I'm looking for a formula that will return the column header (a date) of the first instance of a number greater than 0. For example if columns A through S had dates as in row 1 (header row), and in row 2, every column contained a 0 up until column P, I would want the date (Row 1, Column P) returned? I think this might be a sort of index/match formula, but I am not very familiar with these.
View 3 Replies[Code] ......
This works, UNLESS "My Column Header" is the last column, or second to last column, then it jumps left two columns, instead of landing on the correct column.
The purpose of this script is to select a cell directly in that column that I was searching for.
I have the following sample data set and I'm trying to return the appropriate column header based on criteria (i.e. DDD) and a number value which will be somewhere within the range of the table. In example below, the value returned should be Header 2 because the value is greater than those in Header 1 column (range H9 to L26).
Here's data table:
CriteriaHeader 1Header 2Header 3Header 4
ZZZ5.0015.0050.00130.00
ZZ5.0015.0050.00130.00
Z5.0015.0050.00130.00
YYY5.0015.0050.00130.00
YY5.0015.0050.00130.00
Y5.0015.0050.00130.00
DDD5.0015.0050.00130.00
DD5.0015.0025.0075.00
D5.0015.0020.0065.00
RRR5.0015.0015.0045.00
RR2.5010.0010.0030.00
R1.503.0010.0025.00
UUU0.751.505.0020.00
UU0.751.505.0020.00
U0.751.505.0020.00
P0.751.505.0020.00
T0.100.105.0018.00
CriteriaNumberValue
DDD10.00Header 1>>>=INDEX($I$9:$L$9,MATCH(I29,INDEX($I$10:$L$26,MATCH(H29,$H$10:$H$26),)))
I need a formula to return column header if there is data in the column, any data.But I also need to return the second, third, fourth header with data too
In column A row 2, I have =IF(M8"",$M$1,IF(N8"",$N$1,IF(O8"",$O$1,IF(P8"",$P$1,IF(Q8"",$Q$1,IF(R8"",$R$1,IF(S8"",$S$1,IF(T8"",$T$1,""))))))))
This returns the row 1 header for the first instance of data in row 2 columns M thru T But in B2, I need the second header with data in the column.
I need the results in yellow (1st, 2nd, 3rd, 4th) from the array to it's left
1St match2nd 3rd 4thColumn MColumn NColumn OColumn PColumn QColumn R
Column MColumn PColumn QData data2Data3
Column NColumn OColumn PColumn R Data Data2 data3 data4
Would use match/index but can't increment it to the second or 3rd match
I've been trying find an appropriate formula to extract the column header from a table in a different sheet if the row header and value in that table is known.
in the lookup table the row titles (column A) are product codes, column titles (row 2, D through AX) are business names and the table values are quantity.
In a different table I have product codes in column A and in column B i have the max number/quantity of products for that code. In column C i want to put the company name associated with the product and the number/quantity.
I am looking at formula to return the column header, see example attached.
View 2 Replies View RelatedMy file is set up like this:
Deal Jan Feb Mar....... Dec
A 0 11 0
B 0 0 23
C 13 0 12
and so on
Meaning deal A got cash of 11 in Feb and B of 23 in March
For a certain month (which could change), I want to specify the most recent month of a payment and return the month
So in April, row A returns 2, Row B March and Row C March
Cells A3:A500 contain product numbers, e.g. 1001, 1002, 1003 etc.. etc...
Cells G2:N2 are column headers, e.g. North2011, South2011, North2012, South2012 etc... etc...
Cell F2 is a lookup that will return a year, e.g. 2011, 2012, 2013 etc... etc...
Against each product is a "yes" if it was sold in the north or south region for each year. This could be both north and south, one or the other or none at all.
What I would like is a formula in cells E3:E500 that looks at the year in cell F2 and if there is a "yes" in either the North or South for that year to return "yes" otherwise blank.
I am unable to upload a sample document due to firewalls.
I'm working on a spreadsheet where I need to return the column header where the value in that row matches the criteria from an if statement.
The column headers are departments, the row headers are customers numbers, the values show the % of items sold in that department as a % of the total purchases by that customer.
I need to make a formula for each row so that if the % in any of the current row's values is 75%-100% then get the column header for the column that value is in.
I know it's an IF statement, but I don't know how to return the column header for the value when the if statement is true.
I'm trying to get all subjects that are "pass" per student #.
