items shipped columns. I have attempted to add the calculated field using the tool bar but it keeps giving me "0" for every item on the pivot table when there are obvious differences.
View 1 Replies View RelatedI'm trying to create a VBA piece to calculate the standard deviation of the difference of two arrays. I have two columns of data and i want to create a third column that is the first minus the second and them calculate the standard deviation of that. My problem is that i wanted to do all of this behind the scenes in VBA (didn't want to output the third column).
View 3 Replies View RelatedI have a vacation data of my company. I want to calculate difference between two dates (relieving date & rejoining date) after excluding holiday(which I will decide as per my company policy) also note that now i m in gulf country hence here Friday is weekly off not Sunday.
View 9 Replies View RelatedI have a data table with incidents in which one column is equipment number and one is data of occurrence. I now need to calculate how long ago the same equipment number occurred.
View 2 Replies View RelatedI'm working in excel2007:
I want to write a generic formula to calculate the difference of time between cells, the first being a real data point, such as
6/22/2007 8:53
minus a generic constant term using the same date and a given time, 8:30.
So, what I need is something like this:
6/22/2007 8:53 – (same mm/dd/yy @ 8:30)
6/22/2007 12:29 – (same mm/dd/yy @ 8:30)
6/25/2007 11:19 – (same mm/dd/yy @ 8:30)
I wanted to calculate the difference between dates, excluding the weekends. After much thought i used =NETWORKDAYS(A1,B1)+IF(NETWORKDAYS(A1,A1)+ NETWORKDAYS(B1,B1)=2,-SIGN(NETWORKDAYS(A1,B1)),0) that seemed to be working fine. However, I had a problem today with this formula when my start day was saturday (24/05/08) and the last day was monday (26/05/08). What i want is that when i take the difference between these two days, i should get zero as answer as we are not including the weekends in calculation so the start date should ideally be the first weekday which is Monday. However, the formula is giving me 1 as an answer.
This formula works fine if i select 27/05/08 as last date in which case i get 2 as an answer which is right. In gist, what i am looking for is a formula which will give me the difference between two dates and exclude the weekends from the calculation. The last date can't be a weekend, but the start date can. Hence, whenever the start date is a weekend, the formula should take monday as a start day.