Find The First Cell In A Row With A Date

Feb 20, 2010

I have a table which, across the top, has different cell titles, say "Category" in A1, "Budget" in B1, and C1 through F1 are date values. I need a formula which will return "C1", because it's the left-most cell in the first row which contains a date.

I know I can find a date with ISNUMBER or the TYPE functions. But I cannot get TYPE to work on an array. Honestly, I can't even understand the behavior of TYPE. Let's say B1 contains a string, and B2:B8 contain numbers.

If I select one cell and do TYPE(B1:B8) and press enter, I get "2", because B1 contains text. If I change B1 to a number, the TYPE cell returns "16", which means error. Wha....?

If I instead press CTRL+SHIFT+ENTER on the TYPE cell, I get "64", which is the array type. So obviously this is not doing what I want it to do (which is to run the function TYPE on each of the cells B1 through B8). With ISNUMBER, I can get the array functionality, but I want to find the *first* numerical cell, not if each cell is a number.

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Code:
Dim DateSearch As Date
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Cells.Find(What:=DateSearch, After:=ActiveCell, LookIn:=xlValues, _
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Example workbook is attached

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fldcollected fldaccepted Type Time between being received by database and eccepted

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A
B
C
D
E

1
PART NO.
date in
date out
comp1
comp2[code]......

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CREATE TABLES LIKE BELOW?Column A Column B Column C

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March 2, 2008Sunday
March 3, 2008Monday
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In above example the result should be like this.
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VB:
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Spreadsheet with data&code is attached.

VB:
Sub Macro1()
Dim mainrange As Range
Dim rng As Range

[Code].....

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Private Sub CommandButton7_Click()

On Error Goto errorHandler
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[URL]

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MaxDate.jpg

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