Student #MathScienceHistoryStatisticsPhysical EducationHealthPhysicsEconomicsTrigonometryEngineering
5200309PASSPASSPASS5200306PASSPASSPASSPASSPASS5200307PASSPASSPASSPASSPASS
5200305PASSPASSPASSPASSPASS5200257PASSPASSPASS3046109PASSPASSPASSPASS3045539PASSPASSPASSPASS
3045613PASSPASSPASSEnter Student #
If I type student number here the result will be shown below with all subject passed.Subject Passed
I have a table like the following where each ID can have no, 1 or multiple values associated with it:
Table1
ID>>>A>>>B>>>C>>>D
1>>>> >>> >>>10>>>
2>>>> >>> >>> >>>>50
3>>>5>>> >>> >>>>2
4>>> >>> >>> >>>>
I have another table that only lists IDs
Table2
ID
1
2
3
5
I want a VBA code such that if ID is in Table2, VBA looks for the matching ID in Table1 and if the matching ID found, it looks for ALL non-empty cells and if a non-empty cell is found in the row, it returns the value in the cell and the header to give something like this
Table3
ID>Column1>Value1>Column2>Value2
1>>>>c>>>10>>
2>>>>D>>>50>>
3>>>>A>>>5>>>>>>D>>>>>>>2>>>
Requirement
Vendors
Evaluation Results
Sr.
ITEM DESCRIPTION
BRAND
UNIT
A-Z
AL AMEEN
COLOR WORKS
INDEX
OXFORD
PENCIL
SUPPLIES STORE
WAVES
LOWEST PRICE
SECOND LOWEST
Vendor Lowest Price
Vendor 2nd Lowest Price
[Code] .......
I have above table and wants to get the formula for getting the 1) Vendor Name of the Lowest Price per item 2) Vendor Name of the 2nd Lowest Price per item 3) and be able to copy down the formula for other items.
I have on sheet1 a name "brent alpha" which I need to look up in sheet2 and return the header of which ever column it is under,
Sheet 2 consists of 3 columns with a list of data under each one. As I said all I want to do is return the header.
I've got a spreadsheet with various amounts in cells A3:L5. I want to find the last non-blank entry in each row but only where the entry is in a column headed "Guaranteed PRB" (found in row 1). Then I want it to return the column header title found in row 2, which is a date.
I've attached a sample of the spreadsheet with the expected answer in column M.
I've got as far as formula:
=LOOKUP(2,1/(a3:l3<>""),$a$2:$l$2)
how to also make it look at row 1's headers too.
I'm currently using the formula
=IFERROR(INDEX(startmonthsp,MATCH(TRUE,INDEX(ISNUMBER(E2:AR2),0),0)),"").
The startmonthsp name refers to the months across the top of my pivot table. This formula works but I now need one small change. If the value in the columns are zero or less then I do not want the formula to return that column header (bypass it until it gets a positive value above zero).
Attached is a workbook that shows my formula in action.
Excel Forum Question.xlsx
I've got numerical data in columns A through AF, starting in row 4. I need a formula, starting in AG4 that I can drag down. I need the formula to look back across the row until it gets to the last posistive number, then return the column header of that column (the column headers are in row 3)
so for example
Header row
Jan Feb Mar Apr May Jun Jul Aug
Data
0 3 0 0 8 0 0 0
the formula would return May in this example as 8 is the las positive value and the column header for that column is 8. There are no blank cells in the data.
I have a list of names and the chores they need to do on a certain day. I need a formula that returns the chore the person needs to do when the date is filled in.
Ex: Sheet2 Col:A has names filled in A2:11 , row B1:J1 has dates that you would input.
formula goes in B2:J11
Sheet1 is the master with all the data the formula would be pulling from.
column A2:A11 has the names , row B1:S1 has the chore that needs to be done.
B2:S11 has the dates already filled in.
I am having trouble with getting a value (which is the row and column value) from a set of numbers. I have attached an example table to try and make things clearer.
What I have is a table with a set of Row Headers, and Columns Headers all numeric. e.g Columns headed 1, 2, 3, 4, Rows 30, 40, 50 etc. I want to find the 1st occurrence of a value e.g. 1.0 in the table (by 1st Up mean closest to top left), and then give me the value of the Row and Column Header that corresponds to that.
So for the example attached, I want to get the row Value 200 and Column 6 from finding the 1st occurrence of the number 1. I have tried various combinations of index and Match etc. But I can't get my head around the fact that the position of the 1st no. 1.0 can change, therefore I can't use any releative positions etc.
