Extract Last Word Of Sentence Regardless Number Of Spaces

Nov 22, 2013

I've a list of names with different numbers of spaces, i would like a formula to give me the last name regardless the number of spaces...

is that possible?

List example:
Amelia Alexandra Correia Almeida

Maria Albertina Alves Moreira Figueiredo

Mario Miguel de Oliveira Azevedo Feitor

Carla Maria Bastos Soares
Carlos Sousa Teixeira

extract Almeida, Figueiredo, Feitor, Soares and Teixira

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[Code] .....

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I can run the sumproduct....

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Much the same as above when a cell has:

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Sub Macro1()

'this deletes all rows if cell in column J says "total"

Dim DeleteValue2 As String
Dim rng2 As Range
Dim calcmode2 As Long

With Application
calcmode = .Calculation
.Calculation = xlCalculationManual
.ScreenUpdating = False
End With

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To be

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For Example...

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The cell has this word : "LPPJ4K2**" ' in excel the * appear as a white space

Code:

Filler = "LPPJ4K2**" ' this word is actually is in a cell
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I have a cell with a postal address.

eg -

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cell a2 - 'flat 41, first floor, 21 church lane, quorn, loughborough, leicestershire, le12 7zx'

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I have tried
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or
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Find the attachment : File1.xlsx‎

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I have come up with this to Trim all of the data from rows 2:30 removing any trailing spaces after the last word in each cell. The macro takes a couple of minutes to run have I got something wrong that is making it run slowly or does the Trim process just take longer?

Sub TRIM_RANGE()
Dim myRange As Range
Dim myRow As Range
Sheets("CAMPAIGNS_2007").Select
Set myRange = Range("2:30")
If myRange Is Nothing Then Exit Sub
Application. ScreenUpdating = False
myRange.Replace What:=Chr(160), Replacement:=Chr(32), _
LookAt:=xlPart, SearchOrder:=xlByRows, MatchCase:=False
For Each myRow In myRange.Columns
If Application. CountA(myRow) > 0 Then
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DataType:=xlFixedWidth, FieldInfo:=Array(0, 1)
End If
Next myRow
Application.ScreenUpdating = True
End Sub

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