I have this table, which can be seen as a basic custom gantt chart: KLRWo.png
And I would like to fill the A column with start dates, based on the first filled cell of the range on the same row, and the header value of its respective column (row 1). It's easier to show my expected result than write it actually:
WiMZH.png
I have a data set with the weeks of the year as my column headers and a value of 1 (from a pivot table) in a distinct row value (removed for privacy) showing whether it existed in a given week based on pre defined criteria. What i need to do is ID the first (from the left) non blank cell in each row and then return that cells column header. I then need to do the same for the last (from the left) non blank cell in each row and then return that cells column header. On the attached I've put values in column N and O to show an example of what I need to return using a formula.
View 7 Replies View RelatedI've been using a nice colorful spreadsheet to use to schedule rooms for an organization. Visually it has worked out well but now I need to automatically generate a 'report' using that data. So...
I want to scan each row of a table and create another table with that data transformed.
That is, scan each row and whenever I find any text in a cell I want to return that text (the room being used) as well as the row and column header information (who is starting to use that room and on what date). I've attached a jpeg to show the example.
Ideally, when I scan the row and find text to return the headers I'd like the row scan to also find when the fill color changes and return that column header, too as that that would be the date that the room stops being used.
I have a data set, in which Sheet 1 have a matrix of high level showing Engineer, Program and commodity relationship.
I have to create separate sheet for each program on sheet 1, each program sheet should have Engineer name and commodity name from sheet 1.
Multiple commodities and multiple engineers should be separated by definite structure.
find worksheet with input and output (manual) as expected.
For column "B" count all the 1's if column header is equal to name in column A.
For Column "C" needs to be checked if a value was filled in column "I" if yes then check if in column "L" has a value, count all these values.
I am trying to write a formula where the column header of the row in which a value other than 0 exists, will display for each instance (row) where a value exists in an array spanning 3 columns. So the result cell could be any of the three column headers, or a combination thereof.
I started the formula in P2 of the GL Detail-2012 tab. File attached.
Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,))). Not working.
I would like to display the column header of the row in which a value other than 0 exists in a cell for each instance that value exists in an array spanning 3 columns. So the result cell could be any of the three column headers.
I started the formula in P2 of the GL Detail-2012 tab. (FILE TOO BIG)
Excerpt:
Resin Sand Eliminated Segment
- (12,896.65)-
- (6,570.85) -
- (11,503.80) -
- (13,188.50) -
If there is any value other than 0 in Resin, Sand or Eliminated columns, return that column's header under Segment.
Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,)))
I'm looking for an IF function as follow:
IF Column B doesn't have the word NO or NMI or "N/A" then Column A will remain the same. Otherwise, change to column B value.
Column A
375-9323
384-803
267-6491
Column B
D
NO
A
A
NMI
N/A
I've been playing with different Macro but haven't got any luck so far.
I've been searching the forums for this problem but I can't seem to find any answers. Anyway, this is the problem. See screenshot.
I want to compare A1 for the values in column B, then return the corresponding cell (column C) in column D.
e.g. D1 = 2, D2 = 1, D3 = 4, D4 = 5 and D5 = 3.
I have a spreadsheet with several columns (all column names are in row 1).
I have 2 of column names. Note that their actual column# might change so the macro would have to look for the column name and NOT the column position ...
I have software (SAS Add-In for Microsoft Office) that loads external data into Excel. The data has a title, header, and rows/columns. It automatically creates a named range such as Table1. The named range does NOT include the headers.
Here is an example:
Code:
SASApp:SASHELP.CLASS
Name
Sex
[Code]....
As above, can I dynamically derive the column number based on the header row of the named range, where such named range refers to a table?
On a related topic, can I derive the column name given the column number? For example, in pseudocode:
Code:
For currCol = firstCol To (firstCol + lastCol - 1)
' Assume a function called ColumnName
Debug.Print ColumnName(currCol)
Next
I am trying to use a nested INDEX and MATCH array formula to return the value in column C when matching column A and column B, but with a few more criteria.
The range containing all the data
A
B
C
1
Cat 1
January 1, 2014
John
[Code] ..........
I am looking for the array formula to return the name of the person in column C who is in Cat 1 after the date in column B.
For example;
C7 should return "John" because B7 requests "January 15, 2014", which is after the value in B1
C8 should return "John" because B8 requests "February 15, 2014", which is after the value in B1
C9 should return "Andrew" because B9 requests "August 15, 2014", which is after the value in B4
The best try I had for the formula in C7 was
{(INDEX($A$1:$C$4,MATCH(1,($B$1:$B$4>=B7)*(A$1:$A$4=A7),0),3))}
This brings back "John" as desired in C7, but when copying down the table into C8 and C9 both C8 and C9 return Andrew.
I guess this is due to my ">=" condition in the Match formula and it is returning "Andrew" because "Andrew" is also after the date requested, but I cannot for the life of me work out how to get it to work.